One problem, sorry if I sound too silly with such sums but, I am nt able to get an answer to:
2 trains travel in opposite directions at 36km.hr and 45km/hr. A man sitting in the slower train passes the faster train in 8 secs. The length of the faster train is?
80
180
120
150
110
Please tell me your approach as well. Only answer is of no use>

I would suggest Book on Numbers.

Numbers Demystified by Nishit K.Sinha.

That's an awesome book if you really wanna have some good knowledge in numbers also sufficient to crack any question on Numbers..obviously with a little presence of mind.

Rgrds

Bud Can u also sugest a book that provides (step by step or brief)explanatory solutions for along with the problems.

I would suggest Book on Numbers.

Numbers Demystified by Nishit K.Sinha.

That's an awesome book if you really wanna have some good knowledge in numbers also sufficient to crack any question on Numbers..obviously with a little presence of mind.

Rgrds

I guess this question of mine is more apt for this forum than the original Quant forum.

What is modulus and when are we supposed to use it?


Or is it oo dumb for this forum too?

mohit878 Says

I don't think Vedic maths is required for Quant section,Because for vedic maths you require lots of practise,and i think we don't have too much time to practise it....In CAT 2011 i scored 98%ile in section-1 but screwed up in section-2....So my suggestion is just go through basics and try to apply short tricks and practise geometry question(I am very weak in it,and in my slot i got around 5-6 questions of geometry )..........

Quant and DI/LR book of Arun sharma is sufficient to crack section-1.........Solve each and every question of it.......

Hi Puys;
Since this thread is dedicated for basics/zero-level study for quantitative aptitudes then IMO you can't miss Vedic-Maths/Speedo-Maths . Speed calculation techniques are a must to ace in Sec-1 in new CAT pattern.I will gladly post concepts & sums..............
CAT 2K11:89.22(88.53,85.39)
Regards,
Never Back Down

I don't think Vedic maths is required for Quant section,Because for vedic maths you require lots of practise,and i think we don't have too much time to practise it....In CAT 2011 i scored 98%ile in section-1 but screwed up in section-2....So my suggestion is just go through basics and try to apply short tricks and practise geometry question(I am very weak in it,and in my slot i got around 5-6 questions of geometry )..........

Hey Rocker,

Awaiting GEometry's turn... Can I post some... How can u restrict topics yaar? I am doing Geometry and the concepts are puzzling me. Lets all discuss them and solve. Wat say?

We will be taking a good amount of time from into and out of geometry....

Also to numbers.these are the two nighmare topics of everyone and wee shall win it.

What will be today's topic?

Hey Rocker,

Awaiting GEometry's turn... Can I post some... How can u restrict topics yaar? I am doing Geometry and the concepts are puzzling me. Lets all discuss them and solve. Wat say?

Hi Puys;
Since this thread is dedicated for basics/zero-level study for quantitative aptitudes then IMO you can't miss Vedic-Maths/Speedo-Maths . Speed calculation techniques are a must to ace in Sec-1 in new CAT pattern.I will gladly post concepts & sums..............

CAT 2K11:89.22(88.53,85.39)
Regards,
Never Back Down

Sure..Everyone are free to post buddy....!!!!! Give all the tips and tricks that you know at anytime....!!!!

Hi Puys;
Since this thread is dedicated for basics/zero-level study for quantitative aptitudes then IMO you can't miss Vedic-Maths/Speedo-Maths . Speed calculation techniques are a must to ace in Sec-1 in new CAT pattern.I will gladly post concepts & sums..............
CAT 2K11:89.22(88.53,85.39)
Regards,
Never Back Down

Thats very nice of you. So are they books or websites? Most of us would benefit from the speed techniques

1.Profit and Loss
2.Percentages
3.Time and Work

This order is good....!!!!

Hi Puys;
Since this thread is dedicated for basics/zero-level study for quantitative aptitudes then IMO you can't miss Vedic-Maths/Speedo-Maths . Speed calculation techniques are a must to ace in Sec-1 in new CAT pattern.I will gladly post concepts & sums..............

