Please continue here for all the Quant queries and discussions. The links to the previous threads are: Part 1 http://www.pagalguy.com/forum/quantitative-questions-and-answers/74662-official-quant-thread-cat-2012-a.html Part 2 http://www.pagalguy.com/forum/quantitative-questions-and...
@Aizen said: sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*4 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: __/\__ @gs4890 bhai , @sumeet1489 bhai aur sabhi quant maharathi ...
@[521225:Vinaysastra] The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for ...
The value of the ration A/B comes to 13/2, and here this has been expressed in its lowest possible value, we just have to assure that both the numerator as well as the denominator of the ration A/B are less than n. Looking into the Options, 21 is the only value of n for which the aforesaid condition holds true. Thus, this is the wright answer....
My Intrvwr askd me"Wht do u wnt 2 bcum in ur life?" I said"A Gud Humn" n i wsnt slctd bt i'm happy!!
@ashish100 said: Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option
baat to sahi hai ... ho sakta hai aur 2 4 ho...
but objective exams me sahi OPTION choose karna hota hai... sahi ans nahi :)
It would be great if you could xplain how 21... I followed the same steps as @[556294:FoolNFinal] .. Putting n=21 m getting A/B=13/2 But if i put n-13i get A/B=8/1 So shoudnt 13 be the ans?
@FoolNFinal said: ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
@Faruq said: @FoolNFinal @sumeet1489 @ashish100 @pyashraj Ans is D
It would be great if you could xplain how 21...
I followed the same steps as @[556294:FoolNFinal] .. Putting n=21 m getting
bhai there can be a lot of values of n that is why the question is which among the following options can be the value of n so check among the given options which one fits
@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
bhai there can be a lot of values of n that is why the question is which among the following options can be the value of n
Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answersorry for posting two posts ...making correctionthe new PG doesn't have edit option
@ashish100 said: Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
Bhai log mera to 13 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
Bhai log mera to 15 hi aa raha hain which is not in option jara dekho to ...take AB as 81 and n=13then (AB)n=(81)13=105and5(BA)n=5*(18)13=5*21=105so n=13 shoiuld be answer
ye time ki test ka prblem hai na ???? (AB)n = An + B5(BA)n = 5Bn + 5A ... equate both eq..An + B = 5Bn + 5A A/B = (5n-1)/(n-5)now we have to find such value of n for which n>A,Boptions put kar k dekh lo kon si value satiesfy karti hai
@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n? 12/14/16/21
getting 13 as OA
An+B =5Bn +5A
solve for n .....A,B comes out to be 8,1 or AB is 81 and n is 13
@Faruq said: Thanks @culdip Bhai Please solve this one too. If AB is a two digit number in base n such that (AB)n = 5(BA)n, which of the following is a possible value of n?
they will be diametrically opposite 8 times in 9 hours (one time in each hour except between 5 - 6 o'clock) as there are total 27 hours so it will happen 24 times
@Faruq said: On certain planet, there are seven days in a week - Sunday through Saturday. Also, each hour on this planet comprises exactly 60 minutes, just as on earth. However, each day on this planet comprises only 18 hours, when compared to the 24 hours on Earth. Therefore, the dials on the clocks on the planet are designed to show only 9 hours instead of the 12 hours shown on the clocks on Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are the minutes hand and the hours hand of such a clock diametrically opposite each other?
they will be diametrically opposite 8 times in 9 hours (one time in each hour except between 5 - 6 o'clock)
as there are total 27 hours
so it will happen 24 times
I don't have time to hate people who hate me, because I am too busy in loving people who love me.
no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!
no matter how hard I try i am not able to clear the cut off for quant in most of the mocks.I have the TIME material.Any suggestions on how to improve my Quant score?Please help me guys!!!
1... 0 cause n = (a+b)*(a-b)both a+b and a-b should be even or odd but scince we have only one 2 .. so one will be odd and other will always be even .. so 0 ways 2.. not sure bt is it 420???
@victor11 said: Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.
1... 0 cause n = (a+b)*(a-b)
both a+b and a-b should be even or odd but scince we have only one 2 .. so one will be odd and other will always be even .. so 0 ways
@[470247:victor11] For question 2here,take 15 common out so N becomes N=2^2*3^2*5^1sum of factors of this value of N is (1+2+4)(1+3+9)(1+5)=6*13*7and sum of factors divisible by 15 is 6*13*7*15=8190is it correct?
for boats to not collide two conditions must be satisfieddistance travelled by both boats must be less than 2000m.there speed must become zero before 4mins. or 240s. initial speed be Ufor 1st condition to be true (U-0)/240 =0.1u=24m/s for second conditionV is final speed=0S is distance ...
