could anyone help me with solving population growth problems without using formulas.

@[588628:savvy_love]
ans :A

@swahamohapatra said: need help!!

A clock set right at 12 noon on monday loses 1/2% on the correct time in the 1st wk but gains 1/4% on the true time during 2nd wk. the tttime shown on monday after two wks will be

12:25:12

12:50:24

11:34:48

none

@[502438:swahamohapatra] it looses 0.5 % on actual time of a week (say it as x ) and gains 0.25 % on x (2 nd week )=> it totally looses o.25 % on x => total loss 0.25 % x i.e, 0.25*7*24*60/100 => 25.2 mins

@[328071:vivek.jajodia] thanks ...

@[328071:vivek.jajodia] hey hii...

@[562049:rst123456] refer QUANTUM CAT % s chapter and go through the examples ,u can understand the nuances of %

@vivek.jajodia said:

brother there is a gain of 25%.. im not being able to deduce 20% from this.. can u pls show the steps to deduce 20% mixture

@x2maverickc said:

20%

say 1 litre of milk costs 100/-

after mixing he seels 0.8L of milk and 0.2L of water for 100/-

so %age of water= 0.2/1 =20%

@vivek.jajodia said: Q) A dishonest milkman professes to sell milk at CP. But mixes some quantity of water to it, thereby gaining 25%. What is the %age of water added??

Q) A dishonest milkman professes to sell milk at CP. But mixes some quantity of water to it, thereby gaining 25%. What is the %age of water added??

@kpraveen010 said: In 2001 ramu salary was 20000, In 2002 it is increased by 10% and again in 2003 it is increased by 20%. What is salary of ramu in 2003 ? I want the solution in formula based.

@[587220:gobar_singh] hi,the problem of % u discussed based on the concept PRODUCT CONSTANT

@[502438:swahamohapatra]

need help!!

@[543509:kpraveen010]

20000 * 110/100 * 120/100= 26400.

+10%= 110/100

+20%=120/100.

what? :shocked:


as far as i knw arun sharma has correct answer of dis....;)

neway, d shortcut works likes dis.........

if a quantity (price in dis case) increases by 1/n, in order to keep d product (here expense) constant, another quantity (here consumption) should decrease by 1/(n+1)


in this case, the price goes up by 40% i.e. 4/10 or 2/5 or 1/2.5.........
so, to compensate for dis increase, consumption shud decrease by 1/(2.5+1) i.e. 1/3.5.........which is slightly greater dan 25%

hence d ans is 28.56%

hi.. sorry for late reply, was a little busy now a days...btw thnk u very very much bro. it realy helped.. and yes u r right the answer given in arun sharma's book is correct but only in the answer key...in the "Detailed soln and short cut" section the answer of qus 6 has been printed as qus 5 which was the root of all the confusion, hope its corrected in newer editions

here price goes up by 40% i.e. 4/10 or 2/5............which has a direct effect on expense going up by 2/5...

but Mr. A wishes to cut down on his consumption to balance the expense.......

see dis.......40% increase in price means price becoming 1.4 times or 14/10 or 7/5 times..........to compensate for dis, the consumption needs to be brought down by 5/7 times.............which means expense bocomes (7/7 - 5/7) = 2/7 times the original expense....which is 2*14.28 = 28.56 %........



plz note dat der's a shortcut 2 do all dis....let me knw if u r interestd in dat....

hey..thanx brother..this question was giving me nightmares for a long long time, so did the wrong answer given in arun sharma's book..(25%) :shock:

plz tell me the shortcut!!

can some one please explain the thought process behind this..

Mr.. A is worried about the balance of his monthly budget. the price of petrol has increased by 40%. by what percent should he reduce the consumption of petrol so that he is able to balance his budget?

Number1=a, number2=b

N1=a+10 , N2= b+10
percentage increase= /a *100= 1000/a % similarly for Number2 also the percentage increase will be 1000/b %
Hence the numbers now become:
N1'= (a+10) and N2'= (b+10)

On equating any one of these to 72, we get a quadratic equation as:
a^2-52a+100=0
a=50 or 2

diff=50-2=48

There are two distinct natural numbers. Each is first increased by 10 and then by the same percentage as each was increased for the first time. Each number finally results in 72. Find the difference between the numbers.

Options:
a) 46
b) 48
c) 52
d) 44

thank u :-)
:)

Options for the above question:
a) Rs.140000
b)Rs.90000
c)Rs.40000
d)Rs.240000

a) 140000 is the ans.
Solve through options.

Options for the above question:
a) Rs.140000
b)Rs.90000
c)Rs.40000
d)Rs.240000

please help me out with this problem:
a salesman has to choose between two schemes of remuneration. the first scheme has a fixed salary of rs.3700 and a commission of 2% on the sales above rs.50000. the second scheme has no salary but offers commission only. the commission, starting from 3% of sales for the first rs.50000 or part there of, increases at the rate of 1 percentage point for every increase of rs.50000 or part there of sales, upto a maximum of 20% of sales. what is the minimum value of the sales above which he can prefer the second scheme?

(new value / old value ) x 100 . here in dis case the old value is 20000 and new value is 26400

and also percentage increase from 2001 to 2003. but do it in formula base ? :cheers:
:cheers:
plz give reply ?

10% of 20000 =2000

so salary in 2002 =2000+ 20000=22000

20% of 22000 = 4400

so final salary is 26400

its jus the basic % calculation and adding it up to original value to find the final value..

In 2001 ramu salary was 20000, In 2002 it is increased by 10% and again in 2003 it is increased by 20%. What is salary of ramu in 2003 ?
I want the solution in formula based.
:banghead::banghead::banghead::banghead:

Trying getting hold of Time material. A second hand Quant workbook given by Time is also good enuf!!:)