The sides of a rhombus ABCD measure 2 cm each
and the difference between two angles is 90 then the area
of the rhombus is:

OX = XY = YP
=> a = b-a = c-b
=> b = 2a & c = a + b = 3a

Now,
Answer = pi* (4-1)*a^2 / pi* (9-4) * a^2 = 3/5

me too 3/5

Ganu02 Says

When the sun ray's inclination from 30 degree to 60 degree,the length of the shadow of a tower decreases by 60m..Find the height of the tower..

is it 30rt3 ???

I just groaned you for this post , was my first groan ( and could have been yours too), but took it back just because we are peer at this thread. Relax Jatin ain't that big thing.


The value of 1.1!+2.2!+3.3!+--------+n.n! is
(a) (n+1)!
(b) (n+1)!+1
(c) (n+1)!-1
(d) none of these

is it C ?

slam Says

This would be R intersection S as an equivalence relation (If I've got the equivalence relation definition correct). Right?

OA :

option A
An equivalence relation is reflexive, symmetric and
transitive.

Suja

P, Q, S and R are points on the circumference of a circle of radius r, such that PQR is an equilateral triangle and PS is a diameter of the circle. What is the perimeter of the quadrilateral PQSR?

Oh my.........
IIM A guy here......we are lucky:cheerio::cheerio:
Sorry for spam.....but couldnt resist.......

I just groaned you for this post , was my first groan ( and could have been yours too), but took it back just because we are peer at this thread. Relax Jatin ain't that big thing.


The value of 1.1!+2.2!+3.3!+--------+n.n! is
(a) (n+1)!
(b) (n+1)!+1
(c) (n+1)!-1
(d) none of these

When the sun ray's inclination from 30 degree to 60 degree,the length of the shadow of a tower decreases by 60m..Find the height of the tower..


Statistics for road use in a certain county show that in the past year, there were 32
accidents per 100,000 miles driven on rural roads and 18 accidents per 100,000 miles
driven on city roads. Combined statistics for both rural and city roads show that there
were 24 accidents per 100,000 miles driven. Let x be the total number of accidents on
rural roads and y be the total number of accidents on city roads. The value of x/y is
(a) 3/2 (b) 4/3 (c) 5/4 (d) 5/3 (e) 7/5

I don't have the OA for both..

slammed

If R = {(1, 1), (2, 2), (1, 2), (2, 1), (3, 3)} and
S = {(1, 1), (2, 2), (2, 3), (3, 2), (3, 3)} are two relations in the
set X = {1, 2, 3}, the incorrect statement is:
(A) R and S are both equivalence relations
(B) R S is an equivalence relations
(C) R^1 S^1 is an equivalence relations
(D) R S is an equivalence relations

This would be R intersection S as an equivalence relation (If I've got the equivalence relation definition correct). Right?

P(x) is a polynomial of degree 998. P(K) = 1/K
for K is integral varying from 1 to 999. Find the value
of P (1001).


a. 1 b. 1001 c.
1/
1001
d.
1/
(1001!)


Suja

Bhai iska OA kya hai ??? Bheja garam ho raha hai :biggrin:Koi approach dedo

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000

if sp is same & the prof-n-loss %ages are same, then we made an overal loss of (L^2/100)%...where L is the prof(or loss) %age...
so here a loss of 2500

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000


In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

1.d)lost more than 2000, c.p. =62,500. lost 2500.
2 me options mil jaate to acha hota...
here's my jugaad ap.
let a and b be number of persons who passed and failed respectively...
xa+yb=za+zb
=>b(y-z)=a(z-x)
=>b=a(z-x)/(y-z)

Edited:

A rectangular floor is fully covered with square tiles of identical size. The tiles on the edges are white and the tiles in the interior are red. The number of the white tiles is the same as the number of red tiles. A possible value of the number of tiles along one edge of the floor is?

