# Cracking Nishit Sinha Problems on Quant LA and DI , A step more to bell the Cat.Quantitative Report

This is a thread dedicated entirely to the problems faced by CAT Aspirants solving Nishit Sinha's Quant and LA/DI Book.
This thread will help CAt aspirants to understand the Basic concepts thoroughly for those who are using the book and will also help others who are preparing for various MBA e...
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Ahuramazda i have just started preparing for CAT and simultaneously .... 01 Jun '13.
saginav Free webinar From Mr. Nishit Sinha: on ' Art of problem .... 13 Aug '13.
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could you plz help me with this ???
"
SP 0f 1000 gms = x * 1000/950
profit = 50 *x /950
% profit = 5 5/19% :grin:
"
yes sure
3
CP 0f 1000gms = x
SP of 950 gms = x
SP 0f 1000 gms = x * 1000/950
profit = 50 *x /950
% profit = 5 5/19%
Q-23 : Ans - A
Please tell me if it is correct or not ?
Could you help me with rest of other 4 problems ??:)
Time taken by Shramjivi=320 min
Let total distance= D
so, speed of shramjivi Vs=D/320
Magadh starts 22 min before Shramjivi.
So, distance covered by magadh in this duration = 22*D/288
Now let after 't' min both the trains ...
The 22nd problem,
after disc, SP = 0.9MP
MP = SP/0.9
1.17CP = 0.9MP = SP
MP = 1.17CP/.9
Profit% =( (MP-CP)/CP)*100
= 30 %(MP = 1.17CP/0.9):)
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Hi,
The 4th problem,
CP = 375;
SP=0.8*375, as it is sold at a loss of 20%.
CP as % of its SP = (375 / (0.8*375))*100 = 125%
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No, no I do not have the actual answer. Saw your approach anf followed it..thanks!!
actually i guess i did a mistake in step:
9.48 am + 2hrs 42 mins -> 12.54 am
it shud b 12.30 am
so ur approach is also right.
do u hav the actual answer of this question?
PFA,
Plz help me out with detail explanation , i knw the answer , interested in explanation , so i come to knw where i am wrong..
TIA.:nono:
distance left = (133/3)
therefore time when they will meet = (133/(3*(10+9)))
where 10+9 = relative speed
they will meet after 2 hrs 20 mins after shramjivi starts off
therefore at 12:30
10:10 + 2hrs 20 mins...Am I correct plzz tell
hey incognito,
According to me,
Speed of magadh = 10 km/hr
Speed of shramjivi = 9 Km/hr
Therefore total distance already travelled by magadh = 10 * 11/30 = 11/3
Distance left = 48 - (11/3)
The circumference of circle is 22 units
speeds A = 4 units/min
B = 7 units/min
so, if A travels x units before meeting,
(x/4) = (22-x)/7
x = 8
so they will meet after 2mins, and rest for half min
now there speeds get doubled, so now they will meet at hal...
ok got it...because time taken = 16/3 and 24/5 hrs. So for easier calculations LCM of 16 and 24
why did you take LCM of 16 and 24?
my take:
Let the distance between Patna & New Delhi be 48 km (LCM of 16 and 24 )
the time taken by Shramjeevi to reach New Delhi : 5 hrs 20 mins
the time taken by Magadh to reach Patna : 4 hrs 48 mins
so speed of Shramjeevi = 48 / (5+(20/60)) = 9 km/hr
speed of Magadh = 48 ...
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Moderate problem of Time,Distance ,Speed Q(2
Shramjeevi Express leaves Patna for New Delhi at 10:10 am and reaches New Delhi at 3:30 p.m. Magadh Express leaves New Delhi at 9:48 a.m. and reaches Patna at 2:36 p.m.If routes of both the trains are the same, then at what time will the trains mee...
Two persons A and B are standing diametrically opposite on a circular track of radius 3.5 units. They start running in an opposite direction on the circular track with speeds 4 units/min and 7 units/min resp. on meetin each other they take rest of half minute and start running with twice the orgi...