ankitverma.jss's posts

ankitverma.jss
replied to [2010-2012] IIM Indore Call Getters Discussion

@koolmac86

jst write first classs..

jst write first classs..

ankitverma.jss
replied to CAT 2008: Analysis, Experience, Discussions , &...

puys,check the second link(cat-iim 2008-home) given in the derrida's post,u'll see a link for cat iim result 2008 n some latest news.now check the link catiim.in,no such information given there.its becoming really confusing.

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ankitverma.jss
replied to CAT 2008: Analysis, Experience, Discussions , &...

latest news:-

CAT RESULTS The results of CAT 2008 will be available on the cat website: CAT - IIM 2008 - Home on the 8th of January from 3 PM onwards.

CAT RESULTS The results of CAT 2008 will be available on the cat website: CAT - IIM 2008 - Home on the 8th of January from 3 PM onwards.

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ankitverma.jss
replied to CAT 2008: Analysis, Experience, Discussions , &...

i think 61.46 was ur % marks(59/96) not the actual marks...as far as i remember that ques was dropped from evaluation...

ankitverma.jss
replied to new thread for AIMCAT 0905 scores and discussion

i totally agree with u..it seems the ques. asks fo the max value of z...for all values less than 400,U has the max. profit..put this doubt on the time discussion forum too,lets see wat mod. n others have a say on this ......

ankitverma.jss
replied to [31th August, 2008] TIME- AIMCAT 0909 Discussio...

doubt in qn-29.

acc. to time solu. they have taken product of two independent terms at a time and then finds the ratio.but if take the product of all the 4 terms then also the product is coming out to be a constant which means that for the sum to be minimum x/y=z/12x=4y/x=x/3z =>x/y=x/3z =>y:z...

acc. to time solu. they have taken product of two independent terms at a time and then finds the ratio.but if take the product of all the 4 terms then also the product is coming out to be a constant which means that for the sum to be minimum x/y=z/12x=4y/x=x/3z =>x/y=x/3z =>y:z...

1