Last minute study according to importance of topics

Do 20 questions of each of these not as a test but just relax lie on bed and read through them.

Logic ability
Puzzles*****
Coding Decoding*****
Number Series*****
Deductions*****
Decision Making****
Symbols & notations****
Input and Output****

DI/DS
Tables*****
Bar Graphs*****
Line / Pie charts****
DS****

Quant
BODMAS*****
Data Comparison*****
Equations (simple)*****
Geometry*****

Verbal
RCs*****
Cloze passages*****
Fill in the blanks*****
Sentence Correction*****


Visual
Series based questions*****
Analogies*****
Odd man out*****

Verbal Reasoning
Courses of Action*****
Cause and Effect*****
Statements conclusions assumptions and inferences*****

Can someone plzz tell how to solve these n even the approach...complete the series

1) 10 30 68 130 222 350
12 a b c d e
What will come in place of c? -- 105, 252,132 ,150 or none of these.

2) 897 681 556 492 465 457
815 a b c d e
What will come in place of d? -- 367, 375, 364 ,383 or none of these.

Thanks in advance....

1) 150...

The above series is N^3+ N...10 = 2^3+ 2
The below series seems N^3+N^2...or N^2(N+1)...starting from 2 again...

12= 2^3+ 2^2

so C should be 5 square + 5 cube = 150

2) 383

Difference between terms is decreasing in the order of cubes...starting with 6 cube

897 - 681 = 216...6 cube
681 - 556 = 125...5 cube
556 - 492 = 64.....4 cube and so on....

Do the same for below series...you want d...so add 216 + 125 +64 +27 = 432

815 - 432 = 383

Can someone plzz tell how to solve these n even the approach...complete the series

1) 10 30 68 130 222 350
12 a b c d e
What will come in place of c? -- 105, 252,132 ,150 or none of these.

2) 897 681 556 492 465 457
815 a b c d e
What will come in place of d? -- 367, 375, 364 ,383 or none of these.

Thanks in advance....

cmat toppers will occupy more than half of the 18 seats( for oms )...........
chnce 4 getting jbims is less 4 oms students :-(

A suggestion from my side--Don't sit for MHCET...Why waste 2.5 hours of life when you know you are not going to gain anything out of it??!!!

Tell me one thing man, what use is it posting such stuff on a public forum at this crucial time...

Don't be a pessimist man...And even if you wanna be one, don't write it here...As I said, have a sound sleep this sunday afternoon...It would be good for your health at least

Yeah just the two documents. I guess this question has been answered at least 10 times so this should be confirmation enough for you

Statement :

Experts say work overload leads to stress. But some celebrities say that they find work an antidote to stress.

Conclusions:
1. Some celebrities are overloaded by work.
2. Experts don't judge properly every time.

a)Only 1 follows
b)Only 2 follows
c)Either 1 or 2
d)Neither
5)Both

Please give your suggestions. I have a doubt in this and will give the OA later.

My take here is D as well..

Celebrities say they find work antidote to stress and not Being overloaded with work... there is a subtle difference...as both things talk about two different things.

IMO
Conclusions:
1. Some celebrities are overloaded by work.
Some celebrities say that they find work an antidote to stress. we cannot conclude whether all or only few are overloaded with work from this statement. Ruled out.
2. Experts don't judge properly every time.
"work overload" leads to stress not the work itself (as mentioned in second sentence) . Can't conclude.

My answer: D - neither

shrutzvilla Says

puys... we have to carry only two documents to the exam hall - admit card and id proof.. that's it naa.. no third thing? jz confirming #anxious

Yeah just the two documents. I guess this question has been answered at least 10 times so this should be confirmation enough for you

Statement :

Experts say work overload leads to stress. But some celebrities say that they find work an antidote to stress.