Q.1 If a number N= 2* 3^3 * 5^2. In how many ways can N be expressed as a difference of two perfect squares? Q.2 If N= 2^2 * 3^3 * 5^2. Find out the sum of all those factors of N which are completely divisible by 15. Kindly reply with explanations.
It should be 40 rubies. A direct approach is there. 1 kg ruby --> 4/0.3 = 13.33 cr 1 kg emerald --> 5/0.4.= 12.5 cr So Rubies has to be maximised --> so 40 rubies. Alternate approach: 0.3R+0.4E=12 => R/40 + E/30 =1 Draw it on x axis and Y axis: Also 4R+5E = k [As we ha...
@sowmyanarayanan said: CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R c) 28R and 9E d) None of these Can someone explain the above with solution? Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.
8 se to kahi jyada pairs hai iss k ...8! = 2^23 * 3^9 * 5^4 * 7^2 for b = 2 a can be 3 4 5 6 7 8 9 10 12 14......aise hi for b = 3 fir b = 4 ......kuch gadbad hai...
@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
On
certain planet, there are seven days in a week - Sunday through Saturday. Also,
each hour on this planet comprises exactly 60 minutes, just as on earth.
However, each day on this planet comprises only 18 hours, when compared to the
24 hours on Earth. Therefore, the dials on the clocks on the planet are
designed to show only 9 hours instead of the 12 hours shown on the clocks on
Earth. On how many occasions between 9 pm on Monday and 9 am on Wednesday are
the minutes hand and the hours hand of such a clock diametrically opposite each
other?
@Stoicalme said: Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?A) 0<10m/sB)0<20m/sC)0<30m/sD)N.O.TE)CBD
@Stoicalme said: Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
bhai kitni bhi koshish kar lo sai question nahi likh paoge ;) This continous problem should now be reported to mods , i guess p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions cheers :)
@ashish100 said: question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 Ä‚ €” b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
bhai kitni bhi koshish kar lo sai question nahi likh paoge ;)
This continous problem should now be reported to mods , i guess
p.s - @[8964:deepu] sir plz look into this automatic jargon generated questions
Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle. Area of circle=x + ypi * r^2=x + yalso, Area of square=x + yArea of square=pi *r^2
@chevy said: A square intersects a circle at eight distinct points such that the area of the circle outside the square is equal to the area of the square outside the circle. If the radius of the circle is €˜r €™, then the area of the square is a) root(2) pi r^2 b) 2 pi r^2 c) 3/2 r^2 d)none f dese
Let x be the the area of the circle outside the square.Also, x will be the area of the square outside the circle. Let y be the area of remaining portion of the circle.
Area of circle=x + y
pi * r^2=x + y
also, Area of square=x + y
Area of square=pi *r^2
Unseen, in the background, Fate was quietly slipping the lead into the boxing glove.
question is :1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 — b^2, then how many such sets (a, b) are possible?a 5b 6c 7d 8
@ashish100 said: @Stoicalme for ist one:denominator is (a-b)(a+b)now max value of a+b can be till 10 only as 11 won't divide 8!so when a+b=10 then a-b can be 2,4,6,8out of which following sol can be possible : (6,4)(7,3)(8,2)when a+b=9 then a-b can be 1,3,5,7here 0 possible solutions as max power of 3 can be two onlywhen a+b=8 a-b can be 2,4,6so (5,3)(6,2)possible solutionswhen a+b=7 and a-b can be 1,3,5possible sol are :(4,3)(5,2)when a+b=6 and a-b can be 2,4so sol can be :(4,2)when a+b =5 and a-b can be 1,3so sol can be 3,2 when a+b=4 then a-b can be 2so sol can be nothingIn all getting 9 solutions....kahan miss kar raha hoon bhai log
question is :
1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 — b^2, then how many such sets (a, b) are possible?
40 R aa raha hai ans...cost of ruby per kg = 40/3cost of emrald per kg = 50/4since cost of ruby is more we should fill bag with ruby only.. i.e 40 max ruby
@sowmyanarayanan said: CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R c) 28R and 9E d) None of these Can someone explain the above with solution? Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.
40 R aa raha hai ans...
cost of ruby per kg = 40/3
cost of emrald per kg = 50/4
since cost of ruby is more we should fill bag with ruby only.. i.e 40 max ruby
@[576959:Stoicalme] for ist one:denominator is (a-b)(a+b)now max value of a+b can be till 10 only as 11 won't divide 8!so when a+b=10 then a-b can be 2,4,6,8out of which following sol can be possible : (6,4)(7,3)(8,2)when a+b=9 then a-b can be 1,3,5,7here 0 possible solutions as max power of 3 ca...
