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    chana

    0 Followers 0 Following 0 Pings 7 Posts 6 Karma Score
    chana's posts
    chana replied to SPJIMR 2012-2014 Final Converts
    chana
    17 Apr '12
    Made into IIM L Now the Marketing wait list will move Congrats for those making into this wonderful institution
    1 1
    chana
    08:13 PM, 17 Apr '12
    SPJIMR 2012-2014 Fina...
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    17 Apr '12
    Made into IIM L :) Now the Marketing wait list will move :) Congrats for those making into this wonderful institution :) :)
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      chana replied to IIM Lucknow[ Final Converts] Batch of 2014 Disc...
      chana
      17 Apr '12
      Yay!! finally made it to L
      chana
      08:17 AM, 17 Apr '12
      IIM Lucknow[ Final Con...
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      17 Apr '12
      Yay!! finally made it to L
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        chana replied to SPJIMR Profile Sheet and Admission Queries Disc...
        chana
        07 Feb '12
        I was able to submit the form but when I try printing it , I see that my academics and behavioural details are missing. Is anyone else also facing same problem?
        chana
        11:06 AM, 07 Feb '12
        SPJIMR Profile Sheet a...
        • Report
        07 Feb '12
        I was able to submit the form but when I try printing it , I see that my academics and behavioural details are missing. Is anyone else also facing same problem?
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          chana replied to [2012-2014] IIM Lucknow Call Getters Discussion
          chana
          18 Jan '12
          Hi Sushrut,
          I have the similar question as above. When I take aggregate of percentages, it is 80.81. But when I divide total_marks_obtained/total_maximum_marks (for all semesters), I am getting 80.67 which I had to round it off 1 digit after decimal in CAT form, so I entered 80.7% . Is it ok t...
          chana
          05:36 PM, 18 Jan '12
          [2012-2014] IIM Luckno...
          • Report
          18 Jan '12
          Aggregate marks are always the safest bet. Enter your marks for all semesters combined.

          Regards

          Hi Sushrut,
          I have the similar question as above. When I take aggregate of percentages, it is 80.81. But when I divide total_marks_obtained/total_maximum_marks (for all semesters), I am getting 80.67 which I had to round it off 1 digit after decimal in CAT form, so I entered 80.7% . Is it ok that I enter 80.7 for the Lucknow form as well? Thanks.
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            chana replied to Official Quant Thread for CAT 2011 [Part 4]
            chana
            23 Aug '11
            How many such such numbers (pqrs) can exist???
            Is the answer 90?
            chana
            03:41 AM, 23 Aug '11
            Official Quant Thread ...
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            23 Aug '11
            How many such such numbers (pqrs) can exist???
            Is the answer 90?
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              chana replied to Official Quant Thread for CAT 2011 [Part 4]
              chana
              23 Aug '11
              Is the answer 59?
              chana
              03:10 AM, 23 Aug '11
              Official Quant Thread ...
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              23 Aug '11
              chalo ek easy ho jaye
              Identical black tiles, in the shape of a square of side 3 cm, are placed along the two diagonals of a square shaped floor of side 39 cm. The rest of the floor is covered with identical white tiles of same shape and size. How many white tiles need to be replaced by the black tiles so that the black and the white tiles are in alternate positions in all the rows and columns?

              Is the answer 59?
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                chana replied to Official Quant Thread for CAT 2011 [Part 4]
                chana
                23 Aug '11
                (50*1)+ (49*2) + (48*3)+.....(1*50)
                =2 ( 50*1 + 49*2 + 48*3 + .. + 26*25 )
                =2 ( (51-1)*1 + (51-2)*2 + (51-3)*3 + .+(51-25)*25)
                = 2 ( 51(1+2+.+25) (1*1 + 2*2 + .25 *25) )
                =2 ( 51(325) (5525))
                = 2 * 11050 = 22100
                Is it correct?
                2 2
                chana
                02:38 AM, 23 Aug '11
                Official Quant Thread ...
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                23 Aug '11
                Find the value of (50*1)+ (49*2) + (48*3)+.....(1*50) ???

                The options available are
                a) 21050
                b)22100
                c)23100
                d)24200
                e)21300

                (50*1)+ (49*2) + (48*3)+.....(1*50)
                =2 ( 50*1 + 49*2 + 48*3 + .. + 26*25 )
                =2 ( (51-1)*1 + (51-2)*2 + (51-3)*3 + .+(51-25)*25)
                = 2 ( 51(1+2+.+25) (1*1 + 2*2 + .25 *25) )
                =2 ( 51(325) (5525))
                = 2 * 11050 = 22100



                Is it correct?
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