Pls help in answering these:

1. Uncle Shrooz has 3 daughters Loe, Joe and Koe, all of them are older than a year and their ages are integers. The product of their ages is 36 and the marriage of the youngest daughter is scheduled on 5th Jan 2010. What is the present age(in years) of the eldest daughter?
(a) 6 (b) 9 (c) 18 (d) Data Insufficient

2. The value of given that a+b+c=0 is:
a)1 b)0 c)abc d)x

3. The value of given that pqr=1 is:
a)1 b)0 c)pqr d)p+q+r

PS: I do not have the answer key. Hope someone has been thru these ques b4.

1. ages can be:
2,3,6
2,2,9
3,3,4 The ages are unique only in 1st case as the ques mentions "youngest" & "eldest". (Marriage!!??)
Ans: a

Pls help in answering these:

1. Uncle Shrooz has 3 daughters Loe, Joe and Koe, all of them are older than a year and their ages are integers. The product of their ages is 36 and the marriage of the youngest daughter is scheduled on 5th Jan 2010. What is the present age(in years) of the eldest daughter?
(a) 6 (b) 9 (c) 18 (d) Data Insufficient

2. The value of given that a+b+c=0 is:
a)1 b)0 c)abc d)x

3. The value of given that pqr=1 is:
a)1 b)0 c)pqr d)p+q+r

PS: I do not have the answer key. Hope someone has been thru these ques b4.

bs0409 Says

If a@b = (a^3-b^3)/(a-b) , for how many real values of a does a@1 = 0?

a@1 = (a^3-1^3)/(a-1) = (a-1)(a^2+a+1)/(a-1)

a can not be 1 as denominator can not be 0

and
a^2+a+1 = 0 => no real roots exist

so it is 0

bs0409 Says

If a@b = (a^3-b^3)/(a-b) , for how many real values of a does a@1 = 0?

a@b = a^2+ab+b^2
=>a@1 = a^2+a+1

so a^2+a+1=0

a is imaginary.

So 0 real values.
p.s: bs bhai,culdip bhai __/\__

If a@b = (a^3-b^3)/(a-b) , for how many real values of a does a@1 = 0?

bs0409 Says

A combination lock has a 3 number combination, with each number an integer between 0 and 39 inclusive. Call the numbers n1, n2, and n3. If you know that n1 and n3 leave the same remainder when divided by 4, and n2 and n1 + 2 leave the same remainder when divided by 4, how many possible combinations are there?

here is 4 types of numbers 4k, 4k+1, 4k+2 and 4k+3 , 10 of each type

n1 and n3 of same type and if n1 is of type of 4k+a, then n2 will be 4k+a+2 type

if n1 and n2 of 4k type and n2 of 4k+2 type => 10*10*10 combinations
if n1 and n3 of 4k+1 type and, n2 of 4k+3 type => 10*10*10 combinations
if n1 and n3 of 4k+2 type and n3 of 4k type => 10*10*10 combinations
if n1 and n3 of 4k+3 type and n3 of 4k+1 type => 10*10*10 combinations

total = 4*10*10*10 = 4000 combinations

bs0409 Says

A combination lock has a 3 number combination, with each number an integer between 0 and 39 inclusive. Call the numbers n1, n2, and n3. If you know that n1 and n3 leave the same remainder when divided by 4, and n2 and n1 + 2 leave the same remainder when divided by 4, how many possible combinations are there?

the numbers are of the form: 4m+k, 4l+k+2, 4k1+k.
For k=0 putting m=0 to 9, we have corresponding ten values for k1=0 to 9. l goes from 0 to 9 too. thus total = 10*10*10 combinations
similarly we get 1000 for k=1,2,3
So effectively no. of possible combinations would be 4*10*10*10= 4000. :|:shock:

bs0409 Says

A combination lock has a 3 number combination, with each number an integer between 0 and 39 inclusive. Call the numbers n1, n2, and n3. If you know that n1 and n3 leave the same remainder when divided by 4, and n2 and n1 + 2 leave the same remainder when divided by 4, how many possible combinations are there?

