# Official Quant Thread for CAT 2012 [Part 1]Quantitative Report

Hi puys,
CAT 2011 season is finally over [smiley] [smiley]
Let start a new season of Quants thread for CAT 2012.. [smiley] [smiley]
Part-8
http://www.pagalguy.com/forum/quanti...at-2011-a.html (Official Quant Threa...
59 59
a train and car start at same time ...car at rear end reaches front end and come back to rear end . in the mean time train travels 1 km and speed of train is 1 km /hr ...wat is distance covered by car
hope for the best
pls everyone, continue on the thread jain bhai opened (link -above). A thread needs to be closed when it has completed around 1000 pages.
Thanx.
5 5
digits 1 2 3 4 5 & 6
numbers 1 2 ( 7,8,9) (3,6,9) (31,62,93)
Ans would be 3*3*3= 27.
Correct me if i am wrong
Q) A credit card number has 6 digits (between 1 to 9). The first two digits are 12 in that order, the third digit is bigger than 6, the forth is divisible by 3 and the fifth digit is 3 times the sixth. How many different credit card numbers exist?
ans= 27
3rd digit could be 7,8 and 9
...
2 2
my take27
third digit can take 3 values
4th digit can take 3,6,9 = 3 values
5th digit = 3 times 6th. 6th can take only 1,2,3 and corresponding three values for 5th digit
Anjali nd Sachin decided to meet at Barista sometime between 5pm to 6 pm.they decided that they would wait max of 10 min their and then leave.What is the probability that they met?
sorry for repost but i think its worthy of a shot
All the quant enthusiasts
sol:
-----------------------------truck (with 10 tyres)
so clearly 1st tyre will travel 9000km and so by the 2nd tyre so total distance
travelled by individual tyre
=9000*10(forward)+9000*10(backward)
=18000*10
=180000km
now when there are twelve tyres=(10*18000)/12=15000<...
Getting 15000.
18k*10/12 = 15k.
=====================
Q) A credit card number has 6 digits (between 1 to 9). The first two digits are 12 in that order, the third digit is bigger than 6, the forth is divisible by 3 and the fifth digit is 3 times the sixth. How many different credit card n...
1 1
(3/75)=(1.3/A)
=>A=32.5~33
(b)
bhai d ans is x-8
(kx-6)(x^2+2x-
=x^3-ax^2-bx+48
comparing a=4
putting a in d exp.
x^2-4x-32.
div by x-8
my take15000
total distance travelled ( sum of distance travelled by individual tyres) = 18000*10
we have used 12 tyres for this so per tyre it come sot 18000*10/12 = 15000
1 1
A 250 m long train is approaching an unmanned railway crossing. The train is
running at a uniform speed of 75 km/h and is 3 km away from the crossing. At the same instant, a scooter is also approaching the crossing and is 1300 m away from it. The scooter is moving at a uniform speed of A. I...
train___________crossing_________scooter
<---------3---------->,-------1.3------------>
total distance between scooter and train=4.3km
time to collide t= 4.3/75+A................1
also t*A=1.3km....................2
using 1&2 we get A=32.5kmph in order to just avoid collision
s...
sol:
time taken by train =3/75 hr
and time taken by scooter=1.3/A
they will collide if 3/75=1.3/A
A=32.5 km/hr
now for escaping collison A>32.5
option 2)
A truck having ten tyres travels from P to Q and then back to P. If there are 2 additional spare tyres and the distance between P and Q is 9000 kilometres (km), then the maximum distance travelled (in km) by any tyre is at least?
(1) 12000 (2) 18000 (3) 9000 (4) 16000 (5) 15000
my take5:15 a.m.
in 3 hours anil would have travelled 180 kms.
effective speed of ashu and anil = 10 kmph
it would take 18 hours for them to cover 180kms gap. so 9:00 p.m. - 18 hours = 3 a.m. was when ashu started and 00:00 was the time when anil started.
so anil travelled for 21 hrs...
1 1
Getting option 2.
The train will cover this 3km in 0.04 hrs.
The scooter needs to cover 1.3 km in less than 0.04 hrs.
=> Speed of scooter = A = 1.3/Time.
=> 1.3/A < 0.04
=> A > 1.3/0.04.
So A > 32.5 kmph.
2 2