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Quant Basics for Zeros in Quant - CAT 2012
Quantitative
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This thread is exclusively for those who are very weak in Quant and want to start from the scratch. Lets just do quants from basic level and lets become heros from zeros in Quant. I hope this thread will be successful and will give good Quant heros for CAT 2012... [smiley]
I will give minimalistic answers....the way I think one should think in the exam....hope it helps. The new number is 1/25th of the original. Hence 100 would become 4, a decrease of 96%. So (a)
25% of 80 litres is 20 litres milk. After adding water, the same 20 litres is left which is 20% of ne...
25% of 80 litres is 20 litres milk. After adding water, the same 20 litres is left which is 20% of ne...
1
profit earned by selling an article for rs 1060 is 20% more than the loss incurred by selling the article for rs 950 at what price should the article be sold to earn 20%%profit
what was the percentage discount given ?
a) 23.5% profit was earned by selling an almirah for Rs.12350.
b)if there were no discount , the earned profit would have been 30%
c)the cost price of almirah is 10000 rs
option
1)only a and b is required for answering the question
a) 23.5% profit was earned by selling an almirah for Rs.12350.
b)if there were no discount , the earned profit would have been 30%
c)the cost price of almirah is 10000 rs
option
1)only a and b is required for answering the question
what was the percentage discount given ?
a) 23.5% profit was earned by selling an almirah for Rs.12350.
b)if there were no discount , the earned profit would have been 30%
c)the cost price of almirah is 10000 rs
option
1)only a and b is required for answering the question
a) 23.5% profit was earned by selling an almirah for Rs.12350.
b)if there were no discount , the earned profit would have been 30%
c)the cost price of almirah is 10000 rs
option
1)only a and b is required for answering the question
WHAT WAS THE COST PRICE OF WATCH ?
1) THE SHOPKEEPER LABELLED THE PRICE OF THE WATCH 20% ABOVE THE COST PRICE
2) AFTER ALLOWING A DISCOUNT OF 15 % ON THE LABELLED PRICE , THE SHOPKEEPER CHARSES RUPEES 408 FOR THE WATCH
3)HAD THERE BEEN NO DISCOUNT , THE SHOPKEEPER WOULD HAVE EARNED 20%...
1) THE SHOPKEEPER LABELLED THE PRICE OF THE WATCH 20% ABOVE THE COST PRICE
2) AFTER ALLOWING A DISCOUNT OF 15 % ON THE LABELLED PRICE , THE SHOPKEEPER CHARSES RUPEES 408 FOR THE WATCH
3)HAD THERE BEEN NO DISCOUNT , THE SHOPKEEPER WOULD HAVE EARNED 20%...
Let's represent stations chosen by 1 and stations not chosen by 0. Consider that three stations are chosen, we need to put two non-chosen in between, like so: 1 0 1 0 1
Now the remaining 38 - 5 i.e. 33 stations can be placed anywhere in the four regions (before the first chosen one, between fi...
Now the remaining 38 - 5 i.e. 33 stations can be placed anywhere in the four regions (before the first chosen one, between fi...
See the parts I have emphasized in bold above: The total he paid is 4000 for 2 instalments. You have taken each as 4000. Taking each as 2000 should correct it?
regards
scrabbler
regards
scrabbler
1
hey puys....
can anyone help me in solving these questions...
1. A number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to mistake.?(a) 96% (b) 95% (c) 2400% (d) 200% (e) none
2. In a mixture of 80 litres of milk and wat...
can anyone help me in solving these questions...
1. A number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to mistake.?(a) 96% (b) 95% (c) 2400% (d) 200% (e) none
2. In a mixture of 80 litres of milk and wat...
No matter hw hard I study I get only 50-60%ile in mocks... Pls help wat to do?
The answer says its 36C3.But that is in the case of no consecutive stations as
3 stations can be considered as 1
38-3=35
35+1(3 taken together) = 36
36C3
How is it the answer in case of no consecutive stations??
3 stations can be considered as 1
38-3=35
35+1(3 taken together) = 36
36C3
How is it the answer in case of no consecutive stations??
