Nice puzzle,

Break all the 3 pills into 2 parts each.

Take 3 half-parts of the pill. That makes it One B pill and Half A pill. Take another A pill from the box and break that too and eat it. That will complete One A and One B pill. Next day, take all the remaining halves and one-half of A pill left.

Yup, thats correct.

Here is another one.

Consider the following connect-the-dots game played on an m x n rectangular lattice. Two players take alternate turns, a turn consisting of drawing a line segment between two points of the lattice so that the interior of the segment intersects neither lattice points nor previously drawn segments. The last player to be able to play wins the game. Which player has the advantage also what is the winning strategy?

I am a patient of a deadly disease. My doctor has prescribed me two types of pills - A & B. I am supposed to eat one pill of each kind every morning (that is; one A & one B). Plus, I have to eat both of them together, not separately. I have one box of A - pills, & another box of B - pills.
One morning, I woke up & took one pill from the A box in my hand. Then, I put my hand in the B box, but accidently took two pills. Now I have one A pill & two B pills in my hand.
Now, the problem is, that both A & B pills look identical. Their colour, weight, size, shape, all are same. Taking the the wrong combination of pills can result to fatal side-effects. I can't even throw them away as they are very costly.
How can I take exactly one A pill & one B pill?

Nice puzzle,

Break all the 3 pills into 2 parts each.

Take 3 half-parts of the pill. That makes it One B pill and Half A pill. Take another A pill from the box and break that too and eat it. That will complete One A and One B pill. Next day, take all the remaining halves and one-half of A pill left.

I am a patient of a deadly disease. My doctor has prescribed me two types of pills - A & B. I am supposed to eat one pill of each kind every morning (that is; one A & one B). Plus, I have to eat both of them together, not separately. I have one box of A - pills, & another box of B - pills.
One morning, I woke up & took one pill from the A box in my hand. Then, I put my hand in the B box, but accidently took two pills. Now I have one A pill & two B pills in my hand.
Now, the problem is, that both A & B pills look identical. Their colour, weight, size, shape, all are same. Taking the the wrong combination of pills can result to fatal side-effects. I can't even throw them away as they are very costly.
How can I take exactly one A pill & one B pill?

ok puys......here s another puzzle..!!!

Y IS 6 AFRAID OF 7 ???

post ur answers...!!!

old one. Since 7 ate 9 (7 8 9)

ok puys......here s another puzzle..!!!

Y IS 6 AFRAID OF 7 ???

post ur answers...!!!

BCZ 7 IS GREATER THAN 6..simple...

ok puys......here s another puzzle..!!!

Y IS 6 AFRAID OF 7 ???

post ur answers...!!!

can u expalin d logic also plzz...!!!

Another one
Trouble with Sons: A woman had two sons who were born on the same
hour of the same day of the same year. But they were not twins. How
could this be so?

t

ans ...they were triplet...

.


1. Mr.Mathurs jewels have been stolen from his bank locker .
The bank has lockers of 12 people which are arranged in an array of 3 rows and 4 columns like:
1 2 3 4
5 6 7 8
9 10 11 12

* The locker belonging to JONES was to the right of BLACK'S locker and directly above MILLAR'S.
* BOOTH'S locker was directly above MILLAR'S.
* SMITH'S locker was also above GRAY's (though not directly).
* GREEN'S locker was directly below SMITH'S.
* WILSON'S locker was between that of DAVIS and BOOTH.
* MILLAR'S locker was on the bottom row directly to the right of HERD'S.
* WHITE'S locker was on the bottom right hand corner in the same column as BOOTH'S.

Which box belonged to Mr.Mathurs?

