@Rshmi05 is it 6.1???

P.S : last part of the question is not clear. what is V here?? or is it a typo?

plz solve dis one.....................

@rohit406 said: Arjun and Bheem are standing at point A on a circular track with circumference 300 m. Cherry is standing at point B which is diametrically opposite point A on the track. All three of them start running simultaneously on the track; Arjun and Cherry run in clockwise direction at 3 m/s and 4 m/s respectively while Bheem runs in anticlockwise direction at 5 m/s. After how much time from the start will Cherry be equidistant from Arjun and Bheem for the first time?

@karan5 said:

yes ...but how ..i am getting 520 km..plz explain

@swapnil.puy said:

answer should be 450 km

@karan5 said: . One car sets off at 8:00 a.m. at 60kmph, at 11:00 a.m. another car starts at 100kmph. At what distance from the starting point both will meet.

@kratika18 said: A question 4 u guys-Kiran fires a gun at 10:30 a.m. when ben starts on his car towards kiran. kiran fires a second time at 10:41 a.m. but ben hears the second shot ten minutes 48 sec after hearing the first sho. what was ben's speed if speed of sound in air is 330 m/s?

@kratika18 said: A question 4 u guys-Kiran fires a gun at 10:30 a.m. when ben starts on his car towards kiran. kiran fires a second time at 10:41 a.m. but ben hears the second shot ten minutes 48 sec after hearing the first sho. what was ben's speed if speed of sound in air is 330 m/s?

@Homer1 said: 2 cars involved,rate ratio is Rs3:Rs2 per km.,seating capacity ratio=5:2,speed ratio=7:4.find ratio of max.cost incurred given dat no wastage of tym or capacity.ans:105:16plzz help

@jyoti_thakur said: hi, Can anyone help me in solving Escalators questions?? what is the logic behind in analysing relativity in escalators questions , up/down both.. for example i am posting one question: Pls help me out: Rajesh Walked down a descending escalator and took 40 steps to reach the bottom. Sunil started simultaneously from the bottom taking 2 steps for every one step taken by Rajesh. The time taken by Rajesh to reach the bottom from the top is same as time taken by SUnil to reach the top from Bottom. HOw many steps more than Rajesh did Sunil Take before they crossed each other on the escalator? a)20 b) 40 c) 3 4) cnt determined Thanks in advance

hi,
Can anyone help me in solving Escalators questions??
what is the logic behind in analysing relativity in escalators questions , up/down both..

for example i am posting one question: Pls help me out:


Rajesh Walked down a descending escalator and took 40 steps to reach the bottom. Sunil started simultaneously from the bottom taking 2 steps for every one step taken by Rajesh. The time taken by Rajesh to reach the bottom from the top is same as time taken by SUnil to reach the top from Bottom. HOw many steps more than Rajesh did Sunil Take before they crossed each other on the escalator?

a)20 b) 40 c) 3 4) cnt determined





Thanks in advance

Amul and Cadbury run a 12km race around a circular track of circumference 750m. Amul can beat cadbury in a race of 2000 m by 500 m. If amul gives a headstart to cadbury by 500m then how many times amul overtake cadbury in the race?

ans is 4

please help me in solving this question

Hi puys, I am not being able to understand how to solve the following question:


A man rows upstream in a river. When he covered 1 km from starting point his hat fell down and started to move downstream the man kept swimming upstream for 5 minutes but realised he has dropped his hat then rows down stream to catch the hat. Finally the hat and man meet at start. Find the speed of flow of river.




My take:

speed of hat=speed of river =h
speed of man= m

since time will be constant for both to return back
1/h= 1/(m+h) + (m-h)5/(m+h) + 5


h= 0.1 km/min

done

yup i got 6km/hr whch isd same thing

Perfect...infact I also created the same equation as above but left it as there were 2 unknowns and didnt solve to see if the 'm' cancels out or not..... Thanks for the solution... Please read the follows:

It may sound a bit weird but I actually had a solution which I was not being able to understand. Can you please explain me how the following reasoning works? They are saying
Had the speed of stream been zero, the man would have got the hat after 10minutes. But because the hat was 1km behind that point, it means the stream covered 1kms in 10minutes. Hence 1km/10mins==.1km/min
Sorry if I am being extremely stupid here but I am questioning back, in that case the man must have covered the downstream distance back to the start in 5mins. And if that is true this would lead to a generalisation, as it would not matter where the hat is dropped. If after 3 kms he drops it and remembers after 5mins also, he would cover the entire distance back, i.e. to the start in just 5mins. What I mean to say is the entire logic would hinge upon after what time he remembers the hat. I know its a bit too much to ask for but can someone please elucidate that explanation.:oops::oops:

MY TAKE :

The solution you mentioned is more perfect.
Suppose the speed of stream is zero.
Then if man takes 5 min to realise i.e he travelled for 5 mins
so for going back to that star point he will take 5mins
since speed of stream is zero.
So total of 10 mins he travelled.