OX = XY = YP
=> a = b-a = c-b
=> b = 2a & c = a + b = 3a

Now,
Answer = pi* (4-1)*a^2 / pi* (9-4) * a^2 = 3/5

slammed

If R = {(1, 1), (2, 2), (1, 2), (2, 1), (3, 3)} and
S = {(1, 1), (2, 2), (2, 3), (3, 2), (3, 3)} are two relations in the
set X = {1, 2, 3}, the incorrect statement is:
(A) R and S are both equivalence relations
(B) R S is an equivalence relations
(C) R^1 S^1 is an equivalence relations
(D) R S is an equivalence relations

hmm polynomial ne mujhe bhi sanatte mein dal diya hai !!

1/1001 wale saare galat hein

Three circles A, B and C have a common centre O.
A is the inner circle, B middle circle and C is outer circle. The
radius of the outer circle C, OP cuts the inner circle at X and
middle circle at Y such that OX = XY = YP. The ratio of the
area of the region between the inner and middle circles to
the area of the region between the middle and outer circle
is:
(A)
1/
3 (B)
2/
5
(C)
3/
5 (D)
1/
5

Suja

The Big Bang Theory

assumption pe duniyaa kayam hai.....inner waale ka radius assume kar lo 1
middle waale ka assume karlo 2
outer waale ka assume kar lo 3......
toh uttar aa jayegaa 3/5

Three circles A, B and C have a common centre O.
A is the inner circle, B middle circle and C is outer circle. The
radius of the outer circle C, OP cuts the inner circle at X and
middle circle at Y such that OX = XY = YP. The ratio of the
area of the region between the inner and middle circles to
the area of the region between the middle and outer circle
is:
(A)
1/
3 (B)
2/
5
(C)
3/
5 (D)
1/
5

Suja

The Big Bang Theory

OX = XY = YP
=> a = b-a = c-b
=> b = 2a & c = a + b = 3a

Now,
Answer = pi* (4-1)*a^2 / pi* (9-4) * a^2 = 3/5

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000


In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

1.d)lost more than 2000, c.p. =62,500. lost 2500.
2 me options mil jaate to acha hota...

Itna sannata!! :lookround::lookround:

In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

is it (z-y)/(x-y) ? :lookround:

hmm polynomial ne mujhe bhi sanatte mein dal diya hai !!

1001 wale saare galat hein

Three circles A, B and C have a common centre O.
A is the inner circle, B middle circle and C is outer circle. The
radius of the outer circle C, OP cuts the inner circle at X and
middle circle at Y such that OX = XY = YP. The ratio of the
area of the region between the inner and middle circles to
the area of the region between the middle and outer circle
is:
(A)
1/
3 (B)
2/
5
(C)
3/
5 (D)
1/
5

Suja

The Big Bang Theory

is it 3/5 ??

ratter Says

sannata polynomial ne kar rakha hai!!!!

hmm polynomial ne mujhe bhi sanatte mein dal diya hai !!

1/1001 wale saare galat hein

Three circles A, B and C have a common centre O.
A is the inner circle, B middle circle and C is outer circle. The
radius of the outer circle C, OP cuts the inner circle at X and
middle circle at Y such that OX = XY = YP. The ratio of the
area of the region between the inner and middle circles to
the area of the region between the middle and outer circle
is:
(A)
1/
3 (B)
2/
5
(C)
3/
5 (D)
1/
5

Suja

The Big Bang Theory

Ratter bhai Q sahi hai yaar !! swimming pool ko wedge ki form mein maan rakha hai !! mein toh kisi pool mein gaya nhn aaj tak jismein gaya hun usmein aisa kuch toh nhn tha !! Chalo Internation Pool hoga fir

1 n 18.33 are rite!!

P(x) is a polynomial of degree 998. P(K) = 1/K
for K is integral varying from 1 to 999. Find the value
of P (1001).


a. 1 b. 1001 c.
1/
1001
d.
1/
(1001!)


Suja

Answer in bold!:)

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000

D) is the answer.
Bhai, I am getting loss of 2500.

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000
.

Is it option D)>2000

Itna sannata!! :lookround::lookround:

sannata polynomial ne kar rakha hai!!!!

