# Official Quant Thread for CAT 2012Quantitative Report

Please continue here for all the Quant queries and discussions.
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@[555978:yashasvi5]

Let the total units of work be W units. Let x units/hour be the rate of work of the second person and let y units/hour be the rate of work of the woman. Let a units/hour be the rate of the first person.

Now, as per the given condition,

(W/x)=3+[(W)/(x+y)] ....(i)

(W/a)=[(W)/(x+y)] ....(ii)

(W/a)=[2*(W/x)] -8 ...(iii)

from eqn(ii) we get as

a=x+y...(iv)

Solving eqn (i) and eqn(iii), we get..

W/a=2 hours, W/x=5 hours

Thus, from eqn(ii), we can write as

W/y=10/3 hours.
Now, the required time can be written as

T=(W)/(x+y+a)

Substituing the value of x, y and a in terms of W, get T as 1 hour, which is our required answer..

My Intrvwr askd me"Wht do u wnt 2 bcum in ur life?" I said"A Gud Humn" n i wsnt slctd bt i'm happy!!
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