And the hat travelled 1 km by that time.
So speed of hat = 1km/10mins.

---------------------------------------------------
And suppose after 3km it drops and remember after 5 mins
then
speed = 3km/10 mins

----------------------------------------------------
And Just post your query ,dont apologise and all.
We are here to share and learn :)
cheers!!!!!!!!!!!!!!!!!

Done.

Hi puys, I am not being able to understand how to solve the following question:


A man rows upstream in a river. When he covered 1 km from starting point his hat fell down and started to move downstream the man kept swimming upstream for 5 minutes but realised he has dropped his hat then rows down stream to catch the hat. Finally the hat and man meet at start. Find the speed of flow of river.




My take:
speed of hat=speed of river =h
speed of man= m
since time will be constant for both to return back
1/h= 1/(m+h) + (m-h)5/(m+h) + 5
h= 0.1 km/min

done

Perfect...infact I also created the same equation as above but left it as there were 2 unknowns and didnt solve to see if the 'm' cancels out or not..... Thanks for the solution... Please read the follows:

It may sound a bit weird but I actually had a solution which I was not being able to understand. Can you please explain me how the following reasoning works? They are saying
Had the speed of stream been zero, the man would have got the hat after 10minutes. But because the hat was 1km behind that point, it means the stream covered 1kms in 10minutes. Hence 1km/10mins==.1km/min

Sorry if I am being extremely stupid here but I am questioning back, in that case the man must have covered the downstream distance back to the start in 5mins. And if that is true this would lead to a generalisation, as it would not matter where the hat is dropped. If after 3 kms he drops it and remembers after 5mins also, he would cover the entire distance back, i.e. to the start in just 5mins. What I mean to say is the entire logic would hinge upon after what time he remembers the hat. I know its a bit too much to ask for but can someone please elucidate that explanation.:oops::oops:

Hi puys, I am not being able to understand how to solve the following question:


A man rows upstream in a river. When he covered 1 km from starting point his hat fell down and started to move downstream the man kept swimming upstream for 5 minutes but realised he has dropped his hat then rows down stream to catch the hat. Finally the hat and man meet at start. Find the speed of flow of river.




My take:

speed of hat=speed of river =h
speed of man= m

since time will be constant for both to return back
1/h= 1/(m+h) + (m-h)5/(m+h) + 5

h= 0.1 km/min

done

do such questions by taking gaps..
here..
for 6 gaps(between 7 strikes x-x-x-x-x-x-x - is gap) takes 7 seconds
1 gap=7/6 sec
so 9 gaps for 10 strikes will take 7/6x9 strikes

ans. 21/2

m getting 6km/hr or .1km/min...
if the ans is correct i'll post the solution...

Hi puys, I am not being able to understand how to solve the following question:


A man rows upstream in a river. When he covered 1 km from starting point his hat fell down and started to move downstream the man kept swimming upstream for 5 minutes but realised he has dropped his hat then rows down stream to catch the hat. Finally the hat and man meet at start. Find the speed of flow of river.


Please explain the solution....

Hi puys, I am not being able to understand how to solve the following question:


A man rows upstream in a river. When he covered 1 km from starting point his hat fell down and started to move downstream the man kept swimming upstream for 5 minutes but realised he has dropped his hat then rows down stream to catch the hat. Finally the hat and man meet at start. Find the speed of flow of river.


Please explain the solution....

My approach :

let the total distance =d
path travelled my Amar=d1
".........................wife= d-d1
speed of man = M
"............car = C

so total time had he walked = (d1/m) -(d-d1/c) = P
''..........................didnt walked = d/C = Q

& P-Q=12

solving we get
d1/M = 15
d1/C = 3

we are finding time for d1 distance covered so that we could find
the time he would reach early

so tym difference =12 mins
& also he reaches 12 minutes earlier than 6
so total time lessened FROM 6'Oclock = 24 mins

i.e 5.36