Please continue here for all the Quant queries and discussions. The links to the previous threads are: Part 1 http://www.pagalguy.com/forum/quantitative-questions-and-answers/74662-official-quant-thread-cat-2012-a.html Part 2 http://www.pagalguy.com/forum/quantitative-questions-and...
"From condition 1 and 2, we can safely say that we have to find the number of odd factors of 600"
@varun.tyagi said: I have explained it earlier also Basically we have to find an A.P. such that the sum of the numbers = 600Let the first term = a which should be a positive number,Common difference = 1 and Number of terms = n=> Sum of this A.P. = n*(2a + n - 1)/2 = 600 = 2^3 * 3 * 5^2=> Now we have to express 600 into product of two numbers which is equal to number of factors = 4*2*3 = 24 waysBut we have to take care of few things here.1.) If n is odd, (2a + n - 1) must be even (because there is a 2 in the denominator)2.) If n is even, (2a + n - 1) must be odd3.) n should be greater than 24.) 'a' must be a positive integerFrom condition 1 and 2, we can safely say that we have to find the number of odd factors of 600 = 6. But there will be a case when n = 1, which is not allowedSo total ways = 6 - 1 = 5P.S. Enjoying my trip in Kerala. Really the god's own country
The number of ways of factorising 91000 into two factors, m and n, such that m>1,n>1 and gcd(m,n)=1 is a.7 b.15 c.32 d.None of these P.S. dont have the ans to this ques....
connect the centers of all three circles. you'll get a equilateral triagle with sides 2. 2/3rd of the height of the triangle will give you the radius of the circle which passes through centers of all the 3 circles. now just add 1 to that value to get the radius of the circle that touches all...
@nidaparveen said: oa 2 Pi (2 + _/3)/ _/3@swamyanarayanancan you please elaborate..
connect the centers of all three circles. you'll get a equilateral triagle with sides 2. 2/3rd of the height of the triangle will give you the radius of the circle which passes through centers of all the 3 circles. now just add 1 to that value to get the radius of the circle that touches all the three circles. (from outside)
9 days? If capacity of container is 1024a,then 512a of the capacity ll be done in 9 days... @[172182:varun.tyagi] - But still u'd prefer PG to God's own country:P
@anshulagrawala said: A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
9 days?
If capacity of container is 1024a,then 512a of the capacity ll be done in 9 days...
@[172182:varun.tyagi] - But still u'd prefer PG to God's own country:P
I won't run on Sunday even if it's 100m event in Olympic games
@[589932:nidaparveen] three equal circles of radius 1 cm are circumscribed by a larger circle.Find the perimeter of the circumscribing circle 2.866 pie cm..????
I have explained it earlier also :D Basically we have to find an A.P. such that the sum of the numbers = 600 Let the first term = a which should be a positive number, Common difference = 1 and Number of terms = n => Sum of this A.P. = n*(2a + n - 1)/2 = 600 = 2^3 * 3 * 5^2 =>...
@Vijay2405 said: In how many ways can 600 be expressed as sum of 2 or more consecutive natural nos.a. 14b. 7c. 6d. 5
I have explained it earlier also :D
Basically we have to find an A.P. such that the sum of the numbers = 600
Let the first term = a which should be a positive number, Common difference = 1 and Number of terms = n
=> Sum of this A.P. = n*(2a + n - 1)/2 = 600 = 2^3 * 3 * 5^2
=> Now we have to express 600 into product of two numbers which is equal to number of factors = 4*2*3 = 24 ways
But we have to take care of few things here. 1.) If n is odd, (2a + n - 1) must be even (because there is a 2 in the denominator) 2.) If n is even, (2a + n - 1) must be odd 3.) n should be greater than 2 4.) 'a' must be a positive integer
From
condition 1 and 2, we can safely say that we have to find the number of
odd factors of 600 = 6. But there will be a case when n = 1, which is
not allowed
So total ways = 6 - 1 = 5
P.S. Enjoying my trip in Kerala. Really the god's own country :D
@anshulagrawala said: A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
It should be 9 days as on the next day i.e. the 10th day it will double itself to completely fill the container.
@anshulagrawala said: A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??
21 me kya galat hai???? n = 21 matlab iss base system me 21 digits hai aur fir uss ke baad 2 digit no chalu hote hai.. .. so 13 can be considered as single digit no in base 21 aur n = 13 bhi sahi hai .. but ye option me nahi hai iss liye chhod diya..
@Vinaysastra said: It would be great if you could xplain how 21... I followed the same steps as @FoolNFinal .. Putting n=21 m getting A/B=13/2 But if i put n-13i get A/B=8/1 So shoudnt 13 be the ans?
21 me kya galat hai???? n = 21 matlab iss base system me 21 digits hai aur fir uss ke baad 2 digit no chalu hote hai.. .. so 13 can be considered as single digit no in base 21
aur n = 13 bhi sahi hai .. but ye option me nahi hai iss liye chhod diya..
@Aizen said: sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*4 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: __/\__ @gs4890 bhai , @sumeet1489 bhai aur sabhi quant maharathi ...
@[521225:Vinaysastra] The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for ...
