Pia and Ria start running simultaneously from the same point on a circular track of length 4200 m. If they run in opposite directions, they meet for the first time exactly after 2 minutes from the start and they meet at seven distinct points on the track. If they run in the same direction, they meet at three distinct points on the track. How much time (in minutes) does Ria take to complete one round, if she is the slower runner?

3.5
7
10.5
none of these

need help with this question!

atharvaalok Says

Anybody??????

Answer : 78 ? (Assuming all 11 books each of maths, phy, chem to be identical)

0 0 11 .... 3
0 1 10 .... 6
0 2 9 ...... 6
0 3 8 ...... 6
0 4 7 ...... 6
0 5 6 ...... 6

1 1 9 ..... 3
1 2 8 ..... 6
1 3 7 ......6
1 4 6 ......6
1 5 5 ......3

2 2 7 .... 3
2 3 6 .....6
2 4 5 .....6

3 3 5 .... 3
3 4 4 ... 3

Total : 78

I've been solving Nishit Sinha quants. Been having problems with the following problem:
A shopkeeper sells 2 types of goods, both at 120, whereas the first cost him Rs 90, and the second Rs 160. Sale of A started from 1 for the first day and went on increasing every day by 4 units, whereas the sale of B was 450 first day and went on decreasing by 6.

1. Shopkeeper has planned in such a way that he starts earning profit exactly on diwali which is N days from now. What is the value of N?
a. 103 b. 105 c. 107 d. 109

2. On which day will he earn profit for the first time on a day to day basis?
a. 49 b. 51 c. 53 d. 55

any help will be appreciated

For 1st day , is it 103??

atharvaalok Says

A library has 11 books on chemistry, 11 books on Maths, 11 books on physics. In how many ways can these books be arranged in groups of eleven?

Assuming all books different 33c11*11!

Q10. 17^12 + 10^12 - (16^6 + 9^6) wen divided by 13 remainder r1
wen divided by 14 remainder r2

what is r1
and r2

Q11. N=296x + 75 remainder wen N is divided by 37

My take 0 for r1 & r2

N=296x + 75 remainder wen N is divided by 37

37 divides 296 completely and when divides 75 it is 1 so my take 1

atharvaalok Says

A library has 11 books on chemistry, 11 books on Maths, 11 books on physics. In how many ways can these books be arranged in groups of eleven?

Anybody??????

Rahulacc Says

Try this 1..

1 hai kya ???

values le ke kia...like
p=1 k=1
p=1 k=2........

wahi aaya.....

Try this 1..

pq * pr
------------
-- ---(pr) (qr)
-(p)(pq)x
------------
---p--q---r

Clearly p= q =1 and r=0

Hence

pq = 11 , pr =10 , pqr = 110 , prrp = 1001


(qp*prrp) Mod pp

(11 * 1001) Mod 11

0 mod 11


So i guess it shud be 0 !!

Neetu its pq*pr=pqr
and not pq+pr=pqr

pq+pr=pqr

(10p+q)(10p+r) = 100p+10Q+r
100 (p^2-p) +10(pr+pq-q)+qr-r =0

=> (p^2-p) =0
(pr+pq-q)= 0
qr-r=0

=> p=1
q=1
r=0

so 11*1001/11 remainder 0 my take

OA its 0

Q10. 17^12 + 10^12 - (16^6 + 9^6) wen divided by 13 remainder r1
wen divided by 14 remainder r2

what is r1
and r2

Q11. N=296x + 75 remainder wen N is divided by 37

Q10==>
17^12-16^6+10^12-9^6
-----------------------
289^6-16^6|100^6-9^6
(289-16)Y | (100-9)Z
273Y 91Z <=(273 and 91 divisible by 13)
r1=0
similarly u can also try combn of 17^12-9^6 & 10^12-16^6
i.e. 17^12-3^12 & 10^12-4^12
again divisible by 14.. r2=0
Q11
296=37*8 , so rem=> 1

PS Please do not expect so direct Qs in CAT...