CAT 2K11:89.22(88.53,85.39)
Regards,
Never Back Down

You just have to know this.
When ever something increases by 10%. We can directly multiply it by 1.1 and get the final result. Because 1 is actual amount and that .1 is 10% increase.
So for 10% it is 1.1, 15% is 1.15, 23% is 1.23 etc.

Cool thanks! Im a genuine Quant zero. This section shudve been named after me!

ajayjr Says

Bud good initiative but can u explain this problem more clearly?

You just have to know this.
When ever something increases by 10%. We can directly multiply it by 1.1 and get the final result. Because 1 is actual amount and that .1 is 10% increase.
So for 10% it is 1.1, 15% is 1.15, 23% is 1.23 etc.

1) Lets say the value is 100 in 2001
100 * 1.25 * 1.20 * 1.1 = 125 * 1.20 * 1.1 = 125 * 1.32 = 165
So the value increased by 65%.

Bud good initiative but can u explain this problem more clearly?

At what rate were the oranges sold per dozen if by bargaining to get one orange per rupee more, I saved Rs 16 per dozen?
1. Rs.8 2. Rs.4 3. Rs.5 4. Rs.12

Two days and nobody is here....How cum ?

Aise kaise CAT clear hoga dosto....come on....

Lets make it hot,humorous and enjoying...
ATB...Hope to see al of you within the scheduled time...

8pm to 11:30pm Everyday....

Come on Lets Rock....

subscribing ...

PROBLEMS :-

1) The Percentage increase in the value of Exports of apples of a country is as follows :
2001 - 2002 ---> 25%
2002 - 2003 ---> 20%
2003 - 2004 ---> 10%
What is the percentage increase in the value of exports of apples of the country from 2001 to 2004?

2)The length of a rectangle is increased by 10% and the breadth is increased by 20%. What is the consequent percentage increase in its area.?

3) If the price of an item goes up by 10%, by what percentage should the new price be reduced to bring it down to the original price?

4) If Dinesh's salary is 20% less than Eswar's salary, then by what percentage is Eswar's salary more than Dinesh's salary?

1) Lets say the value is 100 in 2001
100 * 1.25 * 1.20 * 1.1 = 125 * 1.20 * 1.1 = 125 * 1.32 = 165
So the value increased by 65%.

Note :- You can use the formula also
{(100+p/100)(100+q/100)(100+r/100)-1} * 100

2) Let the length be l and breadth be b initially.
Length increases by 10% = 1.1 l
Breadth increases by 20% = 1.2 b
Area = l*b = 1.1 l * 1.2 b = 1.32 lb
So the percentage increase is area is 32%

3) Lets use the formula here .
100*x/100+x = 100*10/100+10 = 1000/110 = 9.09 %
OR
Let the value be 100. Now it is increased by 10%. So it becomes 110.
Now to bring it back to 100 we should decrease it by 10.
10/110 * 100 = 100/11 = 9.09%

4) Lets use the formula here.
100*x/100 -x = 100*20/100-20 = 200/80 = 25%
OR
Let Eashwar salary be 100.
Now dinesh salary is 20% less = 80
Eashwar salary is more than dinesh salary by 100-80 = 20
Percentage = 20/80*100 = 25%

kolaveriCAT Says

Basically which area should i start from...??

1.Profit and Loss
2.Percentages
3.Time and Work
4.Time and Distance
5.Averages Mixtures and Allegation
6.Simple Equations
7.Permutation & Combinations
8.Probability
9.Quadratic Equations
10.Geometry
11.Numbers

This order is good....!!!!

#1. cost price of 12 articles = selling price of 15 articles . wat will be the profit or loss percentage????? just want ur approach as it is a cake walk to solve ????


#2. cost price of 25 articles = selling price of 20 articles. find profit or loss percentage ?????