Ans:-4th Box.....

okay.. look the basic is that right from rupee 1 we need to go to rupee 560..so..
1=we need this note
2=we need this note
3=1+2
4=we need this note
5=4+1
6=4+2
7=4+2+1
8=we need this note
9=8+1
10=8+2
11=8+2+1
12=8+4
13=8+4+1
14=8+4+2
15=8+4+2+1...

so every power of 2 is needed as a base to GET FURTHUR DENOMINATIONS OF NOTES... i hope u understand the point...

in the previous method of weighing we used power of 3 cause we can use 1 and 3 in two oppossite parts in the balance to make the difference as 2... I HOPE ITS CLEAR NOW... any other doubts for which i know the solution i will be happy to answer..

Okay got the concepts absolutely clear. Thanks for the wonderful explaination .

ABhishek009 Says

Yeah i know the method I just want to know the concept behind this method.

okay.. look the basic is that right from rupee 1 we need to go to rupee 560..so..
1=we need this note
2=we need this note
3=1+2
4=we need this note
5=4+1
6=4+2
7=4+2+1
8=we need this note
9=8+1
10=8+2
11=8+2+1
12=8+4
13=8+4+1
14=8+4+2
15=8+4+2+1...

so every power of 2 is needed as a base to GET FURTHUR DENOMINATIONS OF NOTES... i hope u understand the point...

in the previous method of weighing we used power of 3 cause we can use 1 and 3 in two oppossite parts in the balance to make the difference as 2... I HOPE ITS CLEAR NOW... any other doubts for which i know the solution i will be happy to answer..

is it bags or is it notes??? if it is notes then try to find the highest power if 2 which is closest to 560..
2^9=512.. that is 10 notes of 1,2,4,8,16,32,64,128,256,512.....

i hope i have answered ur question.. your queston seems a little dubious??

Yeah i know the method I just want to know the concept behind this method.

Okay I get it but what is the logic for finding the questions such as :

Find the minimum number of bags required to pay Re 1 to 560.

is it bags or is it notes??? if it is notes then try to find the highest power if 2 which is closest to 560..
2^9=512.. that is 10 notes of 1,2,4,8,16,32,64,128,256,512.....

i hope i have answered ur question.. your queston seems a little dubious??

i m trying to explain..in case of any mistake please rectify me...
Suppose u need 1 kg den u have the 1kg weight,so no problem..
for 2kg u can put 3kg in one side and 1 kg in the opposite side,so the difference gives 2kg..
3kg readily available..
4=3+1
5=9-(3+1)
6=9-3
7=9+1-3
8=9-1
9=9
10=9+1
similarly u can get all the integers from 1 to 100 with these weights..This is the only combinaton possible...i.e.1,3,9.....3^x which is less than the largest weight to be measured..
Hope u get my point...

Okay I get it but what is the logic for finding the questions such as :

Find the minimum number of bags required to pay Re 1 to 560.

i m trying to explain..in case of any mistake please rectify me...
Suppose u need 1 kg den u have the 1kg weight,so no problem..
for 2kg u can put 3kg in one side and 1 kg in the opposite side,so the difference gives 2kg..
3kg readily available..
4=3+1
5=9-(3+1)
6=9-3
7=9+1-3
8=9-1
9=9
10=9+1
similarly u can get all the integers from 1 to 100 with these weights..This is the only combinaton possible...i.e.1,3,9.....3^x which is less than the largest weight to be measured..
Hope u get my point...

Mr.Kool Says

Any other way to measure.

No other method this is the only method. By the way I am looking for the derivation if someone knows then plz let me know.

ABhishek009 Says

U need 5 weights they are as follows 1 , 3 , 9 , 27 , 81.

Any other way to measure.

here is another one.....

I want to weigh weights from 1 to 100Kgs(all integer weights
only) using a common balance. What is the minimum no. of weights i
require to do the job and what are those? How many such possible
combinations are there?

U need 5 weights they are as follows 1 , 3 , 9 , 27 , 81.

here is another one.....

I want to weigh weights from 1 to 100Kgs(all integer weights
only) using a common balance. What is the minimum no. of weights i
require to do the job and what are those? How many such possible
combinations are there?

shanks4mba Says

we need to start posting new puzzles for this season...i'll try doin tht from tomm...:)

gr8 :, i just hope they r placement oriented.
i have a company onmobile tomorow and thanx :banghead: to recession half of the college has applied for it.

keep posting

viveknitw Says

r there no more?

we need to start posting new puzzles for this season...i'll try doin tht from tomm...:)

r there no more?

