9 days. 10th day it will double itself and completely fills the container.

@anshulagrawala said: A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??

A bacterium doubles in a day. A bacterium is kept in a container. After 10 days the container is completely filled with bacteria. How much time will take to half fill the container??

@sowmyanarayanan said: i got it as 98878. is it right?

@Vinaysastra said: It would be great if you could xplain how 21... I followed the same steps as @FoolNFinal .. Putting n=21 m getting A/B=13/2 But if i put n-13i get A/B=8/1 So shoudnt 13 be the ans?

@Aizen said: sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*4 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: __/\__ @gs4890 bhai , @sumeet1489 bhai aur sabhi quant maharathi ...

@[521225:Vinaysastra]

@ashish100 said: Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option

@FoolNFinal said: ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai

@Faruq said: @FoolNFinal @sumeet1489 @ashish100 @pyashraj Ans is D

@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer

@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer

@ashish100 said: getting 13 as OAAn+B =5Bn +5Asolve for n .....A,B comes out to be 8,1 or AB is 81 and n is 13

@[556294:FoolNFinal] @[367896:sumeet1489] @[271527:ashish100] @[512657:pyashraj]

Ans is D

@Faruq said: If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n? 12/14/16/21

@Faruq said: If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n? 12/14/16/21

@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n? 12/14/16/21

@[569305:Faruq]

If AB is a two digit number in base n such that (AB)_n = 5(BA)_n, which of the following is a possible value of n?

12/14/16/21

@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n?

Thanks @[515110:culdip] Bhai
Please solve this one too.

If AB is a two digit number in base n such that (AB)_n = 5(BA)_n, which of the following is a possible value of n?

12/14/16/21

@Faruq said: On certain planet, there are seven days in a week - Sunday through Saturday. Also, each hour on this planet comprises exactly 60 minutes, just as on earth. However, each day on this planet comprises only 18 hours, when compared to the 24 hours on Earth. Therefore, the dials on the clocks on the planet are designed to show only 9 hours instead of the 12 hours shown on the clocks on Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are the minutes hand and the hours hand of such a clock diametrically opposite each other?

no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!

@victor11 said: Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.

@[470247:victor11]

KINDLY USE QUOTE FEATURE IF YOU ARE ANSWERING SOMEONE'S QUESTION OR DOUBT, BECAUSE EVERYONE WOULD BE ABLE TO TRACE BACK TO THE QUESTION. THANKS!!

@Stoicalme said: @addikted @sumeet1489 Answer is B.Approach please.

@[569305:Faruq] bhai jaan : 24 hain kya answer????

Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares?

Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15.

Kindly reply with explanations.

@Stoicalme said: @ashish100 Bhai,sorry lekin question a^2 * b^2 tha.Check the later posts. But thanks anyway.

@sowmyanarayanan said: CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R c) 28R and 9E d) None of these Can someone explain the above with solution? Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.

@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8

On certain planet, there are seven days in a week - Sunday through Saturday. Also, each hour on this planet comprises exactly 60 minutes, just as on earth. However, each day on this planet comprises only 18 hours, when compared to the 24 hours on Earth. Therefore, the dials on the clocks on the planet are designed to show only 9 hours instead of the 12 hours shown on the clocks on Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are the minutes hand and the hours hand of such a clock diametrically opposite each other?

@[271527:ashish100] Bhai,sorry lekin question a^2 * b^2 tha.Check the later posts. But thanks anyway.

@Stoicalme said: Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?A) 0<10m/sB)0<20m/sC)0<30m/sD)N.O.TE)CBD

@Stoicalme said: Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2

@[577366:chevy]

@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8

Does any have ebbok: Quantitative Aptitude for MBA Entrance Exams by Guha Abhijit. I want to refer P&C; and Probability.

@chevy said: A square intersects a circle at eight distinct points such that the area of the circle outside the square is equal to the area of the square outside the circle. If the radius of the circle is €˜r €™, then the area of the square is a) root(2) pi r^2 b) 2 pi r^2 c) 3/2 r^2 d)none f dese

@ashish100 said: @Stoicalme for ist one:denominator is (a-b)(a+b)now max value of a+b can be till 10 only as 11 won't divide 8!so when a+b=10 then a-b can be 2,4,6,8out of which following sol can be possible : (6,4)(7,3)(8,2)when a+b=9 then a-b can be 1,3,5,7here 0 possible solutions as max power of 3 can be two onlywhen a+b=8 a-b can be 2,4,6so (5,3)(6,2)possible solutionswhen a+b=7 and a-b can be 1,3,5possible sol are :(4,3)(5,2)when a+b=6 and a-b can be 2,4so sol can be :(4,2)when a+b =5 and a-b can be 1,3so sol can be 3,2 when a+b=4 then a-b can be 2so sol can be nothingIn all getting 9 solutions....kahan miss kar raha hoon bhai log

@sowmyanarayanan said: CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R c) 28R and 9E d) None of these Can someone explain the above with solution? Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.

@[576959:Stoicalme]

Option C

@Stoicalme said: Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?A) 0<10m/sB)0<20m/sC)0<30m/sD)N.O.TE)CBD

@sravan1989 said: Any one knows the sum of first n terms of Harmonic progression ???

Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?

@[525438:taurean11]:

@htomar said: FoolNFinal Bhai, i need one clarification in first part. In first part, we have assumed the boxes to be distinct and balls to be identical, and used the formula to get the answer. Which is nothing but 8!/(4!*4!). Now,I will get the same answer, if i assume that there are 4 identical balls placed in a row and i put four identical bars in the gaps to divide the balls into 5 groups. Then the situation will be same as arraning 8 objects out of which 4 are of one type and 4 another type. This will come out same as 8!/(4!*4!) Question is, for your part you assumed boxes to be distinct and balls to be identical whereas in the above approach i assumed balls to be identical but nothing about boxes. Is it correct approach?

A square intersects a circle at eight distinct points such that the area of the circle outside the square is equal to the area of the square outside the circle. If the radius of the circle is ‘r’, then the area of the square is

a) root(2) pi r^2

b) 2 pi r^2

c) 3/2 r^2

d)none f dese

@Stoicalme said: 1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 — b^2, then how many such sets (a, b) are possible? a 5 b 6 c 7 d 8 2) The lines y = 3x and x + y = 40 and the x axis bound a triangular area. Find the total number of points on or inside this triangle with integral coordinates. a 600 b 641 c 655 d 662 e 625 _____/\_____

@[576959:Stoicalme]

CAT 1998
You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth?
a) 20R and 15E
b) 40R
c) 28R and 9E
d) None of these

Can someone explain the above with solution?
Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.

@[470280:gs4890] @[271527:ashish100] @[525438:taurean11] @[509517:kpcat]

@Aizen said: sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*1 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: __/\__ @gs4890 bhai , @sumeet1489 bhai aur sabhi quant maharathi ...

@rachit_28 said: I have the same doubt as Raghav. Can you please tell the logic of taking the form 2^x * 3^y or could you redirect to the post you are mentioning?

@mani0303 said: Try this: the sum of the series - 1,5,14,28,47... until 10th term

Any one knows the sum of first n terms of Harmonic progression ???

@mani0303 said: Try this: the sum of the series - 1,5,14,28,47... until 10th term

@Stoicalme said: @gs4890 @sumeet1489 As @taurean11 pointed out i checked out the question again and it was indeed the multiplication of both. Extremely sorry for your loss of time and energy bhailogo.