A train encounters 38 intermediate stations between two cities. In how many ways can the train stop at exactly 3 intermediate stations such that no two of them are consecutive?
1) 6545
2) 5984
3) 7140
4) 8436
1) 6545
2) 5984
3) 7140
4) 8436
soln....
1. there will be three installments.....
on 1st installment he will get 2 years interest
on 2nd installment he will get 1 year interest
on 3rd installment he will get no interest as it would be final installment
let each installment be x
interest on 1st installment for ...
1. there will be three installments.....
on 1st installment he will get 2 years interest
on 2nd installment he will get 1 year interest
on 3rd installment he will get no interest as it would be final installment
let each installment be x
interest on 1st installment for ...
SI / CI :
1) what annual installment will discharge a debt of Rs 1815 due in 3 years at 10% simple interest ?
a - 500
b - 520
c - 550
d - 580
2) A person invested Rs 20,000 in a bank which is offering 10% per annum simple interest. After two years, he withdrew the money from the...
1) what annual installment will discharge a debt of Rs 1815 due in 3 years at 10% simple interest ?
a - 500
b - 520
c - 550
d - 580
2) A person invested Rs 20,000 in a bank which is offering 10% per annum simple interest. After two years, he withdrew the money from the...
Having Doubt...
Plz explain
In this
"
(s-c)/c = 20/100 ............................(1)
(s-100)-(c-100)=(c-100)(104/100).....(2)
"
Why its not 120/100 in eq (1) ???
And
How these two eq made ??
"
x(1+25/200) + y(1-25/300) - (x+y) =25......(1)
x(1-25/300) + y(1...
Plz explain
In this
"
(s-c)/c = 20/100 ............................(1)
(s-100)-(c-100)=(c-100)(104/100).....(2)
"
Why its not 120/100 in eq (1) ???
And
How these two eq made ??
"
x(1+25/200) + y(1-25/300) - (x+y) =25......(1)
x(1-25/300) + y(1...
Ton of thanks....
I had done "5" with "S.P. = (100 + profit%) C.P 100 "
and my answer is 266.
Plz correct me ??
and my answer is 266.
Plz correct me ??
An alternate approach (seems logical, though I can't quite prove it correct):
Let me represent a person by a "1" and a chair by a "0". So first I will put in the sequence "1 0 1 0 1" which satisfies the condition that the people should be separated. Now the remaining 5 "0"s can be placed in an...
Let me represent a person by a "1" and a chair by a "0". So first I will put in the sequence "1 0 1 0 1" which satisfies the condition that the people should be separated. Now the remaining 5 "0"s can be placed in an...
Hi crab365,
I am afraid this won't work. When you have counted the 36 cases, you have missed cases where the 2nd and 3rd chairs are consecutive. This adds another 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 cases such as (1, 3, 4), (1, 4, 5) (2, 4, 5)....till (7, 9, 10)
So we must do 120 - 36 - 28 = 56...
I am afraid this won't work. When you have counted the 36 cases, you have missed cases where the 2nd and 3rd chairs are consecutive. This adds another 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 cases such as (1, 3, 4), (1, 4, 5) (2, 4, 5)....till (7, 9, 10)
So we must do 120 - 36 - 28 = 56...
--------------------------
-----------------------
=>18^322*18
=>(324)^161*18 (taking 18^2=324)
=>(325-1)^161*18
=>(-1)^161*18
=>-1*18=-18
Remanider = 325-18=307
What is the answer?
=>(324)^161*18 (taking 18^2=324)
=>(325-1)^161*18
=>(-1)^161*18
=>-1*18=-18
Remanider = 325-18=307
What is the answer?
what is the remainder when 18^323/325?
is it 39
total even numbers 51
numbers divisible by 7 -7
numbers divisible by 9- 6
and one number is common in both so total even numbers will be
51-(7+6-1)
39
total even numbers 51
numbers divisible by 7 -7
numbers divisible by 9- 6
and one number is common in both so total even numbers will be
51-(7+6-1)
39
For Qa please participate in this thread also to get your fundas clear...
http://www.pagalguy.com/forum/prep-resources/82497-how-crack-section-i-cat.html
ps- Number system week
http://www.pagalguy.com/forum/prep-resources/82497-how-crack-section-i-cat.html
ps- Number system week
Somebody please solve this, Thanks.