@Stoicalme said: Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?A) 0<10m/sB)0<20m/sC)0<30m/sD)N.O.TE)CBD
@[592873:sravan1989]: Just directly apply this formula: S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171) You can leave the last term as it will be very very low... So S= ln(n+0.5) + 0.5772
@[525438:taurean11] @[470280:gs4890] answer 42 kmph diya hai... actually Q)Shyam went from Delhi to Shimla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times the distance from Chandigarh to Shimla. The average speed from Delhi to Chandigarh was half as much again as th...
actually Q)Shyam went from Delhi to Shimla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times the distance from Chandigarh to Shimla. The average speed from Delhi to Chandigarh was half as much again as thatfrom Chandigarh to Shimla. If the average speed for the entire journey was 49 kmph. What was the average speed from Chandigarh to Shimla? a)39.2 kmphb)63 kmphc)42 kmphd)70 kmph Bhai log good evening
the text in bold according to the solution bol raha hai ki Delhi se Chandigarh ka avg speed s/2 na hoke s+s/2=3s/2 hai...this is a question from cat 1994...
When life leaves you with no option ,create yours and choose it ! SCMHRD 2013-15
Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscrip...
Q) Two ships sail in a fog towards each other with the same speed.When they are 4 kms apart,the captains decelerate the engines for 4 minutes with a deceleration rate of 0.1m/s^2,and then the ships continue sailing with the speeds attained.For what range of values of the initial speed V0(subscript) will the ships avoid collision?
A) 0<10m/s
B)0<20m/s
C)0<30m/s
D)N.O.T
E)CBD
Unseen, in the background, Fate was quietly slipping the lead into the boxing glove.
@[485958:htomar] bhai in your approach also u assumed boxes identical .. tabhi to 4! 2 baar aa raha hai... u solved it like arranging 8 objects of which 4 are of same kind and other 4 are of same kind.. so u got 8!/4!*4!
@htomar said: FoolNFinal Bhai, i need one clarification in first part. In first part, we have assumed the boxes to be distinct and balls to be identical, and used the formula to get the answer. Which is nothing but 8!/(4!*4!). Now,I will get the same answer, if i assume that there are 4 identical balls placed in a row and i put four identical bars in the gaps to divide the balls into 5 groups. Then the situation will be same as arraning 8 objects out of which 4 are of one type and 4 another type. This will come out same as 8!/(4!*4!) Question is, for your part you assumed boxes to be distinct and balls to be identical whereas in the above approach i assumed balls to be identical but nothing about boxes. Is it correct approach?
@[485958:htomar] bhai in your approach also u assumed boxes identical .. tabhi to 4! 2 baar aa raha hai... u solved it like arranging 8 objects of which 4 are of same kind and other 4 are of same kind.. so u got 8!/4!*4!
A square intersects a circle at eight distinct points such that the area of the circle outside the square is equal to the area of the square outside the circle. If the radius of the circle is €˜r €™, then the area of the square is a) root(2) pi r^2 b) 2 pi r^2 c) 3/2 r^2 d)none f...
A square intersects a circle at eight distinct points such that the area of the circle outside the
square is equal to the area of the square outside the circle. If the radius of the circle is ‘r’, then the
area of the square is
a) root(2) pi r^2
b) 2 pi r^2
c) 3/2 r^2
d)none f dese
It is during our failures that we discover the true desire for success
8! = 2*2^2*2^2*2^2*3^2*5*73^2*2^2, 4^2*2^2, 4^2*3^2, 8^2*3^2, 6^2*2^2, 6^2*4^2, 12^2*2^2 =>7 pairs 2-after solving 3 equations we got vertices of triangle as (0,0), (40,0), (10, 30) draw a line from (10,30) perpendicular to x axis we got 2 triangles (0,0), (10,0), (10,30) and (10,0) (40...
@Stoicalme said: 1) a and b are natural numbers such that a > b > 1. If 8! is divisible by a^2 — b^2, then how many such sets (a, b) are possible? a 5 b 6 c 7 d 8 2) The lines y = 3x and x + y = 40 and the x axis bound a triangular area. Find the total number of points on or inside this triangle with integral coordinates. a 600 b 641 c 655 d 662 e 625 _____/\_____
CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you should collect to get maximum wealth? a) 20R and 15E b) 40R
CAT 1998 You can collect Rubies and Emralds as many as you can. Each Ruby is
worth 4 Crores and each Emrald is worth 5 Crores. Each Ruby weighs 0.3kg
and each emrald weighs 0.4kg. Your bag can carry at most 12kg. What you
should collect to get maximum wealth?
a) 20R and 15E
b) 40R
c) 28R and 9E
d) None of these
Can someone explain the above with solution?
Since the answer cjoice has 'None of these' i was not able to pick one from the top three. please help.