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000


In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

first ka option d.........


second mein fir jugaad hai saala.........assume x=60
y=30
toh z will be 45.........
now use options.......

aur ussey pehley waale mein 1/1001 lag rahaa hai....

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000


In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

pehele mei 2500 ka loss.......

doosre ka..........100(z-x)/(y-x).............nt sure though..........

Ratter bhai Q sahi hai yaar !! swimming pool ko wedge ki form mein maan rakha hai !! mein toh kisi pool mein gaya nhn aaj tak jismein gaya hun usmein aisa kuch toh nhn tha !! Chalo Internation Pool hoga fir

1 n 18.33 are rite!!

P(x) is a polynomial of degree 998. P(K) = 1/K
for K is integral varying from 1 to 999. Find the value
of P (1001).


a. 1 b. 1001 c.
1/
1001
d.
1/
(1001!)


Suja

Is it 1/1001 ?? Galat ho sakta hai...

DEEPAK MARWAH Says

Sir can u explain volume 48+51=99 Kaise?????

slightly easier way is to take it as a 2 D figure, a rectangle wid sides 10 and .8 m and a rt triangle wid base 10 n ht 1.7 m mounted on it... area =16.5 sq. m
multiply wid breadth to get volume= 16.5 *6=99 cubic m.
=>99000 ltr/90*60=18.33 hrs

Ratter bhai Q sahi hai yaar !! swimming pool ko wedge ki form mein maan rakha hai !! mein toh kisi pool mein gaya nhn aaj tak jismein gaya hun usmein aisa kuch toh nhn tha !! Chalo Internation Pool hoga fir

1 n 18.33 are rite!!

P(x) is a polynomial of degree 998. P(K) = 1/K
for K is integral varying from 1 to 999. Find the value
of P (1001).


a. 1 b. 1001 c.
1/
1001
d.
1/
(1001!)

Suja

Itna sannata!! :lookround::lookround:


Last year Mr Basu bought two scooters. This year
he sold both of them for Rs 30,000 each. On one, he earned
20% profit, and on the other he made a 20% loss. What was
his net profit or loss?
(A) He gained less than Rs 2000
(B) He gained more than Rs 2000
(C) He lost less than Rs 2000
(D) He lost more than Rs 2000


In an examination, the average marks obtained by
students who passed was x%, while the average of those
who failed was y%. The average marks of all students taking
the exam was z%. Find in terms of x, y and z, the percentage
of students taking the exam who failed.

Please please explain all the three questions ??

What is the minimum number of people in a group such that the probability that atleast two of them have b'day on same day is 1?

->Bhai, here it is given that when we select atleast two people, they have their birthday on the same day. For this, we must see that 7 people must be there for each of the days (Sun, Mon, Tue, Wed, Thus, Fri, Sat) + 1 more person who will be born on any of the days. So, a total of 8 people.

What is the minimum no of people in a group such that the b'day of atleast two of them falls on the same date?

->On the same lines as above, we need to have atleast those many people who are born on each of the dates (1,2,3,...,31. We have to take till 31 because the maximum in a month can be 31) which is 31 + 1 more person who can be born on any of the dates. So, 32 people.

What is the minimum number of persons in a grup such that atleast two of them have same b'day?
->ATleast 2 of them have same birthdays means, first take all 366 people (leap year can be the maximum no. of days) and then additional 1 person who can be born on any date. A total of 367. Hope it helps!! (Also hope I am right in my explanation).

DEEPAK MARWAH Says

Sir can u explain volume 48+51=99 Kaise?????

ratter Says

appurv sir volume kaise nikali aapne bata do????

Swiming pool can be broken down in to two pieces. One is a cube of sides 10*6*0.8. And other one is a 3-D triangle of base 1.7, height-10 and breadth-6 giving volume as 1/2*(10*6*1.7). So total = 48 + 51 = 99

pehla waala interesting tha a =1 , b = 2 , c = 3
Answer 1

question 2 . data inadequate lag raha hai.... specially jo log swimming karte hsin unko pakka lagega

GoodKnight Says

is it c. 1 and c. 18.33 ? :lookround:

volume of pool=48+51=99 cubic meter

1 cubic m=1000 lit
99 cubic m=99000lit
so 1100 min or 18.33 hrs............:drinking:

1??
a=1,b=2,c=3 =>6/6=1

Ratter bhai Q sahi hai yaar !! swimming pool ko wedge ki form mein maan rakha hai !! mein toh kisi pool mein gaya nhn aaj tak jismein gaya hun usmein aisa kuch toh nhn tha !! Chalo Internation Pool hoga fir

1 n 18.33 are rite!!