1) lets say C.p of 1 article is x.
C.p of 12 articles = 12x = S.p of 15 articles
C.P of 15 articles = 15x
C.P > S.P (loss)
Loss = C.P - S.P = 15x - 12x = 3x
Loss % = 3x/15x * 100 = 20%

2) Lets say C.P of 1 article is x.
C.P of 25 articles = 25x = S.P of 20 articles
C.P of 20 articles = 20x
S.P > C.P ( Profit )
Profit = S.P - C.P = 25x - 20x = 5x
Profit % = 5x/20x * 100 = 25 %

Basically which area should i start from...??

Guys for a person who nearly flunked his 10th board exams just because he was pathetic in maths...:banghead:

How should he start preparing for CAT quants...??

What materials should he start with..??



P.s : That guy is me

Start from the very basics . Don't go for any mock level questions. You should complete your basics by April. And in may you should do mock level questions and then start giving mocks and analyse. That will help...!!!!

Guys for a person who nearly flunked his 10th board exams just because he was pathetic in maths...:banghead:

How should he start preparing for CAT quants...??

What materials should he start with..??



P.s : That guy is me

In 6 q. 1920-x = x-1280
2x= 3200
x= 1600

In 10. q 6/5 - 5/6
= 36-25/30
= 11/30 which is equal to app. 39%

#1. cost price of 12 articles = selling price of 15 articles . wat will be the profit or loss percentage????? just want ur approach as it is a cake walk to solve ????


#2. cost price of 25 articles = selling price of 20 articles. find profit or loss percentage ?????

Percents:

What is a % of b? Problem Set-Up: x = (a/100)*b
a is what percent of b? Problem Set-Up: a = (x/100)*b
What % of a is b? Problem Set-Up: b = (x/100)*a
a is b% of what number? Problem Set-Up: a = (b/100)*x
a% of what number is b? Problem Set-Up: b = (x/100)*a

Percent Changes:

Percent Change (Actual Change/Original Value) * 100 %
Percent Increase ((New Value V Original Value)/ (Original Value)) * 100 %
Percent Decrease ((Original Value V New Value)/(Original Value)) * 100 %
To Increase a number by K%, multiply it by (100% + K%)
To Decrease a number by K%, multiply it by (100 - K%)
If a number is the result of increasing another number by K%, then, to find the original number, divide by (100% + K%)
If a number is the result of decreasing another number by K%, then, to find the original number, divide by (100% - K%)

Successive Percent Changes

Apply the following steps when two or more series of subsequent percent changes are applicable:
Step-1: Compute the first percentage change on the original base. If the original base is not given, assume it to be 100
Step-2: Add/Subtract the first percent change from the base of 100 to find the value after first percent change, also known as the intermediate value.
Step-3: Compute the second percent change on the value of first percent change
Step-4: Add/Subtract the second percent change from value after the first percent change to find the final percent change

Percent Discounts

Original Price = Sale Price + Discount Amount
Original Price = (Discount Amount/Discount %) * 100
Original Price = Sale Price / (100% + Markup %)
New Price Original Price (100 % + Mark-up %) or Original Price (100 % - Mark-up %)
Sale Price Original Price - Discount Amount
Discount Amount Original Price - Sale Price
Discount % (Rate of Discount) ((Original Price - Selling Price)/Original Price) * 100 (Discount Amount/Original Price) * 100

Percent Mark-Ups/Downs

Cost Price: Amount that costs the seller without any profit or loss. It is the cost that the seller pays or incurs to procure or produce an item.
Selling Price: Amount that a seller sells an item for, which may include a profit (mark-up) or loss (mark-down) or neither (break-even price)
Break-Even Price: Nothing but the Cost price
Mark-up or Profit = Selling price cost price
Selling Price = Cost Price + Profit
Original Price or Cost Price= Sale Price/ (100% + Mark-Up %)
New Price = Original Price + Mark-up (Increase)
Mark-down or Loss = Cost price - Selling price
Selling Price = Cost Price - Loss
Original Price = Sale Price/ (100% - Mark-down %)
New Price ďƒ¨ Original Price - Mark-Down (Decrease)

Nice initiative. I suggest everyone to watch Sir Ravi Handa's video in youtube.
Basics are awesome in those videos. I started my prep with those videos . All the best puys.