Question:

A drum of 20L is filled with milk. A guy has only 2 vessels of 3L n 5L. He has to measure 4L of milk using the above 2 vessels. Minimum operations required are? (an operation is transferring milk from 1 vessel to another).

5
6
8
11

Please post the approach too.


AT

3-0<=
0-3
3-3<=
1-5
1-0<=
0-1
3-1<=(this is where we have measured 4L milk)
0-4

is it 5? HELP

A library has 11 books on chemistry, 11 books on Maths, 11 books on physics. In how many ways can these books be arranged in groups of eleven?

I've been solving Nishit Sinha quants. Been having problems with the following problem:
A shopkeeper sells 2 types of goods, both at 120, whereas the first cost him Rs 90, and the second Rs 160. Sale of A started from 1 for the first day and went on increasing every day by 4 units, whereas the sale of B was 450 first day and went on decreasing by 6.

1. Shopkeeper has planned in such a way that he starts earning profit exactly on diwali which is N days from now. What is the value of N?
a. 103 b. 105 c. 107 d. 109

2. On which day will he earn profit for the first time on a day to day basis?
a. 49 b. 51 c. 53 d. 55

any help will be appreciated

Q1.Find the remainder when (12!)^14!+1 is divided by 13!?
Q2.In how many ways a cube can be colored using 6 colors if each color should be used at least once?
Post solution with approach :)

1)12! ^14! =rem 1
ans is 2

Q10. 17^12 + 10^12 - (16^6 + 9^6) wen divided by 13 remainder r1
wen divided by 14 remainder r2

what is r1
and r2

Q11. N=296x + 75 remainder wen N is divided by 37

Bhai r1, r2 =0??

11- divide N by 37, Remainder =1.

vivekmohit Says

Is it -24 to 30?

OA says it is [-24,-1

Q10. 17^12 + 10^12 - (16^6 + 9^6) wen divided by 13 remainder r1
wen divided by 14 remainder r2

what is r1
and r2

Q11. N=296x + 75 remainder wen N is divided by 37

Is it -24 to 30?

Find Range which x can take..
2[x/6]^2 + 3[x/6] = 20.
[ ] --> GIF.

Acc.to me
-29<=x<=-24

Find Range which x can take..
2[x/6]^2 + 3[x/6] = 20.
[ ] --> GIF.

A man covers a certain distance at some speed. had he moved 3 kmph faster, he would taken 40 minutes less, had he moved 2 kmph slower he would have taken 40 minutes more?
find the distance that he travelled ?

d/s - d/s+3 = 40/60 (i)

d/s-2 - d/s = 40/60(ii)
dIVIDE i by ii,
on solving s=12
then substitute in any equation to get d=40.

Let Sn be sum of squares of first N natural numbers. How many values of N satisfy the condition N<100 and Sn is divisible by 4?

1)50
2)12
3)24
4)25

S = n (n+1) (2n+1) /6
Since the number is div by 4...

Therefore n (n+1)(2n+1) is div by 24....
24= 2^3*3
For that to happen , let n =7 the number would divisible..
so it would be divisible by numbers of the form 8n and 8n - 1,

So 13 (starting from 7 and common difference of 8 till 100) , 12 (starting from 8 and cd of an minus 1 (56)
below 100 ; would be 24
I think , it should be correct

Let Sn be sum of squares of first N natural numbers. How many values of N satisfy the condition N<100 and Sn is divisible by 4?

1)50
2)12
3)24
4)25

In table tennis, the first player to score 21 points wins. Service alternates between two players every 5 points. A player can score both during his service and his opponent's service. Doshi beats venkat 21-16. 24 out of 37 points were won on service. Who served first?

options ki kya zarurat hai:biggrin:

4 boxes labeled "Green & Red", "Red & White", "White & Black" and "Only Black" are there. All the labels are incorrect. How many minimum balls do have to sample to correctly label the boxes.
a) 2
b) 3
c) 4
d) 1

i think ans is 3...
suppose v see 'only B' box and finds say ' G & R' and label it acc..
then v see 'G & R' box and label it correctly(say R & W)..
then we know box with 'R & W' label contain 'W & B' and box with 'W & B' contains 'only B'..so 3

4 boxes labeled "Green & Red", "Red & White", "White & Black" and "Only Black" are there. All the labels are incorrect. How many minimum balls do have to sample to correctly label the boxes.
a) 2
b) 3
c) 4
d) 1

Hope it is 3?

