The links to the previous threads are:
Part 1
http://www.pagalguy.com/forum/quantitative-questions-and-answers/74662-official-quant-thread-cat-2012-a.html
Part 2
http://www.pagalguy.com/forum/quantitative-questions-and...
59
59
Official Quant Thread for CAT 2012
Quantitative
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Please continue here for all the Quant queries and discussions.
The links to the previous threads are:
Part 1
http://www.pagalguy.com/forum/quantitative-questions-and-answers/74662-official-quant-thread-cat-2012-a.html
Part 2
http://www.pagalguy.com/forum/quantitative-questions-and...
The links to the previous threads are:
Part 1
http://www.pagalguy.com/forum/quantitative-questions-and-answers/74662-official-quant-thread-cat-2012-a.html
Part 2
http://www.pagalguy.com/forum/quantitative-questions-and...
please explain..
Ok i got it..
Ok i got it..
96 should be the ans.
@[367896:sumeet1489]
Infinite??
Infinite??
connect the centers of all three circles. you'll get a equilateral triagle with sides 2.
2/3rd of the height of the triangle will give you the radius of the circle which passes through centers of all the 3 circles. now just add 1 to that value to get the radius of the circle that touches all...
2/3rd of the height of the triangle will give you the radius of the circle which passes through centers of all the 3 circles. now just add 1 to that value to get the radius of the circle that touches all...
1
9 days?
If capacity of container is 1024a,then 512a of the capacity ll be done in 9 days...
@[172182:varun.tyagi] - But still u'd prefer PG to God's own country:P
If capacity of container is 1024a,then 512a of the capacity ll be done in 9 days...
@[172182:varun.tyagi] - But still u'd prefer PG to God's own country:P
1
How many perfect squares are the divisors of 15! ??
A. 60B. 72C. 96D. 108E. 112
A. 60B. 72C. 96D. 108E. 112
f(p) = 2^p + p^2, where p is a prime number. What is the number of prime numbers forwhich f(p) is prime.
1,2,3,infinite
1,2,3,infinite
1x3 + 5x7 + 9x11 + ..... + 101x103
= 1x3 + Sigma(1 to 25) (4n + 1) (4n + 3)
= 3 + Sigma(1 to 25)(16n^2 +16n + 3)
= 3 + 88400 + 5200 + 75
= 93678
Sorry i had provided the wrong answer before
= 1x3 + Sigma(1 to 25) (4n + 1) (4n + 3)
= 3 + Sigma(1 to 25)(16n^2 +16n + 3)
= 3 + 88400 + 5200 + 75
= 93678
Sorry i had provided the wrong answer before
oa 2 Pi (2 + _/3)/ _/3
@swamyanarayanancan you please elaborate..
@swamyanarayanancan you please elaborate..
@[589932:nidaparveen]
three equal circles of radius 1 cm are circumscribed by a larger circle.Find the perimeter of the circumscribing circle
2.866 pie cm..????
three equal circles of radius 1 cm are circumscribed by a larger circle.Find the perimeter of the circumscribing circle
2.866 pie cm..????
2 Pi (2 + _/3)/ _/3
1
I am getting perimeter as
2*pi*(2 + _/3)
what is the OA?
2*pi*(2 + _/3)
what is the OA?
I have explained it earlier also :D
Basically we have to find an A.P. such that the sum of the numbers = 600
Let the first term = a which should be a positive number,
Common difference = 1 and
Number of terms = n
=> Sum of this A.P. = n*(2a + n - 1)/2 = 600 = 2^3 * 3 * 5^2
=>...
Basically we have to find an A.P. such that the sum of the numbers = 600
Let the first term = a which should be a positive number,
Common difference = 1 and
Number of terms = n
=> Sum of this A.P. = n*(2a + n - 1)/2 = 600 = 2^3 * 3 * 5^2
=>...
3
three equal circles of radius 1 cm are circumscribed by a larger circle.Find the perimeter of the circumscribing circle.
It should be 9 days as on the next day i.e. the 10th day it will double itself to completely fill the container.
9 days. 10th day it will double itself and completely fills the container.
9 days
A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
can u please share the solution sir, i am not sure of the answer
21 me kya galat hai???? n = 21 matlab iss base system me 21 digits hai aur fir uss ke baad 2 digit no chalu hote hai.. .. so 13 can be considered as single digit no in base 21
aur n = 13 bhi sahi hai .. but ye option me nahi hai iss liye chhod diya..
aur n = 13 bhi sahi hai .. but ye option me nahi hai iss liye chhod diya..
1
Guru hain aap. __/ /\ \__
1
@[521225:Vinaysastra]
The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for ...
The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for ...
baat to sahi hai ... ho sakta hai aur 2 4 ho...but objective exams me sahi OPTION choose karna hota hai... sahi ans nahi :)
2
:)@FoolNFinal said: ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
@Faruq said: @FoolNFinal @sumeet1489 @ashish100 @pyashraj Ans is D
It would be great if you could xplain how 21...