4. Boys are allowed to watch football at C.V.Raman auditorium subjected to conditions.

* The boy over age 16 can wear overcoat
* No boy over age 15 can wear cap
* To watch the football either he has to wear overcoat or cap or both
* A boy with an umberella or above 16 or both cannot wear sweater.
* Boys must either not watch football or wear sweater.

What is the appearence of the boy who is watching football..

Answer for this question,according to me is :the boy is wearing overcoat and having umberealla with him.
The boy over 16 can wear overcoat but no boy over 15 can wear cap.So one cannot wear overcoat and cap at the same time.
A boy with umberella or above 16 or both cannot wear sweater.In order to watch football wearing sweater is forbidden by the condition.
When a boy is wearing cap to carry umberella at the same time sounds absurd.So the boy above 16 wearing overcoat and having umberella with him is watching football.

Please tell me if my answer is correct or not.Please help.

Question: How many times can you subtract 6 from 36???

Answer:

I can subtract 6 from 36 just once because after that I will be subtracting 6 from 30 and not from 36.

First Step: 36 - 6 = 30

Second Step: 30 - 6 = 24

............

............

.............

I hope this is the answer that you were looking for.

Thank You

Ravi Raja

An easy one for you guys...
how many times can you subtract 6 from 36???

THUSSU Says

quite simply, the efect of gravity remains the same on both the bodies. so the monkey is dead. it might have stayed alive if it hadnt jumped. ironic.

One thing to take notice is that "THE BULLET WILL MISS THE MONKEY IF THE TIME IN WHICH THE MONKEY HITS THE GROUND IS NOT SUFFICIENT FOR THE BULLET TO TRAVEL THE HORIZONTOL DISTANCE BETWEEN THE GUN AND THE MONKEY"

Yeah gravity and all fine but this though a rare case needs consideration!

Hi folks,
here is another one ...........

A king has decides to hold a royal feast on occasion of his marriage. He has 40 bottles of wine that are for the guests but out of these 40 bottles there is exactly 1 bottle that has poision.King has to start the party in exactly 1 hour.

Now the king has to find out the poison bottle so that the remaining 39 bottles of wine can be used for the party. The king has 20 prisoners who have been awarded death penalty. At the expense of his prisoners the king has to find out the poision bottle.

The property of the poison is such that no matter how much ever quantity one consumes the poison will take effect only after 1 hour and therefore the person consuming the poison will die only after 1 hour.
So the king has to find poison bottle within 1 hour so that the party can be started on time. What should the king do??

he has to use 6 of his prisoners. as 2^6>40

suppose the prisoners are 1,2,3,4,5,6

and botlles are 1,2 ...40

Bottle..Prisoner
1........1
2........2

7.......1,2
8.......1,3


22.....1,2,3


so only a unique combination will die and he will get to know.

in fact using 6 he can test 64 bottles not 40

Hi folks,
here is another one ...........

A king has decides to hold a royal feast on occasion of his marriage. He has 40 bottles of wine that are for the guests but out of these 40 bottles there is exactly 1 bottle that has poision.King has to start the party in exactly 1 hour.

Now the king has to find out the poison bottle so that the remaining 39 bottles of wine can be used for the party. The king has 20 prisoners who have been awarded death penalty. At the expense of his prisoners the king has to find out the poision bottle.

The property of the poison is such that no matter how much ever quantity one consumes the poison will take effect only after 1 hour and therefore the person consuming the poison will die only after 1 hour.
So the king has to find poison bottle within 1 hour so that the party can be started on time. What should the king do??

6. A hotel has 10 storeys.Which floor is above the floor below the floor, below the floor above the floor, below the
floor above the fifth.

Ans: The sixth floor.