@[470280:gs4890] @[271527:ashish100] @[525438:taurean11] @[509517:kpcat] answer 42 kmph diya hai... actually Q)Shyam went from Delhi to Shimla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times the distance from Chandigarh to Shimla. The average speed from Delhi to Cha...
actually Q)Shyam went from Delhi to Shimla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times the distance from Chandigarh to Shimla. The average speed from Delhi to Chandigarh was half as much again as that from Chandigarh to Shimla. If the average speed for the entire journey was 49 kmph. What was the average speed from Chandigarh to Shimla? a)39.2 kmphb)63 kmphc)42 kmphd)70 kmph Bhai log good evening
the text in bold according to the solution bol raha hai ki Delhi se Chandigarh ka avg speed s/2 na hoke s+s/2=3s/2 hai...this is a question from cat 1994...
When life leaves you with no option ,create yours and choose it ! SCMHRD 2013-15
@Aizen said: sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*1 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: __/\__ @gs4890 bhai , @sumeet1489 bhai aur sabhi quant maharathi ...
just a small mistake..first term is 4..so "2*4" in tn =1 + (n-1)/2*(2*1 +(n-2)*5)
@[594243:rachit_28] bhai:Reposting: 28 = 2*2*7 30= 2*5*3 But see the power in the 1st case 1number has to be raised to power 6.... so that (6+1) has occurred. But there is no 7 in the factor of 3n.... so 2 has to be multiplied 2^5 ---> to get 2^6It satisfies will 32=6*5 --> Now we ...
@rachit_28 said: I have the same doubt as Raghav. Can you please tell the logic of taking the form 2^x * 3^y or could you redirect to the post you are mentioning?
@[594243:rachit_28] bhai:
Reposting:
28 = 2*2*7
30= 2*5*3
But see the power in the 1st case 1number has to be raised to power 6.... so that (6+1) has occurred.
But there is no 7 in the factor of 3n.... so 2 has to be multiplied 2^5 ---> to get 2^6
It satisfies will 32=6*5 --> Now we have 1 less power of 2 .e 5 --->(5+1) =6
As 5 is a prime numbrer --> (2*2) =4 must be power of 3 in the second case --> So power of 3 in 1st case has to be 3^3 -->(3+1)=4;
So n=2^5*3^3; so 6n =2^6*3^4 -->factors = (6+1)*(4+1)=35
sn = 1+5+14+28+47 + ....+tn sn = 1+5 +14+28+ ... +tn-1 +tn [Shift it by 1] Subtract.. 0 = 1+(4+9+14+19+... (n-1) terms) - tn [See in brackets the terms are in AP] => tn =1 + (n-1)/2*(2*4 +(n-2)*5) Now multiply and get tn in form of n. Just do sigma over 1 to 10. p.s: ...
@Stoicalme said: @gs4890 @sumeet1489 As @taurean11 pointed out i checked out the question again and it was indeed the multiplication of both. Extremely sorry for your loss of time and energy bhailogo.
koi baat nai ho sakta hai a^2+b^2 vaala CAT mein puchh le
@Debasis070 said: Q)Shyam went from Delhi to Shimla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times thedistance from Chandigarh to Shimla. The average speed from Delhi to Chandigarh was half as much again as that fromChandigarh to Shimla. If the average speed for the entire journey was 49 kmph. What was the average speed fromChandigarh to Shimla? a)39.2 kmphb)63 kmphc)42 kmphd)70 kmph Bhai log good evening
70 Km/hr
There is great value in disaster because we can start anew" - Edison
@[470280:gs4890] @[367896:sumeet1489] As @[525438:taurean11] pointed out i checked out the question again and it was indeed the multiplication of both. Extremely sorry for your loss of time and energy bhailogo.
@[470280:gs4890] @[367896:sumeet1489] As @[525438:taurean11] pointed out i checked out the question again and it was indeed the multiplication of both. Extremely sorry for your loss of time and energy bhailogo.
Unseen, in the background, Fate was quietly slipping the lead into the boxing glove.
forget about circle and straight lines. if two geometry figures can intersect at two points, then 2 x no. of intersection of the two geometric figures will give you the total number of points they intersect. here there are 12 such geometric figures. there are 12C2 ways of selecting, two objec...
@rachit_28 said: i am unable to appreciate the multiplication of 2 qirh 12C2 - 8C2.Can you please tell why it is being multiplied?
forget about circle and straight lines. if two geometry figures can intersect at two points, then 2 x no. of intersection of the two geometric figures will give you the total number of points they intersect.
here there are 12 such geometric figures. there are 12C2 ways of selecting, two objects and that 2x will give you the total number of points they intersect.
@[573636:Debasis070] Answer is 70distance and speed from D to ch =3x and Vdistance and speed from ch to S=4x,V So, equation is :49=7x/(3x/v + 4x/2v)solving V=35and 2V=70km/h
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