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    bakra
    Nitin Tibrewal
    0 Followers 0 Following 0 Pings 7 Posts 0 Karma Score
    bakra's posts
    bakra replied to Official Quant Thread for CAT 2011 [Part 2]
    bakra
    28 Jun '11
    cn sum1 plz help me out wid dis 1......
    all the nine digits are arranged here so as to form four square numbers
    9 81 324 576
    how wld you put them together so as to form a single smallest and single largest square number respectively???? kindly...
    bakra
    05:23 PM, 28 Jun '11
    Official Quant Thread for CAT 2011 [P...
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    28 Jun '11
    cn sum1 plz help me out wid dis 1......

    all the nine digits are arranged here so as to form four square numbers
    9 81 324 576
    how wld you put them together so as to form a single smallest and single largest square number respectively???? kindly send in your solution wid d explanations.......
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      bakra replied to Official Quant Thread for CAT 2011 [Part 2]
      bakra
      28 Jun '11
      cn ne1 plz help me out wid dis prob????
      Fifty mins ago if it was four times as many mins past three o'clock, how many minutes is it to six o'clock??
      bakra
      03:38 PM, 28 Jun '11
      Official Quant Thread for CAT 2011 [P...
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      28 Jun '11
      cn ne1 plz help me out wid dis prob????

      Fifty mins ago if it was four times as many mins past three o'clock, how many minutes is it to six o'clock??
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        bakra replied to GMAT Problem Solving Discussions
        bakra
        27 Jun '11
        i think 2520 is correct even i gt d same answer
        bakra
        01:25 PM, 27 Jun '11
        GMAT Problem Solving Discussions
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        27 Jun '11
        We have to make 4 Teams out of the available 8 people.....
        8C2*6C2*4C2*2C2 should give us the answer = 2520
        Thus, B

        But I doubt if this is correct, because 2520 is an insanely high number for just 8 teams, what is it that I am missing? Can someone please figure out.


        i think 2520 is correct even i gt d same answer
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          bakra replied to CAT 2011 LR-DI thread
          bakra
          27 Jun '11
          my answers are cuming 130, 80 and 10...... i used the venn diagram concept of n(A U B U C).....
          bakra
          01:13 PM, 27 Jun '11
          CAT 2011 LR-DI thread
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          27 Jun '11
          6

          6

          Thursday

          I am getting answers as

          1.150
          2.100
          3.10

          Answers are not matching with the options .Please help


          my answers are cuming 130, 80 and 10...... i used the venn diagram concept of n(A U B U C).....
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            bakra replied to CAT 2011 LR-DI thread
            bakra
            27 Jun '11
            cn sum1 plpz help me n temme y is thursday n nt friday..... If thursday is correct den friday may also b correct.....
            bakra
            01:00 PM, 27 Jun '11
            CAT 2011 LR-DI thread
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            27 Jun '11
            6

            6

            Thursday


            cn sum1 plpz help me n temme y is thursday n nt friday..... If thursday is correct den friday may also b correct.....
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              bakra replied to Official Quant Thread for CAT 2011 [Part 2]
              bakra
              24 Jun '11
              can u plz elaborate on dis a lil more.... d 1st line???
              bakra
              11:08 PM, 24 Jun '11
              Official Quant Thread for CAT 2011 [P...
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              24 Jun '11
              groups of six 8s and 9s are divisible by 7.
              first 48 8s and last 48 9s are taken care of this way.
              Hence the number in the middle, 88A99 has to be divisible by 7.
              So A=5


              can u plz elaborate on dis a lil more.... d 1st line???
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                bakra replied to Official Quant Thread for CAT 2011 [Part 2]
                bakra
                24 Jun '11
                Solution:
                the answer is 42...... any number ending with 5 can only occur once as any duplication will render it divisible by 10..... the same logic applies to any direct multiple of 10..... now 1 and 9 cannot appear together.... bt either of d two can appear and dat is possible in 10 ways........
                bakra
                11:00 PM, 24 Jun '11
                Official Quant Thread for CAT 2011 [P...
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                24 Jun '11
                rahul005 Says
                Let A be a set of N different integers from the set (1,2,3....100) such that the sum of two different elements of A is never divisible by 10.The greatest possible value of N is.....a)42 b)41 c)49...pls do show the entire procedure.

                Solution:
                the answer is 42...... any number ending with 5 can only occur once as any duplication will render it divisible by 10..... the same logic applies to any direct multiple of 10..... now 1 and 9 cannot appear together.... bt either of d two can appear and dat is possible in 10 ways...... same goes for 2 or 8, 3 or 7, 4 or 5..... so dat makes it 4*10=40 plus 2( for 5 and 10 as discuused before)..... thus the answr is 42
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