P(x) is a polynomial of degree 998. P(K) = 1/K
for K is integral varying from 1 to 999. Find the value
of P (1001).


a. 1 b. 1001 c.
1/
1001
d.
1/
(1001!)


Suja

ratter Says

appurv sir volume kaise nikali aapne bata do????

bro swimming pool ko do part mei divide kar do, upar cuboid aur neeche prism......upar ka volume 10*6*0.8

neeche prism ka volume= 1/2*(2.5-0.8 )*10*6

wHiTe_HoLe Says

A function f(x,y) is defined as x^2y^2+xy+3 for real (x,y). Find the minimum and maximum possible values of f(x,y).

(xy + 1/2)^2 + 11/4

=> Range is [11/4, inf)

If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11


The length of a swimming pool is 10 m & its width is 6 m. Water is 0.8 m deep at the shallow end
& it is 2.5 m at the deep end. It is to be filled by a water source supplying water at a rate 90 l/min.
The total time taken to file the pool is:
a. 18.6 hrs b. 18 hrs c. 18.33 hrs d. 19 hrs

1 for the first one.

Volume = (1/2)(0.8 + 2.5)*10*6*1000
=> Time taken = 3300*30/90 = 1100 min = 18.33 hrs

ratter Says

appurv sir volume kaise nikali aapne bata do????

bhai shayd aap ko shallow aur deep end ki confoosion hai....
aisaa karoo ki jugaad se karogey toh take avg. of 2.5+.8=3.3/2=1.65
yeh height ho gayi
length ,breadth di hui hai it will be 10*6*1.65

min = 3
max= infinity


If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11

1??
a=1,b=2,c=3 =>6/6=1

volume of pool=48+51=99 cubic meter

1 cubic m=1000 lit
99 cubic m=99000lit
so 1100 min or 18.33 hrs............:drinking:

Sir can u explain volume 48+51=99 Kaise?????

wHiTe_HoLe Says

Yeah, right!!

Please please explain all the three questions ??

What is the minimum number of people in a group such that the probability that atleast two of them have b'day on same day is 1?

What is the minimum no of people in a group such that the b'day of atleast two of them falls on the same date?


What is the minimum number of persons in a grup such that atleast two of them have same b'day?

volume of pool=48+51=99 cubic meter

1 cubic m=1000 lit
99 cubic m=99000lit
so 1100 min or 18.33 hrs............:drinking:

appurv sir volume kaise nikali aapne bata do????

min = 3
max= infinity

GoodKnight Says

[11/4,infinity) ?? :splat:

x^2y^2+xy+3
=(xy+1/2)^2+11/4
Clearly, min=11/4 and max=infinity

min = 3
max= infinity


If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11


The length of a swimming pool is 10 m & its width is 6 m. Water is 0.8 m deep at the shallow end
& it is 2.5 m at the deep end. It is to be filled by a water source supplying water at a rate 90 l/min.
The total time taken to file the pool is:
a. 18.6 hrs b. 18 hrs c. 18.33 hrs d. 19 hrs

volume of pool=48+51=99 cubic meter

1 cubic m=1000 lit
99 cubic m=99000lit
so 1100 min or 18.33 hrs............:drinking:

GoodKnight Says

is it 2/3? :lookround:

I think you're posting this question for a second time (or am I getting a Deja Vu:drinking:)
y=2-3ax
2ax^2+(2-3ax)^2=1
2ax^2+4+9a^2x^2-12ax=1
x^2(2a+9a^2)-12ax+3=0
discrimiant>=0
144a^2-12(2a+9a^2)>=0
144a^2-24a-108a^2>=0
36a^2-24a>=0
12a(3a-2)>=0
aE(-infinity,0]U[2/3,infinity)
Clearly, least positive value is a=2/3

2/3 ?

