Login
Advertisements
Advertisements
MaskedMenace's posts
MaskedMenace replied to AIMCAT 1318: Discussion thread
The guy who started the thread should have made it public while creating a poll, then its possible to see the names of guys who polled.
I think, now a moderator can change it.
1 1
MaskedMenace commented on an article
Shaishav Amrut Solanki, is the Indian Institute of Management (IIM) Indore's first author - could very well be the first on-campus author among all IIMs. Having just released a book few days ago, the young author is all smiles seeing it do brisk business. The book, the author claims is as much fiction as non-fiction and abo...
46 31 Comments
Clifford_Dsouza if writers move into Managerial colleges then where would.... 17 Nov '11.
AssassinCT Disheartened after reading his interview. Very negativ.... 07 Feb '12.
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 6]
We need to find numbers divisible by 3,5 and eliminate those divisible by 21,35,15 and add those divisible by 105.
divisible by 3 => 102 to 999 => 897/3 + 1 => 300
divisible by 5 => 105 to 995 => 895/5 + 1 => 180
Divisible by 21 => 21*47 is near 999 so , 47 - 4 = 43 such numbers
Divis...
4 4
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
Its not possible to make all of them equal.
2 2
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
129*127*125*122*119*117
Last digit is 0
now, Last two digits of
29*27*25*61*19*17 is 25
1/x + 1/y = 1/196
(x+196)(y+196) = 196^2
RHS takes all the divisors of 196^2 = 14^4 => 7^4 * 2^4 => 25
(Oops Ordered pairs i ignored)
@RC89 : Wish you a Happy Birthday
3 3
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
Its 2^n - 1, n is number of weights
(For more info search for towers of Hanoi)
1 1
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
It will be 168
2 2
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
7^6 is the number of cases in which the 6 tickets chosen are numbered between 1 to 7 i.e., where there is no 8, 9 or 10.
6^6 is the number of cases in which the 6 tickets are numbered between 1 to 6 i.e. where there is no 7, 8, 9 or 10.
7^6 - 6^6 is the no of cases in which 7 is there and a...
5 5
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
Here are the solutions
(19,684)
(21,252)
(27,108 )
(45,60)
(99,44)
4 4
MaskedMenace replied to Official Quant Thread for CAT 2011 [Part 5]
Two digit prime numbers can be
(11,31,41,61,71) & (17,37,47,67,97)
or
(13,23,43,53,73,83)&(19,29,59,79,89)
So, total distinct products are 5*5 + 6*5 = 55
Case 1: 3_ _ _ => 27 - 2 => 25
Because, we do not get 222 & 333 case
Case 2: 4_ _ _ => 27 - 1 => 26
Because we do not g...