I. a is divisible by 3.

II. (b+1) is divisible by 4.

The correct answer it says is II, how??

If x^a = y^b > z^c, is x = y > z?

I. a = b > c

II. a = b = c

The answer is III, how??

If n is a natural number, is n ! < ^x ?

I. n is an even numbe...

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I. a is divisible by 3.

II. (b+1) is divisible by 4.

The correct answer it says is II, how??

If x^a = y^b > z^c, is x = y > z?

I. a = b > c

II. a = b = c

The answer is III, how??

If n is a natural number, is n ! < ^x ?

I. n is an even numbe...

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2x+2y<=40

that is x+y<=20

(5+15=20 , 8+12=20..... )

so nothing can be said abt the value of x

Statement 2 -

x-2y>=20

(30-2*5=20,40-2*9=22)

so nothing can be said abt the value of x

now combining both the statements .....

we know that both x,y are non n...

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Bharathi.

ab = 10a + b

10a is even.

b+1 is div by 4 --> b is odd.

so even + odd = odd

So only ii is enough to answer

2

i think the ans is III...i.e the Q can be answered by using both the statements together.

cos...

(a) implies tat '#' cud b '+' or '-'

(b) implies tat '#' cud b '+' or '*'

so no definite ans considering the statements individually,BUT if we combine them

then '#' sign ...

a.2#0 =2

b.2#2 = 4.

:) Bharathi

Thanks for this tip.

When dealing with powers, you should see a few things.

(i) The sign of those numbers

(ii) whether the powers are odd or even

(i...

i think the answer 2 the first question shud b choice 3.. from second option we get b is an odd number.. but we don't know anthg abt a.. it can even b a frction.. from the fact that a is a multiple of 3, we know that a is also an integer. so we can safely say that ab will b odd...

How come both the statements can hold true at the same time !!

take a=3k

b is odd as (b+1) divisible by 4

so No.=ab= 3bk=Odd no. x k

Now depending on k the No. wud change so it shud b IV

What do u say about a=12

I think the correct answer is not II. it shud be III

a is divisible by 3, so it is an odd number.

(b+1) is divisible by 4,so (b+1) is a even number and hence b an odd number

As both a and b are odd numbers their product can never be an even number. therefore ab is an odd numbe...