Suja

ratter Says

yaar 2/3 hoga ... aise questions ke saath options dediya karo yaar!!!!

Sab sahi

min = 3
max= infinity


If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11


The length of a swimming pool is 10 m & its width is 6 m. Water is 0.8 m deep at the shallow end
& it is 2.5 m at the deep end. It is to be filled by a water source supplying water at a rate 90 l/min.
The total time taken to file the pool is:
a. 18.6 hrs b. 18 hrs c. 18.33 hrs d. 19 hrs

pehla waala interesting tha a =1 , b = 2 , c = 3
Answer 1

question 2 . data inadequate lag raha hai.... specially jo log swimming karte hsin unko pakka lagega

min = 3
max= infinity


If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11


The length of a swimming pool is 10 m & its width is 6 m. Water is 0.8 m deep at the shallow end
& it is 2.5 m at the deep end. It is to be filled by a water source supplying water at a rate 90 l/min.
The total time taken to file the pool is:
a. 18.6 hrs b. 18 hrs c. 18.33 hrs d. 19 hrs

is it c. 1 and c. 18.33 ?

wHiTe_HoLe Says

A function f(x,y) is defined as x^2y^2+xy+3 for real (x,y). Find the minimum and maximum possible values of f(x,y).

[11/4,infinity) ??

wHiTe_HoLe Says

A function f(x,y) is defined as x^2y^2+xy+3 for real (x,y). Find the minimum and maximum possible values of f(x,y).

min = 3
max= infinity


If a, b, c are distinct real numbers from 1 to 9. The minimum value of
abc/a + b + c

is:
a. 9 b. 10 c. 1 d. 11


The length of a swimming pool is 10 m & its width is 6 m. Water is 0.8 m deep at the shallow end
& it is 2.5 m at the deep end. It is to be filled by a water source supplying water at a rate 90 l/min.
The total time taken to file the pool is:
a. 18.6 hrs b. 18 hrs c. 18.33 hrs d. 19 hrs

A function f(x,y) is defined as x^2y^2+xy+3 for real (x,y). Find the minimum and maximum possible values of f(x,y).

Eight distinct natural numbers are written in an ascending order as a, b, c, d, e, f, g and h. Given that a, c and f are in a Arithmetic Progression and b, d and h are in a Geometric Progression. It is also known that h 16.

16. If h = 12, then how many distinct sequences of these 8 natural numbers are possible?
A. 3 B. 4 C. 6 D. 7 E. 9

7........

h=12=2^2*3
for b and d to be natural nos, common ratio should be a natural no, only possible seems r=2
So, b=3,d=6,h=12
Now a,c and f are in AP
a=1 or 2,c=4 or 5, f=8,9 or 10
(a,c,f)==(1,5,9),(2,5,8 )
(1,5,9)==(e,g)==2*2=4
(2,5,8 )==(e,g)==1*3=3
Total=7

praks1529 Says

What is the minimum possible positive value of a constant a for which the system of equations 3ax + y = 2 and 2ax^2 + y^2 = 1 has a real solution?

yaar 2/3 hoga ... aise questions ke saath options dediya karo yaar!!!!

praks1529 Says

What is the minimum possible positive value of a constant a for which the system of equations 3ax + y = 2 and 2ax^2 + y^2 = 1 has a real solution?

2/3 ?

Suja

praks1529 Says

What is the minimum possible positive value of a constant a for which the system of equations 3ax + y = 2 and 2ax^2 + y^2 = 1 has a real solution?

I think you're posting this question for a second time (or am I getting a Deja Vu:drinking:)
y=2-3ax
2ax^2+(2-3ax)^2=1
2ax^2+4+9a^2x^2-12ax=1
x^2(2a+9a^2)-12ax+3=0
discrimiant>=0
144a^2-12(2a+9a^2)>=0
144a^2-24a-108a^2>=0
36a^2-24a>=0
12a(3a-2)>=0
aE(-infinity,0]U[2/3,infinity)
Clearly, least positive value is a=2/3

Eight distinct natural numbers are written in an ascending order as a, b, c, d, e, f, g and h. Given that a, c and f are in a Arithmetic Progression and b, d and h are in a Geometric Progression. It is also known that h 16.