I am in even

Hey all,
Great thread, I am one of those whose carerr is getting in doom for Quants, my achillies Hill... Can I post some geometry doubts? The questions r eating me up!
Regards

Not as of now as because we are currently going with P & L ,Partnerships and Percentages....If u are strong then you can obviously do what is to help...

We will be taking up Geometry a bit later.

Thanks

ATB

Hey all,
Great thread, I am one of those whose carerr is getting in doom for Quants, my achillies Hill... Can I post some geometry doubts? The questions r eating me up!
Regards

Few Simple Concepts of Percentages :-

1) If there are successive increases of p%,q% and r% in three stages, the effective percentage increase is { ( 100+p/100)(100+q/100)(100+r/100)-1} * 100.
If one or more of p,q and r are decrease percentage figures and not increase percentage, then it will be taken as a negative figure and not as positive figure.

2) If the value of an item goes up/down by x% the percentage reduction/increment to be now made to bring it back to the original level is
100x/(100+/-x) %.
Note :- If A is x% more/less than B, then B is 100x/(100+/-x) % less/more than A.

3) When two articles are sold at the same price such that there is a profit of p% on one article and a loss of p% on another article then, irrespective of what S.P actually is, the net result of the transaction is LOSS.
Loss Percentage = (Common profit or loss)^2/100 = p^2/100

HydRocker Says

i know that method of percentages. I guess you wanted to say conversion of fraction to percentages and percentages to fractions. We shall do these 3 topics together. Lets take 5 more days and complete these topics. I will keep posting questions from all topics. As we are still doing basics i didn't post any difficult question yet...

Ok it looks good I suppose 5 days will be enough but pls all puys must actively participate in this otherwise we 2 are definitely there to discuss it out......but that would not make this thread successful.

Rgrds

Still there are very good questions on P&L; left....U must have some good quality questions.....

Also I would give a way to remember %ages so that would take time....tooo...

Partnerships can be merged but we need to give a bit of time to %ages...some 3 days so that everybody remembers it properly ....

WHAT SAY????

i know that method of percentages. I guess you wanted to say conversion of fraction to percentages and percentages to fractions. We shall do these 3 topics together. Lets take 5 more days and complete these topics. I will keep posting questions from all topics. As we are still doing basics i didn't post any difficult question yet...

PROBLEMS :-

1) The Percentage increase in the value of Exports of apples of a country is as follows :
2001 - 2002 ---> 25%
2002 - 2003 ---> 20%
2003 - 2004 ---> 10%
What is the percentage increase in the value of exports of apples of the country from 2001 to 2004?

2)The length of a rectangle is increased by 10% and the breadth is increased by 20%. What is the consequent percentage increase in its area.?

3) If the price of an item goes up by 10%, by what percentage should the new price be reduced to bring it down to the original price?

4) If Dinesh's salary is 20% less than Eswar's salary, then by what percentage is Eswar's salary more than Dinesh's salary?

HydRocker Says

Profit and Loss is not a very big topic. So lets combine Profit and Loss, Partnerships and Percentages. I will post questions...!!!

Still there are very good questions on P&L; left....U must have some good quality questions.....

Also I would give a way to remember %ages so that would take time....tooo...

Partnerships can be merged but we need to give a bit of time to %ages...some 3 days so that everybody remembers it properly ....

WHAT SAY????

Guys today is the 2nd Day of discussion on Profit and Loss...

Till 20 th we need to finish this topic so pls pour in questions...Difficulty wise and

Then actively participate in the discussions so that maximum learning can be done...

Rgrds
Myth Less

Profit and Loss is not a very big topic. So lets combine Profit and Loss, Partnerships and Percentages. I will post questions...!!!

Guys today is the 2nd Day of discussion on Profit and Loss...

Till 20 th we need to finish this topic so pls pour in questions...Difficulty wise and

Then actively participate in the discussions so that maximum learning can be done...