I followed the same steps as @[556294:FoolNFinal] .. Putting n=21 m getting
A/B=13/2
But if i put n-13
i get A/B=8/1
So shoudnt 13 be the ans?
bhai there can be a lot of values of n that is why the question is which among the following options can be the value of n so check among the given options which one fits
1
Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option
Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
@[556294:FoolNFinal] @[367896:sumeet1489] @[271527:ashish100] @[512657:pyashraj]
Ans is D
Ans is D
1
ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ...
equate both eq..An + B = 5Bn + 5A
A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
equate both eq..An + B = 5Bn + 5A
A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
2
option D hai kya iska ans.
1
getting 13 as OAAn+B =5Bn +5Asolve for n .....A,B comes out to be 8,1 or AB is 81 and n is 13
@[569305:Faruq]
21..?
21..?
1
If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n?
12/14/16/21
12/14/16/21
faruq bhai options to do :)
[if gte mso 9]> Normal 0 false
they will be diametrically opposite 8 times in 9 hours (one time in each hour except between 5 - 6 o'clock)
as there are total 27 hours
so it will happen 24 times
as there are total 27 hours
so it will happen 24 times
1
no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!
1... 0 cause n = (a+b)*(a-b)both a+b and a-b should be even or odd but scince we have only one 2 .. so one will be odd and other will always be even .. so 0 ways
2.. not sure bt is it 420???
2.. not sure bt is it 420???
2
@[470247:victor11] For question 2here,take 15 common out so N becomes N=2^2*3^2*5^1sum of factors of this value of N is (1+2+4)(1+3+9)(1+5)=6*13*7and sum of factors divisible by 15 is 6*13*7*15=8190is it correct?
2
KINDLY USE QUOTE FEATURE IF YOU ARE ANSWERING SOMEONE'S QUESTION OR DOUBT, BECAUSE EVERYONE WOULD BE ABLE TO TRACE BACK TO THE QUESTION. THANKS!!
for boats to not collide two conditions must be satisfieddistance travelled by both boats must be less than 2000m.there speed must become zero before 4mins. or 240s.
initial speed be Ufor 1st condition to be true
(U-0)/240 =0.1u=24m/s
for second conditionV is final speed=0S is distance ...
initial speed be Ufor 1st condition to be true
(U-0)/240 =0.1u=24m/s
for second conditionV is final speed=0S is distance ...
1
@[569305:Faruq] bhai jaan : 24 hain kya answer????
1
Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.
@[497904:addikted] @[367896:sumeet1489] Answer is B.Approach please.
@[556294:FoolNFinal]
1
It should be 40 rubies.
A direct approach is there.
1 kg ruby --> 4/0.3 = 13.33 cr
1 kg emerald --> 5/0.4.= 12.5 cr
So Rubies has to be maximised --> so 40 rubies.
Alternate approach:
0.3R+0.4E=12
=> R/40 + E/30 =1
Draw it on x axis and Y axis:
Also 4R+5E = k [As we ha...
A direct approach is there.
1 kg ruby --> 4/0.3 = 13.33 cr
1 kg emerald --> 5/0.4.= 12.5 cr
So Rubies has to be maximised --> so 40 rubies.
Alternate approach:
0.3R+0.4E=12
=> R/40 + E/30 =1
Draw it on x axis and Y axis:
Also 4R+5E = k [As we ha...
2
8 se to kahi jyada pairs hai iss k ...8! = 2^23 * 3^9 * 5^4 * 7^2
for b = 2 a can be 3 4 5 6 7 8 9 10 12 14......aise hi for b = 3 fir b = 4 ......kuch gadbad hai...
for b = 2 a can be 3 4 5 6 7 8 9 10 12 14......aise hi for b = 3 fir b = 4 ......kuch gadbad hai...
1
[if gte mso 9]> Normal 0 false false ...
@[271527:ashish100] Bhai,sorry lekin question a^2 * b^2 tha.Check the later posts. But thanks anyway.
But thanks anyway.
option B lag raha hai
superb solution!!
1
@[577366:chevy] None of these means pi*r^2 aa raha hain
bhai kitni bhi koshish kar lo sai question nahi likh paoge ;)
This continous problem should now be reported to mods , i guess
p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions
cheers :)
This continous problem should now be reported to mods , i guess
p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions
cheers :)
Does any have ebbok: Quantitative Aptitude for MBA Entrance Exams by Guha Abhijit. I want to refer P&C; and Probability.
Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.
Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
2
question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 — b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
40 R aa raha hai ans...cost of ruby per kg = 40/3cost of emrald per kg = 50/4since cost of ruby is more we should fill bag with ruby only.. i.e 40 max ruby
@[576959:Stoicalme] for ist one:denominator is (a-b)(a+b)now max value of a+b can be till 10 only as 11 won't divide 8!so when a+b=10 then a-b can be 2,4,6,8out of which following sol can be possible : (6,4)(7,3)(8,2)when a+b=9 then a-b can be 1,3,5,7here 0 possible solutions as max power of 3 ca...
Option C
@[592873:sravan1989]:
Just directly apply this formula:
S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)
You can leave the last term as it will be very very low...
So S= ln(n+0.5) + 0.5772
Just directly apply this formula:
S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)
You can leave the last term as it will be very very low...
So S= ln(n+0.5) + 0.5772