Conclusions:
1. Some celebrities are overloaded by work.
2. Experts don't judge properly every time.

a)Only 1 follows
b)Only 2 follows
c)Either 1 or 2
d)Neither
5)Both

Please give your suggestions. I have a doubt in this and will give the OA later.

puys... we have to carry only two documents to the exam hall - admit card and id proof.. that's it naa.. no third thing? jz confirming #anxious

me4fms Says

The circumference of the front wheel of cart is 40 ft & tht of back wheel is 48 ft long.What is distance traveled by cart,when the front wheel has done 5 more revolutions than the rear wheel ?

My take:
Let n1 be revolutions of front wheel & n2 be that of rear wheel

now we know n2/n1 = 40/48 = 5/6

Give n1-n2 =5

n1 -5/6 n1 = 5 => n1 = 30

For 1 rev Front Wheel covers 40 ft, thus for 30 rev = 1200 :|

Wats d OA?

me4fms Says

The circumference of the front wheel of cart is 40 ft & tht of back wheel is 48 ft long.What is distance traveled by cart,when the front wheel has done 5 more revolutions than the rear wheel ?

My take :

Front wheel does 1 revolution for 40m
Back wheel does 1 revolution per 48m

Back wheel travels 8m more per revolution.
It will travel 40m more per 5 revolutions which is eqvt to one extra revolution of front wheel.

So for 5 more such extra revolutions, distance travelled by back wheel = 48x5x5 = 1200m.

Dear aspirants,

Hope this finds you in good spirit. My intention is not to bore you with addition to strategic gyan that floats around when CET is near, but to tell you few things that I have realized over a period of time when it comes to CET.

This is the time to wish you all the best and give some last-minute words of wisdom (If I may)

1. Enough of traditional preparation and mocks. This is the time to go through all the previous mocks, important notes, tips and tricks. Visit your old mocks, see where you made mistakes, what you could have done to avoid them. Focus on your strengths and keep your areas of weaknesses at the back of the mind. Dont get tempted by questions which might look easy on their face-value and end of wasting time on them.
At the same time, Dont study anything new now. There is no point. but personal suggestion, dont leave a particular area altogether. at-least you should be aware of the basics. It will always come handy in worst case scenario.

2. Strategy have a back up strategy. I am sure all of you have some strategy in mind, but its always advisable to have a realistic picture of its possible failure. Frame in mind what you gonna do if paper is too difficult or too easy. have a plan B.

3. Avoid distractions and temptations in next two days. Think of CET as the last exam of the season and put a definitive end to it. Dont get tensed at the same time don be casual about it. Be serious. 2012 CET is going to be the last CET. so why not give the best shot at it?

4. Dont assume anything with respect to CET difficulty level. (CET 2007 difficult, CET 08,09 moderate, CET 10 easy, CET 11 difficult.in short no particular pattern) Dont get into mode of speculation.

5. Success in all these tests is relative. When you are solving the paper, the only thing of your concern is your own paper, attempts and accuracy. The paper is going to be same for everyone, so there is no point pondering over what might be the cutoff during the exam. Your strategy is Maximum possible attempts in minimum possible time with maximum possible accuracy
6. On Saturday, do some light questions here and there, or five sprints of 40 questions so that you dont lose focus. Read important things and relax. Take sufficient rest. On Sunday, pray! Please reach at the venue in time. Take someone with you, it helps in getting rid of the anxiety. Carry all the prerequisites with you such as hall-ticket, application, water, watch, identity proof, extra pens etc. Enter all the details carefully. Dont panic. During the test, mark OMR carefully.


Nothing more from my side. Give your best shot. CET is you against yourself. Go and just do it. If you have worked hard before and do justice to the paper in those 2.5 hours, I am sure you will end up winning.
Give your best, thats all I want to say!

Ending the post with one of my favorite quotes:
When nothing seems to help, I go look at a stone-cutter hammering away at his rock perhaps a hundred times without as much as a crack showing in it. Yet at the hundred and first blow it will split in two, and I know it was not that blow that did it, but all that had gone before. Jacob Riis

Friday & Saturday last minutes before CET!