Rgrds
Myth Less

4. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Solution

Let CP be Rs.100.
Now profit of 320% on 100 means Rs.320
SP=CP+Profit=Rs.100+Rs.320=Rs.420

Now as CP is increased by 25 % then now NEW CP=100+25=Rs.125.
As SP remains constant=Rs.420
New Profit=420-125=Rs.295
Profit as a %age of SP=(295/420)*100=70.23 %
5.A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
Solution


CP of 6 toffees=100 paise
Now as profit is 20 % then 6 toffees must be sold at 100+20 =120 paise.(SP of 6 Toffees)
Therefore each toffee SP= 120 Paise/6=20 Paise.

Thus for a rupee or 100 paise will come 5 toffees,which will gain him a profit of 20 %.


6. The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
Solution


Let the deviation be "X".So the deviation of X from 1920 and 1280 would be the same in Rupees.

Thus 1920-X=X-1280
2X=640
X=320.

Therefore CP=1600.

Now 25 % profit on CP=(1/4)*1600=400

SP=1600+400=2000 INR
7. A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Solution


If we consider 100 % to be 1 then 22.5 % profit on 1 will be .225

therefore 1.225*X=392
X=320 INR

Thus Profit=392-320=72 INR
8. A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
Solution


CP of Cycle=1400 INR

Loss of 15% =210 INR

SP fo Cycle =1400-210=1190 INR
9. Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
Solution


Total Cost price of 240 Toys(20 Dozen *12 Toys/Dozen)=375*20=7500 INR

CP of Each Toy=7500/240=31.25 INR

SP of Each Toy=33.00 INR

Profit on Each Toy=33.00-31.25=1.75 INR

Profit on 240 Toys=240*1.75=420 INR

Profit %age=*100
=5.6 %
10. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:
Solution


CP of each Article=5/6 Re
SP of each Article=6/5 Re

Profit=(6/5)-(5/6)=9/30=3/10
CP=5/6

Profit %age= (Profiit/CP)*100=*100=36%





Hope u all get it pls do tell me if there is confusion in any of the problems.


ATB




Rgrds
Myth Less

Yup all answers are correct...!!!!!

Mithles Says

What about the rest of the questions Hydrocker?????

Ya i am solving them. I will give it in a while and will post few new questions too...!!!!

What about the rest of the questions Hydrocker?????

RETRIBUTION Says

bhai can anyone explain those p and l questions which of PROFIT equated on the basis of objects like by selling x articles he has a profit of the cp of y articles please explain the concept with an example

For these kind of problems always assume the C.P of single article to be some variable. And then get C.P and S.P in that variable . It will then be easy to calculate profit/loss %.

RETRIBUTION Says

bhai can anyone explain those p and l questions which of PROFIT equated on the basis of objects like by selling x articles he has a profit of the cp of y articles please explain the concept with an example

The Cost Price of 6 Oranges is equal to the Selling Price of 8 oranges. Find Profit or Loss Percentage.?
Sol:- Let the cost Price be x
C.P of 8 Oranges = 8x
Selling Price of 8 Oranges = Cost Price of 6 Oranges = 6x
Percentage of loss = (8x - 6x / 8x) * 100 = 25%

RETRIBUTION Says

bhai can anyone explain those p and l questions which of PROFIT equated on the basis of objects like by selling x articles he has a profit of the cp of y articles please explain the concept with an example

ek Question de do Idea k liye. Then we shall do it and learn the concept.

hi retribution can u post the question realted to your query???

11. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Sol

Let the CP of Each Ball be X and SP of each Ball be Y.

Thus,17*X-17*Y=5*X
12*X=17*Y--------(1)
Also,17*Y=720.--------(2)

From (1) and (2)

12*X=720
Thus X=60 INR

Thus CP of each ball is 60 INR
12. When a plot is sold for Rs. 18,700, the owner loses 15%. At what price must that plot be sold in order to gain 15%?
Sol

If 100 % is considered to be 1 then 85 % is 0.85.

Let the CP be X

Thus,0.85*X=18,700 INR.
X=22,000 INR

As 15 % profit is asked thus,15 % of 22,000 is 3300 INR

Thus the SP must be 22,000+3,300=25,300 INR to make a profit of 15%.