81 x 38 ?? by any chance
: bs bhai

bs0409 Says

A combination lock has a 3 number combination, with each number an integer between 0 and 39 inclusive. Call the numbers n1, n2, and n3. If you know that n1 and n3 leave the same remainder when divided by 4, and n2 and n1 + 2 leave the same remainder when divided by 4, how many possible combinations are there?

n1 n2 n3
when n1 of the form 4n then n2 of the form 4n+2
hence n1 and n3 each can take 10 values and n2 can take 10 values...hence 10*10*10 possibilities
when n1 of the form 4n+1 then n2 of form 4n+3
hence n1 and n2 can take 10 values each and n2 can take 10 values
hence 10*10*10
when n1 of form 4n+2 then n1 and n3 can take 10 values and n2 10 values

hence 10*10*10

similarly for n1 of the form 4n+3 there would be 10*10*10 combinations...

hence 4*10*10*10???

A combination lock has a 3 number combination, with each number an integer between 0 and 39 inclusive. Call the numbers n1, n2, and n3. If you know that n1 and n3 leave the same remainder when divided by 4, and n2 and n1 + 2 leave the same remainder when divided by 4, how many possible combinations are there?

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

yes it is 21.

sum of all angles = (n-2 )*180
lets say no. of angles which is 270 =x

(n-2)180 = 25*90+x*270
x = n-25
calculating x =21

log2(3x+21) -log2(3x-15) = log2(3x-15) - log23(hope this is not log twenty three)

thus, 3x+21/3x-15 = 3x-15/3

at, x=2 equations are equal.

culdip bhai se diff aa raha hain...kuch to locha hain bhai

log2(3) hai, not log23

at x = 9

log2(3), log2(12) and log2(48 ) are in AP as 3, 12, 48 in GP

it becomes log3, 2 + log3 and 4 + log 3 => in AP with common difference 2 (base is 2 here)

so x = 9 satisfies

log2(3x+21) -log2(3x-15) = log2(3x-15) - log23(hope this is not log twenty three)

thus, 3x+21/3x-15 = 3x-15/3

at, x=2 equations are equal.

culdip bhai se diff aa raha hain...kuch to locha hain bhai

loga,logb,log c are in A.P implies a,b,c are in GP
so (3x-15)^2 = 3(3x+21).
x=2,9.
since log(3x-15) is not defined at x=2. X=9 is the solution.

log2(3x+21) -log2(3x-15) = log2(3x-15) - log23(hope this is not log twenty three)

thus, 3x+21/3x-15 = 3x-15/3

at, x=2 equations are equal.

culdip bhai se diff aa raha hain...kuch to locha hain bhai

Dude for you soln second equation will become negative and wont exist..yahi locha hai

If log23, log2 (3x 15) and log2 (3x + 21) are in arithmetic progression,
find x.
A. 2
B. 3
C. 4
D. log36

log2(3x+21) -log2(3x-15) = log2(3x-15) - log23(hope this is not log twenty three)

thus, 3x+21/3x-15 = 3x-15/3

at, x=2 equations are equal.

culdip bhai se diff aa raha hain...kuch to locha hain bhai

If log23, log2 (3x 15) and log2 (3x + 21) are in arithmetic progression,
find x.
A. 2
B. 3
C. 4
D. log36

log2(3), log2 (3x 15) and log2 (3x + 21) are in AP

then 3, (3x-15) and (3x+21) will be in GP

so (3x-15)^2 = 3*(3x+21)
=> 9x^2 - 90x + 225 = 9x + 63
=> x^2 - 11x + 18 = 0
=> (x-2)(x-9) = 0

so x = 2 or 9
but 3x-15 can not be -ve, so x = 9

The multiplication of two numbers is shown below.
AD4
E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

My take 10.

AD4*E = A206
A can be 4 or 9.
if it is 4, it will be less than A206.

(100A+10D+4) 9 = 1000A+206

9(100A+10D) = 1170
100A +10D = 130
A= 1 , D=3
So 10

If log23, log2 (3x 15) and log2 (3x + 21) are in arithmetic progression,
find x.
A. 2
B. 3
C. 4
D. log36

for all other values except D value of log is negative for second term which is not possible.

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

suppose polygon has n sides and 25 angles are convex then n-25 angles will be concave (as n sided polygon has n angles)

so (n-2)*180 = 25*90 + (n-25)*270
180n - 360 = 2250 + 270n - 6750

n = 4140/90 = 46

so number of concave angles = 46 - 25 = 21

The multiplication of two numbers is shown below.
AD4
E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

Value of A=1 ,E=9 ,D=3.Hence answer is 10

If log23, log2 (3x 15) and log2 (3x + 21) are in arithmetic progression,
find x.
A. 2
B. 3
C. 4
D. log36

The multiplication of two numbers is shown below.
AD4
E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

Here 4 multiplied by something gives 6 hence E has to be 4 or 9.
Let's try 4
AD4
X4
----
Tens digit will be 4D+1 which can never be zero.
Hence E is 9.
AD4
X9
----
Tens digit will be 9D+3 now D has to 3
Now we have
A34
X9
---
A206

9A+3=10A + 2
A = 1
Therefore A+E=10
________/\_________ Everyone.