1. Mr.Mathurs jewels have been stolen from his bank locker .
The bank has lockers of 12 people which are arranged in an array of 3 rows and 4 columns like:
1 2 3 4
5 6 7 8
9 10 11 12

* The locker belonging to JONES was to the right of BLACK'S locker and directly above MILLAR'S.
* BOOTH'S locker was directly above MILLAR'S.
* SMITH'S locker was also above GRAY's (though not directly).
* GREEN'S locker was directly below SMITH'S.
* WILSON'S locker was between that of DAVIS and BOOTH.
* MILLAR'S locker was on the bottom row directly to the right of HERD'S.
* WHITE'S locker was on the bottom right hand corner in the same column as BOOTH'S.

Which box belonged to Mr.Mathurs?



4. Boys are allowed to watch football at C.V.Raman auditorium subjected to conditions.

* The boy over age 16 can wear overcoat
* No boy over age 15 can wear cap
* To watch the football either he has to wear overcoat or cap or both
* A boy with an umberella or above 16 or both cannot wear sweater.
* Boys must either not watch football or wear sweater.

What is the appearence of the boy who is watching football.


5. A bird keeper has got P pigeons, M mynas and S sparrows.
The keeper goes for lunch leaving his assistant to watch the birds.

* Suppose p=10, m=5, s=8 when the bird keeper comes back, the assistant informs the x birds have escaped. The bird keeper exclaims: "Oh no! All my sparrows are gone."
How many birds flew away?
* When the bird keeper comes back, the assistant told him that x birds have escaped. The keeper realised that atleast 2 sparrows have escaped.
What is minimum no of birds that can escape?




6. Answer the following questions based on the conditions from the choices A, B, C, D, E as described below:
(A) if a definete conclusion can be drawn from condition 1
(B) if a definete conclusion can be drawn from condition 2
(C) if a definete conclusion can be drawn from condition 1 and 2
(D) if a definete conclusion can be drawn from condition 1 or 2
(E) no conclusion can be drawn using both conditions

* person 1 says N<5
* person says N>5
* person 3 says 3N>20
* person 4 says 3N>10
* person 5 says N<8

What is the value of N?


a) 1. No of persons who speak false being less than no of persons who tells the truth.
2. Person 2 is telling the truth.

b) 1. no of persong telling the truth is greater than no of persons telling lies
2. person 5 is telling the truth.

answer of knight and knave prob........



i would go and ask any one, "if i ask the other one, the way to the lion, wat wil his answer be?" i would take the way he shows............ is it right??????????????

Hello Akshat/everyone,

I am not clear with the soln for camel's problem...plz elaborate it at the earliest possible moment.

Regards,
Pragati

Bhaiyaa?

Almost forgot i posted puzzles here
Here are the solutions :)



divide 25 horses in 5 groups for 5 races...
Now take toppers of all the races for another race....6th Race
Now in this race the 4th and 5th are out because we want only top 3....
2nd and 3rd of the group of third horse in 6th race are also out...as they will have position lower than 3 in 25 horses togethar...
3rd horse of the group of second horse in 6th race is also out for same reason...
take tooper of 6th race out as this will be topper of all 25 horses...

Now we have 5 horses and we want top 2 of them....1 more race :)

Ans 7 races minimum....



Camel will need 5 bananas to transfer all the bananas 1 mile away...
5 as for 1st 1000 he'll go n come back then for another 1000 he'll go n come back but for last 1000 he'll only go as nothing will be left behind...

For second mile too it'll take 5 bananas...

Now it'll require 5 bananas per mile for total banana count > 2000
and for banana count < 2000 it'll eat 3 bananas...

and for < 1000 it'll eat 1 banana....

so 1st 1000 bananas will be finished in 1000/5 = 200 Miles
next 1000 in 1000/3 = 334 Miles...

Finaly he'll have 1000 bananas and 466 miles to go...

