Doing the first one... Let 10^10 = R => 10^30 mod(10^10 + 3) = R^3 mod (R+3) = (-3)^3 => 10^30 = (10^10+3)*D - 27 Highest power of 2 shd be 3..as no other values give a perfect remainder..

i thnk u frgot 2 consider greatest integer function

mere bhai, kabhi bhi de de. koi tension ki baat nahi. of course, itna to clear hi hoga ki ab tu center pe jaake nahi de sakta. ab tujhe url ko manipulate karke ghar pe hi dena padega.:splat::splat:

godfather...i heard that ...dat url thing is not working now:shocked:

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