The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for which the aforesaid condition holds true. Thus, this is the wright answer....
My Intrvwr askd me"Wht do u wnt 2 bcum in ur life?" I said"A Gud Humn" n i wsnt slctd bt i'm happy!!
@ashish100 said: Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option
baat to sahi hai ... ho sakta hai aur 2 4 ho...
but objective exams me sahi OPTION choose karna hota hai... sahi ans nahi :)
It would be great if you could xplain how 21... I followed the same steps as @[556294:FoolNFinal] .. Putting n=21 m getting A/B=13/2 But if i put n-13i get A/B=8/1 So shoudnt 13 be the ans?
@FoolNFinal said: ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
@Faruq said: @FoolNFinal @sumeet1489 @ashish100 @pyashraj Ans is D
It would be great if you could xplain how 21...
I followed the same steps as @[556294:FoolNFinal] .. Putting n=21 m getting
bhai there can be a lot of values of n that is why the question is which among the following options can be the value of n so check among the given options which one fits
@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
bhai there can be a lot of values of n that is why the question is which among the following options can be the value of n
Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option
@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n? 12/14/16/21
getting 13 as OA
An+B =5Bn +5A
solve for n .....A,B comes out to be 8,1 or AB is 81 and n is 13
@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n?
they will be diametrically opposite 8 times in 9 hours (one time in each hour except between 5 - 6 o'clock) as there are total 27 hours so it will happen 24 times
@Faruq said: On certain planet, there are seven days in a week - Sunday through Saturday. Also, each hour on this planet comprises exactly 60 minutes, just as on earth. However, each day on this planet comprises only 18 hours, when compared to the 24 hours on Earth. Therefore, the dials on the clocks on the planet are designed to show only 9 hours instead of the 12 hours shown on the clocks on Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are the minutes hand and the hours hand of such a clock diametrically opposite each other?
they will be diametrically opposite 8 times in 9 hours (one time in each hour except between 5 - 6 o'clock)
as there are total 27 hours
so it will happen 24 times
I don't have time to hate people who hate me, because I am too busy in loving people who love me.
no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!
no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!
1... 0 cause n = (a+b)*(a-b)both a+b and a-b should be even or odd but scince we have only one 2 .. so one will be odd and other will always be even .. so 0 ways 2.. not sure bt is it 420???
@victor11 said: Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.
1... 0 cause n = (a+b)*(a-b)
both a+b and a-b should be even or odd but scince we have only one 2 .. so one will be odd and other will always be even .. so 0 ways
@[470247:victor11] For question 2here,take 15 common out so N becomes N=2^2*3^2*5^1sum of factors of this value of N is (1+2+4)(1+3+9)(1+5)=6*13*7and sum of factors divisible by 15 is 6*13*7*15=8190is it correct?
for boats to not collide two conditions must be satisfieddistance travelled by both boats must be less than 2000m.there speed must become zero before 4mins. or 240s. initial speed be Ufor 1st condition to be true (U-0)/240 =0.1u=24m/s for second conditionV is final speed=0S is distance ...
Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.
It should be 40 rubies. A direct approach is there. 1 kg ruby --> 4/0.3 = 13.33 cr 1 kg emerald --> 5/0.4.= 12.5 cr So Rubies has to be maximised --> so 40 rubies. Alternate approach: 0.3R+0.4E=12 => R/40 + E/30 =1 Draw it on x axis and Y axis: Also 4R+5E = k [As we ha...
@sowmyanarayanan said: CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R c) 28R and 9E d) None of these Can someone explain the above with solution? Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.
8 se to kahi jyada pairs hai iss k ...8! = 2^23 * 3^9 * 5^4 * 7^2 for b = 2 a can be 3 4 5 6 7 8 9 10 12 14......aise hi for b = 3 fir b = 4 ......kuch gadbad hai...
@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
On
certain planet, there are seven days in a week - Sunday through Saturday. Also,
each hour on this planet comprises exactly 60 minutes, just as on earth.
However, each day on this planet comprises only 18 hours, when compared to the
24 hours on Earth. Therefore, the dials on the clocks on the planet are
designed to show only 9 hours instead of the 12 hours shown on the clocks on
Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are
the minutes hand and the hours hand of such a clock diametrically opposite each
other?
@Stoicalme said: Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?A) 0<10m/sB)0<20m/sC)0<30m/sD)N.O.TE)CBD
@Stoicalme said: Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
bhai kitni bhi koshish kar lo sai question nahi likh paoge ;) This continous problem should now be reported to mods , i guess p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions cheers :)
@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
bhai kitni bhi koshish kar lo sai question nahi likh paoge ;)
This continous problem should now be reported to mods , i guess
p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions
Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle. Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
@chevy said: A square intersects a circle at eight distinct points such that the area of the circle outside the square is equal to the area of the square outside the circle. If the radius of the circle is €˜r €™, then the area of the square is a) root(2) pi r^2 b) 2 pi r^2 c) 3/2 r^2 d)none f dese
Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.
Area of circle=x + y
pi * r^2=x + y
also, Area of square=x + y
Area of square=pi *r^2
Unseen, in the background, Fate was quietly slipping the lead into the boxing glove.
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