Official Quant Thread for CAT 2012 [part 3] Quantitative

All the quant enthusiasts [embedded image]
please continue here.
here is the link to the previous thread:
17 17
Hi ..
is it 0.125% ?
for finding the last 2 digits,always try and find out whether the number can be made to end with 1,which makes it very easy thereafter as final digit in this case will always be 1.
In this case 169 if squared will end up with number ending with 1 :
so (169^2)^29 = (...61)^29 [its enough to ...
Can anyone help me with this question
lagaan is levied on the 60% of the cultivated land .the revenue department collected total of RS 384000 through the lagaan from the village of sukhaya ,sukhaiya a rich farmer paid only RS 480 as lagaan .the percentage of the total land of sukhaiya o...
are sorry use the link of Aizen.ya i know u can use.but ek jagah pe discussion hota he to its good for everyone i guess
page not found??? also still 5 more pages we can spend in this thread itself!!
)"]http://www.pagalguy.com/forum/quanti...ml#post3509369 (Official Quant Thread for CAT 2012 )
bhai please continue here.request
my take is also 0
Please continue your discussions here.
bro, in the binomial expansion of (2+1)^1024= 2^1024*1^0+2^1023*1^1.....2^0*1^1024 -1
thus the highest term will be 2^1024-1=2^1023..
am i wrong anywhere??
it is 12.. break the above into a^2 - b^2 form.. it will reduce like (3^512 +1) (3^512-1) .. at last (3^2-1)(3^2+1) will be left..
Symmetric about Y axis So ,this is an even function.
so use f(x)=f(-x) to find the value of n
Q) If the graph of the function f(x)= (a^x)-1/x^n*((a^x)+1) is symmetric about y-axis then what is the value of n?
ans -1/3
please explain
My mistake sorry brother...
kindly share your approach....
and please will someone explain on which thread we are supposed to post question???????only open thread after this one is closed
12 remainder ... but i find it manually no gud ways
yup im also getting 12 !!!!
1 1
the expression 1*1!+2*2!+....+12*12! = (2! - 1) + (3! - 2!) + (4! - 3!) + ... + (12! - 11!) + (13! - 12!) = 13! - 1
13! - 1 mod 13 = -1 = 12
both are same bro,10/(3)^1/2((3^1/2)+1) = 10/(3 + rt(3))
1 1
SIMPLIFIED BECOMES 13!-1/13=-1 REMAINDER I.E 12 remainder as ans
1 1
Please continue here and refrain from discussing the questions of Mocks till the testing window is over for that particular mock.
Bhai answer is 10/(3)^1/2((3^1/2)+1)