20 is my take

20*5 = 2*(5+10+15+20)

so at end 20 men were working....


ps- good afternoon puyss....3 din se pg pe nai tha..it was biting internally...anyways happy to b back

1 worker = 1 unit per day

20*5 = 100 units

5*2 = 10 units
10*2 = 20 units
15*2 = 30 units
20*2 = 40 units

so , 20 workers at the time of completion

bs bhai red part SUM hoga I guess

a+b+c = 132 ....1
a+b+d = 129 ....2
c+d+e = 119 .....3
b+d+e = 121 ...4
6(a+b+c+d+e) = 1254
=> a+b+c+d+e = 209

add 1 and 3
a+b+2c+d+e = 251
c = 42

add 1 and 4
a+2b+c+d+e = 253
b = 44

put values of 'b' and 'c' in 1
a = 46

put values of 'a' , 'b' in 2
d = 39

put values of 'b' and 'd' in 4
e = 38
highest = 46 and lowest = 38

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

a contractor undertook a project to complete in 20days which needed 5 workers to work continuously for all the days estimated ,but before the start of work the client wanted to complete the work before the scheduled time ,so the contractor employed 5 additional men every two days to complete the work in the time the client wanted

how many men were working on the day when the project was completed ?
a)5 b)10 c)20

Surbhih Says

Find the number of zeroes at the end of 1090!

Absolutely right.............

A,B,C,D,E are five students who took CAT. Following are the sum of their over-all score, taken three at a time.. 119,121,124, 125,123,126,127,128,129, and 132.Which is the highest and lowest score among the scores of ABCDE?

Surbhih Says

Find the number of zeroes at the end of 1090!

Absolutely right.............

A,B,C,D,E are five students who took CAT. Following are the avgs. of their over-all score, taken three at a time.. 119,121,124, 125,123,126,127,128,129, and 132.Which is the highest and lowest score among the scores of ABCDE?

a^6 + b^6 = (a^2)^3 + (b^2)^3
=(a^2 + b^2)(a^4 -(ab)^2 +b^4)
=> for above to be prime either, (a^2 + b^2)=1 or (a^4 -(ab)^2 +b^4)=1
case1. if (a^2 + b^2)=1.
then only possible way is a =1; b=0 ; but in that case a^6 + b^6 =1+0=1 which is not a prime.
so, (a^4 -(ab)^2 + b^4) has to be =1
only way possible is a=1; b= -1;
also then a^6 + b^6 =1+1=2 which is a prime indeed.
so, a=1; b=-1; sum of digits =0

a^6 + b^6 is a prime number. If a and b are distinct integers, then what is their sum?
(a) 0 (b) 2 (c) 1 (d) Data Inconsistent

how can we find if we dont know the Previous position ....???i mean the default position .. it could be closed aur open


ur answer is correct but only iff the Default position is closed ...:)

upudit0 Says

31 count perfect squares between 1 to 1000

a = 1
b = -1

sum = 0
Q) - here are one thousand students at the George Washington High School. Each student is assigned a locker, numbered 1 through 1000. On the first day of school each year, the students participate in an unusual ritual: The students enter the school through one door, parade past the all the lockers, and then exit through another door. While in the school, the first student reverses the door position of each locker -- if the door is open, he closes it, and if it is closed, he opens it. The second student reverses the door position of every other locker, starting with locker number 2. The third student reverses every third locker, starting with locker number 3, etc. After all 1000 students have completed this ritual, which lockers will be left open?

a^6 + b^6 is a prime number. If a and b are distinct integers, then what is their sum?
(a) 0 (b) 2 (c) 1 (d) Data Inconsistent

when all are positive :-

a + b + c = 15 = 17C2 = 136

when all are -ve :-

a + b + c = 12 = 14C2 = 91

when 2 of them are -ve :-

a + b + c = 13 = 15C2 = 105*3C2 = 315

when 1 of them is -ve :-

a + b + c = 14 = 16C2 = 120*3C1 = 360

total = 902 = answer

jain bhai when all r negative a+b+c=12
when 2 of them are -ve

a + b + c = 13
when 1 of them is -ve

a + b + c = 14 kaise huya???

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

bs bhai , pratyasha madam plz derive this formula...not getting it

A2012 Says

Total digits are 11 and why u have written only 9 digit in bold part(incl. 2 A and 2 T)

Another approach:-

AATT can be arranged in total 4!/2^2 =6ways

out of these there is only 1 way acceptable

=> Out of 6 cases -------1 case

now total arrangements are 11!/2^2

=>out of 11!/2^2 ways no of ways possible= 1/6 *

=>ways= 11!/6*4 =11!/24 =11!/4!

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

sol:

X1 A X2 A X3 T X4 T X5

X1+X2+X3+X4+X5=7....also, 0<=X1,...X5<=7

=> No. of ways= C(11,4)

Again, the remaining letters will arrange among themselves 7! ways

also there is no possible arreangement of AATT

Total ways= C(11,4) * 7! =11!/4!

