c + 3/4 * 1/2 * c + 1/2 * c > 42
c > 22.4 => c >=23
c + m + b = 42
2b + 2/3 * b + b < 42
b < 11.4 => b <= 11
m=8, c= 23, b=11
Ans = (a) - 3 more banana's.
i need to do this faster how ???
b=c/2-k becoz bananas are less than half the chikoos, similarly
Now c , m and b have to be integer. c must be of the form 24n.So c must be=24
Now m+b=18 becoz c+m+b=42
Now b must be 4,8,12,or 16.But as b i...
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Hey i dont receive the questions.
Please tell me how to subscribe to question list so that i also get questions along with u guys.
Quant Question # 51
Allwin went to the market and bought some chikoos, mangoes, and bananas. Allwin bought 42 fruits in all. The number of bananas is less than half the number of chikoos; the number of mangoes is more than one-third the number ...
when i got c>22.2...i assumed it to be 23...and it worked fine for the other case
is there any better method....?????
m=42-b-c>42-c/2-c (from eqn 2)i.e 42-3c/2
i.e 2m>84-9m(from eqn 3) i.e m>7.6
B2 M<34B M>C/3
C/3 < M < 3C/8 1)
4C/9 < B < C/2 2)
Adding 1) and 2)
7C//9 < B+M < 7C/8
C + 7C/8 = 42 (taking extreme)
=> C = 22.xx But B+M is less than 7C/8 hence C>22.xx
C + 7C/9 = 42 (taking other extreme)
=> C = 23.xx ...
c=23 , b=11 , m =8
the eqn comes to c/2>3/4b>m>c/3
only soln is above one ; so option (a) 3 is the correct option
Allwin went to the market and bought some chikoos, mangoes, and bananas. Allwin bought 42 fruits in all. The number
of bananas is less than half the number of chikoos; the number of mangoes is more than one-third the number of
chikoos and the number of mangoes is le...