The multiplication of two numbers is shown below.
AD4
--E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

E x 4 => last digit 6

E can be 4 or 9
let us take 4

E*4 = 16...6 carry one...but 1+4D should end in Zero......not possible for any value of D

------------------------------

hence E=9

D=3

AD4
x9
A206
E=9
D=3
A=1
hit and trial
134* 9 =1206
A+E=10

The multiplication of two numbers is shown below.
AD4
E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

AD4
X E
-----
A206
1- E can be 4 or 9.

2- If E is 4, we cannot get 0 in ten's place. E = 9.

3- Product of D and 9 should have 7 as unit's digit, D=3.

4- Product of E and A should have 9 as unit's digit, A=1.

A+E = 10.

Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

Sum of angles of a polygon is (n-2)180
so ATQ
90n+270(n-25)=180(n-2)
solve for n which would would 46 hence value of (n-25) would be 21

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

C.21 foe every 5 convex angles 1 concave; for every 6 2 concaves and so on

The multiplication of two numbers is shown below.
AD4
E
A206
where A, D, and E are all distinct digits.
The value of A + E is

A. 8
B. 9
C. 11
D. 10

Its 10

E can be 4 or 9...but 4 not possible cause in that case 4D+3 has to give units digit of 0...which is not possible
hence E=9
We can now easily find that A=1
hence 10

Farooq purchases two watermelons, one weighing 20% more than the other. However, due to the summer heat, the combined weight of the two watermelons reduces by 1/4th. If the weight of the heavier watermelonreduces to 75% of its initial weight, then the lighter watermelon incurs a
weight loss of

A. 20%
B. 25%
C. 5%
D. 22.5%

Answer: B. 25%

Farooq purchases two watermelons, one weighing 20% more than the other. However, due to the summer heat, the combined weight of the two watermelons reduces by 1/4th. If the weight of the heavier watermelonreduces to 75% of its initial weight, then the lighter watermelon incurs a
weight loss of

A. 20%
B. 25%
C. 5%
D. 22.5%

25% aayega isme

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

No. of convex sides = 25, so sum of angles = 25*pi/2.

The total angle of the polygon should be such that the sum can be expressed in the form : (n-2)*pi.

Now, use the options:

25*pi/2 + x*(3*pi/2). When x = 21, Total angle = 44*pi.

All others are fractions.
Hence, Option (c).

Farooq purchases two watermelons, one weighing 20% more than the other. However, due to the summer heat, the combined weight of the two watermelons reduces by 1/4th. If the weight of the heavier watermelonreduces to 75% of its initial weight, then the lighter watermelon incurs a
weight loss of

A. 20%
B. 25%
C. 5%
D. 22.5%

My take in bold...

Farooq purchases two watermelons, one weighing 20% more than the other. However, due to the summer heat, the combined weight of the two watermelons reduces by 1/4th. If the weight of the heavier watermelonreduces to 75% of its initial weight, then the lighter watermelon incurs a
weight loss of

A. 20%
B. 25%
C. 5%
D. 22.5%

100+120 =220
220*1/4 =55
220-55 =165

120*75/100 = 90
165-90 = 75

100----------75 (so 25% reduction)

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

21 hai kya Neetu ji

Farooq purchases two watermelons, one weighing 20% more than the other. However, due to the summer heat, the combined weight of the two watermelons reduces by 1/4th. If the weight of the heavier watermelonreduces to 75% of its initial weight, then the lighter watermelon incurs a
weight loss of

A. 20%
B. 25%
C. 5%
D. 22.5%

pls post the approach too

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

1. 5.

2. 2*pi*R*(theta)/360 = 11 --> (theta) = 11/25 radians.

3.

4. 2:1.

4/3*pi*r1^3 = 2*pi*r1^2 (CSA of a hemisphere)..............(1)

4/3*pi*r2^3 = 4*pi*r1^2 (TSA of a sphere)..................(2)

r1 = 3; r2 = 3/2 --- > r1:r2 = 2:1

6. Let B's effic = 100. A's = 140.

B can do a work in 1 day, A in .72 days.

