bhai d ans is zero.


In a three-digit number, the unit digit is twice the tens digit and the tens digit is twice the hundreds
digit. The same number is written as 1XY and 1YX in base 8 and base 9 respectively. Find the sum
of X and Y in the decimal system.
(a) 15 (b) 7 (c) 11 (d) Cannot be determined
sabhi bhaiyoo ko pranam!!!

bhai d ans is zero.


In a three-digit number, the unit digit is twice the tens digit and the tens digit is twice the hundreds
digit. The same number is written as 1XY and 1YX in base 8 and base 9 respectively. Find the sum
of X and Y in the decimal system.
(a) 15 (b) 7 (c) 11 (d) Cannot be determined
sabhi bhaiyoo ko pranam!!!

bhai d ans is zero.


In a three-digit number, the unit digit is twice the tens digit and the tens digit is twice the hundreds
digit. The same number is written as 1XY and 1YX in base 8 and base 9 respectively. Find the sum
of X and Y in the decimal system.
(a) 15 (b) 7 (c) 11 (d) Cannot be determined
sabhi bhaiyoo ko pranam!!!

Applying AM>=GM

(p/q + q/r + r/p)/3>=cube root of(p/q*q/r*r/p)=1

or, p/q + q/r + r/p>=3
So no soln

Vivek bhai, the bold part is coming out to be lesser than 1. so ek pipe aur on karni padegi.
and jara 2nd wale ki thodi approach samjao. mere toh dimaag mein hi ni aa ra.

There are infinite no of taps that are fillin a certain tank.
The taps are numbered as 1,2,3 and so on.Any tap numbered p(p>=2)
can fill the tank in p-1 mins while the first tap does not work at all.


1)The min number of tabs that must be opened so that the tank is filled within 106 seconds is
6
3
4
5

sumeet1489 Says

how many positive integers p,q,r exist such that p/q + q/r + r/p=2

sumeet1489 Says

how many positive integers p,q,r exist such that p/q + q/r + r/p=2

1) my take 3

(1/3+1/8+1/15)*106/60>1

so pump no. 2,3,4 if opened can fill the tank with in 106 sec


2) % of work done by respective pumps per min is
(33.33+8.5+6.6 + 4.16 + 2.7 + 2.1+1.xx +1.xx+1.0x + 0.xx+0.xx+.....so on )

this adds to b nearly 66%

so it suld require 3/2 min to complete the job....
but no such option:-o


bs bhai.... sunday koo ranchi chala gaya tha dosto k sath outing pe....kal ka pura din court k chakkar kat reha tha..income tax saving k liye ek affidevit banwana tha.......aisi koi chizz nai hai jo pg se impoertant ho bhai

There are infinite no of taps that are fillin a certain tank.
The taps are numbered as 1,2,3 and so on.Any tap numbered p(p>=2)
can fill the tank in p-1 mins while the first tap does not work at all.


1)The min number of tabs that must be opened so that the tank is filled within 106 seconds is
6
3
4
5


2)If all the taps from the second tap are opened simultaneously then what is the shortest time in which the tank can be filled?

11/3
22/3
2/3
11/5

There are infinite no of taps that are fillin a certain tank.
The taps are numbered as 1,2,3 and so on.Any tap numbered p(p>=2)
can fill the tank in p-1 mins while the first tap does not work at all.


1)The min number of tabs that must be opened so that the tank is filled within 106 seconds is
6
3
4
5

Correct....

Aare wah....Jain bhai.....You seem to be on a rampage....!!!
Any special occasion...?? :p:p

kyon le rahe ho bs bhai question was easy

Aare wah....Jain bhai.....You seem to be on a rampage....!!!
Any special occasion...?? :p:p

How many odd integers from 1000 to 8000 (inclusive) have distinct digits ?a. 2520 b. 1736 c. 1680 d. 1960 e. 3500

my take1680

For the number to be odd it should end with 1,3,5,7,9
thousands digit can take 6 values
hundreds digit can take 8 values
tens digit can take 7 values
units digit can 5 values

total = 6*8*7*5 = 1680 ways

abcd

a(1-7)
b(0-9)
c(0-9)
d(1,3,5,7,9)

if d=9
a=7ways b=8 c=7

if d=1,3,5,7
then a=6 b=8 c=7

total=7*8(7+4*6)=1736

my take-1736
case1) when 1st digit is even = 3*8*7*5
case2) when 1st igit is odd = 4*8*7*4
adding we get 173

my take1680

For the number to be odd it should end with 1,3,5,7,9
thousands digit can take 6 values
hundreds digit can take 8 values
tens digit can take 7 values
units digit can 5 values

total = 6*8*7*5 = 1680 ways

Correct....

Aare wah....Jain bhai.....You seem to be on a rampage....!!!
Any special occasion...?? :p:p

How many odd integers from 1000 to 8000 (inclusive) have distinct digits ?a. 2520 b. 1736 c. 1680 d. 1960 e. 3500

Correct....

Aare wah....Jain bhai.....You seem to be on a rampage....!!!
Any special occasion...?? :p:p

How many odd integers from 1000 to 8000 (inclusive) have distinct digits ?a. 2520 b. 1736 c. 1680 d. 1960 e. 3500

Correct....