Dont take any more mocks you have solved enough mocks
If you want retake the mocks where you have scored good. It will be a great confidence booster to see your score zooming past your average
Laugh on the mistakes you have done or simple questions you left and make a mental note of not repeating the same mistake again
No new topics. dont waste your time on solving any new topics especially the one you are weak in
Revise a few concepts and formulae, foolproof strategies that you have developed for overall mocks and individual topics
Make mental maps of your exam centre and plan how you are going to travel to the centre
Watch movies that make your adrenaline rush! This will motivate you.
Ensure that you get a good nights sleep on last few days before CET.

cmat toppers will occupy more than half of the 18 seats( for oms )...........
chnce 4 getting jbims is less 4 oms students :-(

u need 1 seat for urself..!!

The circumference of the front wheel of cart is 40 ft & tht of back wheel is 48 ft long.What is distance traveled by cart,when the front wheel has done 5 more revolutions than the rear wheel ?

cmat toppers will occupy more than half of the 18 seats( for oms )...........
chnce 4 getting jbims is less 4 oms students :-(

bilious Says

Still confused with 1st ques ...:(

Let me try explaining another time step by step:

Time is 10 + 4:30 = 2:30 pm

At 2:30 both hands are few degrees apart.
Starting from 6 (where longer hand is) to mark of 3, we have 90 degrees.
From 3 to the point between 2 and 3 (where shorter hand is) it measures about 15 degrees.

So total difference is 105 degrees. See this if you still have doubts.

With longer hand leading shorter hand. Right?

Directions are 45 degrees apart : N-NE-E-SE-S-SW-W-NW.

Start with longer hand and move 105 degrees.
00 - NE
45 - N
90 - NW
105 - 15 degrees away from NW, but 30 degrees away from W.

(Hence I wrote NW at first, then got confused and made if W in post above :banghead:
Must log off PG for the day, before I postulate something ridiculous)

Answer should be data insufficient.
You are correct. M can have sons too.

i checked three books. They all say one is sufficient. now im really confused. are you sure about this?

My take:

1. Time is 10+4.5 hr = 2:30 pm
long hand points NE : towards bottom of clock
short hand points : approx W since angle between hands is approx 90+45 degrees.
use an analog clock if still in doubt.

2. Since we need exact amount, a statement with a price-value is required : 1
Now,
we get profit as % of CP directly from 2
OR
we get profit as % of SP from 3. But SP=CP+Profit, so we can determine from this as well

Still confused with 1st ques ...:( 90+45 should point south ....is this what you meant ???

i checked three books. They all say one is sufficient. now im really confused. are you sure about this?

Hi ,
Need help on the below ques :
1. The clock shows 10am . after 4.5 hours if the long hand faces NE , which direction is the short hand facing ?
a. N, b . E, c. NW, d. W, e. SE.

2. What is the profit earned on selling the Calculator ?
1. Cost of calc is Rs. 100
2. Profit is 25% of CP
3. Profit is 20% of SP
a. Only 1 and 2
b. Only 2 and 3
c. Only 1 and 3 or 2
d. Only 1 and 2
e. cbd

My take:

1. Time is 10+4.5 hr = 2:30 pm
See post below.

2. Since we need exact amount, a statement with a price-value is required : 1
Now,
we get profit as % of CP directly from 2
OR
we get profit as % of SP from 3. But SP=CP+Profit, so we can determine from this as well

gollumgollum Says

Hello Guys....I am a type A mumbai university student and i am expecting a very good result in cmat...now if it so happens that my cmat percentile is slightly more than my cet percentile, will i be shifted to the oms category??....if so, wouldnt it be a disadvantage since there would be only 18 seats to compete for instead of 40??...i know its a very noob question, but if not pagalguy, then where else???.http://www.pagalguy.net/pagalguy/smilies/icon_mrgreen.gif... another question: I have got a state rank within 40 in all the time mock cets....even rank 4 on one occasion.....so, on current form, are the time mocks a reasonably good indicator for entry in JBIMS ??