How many even integers n, where 100<=n<=200, are divisible neither by seven nor by nine?
How many even integers n, where 100<=n<=200, are divisible neither by seven nor by nine?
Junta please note that the solution quoted above is true, and mine was wrong.
I had missed out on 4 additional cases:
1,3,5,7,10
1,3,5,8,10
1,3,6,8,10
1,4,6,8,10
So total no. of ways = 6, and no. of seating arrangements = 6X5! = 720.
The above quoted text is obviously a bette...
I had missed out on 4 additional cases:
1,3,5,7,10
1,3,5,8,10
1,3,6,8,10
1,4,6,8,10
So total no. of ways = 6, and no. of seating arrangements = 6X5! = 720.
The above quoted text is obviously a bette...
thanks buddy ,that was really a silly mistake
1
Again there is no option but to count the cases individually.
Select 3 chairs out of 10 such that no two are consecutive. This is done by subtracting cases when 2 consecutive chairs are selected from total no. of ways of selecting 3 chairs out of 10, which is 10 C 3 = 120.
To count ways whe...
Select 3 chairs out of 10 such that no two are consecutive. This is done by subtracting cases when 2 consecutive chairs are selected from total no. of ways of selecting 3 chairs out of 10, which is 10 C 3 = 120.
To count ways whe...
1
Thanks for the reply,what would have been your approach if it was 3 people in 10 chairs with no adjacent sitting..
1
_x_x_x_x_x_
out of 6 dash we need to select 5....so 6C5*5!
out of 6 dash we need to select 5....so 6C5*5!
1
Hi guys,
Can anyone tell me about the weightage of quant and DI in paper one i.e how many questions out of 30 are of quant and how many out of 30 are of DI? Also, tell the distribution for paper II i.e how many questions out of 30 are of VA and how many out of 30 are of LR?
Let me know t...
Can anyone tell me about the weightage of quant and DI in paper one i.e how many questions out of 30 are of quant and how many out of 30 are of DI? Also, tell the distribution for paper II i.e how many questions out of 30 are of VA and how many out of 30 are of LR?
Let me know t...
Hi Freakonomist :)
n+r-1 C r-1 won't work because that formula is used to distribute n identical things in r groups.
To solve your question, number the chairs 1 through 10.
If the chairs are to be occupied in such a way that only alternate ones are occupied, there are two possibilities t...
n+r-1 C r-1 won't work because that formula is used to distribute n identical things in r groups.
To solve your question, number the chairs 1 through 10.
If the chairs are to be occupied in such a way that only alternate ones are occupied, there are two possibilities t...
1
Can any one post me the approach for this type of question:
How to make 5 people sit in 10 chairs so that no 2 people sit adjacent.Here n+r-1Cr-1 doesnt work.How to go about this? Please illustrate the approach.
How to make 5 people sit in 10 chairs so that no 2 people sit adjacent.Here n+r-1Cr-1 doesnt work.How to go about this? Please illustrate the approach.
1.Profit % in 1st case :
10000-8000=2000
2000/8000=25%
.Profit % in 2nd case :
15000-11000=4000
4000/11000=?
to make profit %=25
11000+25*11000=13750,But S.P=15000.so he has to give a discount of 1250 on 15000 to make the sp =13750
so disount%=1250/15000=8.33%
2. Let th...
10000-8000=2000
2000/8000=25%
.Profit % in 2nd case :
15000-11000=4000
4000/11000=?
to make profit %=25
11000+25*11000=13750,But S.P=15000.so he has to give a discount of 1250 on 15000 to make the sp =13750
so disount%=1250/15000=8.33%
2. Let th...
2
all perfect squares of primes have exactly 3 factors
remember all natural numbers have even number of factors except for perfect squares which have odd number of factors.
remember all natural numbers have even number of factors except for perfect squares which have odd number of factors.
