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    CANI
    Nikhilesh Jha
    15 Followers 17 Following 0 Pings 318 Posts 354 Karma Score
    CANI's posts
    CANI replied to CAT 2012 - Registration - Discussion Thread
    CANI
    30 Jul '12
    Guys what is the cost of the form... searched the net but only last years price are mentioned...
    CANI
    05:03 PM, 30 Jul '12
    CAT 2012 - Registration - Discussion ...
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    30 Jul '12
    Guys what is the cost of the form... searched the net but only last years price are mentioned...
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      CANI replied to Official Quant Thread for CAT 2012
      CANI
      26 Jul '12
      @[521683:harry31]In the country the average salary is calculated on the basis of 14 months.and the average expenses is calculated on the basis of 10 months. what will happen to the average saving per month with respect to actual saving (calculated on the basis of 12 months)?
      decrease increa...
      CANI
      04:29 PM, 26 Jul '12
      Official Quant Thread for CAT 2012
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      26 Jul '12

      @[521683:harry31]

      In the country the average salary is calculated on the basis of 14 months.and the average expenses is calculated on the basis of 10 months. what will happen to the average saving per month with respect to actual saving (calculated on the basis of 12 months)?

      decrease
      increase
      no change
      cannot be determined


      in the above question what will be the net percentage change in the saving with respect to the actual saving?
      11.11%
      22.22%
      33.33%
      cannot be determined

      14*sal-10*exp=net saving
      we don't know the no. of months on whose basis saving is calculated so CBD
      If it saving were avg. saving weres difference of averages then change would be 0% in next question and that is not in the option.

      CBD

      So CBD for both??

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        CANI replied to Official Quant Thread for CAT 2012
        CANI
        25 Jul '12
        @Erudite.Cat Q. Three camels are standing in a triangular field, which is exactly 100m on each side. One camel stands at each corner; and simultaneously all three set off running. Each camel runs after the camel in the adjacent corner on his left, thus following a curved course, which terminate...
        CANI
        05:26 PM, 25 Jul '12
        Official Quant Thread for CAT 2012
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        25 Jul '12

        @Erudite.Cat

        Q. Three camels are standing in a triangular field, which is exactly 100m on each side. One camel stands at each corner; and simultaneously all three set off running. Each camel runs after the camel in the adjacent corner on his left, thus following a curved course, which terminates in the middle of the field with all three camel arriving there together. The camels obviously ran at the same speed, but just how far did they run?

        Middle of the field is mentioned so it has to be centroid. Here the height will be ✓3X100/2 and distance from the vertex will be (2/3)X✓3X100/2

        =100/✓3m.???

        Since it is mentioned far I am assuming they are asking for displacement.

        What is the OA?

        Puys please try this question

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          CANI replied to Official Quant Thread for CAT 2012
          CANI
          25 Jul '12
          @[543068:CBZ123] There is a 5x5 square grid,with each of the call having individual identity.In how many ways can 3 identical coins be placed in the grid(one in each cell) such that no 2 are placed in same row or column. One coin can be places in 25ways.
          Second coin in 25-9=16 ways.
          Thi...
          CANI
          05:24 PM, 25 Jul '12
          Official Quant Thread for CAT 2012
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          25 Jul '12

          @[543068:CBZ123]

          There is a 5x5 square grid,with each of the call having individual identity.In how many ways can 3 identical coins be placed in the grid(one in each cell) such that no 2 are placed in same row or column.

          One coin can be places in 25ways.
          Second coin in 25-9=16 ways.
          Third coin in 16-7=9 ways
          So 25X16X9=3600 ways?

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            CANI replied to Official Quant Thread for CAT 2012
            CANI
            25 Jul '12
            @[569305:Faruq] In how many ways can 14 different objects be divided among 4 people, two of them getting 4 items and other two getting 3 items each ? 4C2*14C4*10C4*6C3=6*1001*210*20 Thnx @[569305:Faruq] bhai learnt a lot
            1 1
            CANI
            01:02 PM, 25 Jul '12
            Official Quant Thread for CAT 2012
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            25 Jul '12

            @[569305:Faruq]

            In how many ways can 14 different objects be divided among 4 people, two of them getting 4 items and other two getting 3 items each ?