13. 100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
Sol

CP of 1 Orange=350/100=3.5 INR
A dozen is sold at 48 INR,1 Dozen=12

Thus SP of 1 Orange=4.0 INR

Profit on 1 orange is 0.5 INR and thus on 100 oranges is 100 * 0.5 is 50 INR

Now Profit %age=[50(Profit on the whole transaction)/350(CP of 100 oranges)]*100=(1/7)*100=.1428 *100=14.28 %
14. A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Sol

Let the CP be X1 & X2 for the transistor sold at a profit of 20 % Profit and Loss of 4% respectively.

Thus,1.2 *X1=840--> X1=700 INR
0.96 *X2=960--> X2=1000 INR

Total CP=1000+700=1700 INR
SP=840+960=1800 INR

Profit %age=[ (1800-1700)/1700 ] * 100=(1/17)*100=5.88 %
15. A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Sol

CP of Variety 1 = 26*20=520 INR
CP of Variety 2 = 30*36=1080 INR

Total CP Incurred=1080+520=1600 INR

Total Amount Earned from Selling the whole Quantity=(30+26)*30=56*30=1680 INR

Profit %age = ((1680-1600)/1600)*100=5 %



Hope u all will be able to understand the solutions,if not then pls tell me


Rgrds

Myth Less

Absolutely Correct...!!!!!!

bhai can anyone explain those p and l questions which of PROFIT equated on the basis of objects like by selling x articles he has a profit of the cp of y articles please explain the concept with an example

anyone here?????

Swatysachdeva Says

plzz explain hw hv u taken cp=0.8 MP

"he is given a commission of 20% of the MP by the dealer"
this means that the C.P is 20% less than the actual M.P
C.P = 0.8 M.P

Swatysachdeva Says

plzz explain hw hv u taken cp=0.8 MP

"he is given a commission of 20% of the MP by the dealer"
this means that the C.P is 20% less than the actual M.P
C.P = 0.8 M.P

Swatysachdeva Says

plzz explain hw hv u taken cp=0.8 MP

"he is given a commission of 20% of the MP by the dealer"
this means that the C.P is 20% less than the actual M.P
C.P = 0.8 M.P

PUYS the time was decided to be from 8:00pm to 11:30pm and still nobody is online?

IS this the way we are going to bell the cat?

Sorry guys but it ain't happening this way.

11. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Sol

Let the CP of Each Ball be X and SP of each Ball be Y.

Thus,17*X-17*Y=5*X
12*X=17*Y--------(1)
Also,17*Y=720.--------(2)

From (1) and (2)

12*X=720
Thus X=60 INR

Thus CP of each ball is 60 INR
12. When a plot is sold for Rs. 18,700, the owner loses 15%. At what price must that plot be sold in order to gain 15%?
Sol

If 100 % is considered to be 1 then 85 % is 0.85.

Let the CP be X

Thus,0.85*X=18,700 INR.
X=22,000 INR

As 15 % profit is asked thus,15 % of 22,000 is 3300 INR

Thus the SP must be 22,000+3,300=25,300 INR to make a profit of 15%.

13. 100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
Sol

CP of 1 Orange=350/100=3.5 INR
A dozen is sold at 48 INR,1 Dozen=12

Thus SP of 1 Orange=4.0 INR

Profit on 1 orange is 0.5 INR and thus on 100 oranges is 100 * 0.5 is 50 INR

Now Profit %age=[50(Profit on the whole transaction)/350(CP of 100 oranges)]*100=(1/7)*100=.1428 *100=14.28 %
14. A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Sol

Let the CP be X1 & X2 for the transistor sold at a profit of 20 % Profit and Loss of 4% respectively.

Thus,1.2 *X1=840--> X1=700 INR
0.96 *X2=960--> X2=1000 INR

Total CP=1000+700=1700 INR
SP=840+960=1800 INR

Profit %age=[ (1800-1700)/1700 ] * 100=(1/17)*100=5.88 %
15. A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Sol

CP of Variety 1 = 26*20=520 INR
CP of Variety 2 = 30*36=1080 INR

Total CP Incurred=1080+520=1600 INR

Total Amount Earned from Selling the whole Quantity=(30+26)*30=56*30=1680 INR

Profit %age = ((1680-1600)/1600)*100=5 %



Hope u all will be able to understand the solutions,if not then pls tell me


Rgrds

Myth Less

does any of u have the TG ebook pdfs of quant.....??