3
help pls..
Q1. Which numbers have exactly 3 factors?
Q2. x, a and b are natural numbers. If x is divisible by a and beach then find a condition for which x is definitely divisible by a*b?
Q3.If LCM of a, b, c is x and that of d, e is y then, would the LCM of x,y be the LCM of a, b, c, d...
Q1. Which numbers have exactly 3 factors?
Q2. x, a and b are natural numbers. If x is divisible by a and beach then find a condition for which x is definitely divisible by a*b?
Q3.If LCM of a, b, c is x and that of d, e is y then, would the LCM of x,y be the LCM of a, b, c, d...
profit and loss :
1) i purchased a dining table for rs 8000 two years ago. present price of a similar dining table is rs 15000. if i sell my table, i would get rs 10000 for it. if instead i polish it, i would have to spend rs 3000 on it but can sell it at the price of a new one. at what discou...
1) i purchased a dining table for rs 8000 two years ago. present price of a similar dining table is rs 15000. if i sell my table, i would get rs 10000 for it. if instead i polish it, i would have to spend rs 3000 on it but can sell it at the price of a new one. at what discou...
Should be 1320
~scrabbler
~scrabbler
1
That will not work....the last assumption you made is itself wrong "any number ending with unit digit 5 divided by 4 will have remainder 1" - for example consider 15 divided by 4, leaves remainder 3! Units digit alone is not sufficient - this is an easy trap to fall into (speaking from experience...
No it is not correct
4) What is the sum of the product of all possible pairs of distinct numbers of the first ten natural numbers.
a) 1320
b) 2640
c) 1705
d) 1920
1705 my take
a) 1320
b) 2640
c) 1705
d) 1920
1705 my take
i think it can also be done like this :
7^5^7^5=>
taking unit digit of powers from up to down=> consider 7^5 its unit digit will be 7 as cyclicity of 7 is 4.....
now unit digit of 5^(the number whose unit digit is 7) is 5...as we multiply 5 as many times we get unit digit 5
now unit ...
7^5^7^5=>
taking unit digit of powers from up to down=> consider 7^5 its unit digit will be 7 as cyclicity of 7 is 4.....
now unit digit of 5^(the number whose unit digit is 7) is 5...as we multiply 5 as many times we get unit digit 5
now unit ...
Progressions SET-6 :-
1) If a+b, b+c and c+a are in harmonic progression, then
a) a^2, b^2 and c^2 will be in AP
b) a^2, bc and c^2 will be in HP
c) 2ab, a^2 and b^2 will be in AP
d) b^2, a^2 and c^2 will be in AP
2) If 1/(1+x) , 1/(1-x), 4/(1-x^2) are in Arithmetic progression,...
1) If a+b, b+c and c+a are in harmonic progression, then
a) a^2, b^2 and c^2 will be in AP
b) a^2, bc and c^2 will be in HP
c) 2ab, a^2 and b^2 will be in AP
d) b^2, a^2 and c^2 will be in AP
2) If 1/(1+x) , 1/(1-x), 4/(1-x^2) are in Arithmetic progression,...
thanks.. dude
It will be 7.
If we look at powers of 7 i.e. 7^1, 7^2, 7^3 etc, we find that the last digits follow the pattern 7, 9, 3, 1, 7, 9, 3, 1...repeating after every 4 steps - i.e. the cyclicity of 7 is 4 steps.
So we need to take the given power (in this case (5^(7^5))) and see what happens when ...
If we look at powers of 7 i.e. 7^1, 7^2, 7^3 etc, we find that the last digits follow the pattern 7, 9, 3, 1, 7, 9, 3, 1...repeating after every 4 steps - i.e. the cyclicity of 7 is 4 steps.
So we need to take the given power (in this case (5^(7^5))) and see what happens when ...
2
The answer should be 7
1
My take 7...
hey.. can anyone pls tell me what is the answer and solving method for the question:
unit's digit of 7^(5^(7^5))
thanks..
unit's digit of 7^(5^(7^5))
thanks..