            4C2*14C4*10C4*6C3=6*1001*210*20

            Thnx @[569305:Faruq] bhai learnt a lot

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              CANI replied to Official Quant Thread for CAT 2012
              CANI
              25 Jul '12
              @[569305:Faruq] In how many ways can 4 different rings go in to 2 fingers ?
              In how many ways can 4 identical rings go in to 2 fingers ?
              4 different rings, 2 fingers arrangement matters 5!/1!=120 4 Identical rings, 2 groups 5C1=5??
              1 1
              CANI
              12:33 PM, 25 Jul '12
              Official Quant Thread for CAT 2012
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              25 Jul '12

              @[569305:Faruq]

              In how many ways can 4 different rings go in to 2 fingers ?


              In how many ways can 4 identical rings go in to 2 fingers ?

              4 different rings, 2 fingers arrangement matters
              5!/1!=120

              4 Identical rings, 2 groups

              5C1=5??

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                CANI replied to Official Quant Thread for CAT 2012
                CANI
                25 Jul '12
                @[595020:Erudite.Cat] The first two are eliminated since the 10s digit is not a multiple of 5 The last one when multiplied by 5 will not satisfy the condition. The third one 142857 multiplied by 5 does so 142857.
                1 1
                CANI
                12:23 PM, 25 Jul '12
                Official Quant Thread for CAT 2012
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                25 Jul '12

                @[595020:Erudite.Cat]

                The first two are eliminated since the 10s digit is not a multiple of 5

                The last one when multiplied by 5 will not satisfy the condition.

                The third one 142857 multiplied by 5 does so

                142857.

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                  CANI replied to Official Quant Thread for CAT 2012
                  CANI
                  24 Jul '12
                  @[340778:freebull] say the weight is 5
                  Initial value-- 25k
                  After breaking 4k+9k=13k
                  Loss 12k
                  Loss%12/25X100=48%
                  1 1
                  CANI
                  05:44 PM, 24 Jul '12
                  Official Quant Thread for CAT 2012
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                  24 Jul '12

                  @[340778:freebull]

                  say the weight is 5
                  Initial value-- 25k
                  After breaking 4k+9k=13k
                  Loss 12k
                  Loss%12/25X100=48%

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                    CANI replied to Official Quant Thread for CAT 2012
                    CANI
                    24 Jul '12
                    @[367795:arpitrkothari] @[474787:deedeedudu] what are the remainders when 1234567...........979899 is divided by 101 and 1001??? plz share the approach also, i dont know the OA.. For the 1st case it'll be 34
                    For getting divisibility 2 pairs from right are considered with alternating + & - ...
                    CANI
                    05:22 PM, 24 Jul '12
                    Official Quant Thread for CAT 2012
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                    24 Jul '12

                    @[367795:arpitrkothari]

                    @[474787:deedeedudu]

                    what are the remainders when 1234567...........979899 is divided by 101 and 1001???

                    plz share the approach also, i dont know the OA..

                    For the 1st case it'll be 34
                    For getting divisibility 2 pairs from right are considered with alternating + & - sign
                    eg 96979899
                    -96+97-98+99=2 this will be the remainder when divided by 101
                    For 1001 3 no pair is considered

                    DD Bhai a little help from 10 to 99 there will be 99-10+1=90 numbers which will give 90/2=45

                    And first ten digits will give 1-23+45-67+89=45

                    So shouldn't it be 90?

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                      CANI replied to Official Quant Thread for CAT 2012
                      CANI
                      24 Jul '12
                      @[367896:sumeet1489] A calculator company produces a scientific calculator and a graphing calculator. Long-term projections indicate an expected demand of at least 100 scientific and 80 graphing calculators each day. Because of limitations on production capacity, no more than 200scientific and ...
                      CANI
                      04:18 PM, 24 Jul '12
                      Official Quant Thread for CAT 2012
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                      24 Jul '12

                      @[367896:sumeet1489]

                    • A calculator company produces a scientific calculator and a graphing calculator. Long-term projections indicate an expected demand of at least 100 scientific and 80 graphing calculators each day. Because of limitations on production capacity, no more than 200scientific and 170 graphing calculators can be made daily. To satisfy a shipping contract, a total of at least 200 calculators much be shipped each day.

                      If each scientific calculator sold results in a $2 loss, but each graphing calculator produces a $5 profit, how many of each type should be made daily to maximize net profits?

                    • max. 200 scientific
                      max. 170 graphic
                      At least 200 total.
                      Minimum scientific and Maximum graphic
                      make 170 graphic and 30 scientific. 80 graphic will be sold atleast the rest 90 will give no profit or loss since production cost is not mentioned. I think.. what is the OA?

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