4 ??

....

yes 4 hi hai but process kya hai

Theory on mixture allegations plz

Especially the concept of Removal and replacement?

10 hai kya ?? not very sure ..

20x + k = 23(x-n) + n = 21x + 500
=> x + 500 = k

first and third eqns me replace x by the given 4 values , only 10 satisfies

Bhai answer is 13

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Q.4
In the figure given below AE : EC = 1 : 7, AD : DB = 1 : 3, BF : FC = 2 : 3 and the area of ABC = 160 square units

find the area of ADE in square units.

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could anybody help me with this problem
The single digits a and b are neither both nine nor both zero. the repeating decimal 0.ababababab......is expressed as a fraction in lowest terms How many different denominators are possible?
a)4
b)6
c)5
4)3

alps2011 Says

put the expression equal to the given options and for only -1 the quadratic equation has non real roots...so it cant take -1 value

This is an AIMCAT 1209 question. Mods please take some action. people are posting aimcat questions within window period despite the earlier requests to not to post within the window period of test taking

In triangle XYZ,

i have a query...

which of the following cant be the value of (x^2+4x+5/x+2) for real x?

options- -3,-2,2,-1

plz post your approach also......

put the expression equal to the given options and for only -1 the quadratic equation has non real roots...so it cant take -1 value

that was quick ..... normally 1000 pages par band hoti thi

fungus 2^1990/1990 find remainder
what is oa 1989 or 1024 ??

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Thread Closed!!!!

i have a query...

which of the following cant be the value of (x^2+4x+5/x+2) for real x?

options- -3,-2,2,-1

plz post your approach also......

2/3 *(pi)*r^2 * h = 718 2/3
Base of cone covers one side of cube, h = 2r

So, radius will come out to be 7
Cube : 14x14x14
Cone : radius = 7, height = 14

Now, calculate...

2/3 or 1/3 ???!!
thank you very much anyway !!

Madan is going from Mumbai to Delhi in order to join a new job there. He has a glass memento of right
circular conic shape under his possession and he does not want it to break during transportation. So,
he purchases a cubic metal box from the market spending Rs. 500. The cone is exactly fitted in the
metal cube in such a way that while the edges of the base of the cone are touching the edges of all the
sides of the cube, the vertex of it touches the opposite face of he cube After inserting the memento in
the box, he packed the metal box from outside with wallpaper costing Rs. 1.5 per sq cm. Given that the
volume of the glass memento is 718 2/3 cc, mark all the correct statements

a. Madan had incurred total expenditure of Rs. 2,264 on the metal box.
b. Madan had incurred an expenditure of Rs. 1,754 on packing the metal box.
c. The area of any one side of the metal box is 196 sq. cm
d. The volume of the metal box is 2,644 cc.

DK396 Says

please explain

1/3 *(pi)*r^2 * h = 2/3 *(pi)*r^3 = 718 2/3
Base of cone covers one side of cube, h = 2r

So, radius will come out to be 7
Cube : 14x14x14
Cone : radius = 7, height = 14

Now, calculate...

Laxman and Bharat decide to go from Agra to Delhi for watching a cricket match and board two
different trains for that purpose. While Laxman takes the first train the leaves for Delhi, Bharat decides
to wait for some time and take a faster train. On the way, Laxman sitting by the window-seat noticed
that the train boarded by Bharat crossed him in 12 seconds. Now the faster train can travel 180 km in
three hours, while the slower train takes twice as much time to do it. Given this, mark all the correct
options.

a. If the faster train has taken 30 seconds to cross the entire length of the slower train, the
difference between the lengths of the two trains is 50 m.

b. If the faster train had been running twice as much faster, it would have taken 10 seconds to
overtake the slower train.

c. Had the faster train taken 24 seconds to cross the entire length of the slower train, the length of
the slower train would have been 100 m.

d. If the slower train had been running at one and a half times of its current speed, the faster train
would have taken 24 seconds to overtake Laxman.

Madan is going from Mumbai to Delhi in order to join a new job there. He has a glass memento of right
circular conic shape under his possession and he does not want it to break during transportation. So,
he purchases a cubic metal box from the market spending Rs. 500. The cone is exactly fitted in the
metal cube in such a way that while the edges of the base of the cone are touching the edges of all the
sides of the cube, the vertex of it touches the opposite face of he cube After inserting the memento in
the box, he packed the metal box from outside with wallpaper costing Rs. 1.5 per sq cm. Given that the
volume of the glass memento is 718 2/3 cc, mark all the correct statements

a. Madan had incurred total expenditure of Rs. 2,264 on the metal box.
b. Madan had incurred an expenditure of Rs. 1,754 on packing the metal box.
c. The area of any one side of the metal box is 196 sq. cm
d. The volume of the metal box is 2,644 cc.

ans A & C......