B earns B/day, A earns (13B/10) /day

(13B/10)*.72 = 65 --> B = 70.

length of arc= (x *2* pi*r)/(2*pi)


nah... A kam din me kaam comlpete krta hai.. B ko jyada din lgte hai..
aur unka wages din k according hai na ki kaam k accoding...

Ye anayay hai A pe, Me nahi manti aise unjustice ko. Me A ko jyada dungi


Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a polygon is said to be convex if the internal angle is 90 or concave if the internal angle is 270. If the number of convex corners in such a polygon is 25, the number of concave corners must be a. 20 b. 0 c. 21 d. 22

gs4890 Says

Q.2 plz explain :banghead:

Gs bhai Q2 simple he

2pi*25 ke lie 2pi radians

11 ke lie 2pi*11/2pi*25=11/25 radians

gs4890 Says

Q.2 plz explain :banghead:

length of arc= (x *2* pi*r)/(2*pi)
11 = x*50/2
x = 11/25 radian .. to convrt it in degree multiply by 180/pi

6. B...........1 work
A...............1.4 work

wages A..........65.............1.4
A...................46..............1 work

46*100/130 = 35 (I am not sure though)



B should earn less than A. nahi kya A is more efficient & earning also more.

nah... A kam din me kaam comlpete krta hai.. B ko jyada din lgte hai..
aur unka wages din k according hai na ki kaam k accoding...

2. = 360*11/(2*22/7*25) = 25.7

4. r1 = 9/4
r2 = 3

r1:r2 = 3:4

5. 4!*36c9*27c9*18c9

6. B...........1 work
A...............1.4 work

wages A..........65.............1.4
A...................46..............1 work

46*100/130 = 35 (I am not sure though)



B should earn less than A. nahi kya A is more efficient & earning also more.

Neetuji the time for which B works is more.....hence i think it can be more than that of A

Find the sum
101C50 + 101C52 + 102C53 + 103C54 + 104C55 + + 179C130

C(n, r) + C(n, r + 1) = C(n + 1, r + 1)

C(101, 50) = C(101, 51)

So, C(101, 51) + C(101, 52) = C(102, 52)
After several repetitions we will get

C(179, 29) + C(179, 30) = C(180, 30)

q.3 - infinite terms
q.6 - nice strategy sirjee



Q.The cost price of an article is Rs.16. The percentage of profit when calculated on the selling price is
numerically equal to the selling price. Then the selling price of the article is

let the selling price = (x+16)
profit % = selling price
x/(x+16)*100 = x+16
x^2-68x +256 =0
(x-64)(x-4) =0

so selling price of the article is either 20 or 80
sam bhai,gs4890 bhai aur baki sabhi bhaiyon mera ___/\___

2. = 360*11/(2*22/7*25) = 25.7

4. r1 = 9/4
r2 = 3

r1:r2 = 3:4

5. 4!*36c9*27c9*18c9

6. B...........1 work
A...............1.4 work

wages A..........65.............1.4
A...................46..............1 work

46*100/130 = 35 (I am not sure though)



B should earn less than A. nahi kya A is more efficient & earning also more.

b is gng to earn more because he is 40% less efficient so he is gng to take more days....:|

___________________________________

10:14==5/7==thr efficiencies
65/5==13==A's earning per day
10==b's earning
10*7==70

Q.The cost price of an article is Rs.16. The percentage of profit when calculated on the selling price is
numerically equal to the selling price. Then the selling price of the article is

getting 2 values.. 20 and 80

solve this eq (s-16)/s = s/100

Find the sum
101C50 + 101C52 + 102C53 + 103C54 + 104C55 + + 179C130

Use C(n,r) + C(n,(r+1)) =C((n+1),(r+1))

C(101,50)=C(101,51)

So C(101,51)+C(101,52) = C(102,52)

Continue like this ....

Finally C(179,129)+C(179,130) = C(180,130)

P.s: Namaskar Sam bhai

q.3 - infinite terms
q.6 - nice strategy sirjee



Q.The cost price of an article is Rs.16. The percentage of profit when calculated on the selling price is
numerically equal to the selling price. Then the selling price of the article is

Its 80 or 20....both are possible

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

for qstn 1., are 2 & 5 the bases on either side of the equal sign ?