For the first one, there are separate rank lists for all india seats and maharashtra state seats. You can opt for college of your choice based on which list can get you there. You may mail DTE for further clarification of allotment rules this year.

Second question I cant answer. Not unless we see actual CET paper. But based on your ranks, you seem to have a very good chance of making it. BTW ,if you can, try another mock from another source, so that there is no doubt in your mind.

Good luck.

P.S. I think we will enter CMAT marks after we get CET results, so you would know which one is comparatively better (and most probably you have an option to opt out of all india seats, if you want)

Hi ,
Need help on the below ques :
1. The clock shows 10am . after 4.5 hours if the long hand faces NE , which direction is the short hand facing ?
a. N, b . E, c. NW, d. W, e. SE.

2. What is the profit earned on selling the Calculator ?
1. Cost of calc is Rs. 100
2. Profit is 25% of CP
3. Profit is 20% of SP
a. Only 1 and 2
b. Only 2 and 3
c. Only 1 and 3 or 2
d. Only 1 and 2
e. cbd

CET 2006 paper

Data Sufficiency question

44. How many children does M have ?
I) H is the only daughter of X who is wife of M
II) K and J are brothers of M

The answer given is that one is sufficient. But M could have sons too right ?

please help!

Answer should be data insufficient.
You are correct. M can have sons too.

Hello Guys....I am a type A mumbai university student and i am expecting a very good result in cmat...now if it so happens that my cmat percentile is slightly more than my cet percentile, will i be shifted to the oms category??....if so, wouldnt it be a disadvantage since there would be only 18 seats to compete for instead of 40??...i know its a very noob question, but if not pagalguy, then where else???.http://www.pagalguy.net/pagalguy/smilies/icon_mrgreen.gif... another question: I have got a state rank within 40 in all the time mock cets....even rank 4 on one occasion.....so, on current form, are the time mocks a reasonably good indicator for entry in JBIMS ??

thanks and what is the circumference of a semi-circle?

what is the perimeter of a semicircle?
(pie*r) or (pie*r +2*r)??

pretty basic Q i know .. bt i have seen both them in diff mocks ..

It has to be (pie*r +2*r).

Perimeter means sum of length of sides, so pie*r (for circular part its)+ 2*r (for diameter)

It has to be pie*R

For eg = Radis of a circle is 2 then circumference: 2*pie*r = 4* pie = 12.56...

Circumference of Semi Circle = 2*Pie = 6.28...

But as per " ( pie*r + 2*r) "= ( 2*pie + 4 ) = 10.28.... which is not possible

Suppose the semicircle is actually a garden with a path along the borders.
You are taking a walk and if you are to calculate the total distance traveled, then won't you consider the path which is equal to 2r?

Perimeter is (pie*r + 2*r)

what is the perimeter of a semicircle?
(pie*r) or (pie*r +2*r)??

pretty basic Q i know .. bt i have seen both them in diff mocks ..

It has to be pie*R

For eg = Radis of a circle is 2 then circumference: 2*pie*r = 4* pie = 12.56...

Circumference of Semi Circle = 2*Pie = 6.28...

But as per " ( pie*r + 2*r) "= ( 2*pie + 4 ) = 10.28.... which is not possible

what is the perimeter of a semicircle?
(pie*r) or (pie*r +2*r)??

pretty basic Q i know .. bt i have seen both them in diff mocks ..

guys... how CMAT score will convert in mhcet,,.........????


one of my friend told.--------if some 1 gets 250/400 in cmat then tht will be as 125/200 in cet

is this true...as CMAT result will not contain the %ile

The conversion method you mentioned has very slim chances of being implemented in cet.

Traditionally, percentiles have been considered. But since cmat has ranks, they might either calculate percentile based on ranks or directly award you cet marks of equivalent rank.