Important : PM AB
Now, OPQ = S, So, OPM = 2S
AO:OM = 2:1

So, APO = 4S

So, AMP = 6S
And hence, AMC = 12S
And, ABC = 24S

P.S.: how is OPQ = S ??

Madan is going from Mumbai to Delhi in order to join a new job there. He has a glass memento of right
circular conic shape under his possession and he does not want it to break during transportation. So,
he purchases a cubic metal box from the market spending Rs. 500. The cone is exactly fitted in the
metal cube in such a way that while the edges of the base of the cone are touching the edges of all the
sides of the cube, the vertex of it touches the opposite face of he cube After inserting the memento in
the box, he packed the metal box from outside with wallpaper costing Rs. 1.5 per sq cm. Given that the
volume of the glass memento is 718 2/3 cc, mark all the correct statements

a. Madan had incurred total expenditure of Rs. 2,264 on the metal box.
b. Madan had incurred an expenditure of Rs. 1,754 on packing the metal box.
c. The area of any one side of the metal box is 196 sq. cm
d. The volume of the metal box is 2,644 cc.

in a triangle ABC,medians AM and CN to the sides BC and AB respectively,intersect at the point o. let p be the midpoint of AC and let MP intersect CN at Q.if the area of the triange omq is "S" sq units, area of abc is?


mn bhai - ab toh aap kagaz kalam ke bhi zaroorat nahi pad rahi !

Important : PM | AB. So, CN will be a median to MP as well...
Now, OPQ = S, So, OPM = 2S
AO:OM = 2:1

So, APO = 4S

So, AMP = 6S
And hence, AMC = 12S
And, ABC = 24S

|kunal v.t Says

what does the bold part represent ?

*#***#****#*#***

The red # is the blank space, So, we will have 5 place where we have to adjust 12 cars, such that between any two #, there is atleast one car!
_____________________________________________________________________
Remember remember the fifth of November
Gunpowder, treason and plot.
I see no reason why gunpowder, treason
Should ever be forgot...

No Adjacent space :
a + b + c + d + e = 9
where a and e can be 0, but b,c,d can be minimum '1'

Ways = C(13,4) = 715

Total ways = C(16,12)

Probability of no adjacent = 715/C(16,12) = 11/28
Probability she can park = 1-11/28 = 17/28

what does the bold part represent ?

Vijay has been invited for dinner in a club. While walking through the garden path towards the tower, he
observes that there is an electric rod on the top of the tower. From the point where he is standing, the
angles of elevation of the top of the electric rod and the top of the tower are and respectively. If the
heights of the electric rod and the tower are p and q respectively, mark all the correct statements.
a. The height of the tower is p tan/(tan tan)

b. The height of the electric rod is q tan/(tan tan)

c. The height of the tower is p tan/(tan tan)

d. The height of the electric rod is q (tantan)/tan

@kunal Harrison Ford{Han solo in star wars & indiana jones}

A parking lot has 16 spaces in a row. Twelve cars arrive, each of which requires one parking space, and their drivers chose spaces at random from among the available spaces. Auntie Em then arrives in her SUV, which requires 2 adjacent spaces. What is the probability that she is able to park?

a)137/280 b)143/280 c)17/28 d)11/28 e)None of these

No Adjacent space :
a + b + c + d + e = 12(edit)
where a and e can be 0, but b,c,d can be minimum '1'

Ways = C(13,4) = 715

Total ways = C(16,12)

Probability of no adjacent = 715/C(16,12) = 11/28
Probability she can park = 1-11/28 = 17/28

@kunal : isme kaagaz kalam use kiye hain combinatorics tha :D
__________________________________________________________________
Remember remember the fifth of November
Gunpowder, treason and plot.
I see no reason why gunpowder, treason
Should ever be forgot...

in a triangle ABC,medians AM and CN to the sides BC and AB respectively,intersect at the point o. let p be the midpoint of AC and let MP intersect CN at Q.if the area of the triange omq is "S" sq units, area of abc is?


mn bhai - ab toh aap kagaz kalam ke bhi zaroorat nahi pad rahi !