Am I the only one on this thread???

Come On PUYS

We need to get going no time left....We must be ahead of the schedule.

That's how only We can "BELL THE CAT"

4. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Sol

Let CP be 100 INR.
So,320 % of CP =320 INR
SP=100+320=420 INR

As the CP increases 25 % Therefore NEW CP=100+(25% of 100)25=125 INR.

Now NEW Profit=420-125=295 INR

In Question it is asked what % of SP is the profit

Thus,(295/420)*100=70.23 %
5. A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
Sol


1 Re =100 Paise
Now he got 6 toffees for 100 paise
As he want to gain 20 % therefore 20 % of 100 paise=20 paise.
Thus total 6 toffees can be sold at 120 paise for 20 % profit which shows that
CP for each toffee now is 20 Paise.
Thus in 100 paise he has to sell now 100/20=5 toffees in order to gain 20 % Profit.



PS:Do tell me if there is any confusion.

4. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Solution

Let CP be Rs.100.
Now profit of 320% on 100 means Rs.320
SP=CP+Profit=Rs.100+Rs.320=Rs.420

Now as CP is increased by 25 % then now NEW CP=100+25=Rs.125.
As SP remains constant=Rs.420
New Profit=420-125=Rs.295
Profit as a %age of SP=(295/420)*100=70.23 %
5.A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
Solution


CP of 6 toffees=100 paise
Now as profit is 20 % then 6 toffees must be sold at 100+20 =120 paise.(SP of 6 Toffees)
Therefore each toffee SP= 120 Paise/6=20 Paise.

Thus for a rupee or 100 paise will come 5 toffees,which will gain him a profit of 20 %.


6. The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
Solution


Let the deviation be "X".So the deviation of X from 1920 and 1280 would be the same in Rupees.

Thus 1920-X=X-1280
2X=640
X=320.

Therefore CP=1600.

Now 25 % profit on CP=(1/4)*1600=400

SP=1600+400=2000 INR
7. A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Solution


If we consider 100 % to be 1 then 22.5 % profit on 1 will be .225

therefore 1.225*X=392
X=320 INR

Thus Profit=392-320=72 INR
8. A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
Solution


CP of Cycle=1400 INR

Loss of 15% =210 INR

SP fo Cycle =1400-210=1190 INR
9. Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
Solution


Total Cost price of 240 Toys(20 Dozen *12 Toys/Dozen)=375*20=7500 INR

CP of Each Toy=7500/240=31.25 INR

SP of Each Toy=33.00 INR

Profit on Each Toy=33.00-31.25=1.75 INR

Profit on 240 Toys=240*1.75=420 INR

Profit %age=*100
=5.6 %
10. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:
Solution


CP of each Article=5/6 Re
SP of each Article=6/5 Re

Profit=(6/5)-(5/6)=9/30=3/10
CP=5/6

Profit %age= (Profiit/CP)*100=*100=36%





Hope u all get it pls do tell me if there is confusion in any of the problems.


ATB




Rgrds
Myth Less

11)
12) Let the marked price be M.P.
S.P = 0.8 * (1.25 M.P) = M.P
C.P = 0.8 M.P
Profit = M.P - 0.8 M.P = 0.2 M.P
profit % = 0.2/0.8 * 100 = 25%

plzz explain hw hv u taken cp=0.8 MP

good work puys!!!!!!!!!

here are some fundas/concepts which could be useful..

PS: I found them in old QUANT threads in PG... hope it is useful..

@Hydrocker

I am putting in the solutions one by one so would request you to validate them one by one.

Also if you would think there is any better way to make all our ZEROES understand the basics of the game,which will turn them into a hero.Pls do suggest

All are welcome to share in their views and ways.
Participation of all is what will make this thread successful.

ATB


Rgrds
Myth Less