When we pick a ball from box labelled 'W&B;' it has to be 'R' or 'G'. So the box is 'R & G' box.

Shibu and Soren start simultaneously from A and B and walk towards B and A respectively. A and B are 900 m apart. On reaching their respective destinations, they turn back and move towards their respective starting points. They continue to travel this way indefinitely. The second time the two are at the same point at the same time is at the point P, 300 m from B. Which of the following can be the ratio of Shibu's speed to Soren's speed?

2

8

2/5

2/7

Possibilities are:-
i) Shibu traveled (900 + 300) and Soren traveled (900 + 600)
ratio = 4:5
ii) Shibu traveled 600 and Soren traveled (900 + 600)
Ratio = 2:5
iii) Shibu traveled (900 + 300) and Soren traveled 300
Ratio = 4:1

So, only possibility is 2:5

1) In a circular track, there are two points P and Q which are diametrically opposite.
C starts running clockwise with a speed of 4m/s from P.
At the same time, from Q, A starts running clockwise with a speed of 3 m/s and B starts
running anti clockwise with a speed of 5 m/s. If the length of the track is 300m, then
after how much time will C be equidistant from A and B for the first time

Guys plz ans this

yaar options satisy karke dekh lo....starting from the least one....shud not take more than 2 mins i guess

4 boxes labeled "Green & Red", "Red & White", "White & Black" and "Only Black" are there. All the labels are incorrect. How many minimum balls do have to sample to correctly label the boxes.
a) 2
b) 3
c) 4
d) 1

jain4444 Says

How many sets of three distinct factors of the number N = 26 34 52 can be made such that the factors in each set has a highest common factor of 1 with respect to every other factor in that set ?

Is it 14?

N = 13*2^4*17

(13^x,2^y,17) where x can be 0,1,2 and y can be from 0 to 4.

So 3*5 = 15 ways

15-1 = 14; where both x and y are 0.

Please solve this:
The sum of two positive integer quantities is equal to 2n. the probability that their product is not less then 3/4 times their greatest product is

1/3
2/3
1/2
1/4

Is it option 1/2?

i took few numbers and verified,

2+4=6 prod =8 greatest prod = 9

2+6=8 prod = 12 greatest prod = 16

2+8=10 prod = 16 greatest prod = 25

2+10=12 prod = 20 greatest prod = 36

Please solve this:
The sum of two positive integer quantities is equal to 2n. the probability that their product is not less then 3/4 times their greatest product is

1/3
2/3
1/2
1/4

a + b = 2n

Say a = n + k, where k can vary from 1 to (n - 1)
=> b = n - k

ab = n - k 3n/4
=> k n/2

=> Probability = (n/2)/n = 1/2

jain4444 Says

How many sets of three distinct factors of the number N = 26 34 52 can be made such that the factors in each set has a highest common factor of 1 with respect to every other factor in that set ?

http://www.pagalguy.com/forum/quantitative-questions-and-answers/72542-official-quant-thread-cat-2011-a-588.html#post2977159

How many sets of three distinct factors of the number N = 26 34 52 can be made such that the factors in each set has a highest common factor of 1 with respect to every other factor in that set ?

sahilmadan Says

Shibu and Soren start simultaneously from A and B and walk towards B and A respectively. A and B are 900 m apart. On reaching their respective destinations, they turn back and move towards their respective starting points. They continue to travel this way indefinitely. The second time the two are at the same point at the same time is at the point P, 300 m from B. Which of the following can be the ratio of Shibu's speed to Soren's speed?

I think options are required to solve this question!!!!!