At B camel will have 534 bananas :)

-Akshat

hi alllllll..........
i am new to this forum........
i don know how to post qustions to all...............
there s no member list displayed!!!!!!!!!!!!!!!!!!1
can anybody help??????????????????//


here s an interesting number........


find a number which when divided by' i ' wil give ' i-1 ' as remainder............ here i= 1 to 10......

Click on this
http://www.pagalguy.com/cat/showthread.php?t=8927
Mridul

hi alllllll..........
i am new to this forum........
i don know how to post qustions to all...............
there s no member list displayed!!!!!!!!!!!!!!!!!!1
can anybody help??????????????????//


here s an interesting number........


find a number which when divided by' i ' wil give ' i-1 ' as remainder............ here i= 1 to 10......

hi all...........
i am new to this forum.........
i don know how to post puzzles or questions to allllllll............
can anybody help???????????????????


here s an interesting number..............


find a number which when divided by' i ' wil give ' i-1 ' as remainder............ here i= 1 to 10......

finally answer time!

kunwarramru and siddhesh_j, both are very close to the answer. i think logic was abzzolutely right.

The answer is 3 planes and 5 fuel tanks.

Here's how...

A, B and C take off together.
After flying 3000 miles, C fills the tanks of A and B, then turns and
returns to base. At 6000 miles, B, whose tank is now 3/4 full, fills A
up, leaving himself with just enough to get back to base.

'A' now flies on, with fuel to get to the other side of the world and
half-way back. Here, 6000 miles from base, he is met by C (1/2 full)
who has travelled from the other side of the globe,
and they share C's fuel.

This is enough to get them to a rendezvous with B (3/4 full) at a point
3000 miles out. B now tops up A and C, each then having just enough for
the last 3000 miles.well done guys.

(to siddhesh_j- the rock is my idol...no comments tolerated)

hmm, didn't think of using same planes!!:satisfie:

hmm yeah i shud hv thot of B & C doing the work of D, E ... that way is probably the most efficient ...
@ravi -I made no comments ... just said good avtaar ... the smileys just depict rocks fav move , esp the 2nd one

A man plans to make a non stop round the world flight(24,000 miles) form his private fuel store on Virgin islands.

Each of his planes can fly 12000 miles on 1 tank full of fuel and all are equipped to transfer fuel from one another in-flight. We can assume that this process is instantaneous.

How many planes and how many tanks of fuel will he need???

finally answer time!

kunwarramru and siddhesh_j, both are very close to the answer. i think logic was abzzolutely right.

The answer is 3 planes and 5 fuel tanks.

Here's how...

A, B and C take off together.
After flying 3000 miles, C fills the tanks of A and B, then turns and
returns to base. At 6000 miles, B, whose tank is now 3/4 full, fills A
up, leaving himself with just enough to get back to base.

'A' now flies on, with fuel to get to the other side of the world and
half-way back. Here, 6000 miles from base, he is met by C (1/2 full)
who has travelled from the other side of the globe,
and they share C's fuel.

This is enough to get them to a rendezvous with B (3/4 full) at a point
3000 miles out. B now tops up A and C, each then having just enough for
the last 3000 miles.well done guys.

(to siddhesh_j- the rock is my idol...no comments tolerated)

sorry...internet prob. caused repetition. read next post

A man plans to make a non stop round the world flight(24,000 miles) form his private fuel store on Virgin islands.

Each of his planes can fly 12000 miles on 1 tank full of fuel and all are equipped to transfer fuel from one another in-flight. We can assume that this process is instantaneous.

How many planes and how many tanks of fuel will he need???

well I am late in posting da soln ... but here goes
acc to me - 5 planes are reqd.Let A be the main plane and B C D E be fuelers.
ABC start ... At 3000miles C puts in A 3000 and waits ... A B continue.
at 6000 miles , B puts 3000 in A and comes back to C where C puts 3000 in B and B ,C return to base.

Now A which has 12000 miles worth fuel - goes to 18000 miles ... meanwhile ... D E have started from other side ... E is waiting at 21000 miles ... D is waiting at 18000 miles where it puts 3000 miles in A . A