A right angled triangle ABC is right angled at B. The point of contact of the incircle with the hypotenuse, divides it, in the ratio 3:2. If the perimeter of the triangle is 36 cm, find the inradius.


sannata kyun hai bhai ?! :O

Without pen/paper, don't mind if wrong...
inradius = r
(5x)^2 = (3x+r)^2 + (2x+r)^2
Or, 12x^2 = 10xr + 2r^2
Or, 6x^2 - 5xr - r^2 = 0
Or, x = r, -r/6

So, 10x+2r = 36
Or, r = 3
___________________________________________________________________
Remember remember the fifth of November
Gunpowder, treason and plot.
I see no reason why gunpowder, treason
Should ever be forgot...

A parking lot has 16 spaces in a row. Twelve cars arrive, each of which requires one parking space, and their drivers chose spaces at random from among the available spaces. Auntie Em then arrives in her SUV, which requires 2 adjacent spaces. What is the probability that she is able to park?

a)137/280 b)143/280 c)17/28 d)11/28 e)None of these

i dont have the oa , but i think first case me aisa nahi hona chahiye = 1 blue , 0 red in bag 1..and 9 blue, 5 red in bag 2 ??

aur second wale me bhi 1 red , 0 blue in bag 1 .... and 4 red , 10 blue in bag 2

i think these would give better probablilty as per conditions . ??

edit kar diya :D

@ dk - shame on me !! how did i forget stallone - rambo , rocky :D

haan sahi lag rha hai!!

Suja

A right angled triangle ABC is right angled at B. The point of contact of the incircle with the hypotenuse, divides it, in the ratio 3:2. If the perimeter of the triangle is 36 cm, find the inradius.


sannata kyun hai bhai ?!

a man has 5 red and 10 blue balls . he needs to distribute them in 2 bags such that the
1) probability of drawing red is minimum
2) probability of drawing red is maximum
how should he distribute ? given that no bag can be empty

1)5 red and 9 blue in 1 bag & 1 blue in other
2)5 red in 1 bag and 10 blue in another
????

@kunal Ian Mckellan {Xmen and lotr} & Mike myers {shrek and austin powers}
and maybe Arnold has some trilogy other than terminator !!

kunal v.t Says

i dont have the oa , but i think first case me aisa nahi hona chahiye = 1 blue , 0 red in bag 1..and 9 blue, 1 red in bag 2 ??

total 15 balls hai!! aapne toh 11 hee use kari idhar!

Suja

idea se :
1. B1: 5B,2R B2:5B,3R
2. B1: 5 R , B2:10B

Suja

i dont have the oa , but i think first case me aisa nahi hona chahiye = 1 blue , 0 red in bag 1..and 9 blue, 5 red in bag 2 ??

aur second wale me bhi 1 red , 0 blue in bag 1 .... and 4 red , 10 blue in bag 2

i think these would give better probablilty as per conditions . ??

edit kar diya :D

@ dk - shame on me !! how did i forget stallone - rambo , rocky

noblekalra Says

Consider a function f(k) defined for positive integers k = 1, 2, . The function satisfies the condition , where p is a fraction, i.e. 0 < p < 1. Then f(k) is given by

f(k) = p^k (k=1 to inf) kinda gp. 0

<1

Suja

a man has 5 red and 10 blue balls . he needs to distribute them in 2 bags such that the
1) probability of drawing red is minimum
2) probability of drawing red is maximum
how should he distribute ? given that no bag can be empty

@ dk - bang on bro ! one other name is orlando bloom ( pirates and lotr )
p.s try utilising some post which u have already used as an answer for spamming , this is generally not taken well by the puys u kno .

...
Suja

Consider a function f(k) defined for positive integers k = 1, 2, . The function satisfies the condition , where p is a fraction, i.e. 0 < p < 1. Then f(k) is given by

kunal v.t Says

f(1004) = 1004 -3 = 1001 ... not f(1001)

2 f ko single f mein change kar to diya................

1) 7^11^13^17

We need to find 11^13^17 (mod 4) = (-1)^odd (mod 4) = 3 (mod 4)

So, last digit will be 3

2) 2^1990
Euler's number for 199 is 198

=> 2^198 = 1 (mod 199)
=> 2^1980 = 1 (mod 199)
=> 2^1990 = 2^10 (mod 199)

Now, last digit of 2^1990 and 2^10 are same hence
2^1990 = 2^10 (mod 10)

=> 2^1990 = 2^10 (mod 1990)

sir apne 5 se kyu ni kiya
199 k ilawa..................