The best way to find the unit's digit is to find the remainder of a number when it's divided by 10. So, for any x!, x>=10, this will always be zero!!!
1
hi guys,
please let me know which topics you are discussing ..
Regards
kapil
please let me know which topics you are discussing ..
Regards
kapil
Units digit will be Zero..!! Because it is getting multiplied by numbers which have their units digit as zero...!!!
1) M=(5N-4)(5N+1) , 1<= N <= 200
When N=1, M = 1*6
When N=2, M = 6*11
When N=200, M = 996*1001
Harmonic Mean = 200/(1/5+1/5+....+1/5)
= 200/(1/5) = 1001
2) The nth term of an AP can be written in the form of a linear equation an+b.
So the product of 2 A.P's will have terms of...
When N=1, M = 1*6
When N=2, M = 6*11
When N=200, M = 996*1001
Harmonic Mean = 200/(1/5+1/5+....+1/5)
= 200/(1/5) = 1001
2) The nth term of an AP can be written in the form of a linear equation an+b.
So the product of 2 A.P's will have terms of...
hi folks i have recently started my preparation for cat
can some one post a simple way of finding the units digit of:
1^1*2^2*3^3*4^4*5^5*..........*100^100:shocked::shocked:
can some one post a simple way of finding the units digit of:
1^1*2^2*3^3*4^4*5^5*..........*100^100:shocked::shocked:
No answer is 17. Just see the solution clearly...!!! Common difference will not be 1. It is 2.
What didn't you understand in this problem...???
What didn't you understand in this problem...???
hey can u pls explain this model of problem in detail
here the answer is 16 i think.
as the three numbers are 14,15,16 with common difference 1
as the three numbers are 14,15,16 with common difference 1
1
aimcats are going to start from 25 th may ...
Progressions SET-5 :-
1) M and N are natural numbers such that by M = (5N 4) (5N + 1).
If 1N200,what is the harmonic mean of all the possible values of M?
a) 200^2/1001
b) 1001
c) 1001/200^2
d) 1/1001
2) A sequence 192, 360, 576. is formed by multiplying the corresponding t...
1) M and N are natural numbers such that by M = (5N 4) (5N + 1).
If 1N200,what is the harmonic mean of all the possible values of M?
a) 200^2/1001
b) 1001
c) 1001/200^2
d) 1/1001
2) A sequence 192, 360, 576. is formed by multiplying the corresponding t...
1) [a+(r+2-1)d]/[a+(r+5-1)d] = (r+3)/(r+6)
By solving this we get
a=2d ----> I
Given that
(4r/2 * [ 2a+(4r-1)d] ) / (7r/2* [2a+(7r-1)d] = 1/3
Substitute 2d in place of a
4/7 * [(4rd+3d)/(7rd+3d)] = 1/3
48r+36 = 49r+21
r = 36-21 = 15
2) Sum of infinite GP = a/(1-r)
s1...
By solving this we get
a=2d ----> I
Given that
(4r/2 * [ 2a+(4r-1)d] ) / (7r/2* [2a+(7r-1)d] = 1/3
Substitute 2d in place of a
4/7 * [(4rd+3d)/(7rd+3d)] = 1/3
48r+36 = 49r+21
r = 36-21 = 15
2) Sum of infinite GP = a/(1-r)
s1...
Progressions SET-4 :-
1) In an arithmetic progression, if the ratio of (r+2)th term and the (r+5)th term is (r+3):(r+6) and the sum of the first 4r terms and sum of the first 7r terms are in the ratio 1:3. Find value of r.
a) 15 b) 18 c) 27 d) 29
2) Consider 20 infinite geometric progres...
1) In an arithmetic progression, if the ratio of (r+2)th term and the (r+5)th term is (r+3):(r+6) and the sum of the first 4r terms and sum of the first 7r terms are in the ratio 1:3. Find value of r.
a) 15 b) 18 c) 27 d) 29
2) Consider 20 infinite geometric progres...




