1) In a circular track, there are two points P and Q which are diametrically opposite.
C starts running clockwise with a speed of 4m/s from P.
At the same time, from Q, A starts running clockwise with a speed of 3 m/s and B starts
running anti clockwise with a speed of 5 m/s. If the length of the track is 300m, then
after how much time will C be equidistant from A and B for the first time

Guys plz ans this

B and C meets after 150/(4 + 5) = 50/3 seconds.

At this point distance between A and C is 150 + 50 - 200/3 = 400/3

So, suppose that from this moment on wards it take them t time to reach the situation when C is equidistant from A and B

After time t, distance between A and C will be 400/3 + 3t - 4t = 400/3 - t
and distance between B and C will be 9t

9t = 400/3 - t
=> t = 40/3

So, after 50/3 + 40/3 = 30 seconds C will be equidistant from A and B for the first time

sahilmadan Says

Shibu and Soren start simultaneously from A and B and walk towards B and A respectively. A and B are 900 m apart. On reaching their respective destinations, they turn back and move towards their respective starting points. They continue to travel this way indefinitely. The second time the two are at the same point at the same time is at the point P, 300 m from B. Which of the following can be the ratio of Shibu's speed to Soren's speed?

where are the options ???

Please solve this:
The sum of two positive integer quantities is equal to 2n. the probability that their product is not less then 3/4 times their greatest product is

1/3
2/3
1/2
1/4

1) In a circular track, there are two points P and Q which are diametrically opposite.
C starts running clockwise with a speed of 4m/s from P.
At the same time, from Q, A starts running clockwise with a speed of 3 m/s and B starts
running anti clockwise with a speed of 5 m/s. If the length of the track is 300m, then
after how much time will C be equidistant from A and B for the first time

Guys plz ans this

Shibu and Soren start simultaneously from A and B and walk towards B and A respectively. A and B are 900 m apart. On reaching their respective destinations, they turn back and move towards their respective starting points. They continue to travel this way indefinitely. The second time the two are at the same point at the same time is at the point P, 300 m from B. Which of the following can be the ratio of Shibu's speed to Soren's speed?

2

8

2/5

2/7

iimSekar Says

Its radius given as 4...

ohh..still answer will be same....as circumference will cancel out...u can verify urself

The answer must be 7?

7! = 5040

5040/2 = 2520.

This means there must not be F1 and F2. Guess some info would be there in question regarding Fn

sorry my mistake . question galat hain

it should be 2519
and the answer is 5
and not 7

i had marked it as 7

the approach is as follows

upar wala approach sahi hain

we ignore the 0 wala case from all families first.

he can deal with each faimliy in 3, 4, 5, 6 7.... n+ 2
wasy
so (n+2)!/2 - 1 = 2519

damn it you guys are super smart

maine toh yeh angle socha hi nahi :D



now an easy one.

Pooja Missra from , big boss 5 is friends with some families

the families are like Fn = n + 1 (members)

She can call at most 1 person from each family to the party.

If the toal number of ways she has called people from different families to her party is 2520.
Find n

yeh bada kathor sawal hain dekhte hain kitne jaldi aap log iska uttar haasil karke post karte hain yaha :clap:

The answer must be 7?

7! = 5040

5040/2 = 2520.

This means there must not be F1 and F2. Guess some info would be there in question regarding Fn

is it 6 kya....?
yaar pata nahi koschen mein kuch gadbad lag rahi hai

rohitpal Says

the answer is 7 guys :D

bhai simple hain yaar

take for eg

families are like

F 1 = 2 MEMBERs
F2 = 3 MEMBERS

now the condition says that she can call at most 1 member from each of the faimilies


so from family 1

she can call people in the following ways

nobody - 1 way
1 person - 2 ways
total ways - 3

from family 2
she call peple in the following ways

nobody - 1 way
1 person - 3 ways
total ways - 4

aise hi approach hain
btw
you need not have though much coz

7! = 5040

total ways = 5040/2 = 2520

sitter tha

rohitpal Says

the answer is 7 guys :D

approach bhi toh share kr bhai !!!!