Here are details of prev method.

pagalguy.com/2011/01/the-maharashtra-cet-ready-reckoner/

Btw not much point speculating.

guys... how CMAT score will convert in mhcet,,.........????


one of my friend told.--------if some 1 gets 250/400 in cmat then tht will be as 125/200 in cet

is this true...as CMAT result will not contain the %ile

Is your friend the Chairperson, Admissions at the DTE?? If no, I don't see any reason why you should believe him/her...

Even in simple terms, the logic is highly flawed because there would be very few people who would score close to 300 in CMAT whereas if the CET paper is on the lines of 2010, there might be many who would score 150+ in CET...And what if someone scores, say 291 in CMAT...Would he/she get 145.5 in CET??

So far, DTE has also considered CAT scores...The method that is followed is that the percentile one obtains in CAT, if it is higher than that obtained in CET, is taken as the candidate's percentile in CET...This is the first time that CET is also taking CMAT score...So wait for the official stand and

AVOID SPECULATIONS

karan20 Says

is the ans 44 ?

No the ans is 55

how to solve this Q...pls rep...

Q) How many numbers less than 999 have the sum of their digits equal to 9?

Consider the following combinations, these can be rearranged, and zero can not be first digit.

One digit : 9 : 1
Two digit : 90, 81, 72, 63, 54 : 9
Three digit :
a) 2 zeros followed by one digit num : 1
b) zero followed by two digit num (except 90): 8
c) zero between two digits of 2 digit num (except 90): 8
d) three digit combo, each can be written as 3! permutations, divide by factorial of number of digits that are same : 117,126,135,144,225,234,333 : 3+6+6+3+3+6+1 : 28

1+8+1+8+9+28 = 55

You can also use P&C; if you want.

guys... how CMAT score will convert in mhcet,,.........????


one of my friend told.--------if some 1 gets 250/400 in cmat then tht will be as 125/200 in cet

is this true...as CMAT result will not contain the %ile

this is the last year for CET? will be scapped next year?

Thanks

Yes this is the last time that the CET is being conducted...Next year onwards, admissions to CET-affiliated institutes would be done on the basis of CMAT scores...

Even this year, for OMS candidates, best of the scores of CAT/CMAT/MHCET would be considered

this is the last year for CET? will be scapped next year?

Thanks

Going by previous years, no.
But since this is the last year for CET, you never know if it might cross their mind.

how to solve this Q...pls rep...

Q) How many numbers less than 999 have the sum of their digits equal to 9?

is the ans 44 ?

how to solve this Q...pls rep...

Q) How many numbers less than 999 have the sum of their digits equal to 9?

are we allowed to bring back the qs papers from the test hall?
In that case we can calculate our marks as per the keys else we'll have to wait till April..

Thanks

Going by previous years, no.
But since this is the last year for CET, you never know if it might cross their mind.

are we allowed to bring back the qs papers from the test hall?
In that case we can calculate our marks as per the keys else we'll have to wait till April..

Thanks

happy holi and all the best for your exam

With a couple of days left for CET, here is a message for all the JB aspirants.

cetkings Says

u have good knowledge abt the CET paper....i hope u get JBIMS this year....HAPPY HOLI....

Thanks. I am hoping for the same. . Wish you a colorful and joyous holi too
Hope I am able to share the classroom with the dream team.

please send the link to download previous year question papers??????

thanx in advance

http://www.facebook.com/MockEngineering
http://cetking.com/download-zone/
http://www.facebook.com/cetkingworkshops

P.S. Please check previous pages, you may find such requests already answered.

I am assuming a correction here (in bold above)

You can find out BC by applying Pythagorean theorem, then find area as 1/2 BC AD. Then use it in above given formula.