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

2. = 360*11/(2*22/7*25) = 25.7

4. r1 = 9/4
r2 = 3

r1:r2 = 3:4

5. 4!*36c9*27c9*18c9

6. B...........1 work
A...............1.4 work

wages A..........65.............1.4
A...................46..............1 work

46*100/130 = 35 (I am not sure though)

1... 5

6.. 70rs

B should earn less than A. nahi kya A is more efficient & earning also more.

q.3 - infinite terms
q.6 - nice strategy sirjee



Q.The cost price of an article is Rs.16. The percentage of profit when calculated on the selling price is
numerically equal to the selling price. Then the selling price of the article is

snipped.................

1... 5
2... 11/25 radian
3.. general term is x/3^n ..
4... working
5.. 4!*36c9*27c9*18c9
6.. 70rs

Q.2 plz explain

Q.3 till how many terms bro????
Q5..4K,4Q,4J,4A can be distributed amongst A,B,C,D in 4! ways...
now we are left with 36 cards and each of A,B,C,D should get 9 cards each
hence 4!*36C9*27C9*18C9*9C9


Q6...
Let A do the work in 10x days...hence B does in 14x days..
Let the daily wage of B be 10y then that of A is 13y
hence 10*13xy=65
hence xy=1/2
hence we have to find 14*10 xy=14*5=70

q.3 - infinite terms
q.6 - nice strategy sirjee



Q.The cost price of an article is Rs.16. The percentage of profit when calculated on the selling price is
numerically equal to the selling price. Then the selling price of the article is

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

1... 5
2... 11/25 radian
3.. general term is x/3^n ..
4... working
5.. 4!*36c9*27c9*18c9
6.. 70rs

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?


Q2...11/25 radians
5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

Q.3 till how many terms bro????
Q5..4K,4Q,4J,4A can be distributed amongst A,B,C,D in 4! ways...
now we are left with 36 cards and each of A,B,C,D should get 9 cards each
hence 4!*36C9*27C9*18C9*9C9


Q6...
Let A do the work in 10x days...hence B does in 14x days..
Let the daily wage of B be 10y then that of A is 13y
hence 10*13xy=65
hence xy=1/2
hence we have to find 14*10 xy=14*5=70

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

1->5
2->geometry not my area
3->x/3^(n\2)
4->geometry again
5->4!*36c9*27c9*18c9
6->70 rs

few q's ....plz explain yr soln's

1. If log25 = log5y, then what is the appropriate value of y?

2. The angle subtended at the centre of a circle of diameter 50 cm by an arc of length 11 cm is?

3. f(x) = x/root3....then what is f(f(f(f(f....)))) ?

4. If r1 is the radius of the sphere with volume equal to the curved surface area of its hemisphere and r2 is the radius of the sphere with volume equal to its total curved surface area, then the ratio r1 : r2 is equal to ? forgot the formula :O

5. In how many ways can cards be distributed to 4 bridge players A, B, C, D such that each one of them has either all 4 aces or all 4 kings or all 4 queens or all 4 jacks? (Each player gets 13 cards)

6.A is 40% more efficient than B and his daily wages are 30% more. If A is paid Rs.65, how much will B receive for the same work?

_______//\\_______sam bhai(congractz for 1000 posts ) & otherz

Find the sum
101C50 + 101C52 + 102C53 + 103C54 + 104C55 + + 179C130

if both the roots of the quadratic equation ax^2 +bx + c=0 lies in the interval (0,3) then lies between ?

A number N is formed by writing the first 1002 whole numbers in ascending order. Find the remainder when N is divided by 9.

I do not remember the options

1st whole number is 0 and last is 1001
hence 1001*1002/2
which gives a remainder of 3 when divided by 9

Pranam Aizen bhai ___/\___

A number N is formed by writing the first 1002 whole numbers in ascending order. Find the remainder when N is divided by 9.

Sum = 1001X1002/2 = 501501. Whose sum of digits will be 3.

Given that p is prime, when is 2^p + p^2 prime?

P.S with approach,please...

Let f(p)=2^p +p^2

f(p)=(2^p+1)+(p^2-1)

1st we will check for p=2 and 3

f(2)=4+4=8 (Not Prime)
f(3)=8+9=17(Prime)

We know for every prime number > 3 ;(p^2 - 1) is divisible by 24 i.e divisible by 3.
Also For every prime number greater than 3 ; (2^p+1) is divisible by 3.
bcoz (2^p + 1) mod 3 = 0 (bcoz all prime nos except 2 are odd)

So For p>3, f(p) can never be prime.

So we are left out with only one value of p and that is 3.