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

easy one!!!!!!!!!11

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

easy one!!!!!!!!!11

How many arrangement of of the letters of the word CATASTROPHE are there in which both A's appear before both the T's?
(a.)11!/4! (b.)11!/ (c.)11!/6 (d.)/4!

pratyasha1990 Says

allan sir, isnt it odd divisors -1???????

bs bhai , pratyasha madam plz derive this formula...not getting it

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

bs bhai , pratyasha madam plz derive this formula...not getting it

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

sol:- 10^6 = 2^6 * 5^6

no. Of ways a number can be written as a sum of two or more consecutive positive numbers= no. Of odd factors of the number\

=. No of odd factors of 10^6= 7

so ans should be 7.

when all are positive :-

a + b + c = 15 = 17C2 = 136

when all are -ve :-

a + b + c = 12 = 14C2 = 91

when 2 of them are -ve :-

a + b + c = 13 = 15C2 = 105*3C2 = 315

when 1 of them is -ve :-

a + b + c = 14 = 16C2 = 120*3C1 = 360

total = 902 = answer

In what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

bs bhai , pratyasha madam plz derive this formula...not getting it

in what ways can 1,000,000 be expressed as the sum of consecutive positive whole numbers?

ABC is a triangle with AB = 14, BC = 10 and CA = 6. D and E are points on BC and CA respectively such that CD = 3 and CE = 2.5. A line passing through C and the point of intersection of AD and BE cut the side AB at F. Then AF =
(a) 5 (b) 5.25 (c) 6 (d) 6.25 (e) 7.5

:
NO OF SOLN=4N^2+2
=4.225+2=902

Use formula 4n^2+2 where n=15
we get 902.........

Find the number of integral solutions of mod(x) +mod(y) +mod (z) =15.
(1) 902 (2) 728 (3) 734 (4) 904 (5) none of these

:
NO OF SOLN=4N^2+2
=4.225+2=902

ABC is a triangle with AB = 14, BC = 10 and CA = 6. D and E are points on BC and CA respectively such that CD = 3 and CE = 2.5. A line passing through C and the point of intersection of AD and BE cut the side AB at F. Then AF =
(a) 5 (b) 5.25 (c) 6 (d) 6.25 (e) 7.5

Find the number of integral solutions of mod(x) +mod(y) +mod (z) =15.
(1) 902 (2) 728 (3) 734 (4) 904 (5) none of these

Find the number of integral solutions of mod(x) +mod(y) +mod (z) =15.
(1) 902 (2) 728 (3) 734 (4) 904 (5) none of these

OA for previous one = 10sqrt(50)

Charlie has 7 cards numbered 1, 2, 3, 4, 5, 6 and 7 and randomly deals 3 of them to Alice and 3 to Bob. All three people look at the cards that they hold. Can Alice and Bob communicate with each other, in the presence of Charlie, so that after the communication Alice knows which cards Bob has, and Bob knows which cards Alice has, but, for any card except the one he has, Charlie does not know whether Alice or Bob has it?

Consider a square ABCD of side 60 cm. lt contains
arcs BD and AC drawn with centres at A and D
respectively. A circle is drawn such that it is
tangent to side AB, and the arcs BD and AC. What
is the radius of the circle? (5 marks)
(1) 9 cm (2) 10 cm (3) 12 cm
(4) I5 cm (5) None of the above

A man had a 10-gallon keg of wine and a jug. One day, he drew off a jugful of wine and filled up the keg with water. Later on, when the wine and water had got thoroughly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water. What was the capacity of the jug?

__/\__ varun bhai , heaven bhai

let x and y be two four-digit palindromes (numbers that read the same forwards and backwards) and z be a five-digit palindrome. If x + y = z, how many values of z are possible?

jain bhai,heaven bhai ,varun bhai ____________/\_____________

The numerical value of f(1/10) + f(2/10) + . + f(9/10), where f(x)=9^x/(3+9^x) is
(A) 10/3 (B) 4 (C) v10 (D) 5 (E) 9/2

puyzz plzz post some questionssssssss

Let x and y be two four-digit palindromes (numbers that read the same forwards and backwards) and z be a five-digit palindrome. If x + y = z, how many values of z are possible?

jain bhai,heaven bhai ,varun bhai ____________/\_____________

A man had a 10-gallon keg of wine and a jug. One day, he drew off a jugful of wine and filled up the keg with water. Later on, when the wine and water had got thoroughly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water. What was the capacity of the jug?

__/\__ varun bhai , heaven bhai

A man had a 10-gallon keg of wine and a jug. One day, he drew off a jugful of wine and filled up the keg with water. Later on, when the wine and water had got thoroughly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water. What was the capacity of the jug?

__/\__ varun bhai , heaven bhai

A man had a 10-gallon keg of wine and a jug. One day, he drew off a jugful of wine and filled up the keg with water. Later on, when the wine and water had got thoroughly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water. What was the capacity of the jug?

__/\__ varun bhai , heaven bhai