enigma2011's posts
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 4]
Chill bhai can you please xplain the part in Bold., Are I & M simple variables?
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 4]
Hey one doubt, do the sealing rate is 400 bottles per minutes? I m getting none of these:shock:
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 4]
Hey Jainbhai and Xane.. dint understand how its 3. whats the catch here?:banghead:
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 4]
1..The number of quadratic eqns which are unchanged by squaring their roots =
a..2 b..4 c..6 d..none of these
Plz post the approach too
enigma2011 replied to CAT 2011 Exam Dates
hey puys.. CAT Registration has just begun . Please post your dates and location!! The Countdown begins.. ATB!!!! [smiley] [smiley]
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enigma2011 replied to Official Quant Thread for CAT 2011 [Part 3]
same doubt.. Puys how can we be sure that his age is 14? Did i miss out on any part of the question?
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 3]
Is the Venn correct.. I guess the question should be how many read BI & BW
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 3]
Are you sure its 'who will not"? I getting a answer of 59 if the question is "who will be"..
enigma2011 replied to Official Quant Thread for CAT 2011 [Part 3]
Arithmetic mean > Geometric Mean..
As x,y,z are in AP y=(x+z)/2
three numbers : AM=(x+y+z)/3....(i)
GM= (xyz)^1/3 .....(ii)
substitute x+z=2y in (i) and xyz=4 in (ii).
We get 3y/3 > 4 ^(1/3)
Hope its clear..
P.S : There are my first few quant posts. Please bear with me puys..
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enigma2011 replied to Official Quant Thread for CAT 2011 [Part 3]
given xyz = 4 and xyz are in AP.. As xyz are in AP and so 2y= x+z ..
For any series we know AM>=GM..
Hence (x+y+z)/3 >= (xyz)^1/3
3y/3>4^(1/3)
y>= 2^(2/3)..
Whats the OA?
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