enigma2011's posts

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 4]

Chill bhai can you please xplain the part in Bold., Are I & M simple variables?

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 4]

Hey one doubt, do the sealing rate is 400 bottles per minutes? I m getting none of these:shock:

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 4]

Hey Jainbhai and Xane.. dint understand how its 3. whats the catch here?:banghead:

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 4]

1..The number of quadratic eqns which are unchanged by squaring their roots =

a..2 b..4 c..6 d..none of these

Plz post the approach too

a..2 b..4 c..6 d..none of these

Plz post the approach too

enigma2011
replied to CAT 2011 Exam Dates

hey puys.. CAT Registration has just begun . Please post your dates and location!! The Countdown begins.. ATB!!!! [smiley] [smiley]

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enigma2011
replied to Official Quant Thread for CAT 2011 [Part 3]

same doubt.. Puys how can we be sure that his age is 14? Did i miss out on any part of the question?

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 3]

Is the Venn correct.. I guess the question should be how many read BI & BW

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 3]

Are you sure its 'who will not"? I getting a answer of 59 if the question is "who will be"..

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 3]

Arithmetic mean > Geometric Mean..

As x,y,z are in AP y=(x+z)/2

three numbers : AM=(x+y+z)/3....(i)

GM= (xyz)^1/3 .....(ii)

substitute x+z=2y in (i) and xyz=4 in (ii).

We get 3y/3 > 4 ^(1/3)

Hope its clear..

P.S : There are my first few quant posts. Please bear with me puys..

As x,y,z are in AP y=(x+z)/2

three numbers : AM=(x+y+z)/3....(i)

GM= (xyz)^1/3 .....(ii)

substitute x+z=2y in (i) and xyz=4 in (ii).

We get 3y/3 > 4 ^(1/3)

Hope its clear..

P.S : There are my first few quant posts. Please bear with me puys..

6

enigma2011
replied to Official Quant Thread for CAT 2011 [Part 3]

given xyz = 4 and xyz are in AP.. As xyz are in AP and so 2y= x+z ..

For any series we know AM>=GM..

Hence (x+y+z)/3 >= (xyz)^1/3

3y/3>4^(1/3)

y>= 2^(2/3)..

Whats the OA?

For any series we know AM>=GM..

Hence (x+y+z)/3 >= (xyz)^1/3

3y/3>4^(1/3)

y>= 2^(2/3)..

Whats the OA?

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