16. If h = 12, then how many distinct sequences of these 8 natural numbers are possible?
A. 3 B. 4 C. 6 D. 7 E. 9

7........

praks1529 Says

What is the minimum possible positive value of a constant a for which the system of equations 3ax + y = 2 and 2ax^2 + y^2 = 1 has a real solution?

is it 2/3?

f(x) = (x^-1)(x^-4)

360 hai maalik amswer iska..

F(p)= (p-1)(p-2)(p+1)(p+2).
p is always of the form 6k (+/-) 1
case1: If p= 6k+1. Then F(p)= (6k-1)(6k)(6k+2)(6k+3). Product of first two terms are divisible by 6 and product of next two terms is divisible by 12
case2 :If p= 6k-1. Then F(p)= (6k-3)(6k-2)(6k)(6k+1). Product of first two terms are divisible by 12 and product of next two terms is divisible by 6.
Hence (p-1)(p-2)(p+1)(p+2) is always divisible by 12*6= 72. Further (p-1)(p-2)(p+1)(p+2) is also divisible by 5. Hence total product is divisible by 72*5 = 360

right right

ratter Says

would pick option E.

DEEPAK MARWAH Says

I think it should be E

corrrrrreccttt !!!!!!!!!!!!

What is the minimum possible positive value of a constant a for which the system of equations 3ax + y = 2 and 2ax^2 + y^2 = 1 has a real solution?

In a 100 m straight tunnel AB made on a river, boat X enters from end A and boat Y enters from the opposite end B at the same time. There is a safety point O inside the tunnel at which boat Y should reach before boat X to avoid collision. The speed of boat X, boat Y and the stream is 60 m/s, 30 m/s and 10 m/ s respectively. Find the minimum possible distance OA.
A. 77.78 m B. 63.79 m C. 59.62 m D. 52.48 m E. 55.56 m

I think it should be E

In a 100 m straight tunnel AB made on a river, boat X enters from end A and boat Y enters from the opposite end B at the same time. There is a safety point O inside the tunnel at which boat Y should reach before boat X to avoid collision. The speed of boat X, boat Y and the stream is 60 m/s, 30 m/s and 10 m/ s respectively. Find the minimum possible distance OA.
A. 77.78 m B. 63.79 m C. 59.62 m D. 52.48 m E. 55.56 m

would pick option E.

Eight distinct natural numbers are written in an ascending order as a, b, c, d, e, f, g and h. Given that a, c and f are in a Arithmetic Progression and b, d and h are in a Geometric Progression. It is also known that h 16.

16. If h = 12, then how many distinct sequences of these 8 natural numbers are possible?
A. 3 B. 4 C. 6 D. 7 E. 9

17. If h a = 15, then how many distinct sequences of these 8 natural numbers are possible?
A. 16 B. 14 C. 9 D. 10 E. Cannot be determined

A function f(x) is defined as for every m > n such that f(m) > f(n).
It is also known that f(3) * f(4) * f(5) * f(6) < 0 and f(4) - |f(7)| -|f( > 0.

Which of the following statements is true?
A. f(5)| is always greater than both |f(7)| and f(
B. f(x) = 0 has a solution for x (3, 4)
C. f(x) = 0 has a solution for x (5, 6) D. Both (A) and (C) are correct. E. Both (A) and (B) are correct.

In a 100 m straight tunnel AB made on a river, boat X enters from end A and boat Y enters from the opposite end B at the same time. There is a safety point O inside the tunnel at which boat Y should reach before boat X to avoid collision. The speed of boat X, boat Y and the stream is 60 m/s, 30 m/s and 10 m/ s respectively. Find the minimum possible distance OA.
A. 77.78 m B. 63.79 m C. 59.62 m D. 52.48 m E. 55.56 m