Aare wah....Jain bhai.....You seem to be on a rampage....!!!
Any special occasion...?? :p:p

How many odd integers from 1000 to 8000 (inclusive) have distinct digits ?a. 2520 b. 1736 c. 1680 d. 1960 e. 3500

20 is my take

20*5 = 2*(5+10+15+20)

so at end 20 men were working....


ps- good afternoon puyss....3 din se pg pe nai tha..it was biting internally...anyways happy to b back

1 worker = 1 unit per day

20*5 = 100 units

5*2 = 10 units
10*2 = 20 units
15*2 = 30 units
20*2 = 40 units

so , 20 workers at the time of completion

bs bhai red part SUM hoga I guess

a+b+c = 132 ....1
a+b+d = 129 ....2
c+d+e = 119 .....3
b+d+e = 121 ...4
6(a+b+c+d+e) = 1254
=> a+b+c+d+e = 209

add 1 and 3
a+b+2c+d+e = 251
c = 42

add 1 and 4
a+2b+c+d+e = 253
b = 44

put values of 'b' and 'c' in 1
a = 46

put values of 'a' , 'b' in 2
d = 39

put values of 'b' and 'd' in 4
e = 38
highest = 46 and lowest = 38

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

Surbhih Says

Find the number of zeroes at the end of 1090!

Absolutely right.............

A,B,C,D,E are five students who took CAT. Following are the sum of their over-all score, taken three at a time.. 119,121,124, 125,123,126,127,128,129, and 132.Which is the highest and lowest score among the scores of ABCDE?

Surbhih Says

Find the number of zeroes at the end of 1090!

Absolutely right.............

A,B,C,D,E are five students who took CAT. Following are the avgs. of their over-all score, taken three at a time.. 119,121,124, 125,123,126,127,128,129, and 132.Which is the highest and lowest score among the scores of ABCDE?

a^6 + b^6 = (a^2)^3 + (b^2)^3
=(a^2 + b^2)(a^4 -(ab)^2 +b^4)
=> for above to be prime either, (a^2 + b^2)=1 or (a^4 -(ab)^2 +b^4)=1
case1. if (a^2 + b^2)=1.
then only possible way is a =1; b=0 ; but in that case a^6 + b^6 =1+0=1 which is not a prime.
so, (a^4 -(ab)^2 + b^4) has to be =1
only way possible is a=1; b= -1;
also then a^6 + b^6 =1+1=2 which is a prime indeed.
so, a=1; b=-1; sum of digits =0

how can we find if we dont know the Previous position ....???i mean the default position .. it could be closed aur open


ur answer is correct but only iff the Default position is closed ...:)

upudit0 Says

31 count perfect squares between 1 to 1000

a = 1
b = -1

sum = 0
Q) - here are one thousand students at the George Washington High School. Each student is assigned a locker, numbered 1 through 1000. On the first day of school each year, the students participate in an unusual ritual: The students enter the school through one door, parade past the all the lockers, and then exit through another door. While in the school, the first student reverses the door position of each locker -- if the door is open, he closes it, and if it is closed, he opens it. The second student reverses the door position of every other locker, starting with locker number 2. The third student reverses every third locker, starting with locker number 3, etc. After all 1000 students have completed this ritual, which lockers will be left open?

a^6 + b^6 is a prime number. If a and b are distinct integers, then what is their sum?
(a) 0 (b) 2 (c) 1 (d) Data Inconsistent

when all are positive :-

a + b + c = 15 = 17C2 = 136

when all are -ve :-

a + b + c = 12 = 14C2 = 91

when 2 of them are -ve :-

a + b + c = 13 = 15C2 = 105*3C2 = 315

when 1 of them is -ve :-

a + b + c = 14 = 16C2 = 120*3C1 = 360

total = 902 = answer

jain bhai when all r negative a+b+c=12
when 2 of them are -ve

a + b + c = 13
when 1 of them is -ve

a + b + c = 14 kaise huya???

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

bs bhai , pratyasha madam plz derive this formula...not getting it

A2012 Says

Total digits are 11 and why u have written only 9 digit in bold part(incl. 2 A and 2 T)

Another approach:-

AATT can be arranged in total 4!/2^2 =6ways

out of these there is only 1 way acceptable

=> Out of 6 cases -------1 case

now total arrangements are 11!/2^2

=>out of 11!/2^2 ways no of ways possible= 1/6 *

=>ways= 11!/6*4 =11!/24 =11!/4!

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

sol:

X1 A X2 A X3 T X4 T X5

X1+X2+X3+X4+X5=7....also, 0<=X1,...X5<=7

=> No. of ways= C(11,4)

Again, the remaining letters will arrange among themselves 7! ways

also there is no possible arreangement of AATT

Total ways= C(11,4) * 7! =11!/4!

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

easy one!!!!!!!!!11

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

easy one!!!!!!!!!11

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

pratyasha1990 Says

allan sir, isnt it odd divisors -1???????

bs bhai , pratyasha madam plz derive this formula...not getting it

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

bs bhai , pratyasha madam plz derive this formula...not getting it

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

sol:- 10^6 = 2^6 * 5^6

no. Of ways a number can be written as a sum of two or more consecutive positive numbers= no. Of odd factors of the number\

=. No of odd factors of 10^6= 7

so ans should be 7.

when all are positive :-

a + b + c = 15 = 17C2 = 136

when all are -ve :-

a + b + c = 12 = 14C2 = 91

when 2 of them are -ve :-

a + b + c = 13 = 15C2 = 105*3C2 = 315

when 1 of them is -ve :-

a + b + c = 14 = 16C2 = 120*3C1 = 360

total = 902 = answer

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

bs bhai , pratyasha madam plz derive this formula...not getting it

in what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

ABC is a triangle with AB = 14, BC = 10 and CA = 6. D and E are points on BC and CA respectively such that CD = 3 and CE = 2.5. A line passing through C and the point of intersection of AD and BE cut the side AB at F. Then AF =
(a) 5 (b) 5.25 (c) 6 (d) 6.25 (e) 7.5

:
NO OF SOLN=4N^2+2
=4.225+2=902

Use formula 4n^2+2 where n=15
we get 902.........