Which one is correct?

g(n)=f(f(n))+1

ye wala correct hai..



P.S main bhai ni hoon

ksagarwa Says

circumference is given as 4 so 1/8 th of 4...

Its radius given as 4...

is n=5?????/


Who is Pooja Mishra BTW???? :splat:

the answer is 7 guys

now an easy one.

Pooja Missra from , big boss 5 is friends with some families

the families are like Fn = n + 1 (members)

She can call at most 1 person from each family to the party.

If the toal number of ways she has called people from different families to her party is 2520.
Find n

yeh bada kathor sawal hain dekhte hain kitne jaldi aap log iska uttar haasil karke post karte hain yaha :clap:

is it 6 kya....?
yaar pata nahi koschen mein kuch gadbad lag rahi hai

Hi,

Please explain the bold part.

Isn't it 1/8 of the circumference? So Pie/8?

BTW nice approach

circumference is given as 4 so 1/8 th of 4...

If it is not a leap year then the year has to begin on sunday
so 1/7

If it is a leap year then it has to begin on a saturday or sunday
so 2/7

so i gues prob= 3/4*1/7+1/4*2/7= 5/28

Sir in 400 years, if we take shouldn't it be 97/400*2/7+303/400*1/7
because in after 400 years actually the cyclicity begins...with 97 leaps and 303 non-leaps

vyassaurabh Says

Bhai iska answer to 4 aa raha hai, sahe hai kya?

Which one is correct?
g(n)=f(f(n)+1)
g(n)=f(f(n))+1

3/484 it shud be...OA??

let length of arc A56 be x
then length of A45 is x/3..length of A34 is x/9...length of A23 is x/27..length of A12 is x/81..

Adding all these...121x/81...which is equal to 4/8 (given)
so x = 81/242
A23 = 3/242...
now use

theta/360 * 4 = 3/242

theta = 135/121..

convert to radians,,,,135/121 * /180..
so answer is 3/484

PS: For that solution wala question i followed a ditto approach as emanresu...u can refer that

Hi,

Please explain the bold part.

Isn't it 1/8 of the circumference? So Pie/8?

BTW nice approach

is n=5?????/


Who is Pooja Mishra BTW???? :splat:

well she is a contestant on big boss season 5.

answer is not correct :(

quantphobic Says

isko koi solve kardo plz

Bhai iska answer to 4 aa raha hai, sahe hai kya?

vyassaurabh Says

Is the answer '4' for the question?

Naii OA mein toh 6 dia hai

damn it you guys are super smart

maine toh yeh angle socha hi nahi :D



now an easy one.

Pooja Missra from , big boss 5 is friends with some families

the families are like Fn = n + 1 (members)

She can call at most 1 person from each family to the party.

If the toal number of ways she has called people from different families to her party is 2520.
Find n

yeh bada kathor sawal hain dekhte hain kitne jaldi aap log iska uttar haasil karke post karte hain yaha :clap:

is n=5?????/


Who is Pooja Mishra BTW???? :splat:

quantphobic Says

the set of all positive integers is the union of two disjoint sets{f(1),f(2),f(3)..}& {g(1),g(2),g(3)..},where f(1)

isko koi solve kardo plz

6 is represented as a 2 digit number, possible base values are 3,4 &5.

15 will be 3 digit only in base 3.

So ABB?

yes, IIM jaaoge tum sekar

I think its abb ???

convert no.'s to base 3

damn it you guys are super smart

maine toh yeh angle socha hi nahi :D



now an easy one.

Pooja Missra from , big boss 5 is friends with some families

the families are like Fn = n + 1 (members)

She can call at most 1 person from each family to the party.

If the toal number of ways she has called people from different families to her party is 2520.
Find n

yeh bada kathor sawal hain dekhte hain kitne jaldi aap log iska uttar haasil karke post karte hain yaha :clap:

quantphobic Says

the set of all positive integers is the union of two disjoint sets{f(1),f(2),f(3)..}& {g(1),g(2),g(3)..},where f(1)

Is the answer '4' for the question?