@Brooklyn said:

@JS-M : acha thik hai, den hw did u assign wt to D ???

coz BDC or smthng lyk that hai nhi. How did u use AB=AD to assign wt???

@JS-M : acha thik hai, den hw did u assign wt to D ???

@Brooklyn said:

yaar q solve kaise kiye tune using mass point??? q mei locha hai!!!

look it says D is on AB such that AB=AD , either D=B or it isnt possible!!!

@JS-M said:

1/4BC ?? plz lemme knw if it z correct....thanx

@JS-M bhai mene ab notice kia mera to question hi incomplete tha... apne answer kise nikal lia......

Would like to contribute to that. Mass point geometry ka ek badhiya pdf hai mere pass. Attached below.

@Brooklyn said:

@freedom_fighter :smjh aaye to meko bhi btana:

en.wikipedia.org/wiki/Mass_point_geometry

@freedom_fighter :smjh aaye to meko bhi btana:

@freedom_fighter :smjh aaye tto do temme :

@JS-M Pls share d link here bro...

@JS-M : i read it palle nhi pada mere !!

@JS-M said:

yr i used Mass point geomety suggested by Micky dude...

@freedom_fighter said:

@JS-M Yes correct...pls explain

@Brooklyn said:

bhai appraoch btao

@priyaj9090 is it 72

koi IMS ka student hai jiske pass Cat Intesive workshop module (IMS Learning resources)hai
ya koi link jahan se geometry ka workshop mil jaye?

@JS-M said:

1/4BC ?? plz lemme knw if it z correct....thanx

@JS-M Yes correct...pls explain

@freedom_fighter said:

Q -->ABC is a triangle. D is a point on AB such that AD=AB and E is a point on AC such that AE=1/4 AC. then DE=? a) 1/4BC b) 1/3BC c) 2BC d) None of these

Q -->ABC is a triangle. D is a point on AB such that AD=AB and E is a point on AC such that AE=1/4 AC. then DE=? a) 1/4BC b) 1/3BC c) 2BC d) None of these

@pooja888 Yeah. Thanks!

@thePANDA said: I literally suck at geometry. I guess I would not have done even 1 question correctly (In my entire life). Do not know where do I start from. Can I give this section a total miss? Or shall I practice 1 chapter. Because I don't think I'll be able to manage all of it within a month and given that I also have to prepare well in other topics.. Please suggest puys.

@scrabbler thnx!!

@ForSure said:

@ekamsoul :can you explain

For a given perimeter , Area of a triangle will be maximum when all of its sides are equal.

@ekamsoul :can you explain

I literally suck at geometry. I guess I would not have done even 1 question correctly (In my entire life). Do not know where do I start from. Can I give this section a total miss? Or shall I practice 1 chapter. Because I don't think I'll be able to manage all of it within a month and given that I also have to prepare well in other topics.. Please suggest puys.

b.36root(3)

@ForSure said: The perimeter of an isosceles triangle is 36cm.Find the maximum possible area it can have

a.27root(3)

b.36root(3)

c.42root(3)

d.48root(3)

The perimeter of an isosceles triangle is 36cm.Find the maximum possible area it can have

@priyaj9090 said: the perimeter of a sector of circle of radius 42cm is 108 cm.find the area of sector

the perimeter of a sector of circle of radius 42cm is 108 cm.find the area of sector

how to find the area of sector when central angle is not given??????

@blade014 said: As AD is angle bisector of BAC, BAD=DAC=(180-3x)/2

now AB=DC, so ACB=DAC

or, x=(180-3x)/2

x=36

now, BAC= 180-3x = 180-108 = 72

As AD is angle bisector of BAC, BAD=DAC=(180-3x)/2

@mickym said:

wat is ur ans & approach??

@blade014 said: 2x + x + A= 180

A= 180-3x

AB=DC then, x shud be equal to A/2 or 90 - 3x/2

solve and we get 36

now as x=36, A= 180 - 108 = 72

2x + x + A= 180

@deedeedudu said:

I meant ans kya hai?

@mickym said:

????? OA ?????

@blade014 said:

36 hoga kya OA?

@deedeedudu said:

OA kya hai?

@deedeedudu said:

Is it none?

@mickym said: ABC is a triangle given that angle B is equal to 2x and angle C is equal to x. AD is the angle bisector of angle A on line BC.Given that side AB=DC find angle BAC.

1) 36 2) 72 3) 144 4) none

@mickym said:

Kaise bhai??

@deedeedudu said:

I'm getting 102.8

@mickym said:

wat is ur ans & approach??

@deedeedudu said:

Is it none?

@mickym said: ABC is a triangle given that angle B is equal to 2x and angle C is equal to x. AD is the angle bisector of angle A on line BC.Given that side AB=DC find angle BAC.

1) 36 2) 72 3) 144 4) none

ABC is a triangle given that angle B is equal to 2x and angle C is equal to x. AD is the angle bisector of angle A on line BC.Given that side AB=DC find angle BAC.

hi, my cat slot is on 15th oct, only 35 days left, what can be done in this time, to do some thing better in geometry section pls advice. I am writing mock in CL. analyzing the mocks, n practising previous yr CAT papers. ATB to all.

@Lionheartcool said:

@mickym Oh yeah.. they cannot meet if that is the diameter. So is something missing in the quetion?? Does a solution exist for that problem??

@mickym Oh yeah.. they cannot meet if that is the diameter. So is something missing in the quetion?? Does a solution exist for that problem??

@Lionheartcool said:

@mickym

Assuming that the tangents meet the bigger circle at the ends of its diameter, Can you please share the approach of the problem?

@Lionheartcool said:

@mickym Is it 3?

@mickym

@MassiveDynamic in an equilateral triangle ABC,a point P is there such that PA^2=PB^2+PC^2.find angle BPC

@mickym Is it 3?

ABCD is a square whose area is ‘a²’ sq. units. ABE is a equilateral triangle as shown in the diagram. Find the area of ∆ AEF?

@scrabbler said:

I think it should be (3sqrt5 + 5) : 4...since R = sqrt5/2 and r = (2 + 1 - sqrt5)/2 regardsscrabbler

@mickym said:

∆ABC inscribed in a circle C, has its sides in the ratio 1 : 2 : √5. Find the ratio of the radius of the incircle of ∆ABC to that of its circumcircle?