Or you may use :The product of two sides of a triangle equals the altitude to the third side times the diameter of the circumcircle.
20.5 x 36 = 9 x ?
? = 82
radius = 41

Does this fit?

u have good knowledge abt the CET paper....i hope u get JBIMS this year....HAPPY HOLI....

pls help
In a triangle ABC the lengths of the sides AB and AC equal 20.5 cm and 36 cm respectively. Let D
be a point on the line segment be such that AD is perpendicular to BC. If AD = 9 cm, then what is the
radius (in cm) of the circle circumscribing the triangle ABC? (Area of a triangle is equal to the product
of all the sides. of the triangle divided by four times the radius of the circle circumscribing the
triangle)

I am assuming a correction here (in bold above)

You can find out BC by applying Pythagorean theorem, then find area as 1/2 BC AD. Then use it in above given formula.

Or you may use :The product of two sides of a triangle equals the altitude to the third side times the diameter of the circumcircle.
20.5 x 36 = 9 x ?
? = 82
radius = 41

Does this fit?

pls help
In a triangle ABC the lengths of the sides AB and AC equal 20.5 cm and 36 cm respectively. Let D
be a point on the line segment be such that AD is perpendicular to be. If AD = 9 cm, then what is the
radius (in cm) of the circle circumscribing the triangle ABC? (Area of a triangle is equal to the product
of all the sides. of the triangle divided by four times the radius of the circle circumscribing the
triangle)

Some last minute FAQs answered:
pagalguy.com/2011/02/cracking-maharashtra-cet-2011-the-faqs/

please send the link to download previous year question papers??????

thanx in advance

u can visit our website for that...

please send the link to download previous year question papers??????

thanx in advance

Duplicate post... snipped..

Tension tension tension... worried about what will happen.. what if I dont score well....

Guys, we will worry about results after your results in May.. till then think positive....

Do only 2 things for next 3 days:
1. Revise and redo all basics.. just run through everything done so far....
2. Solve last years papers / cetking mockengineering and mugg them....

Dont take any new tough / non sense mocks in last few days....

All the best...

my take, please help me if i am wrong,

apart from
1. some chairs are tables
and
2. some fans are chairs,

no other conclusion can be drawn from the above sentences.

U r right.
If some X are Y
Only possible conclusion is
Some Y are X.

I have a que...

some tables are chairs.
some chairs are fans...

could we deduce a conclusion b/w these two particular affirmative statements??,.,,

my take, please help me if i am wrong,

apart from
1. some chairs are tables
and
2. some fans are chairs,

no other conclusion can be drawn from the above sentences.

some tables may be fans is what you can deduce.

I have a que...

some tables are chairs.
some chairs are fans...

could we deduce a conclusion b/w these two particular affirmative statements??,.,,

Q1) An article was sold at Rs 4500 incurred 10% loss.At what price should it be sold to earn 10% profit ?

Q2) In a school the ratio of boys and girls is 3:2 respectively.When 6 more girls join the ratio becomes 6:5. How many boys are there in school ?

I would prefer to go by the options for the first one as figures are easy.
Or
Simply
100 - loss% / old SP = 100 + Profit / new SP
90 / 4500 = 110 / x
x = 5000

Q1) An article was sold at Rs 4500 incurred 10% loss.At what price should it be sold to earn 10% profit ?

Q2) In a school the ratio of boys and girls is 3:2 respectively.When 6 more girls join the ratio becomes 6:5. How many boys are there in school ?

1. Ans-- 5500
2. Ans-- Boys-- 36

Q1) An article was sold at Rs 4500 incurred 10% loss.At what price should it be sold to earn 10% profit ?

Q2) In a school the ratio of boys and girls is 3:2 respectively.When 6 more girls join the ratio becomes 6:5. How many boys are there in school ?

1. For ten percent loss, the article must be sold at ninety percent of price, which is 4500.
90% = 4500 100% = 5000
similarly for ten percent profit, price is
110% = 5550

2.Prev ratio was (6/4)k, when 6 girls join ratio became (6/5)k. So k = 6. (Since numerator is same)
Boys = 6k = 36