E is a set of consecutive even integers.what is there standard deviations

1. median is 23
2. range is 42.

Help

My answer is "C" . what you guys say ?

My answer : C

as (1) gives whether the number of terms are even or odd....also the mid terms
and (2) range gives the number of terms. hence the whole list.

IS N= 1 ?

1 . N| = 4N-6
2. |N < 4N

help

(C) both together are sufficient.

as 1 gives two values of N, and 2) tells that N is positive.

Ans: 1 alone is sufficient..

Solution: as LCM of fractions = LCM of numerator/GCF of denominators

given: LCM of x/y & 1/3 is 6
hence, x=6 & y=1


P.S : Anybody please correct , if its wrong.

Can i have ans for below question ?
In the fraction x/y, where x and y are positive integers, what is the value of y?
(1) The LCM of x/y and 1/3 is 6. (2) x = 1

X and Y are single digit positive interers.

IS X+Y multiple of 6 ?

1. X+4Y is even
2. YX ( y is tenth digit and x is ones digit) is divisible by 3


Solution : second statement is alone insufficient.....

for X+Y=6x i.e 6,12, 18

Using Hit and trial method, if X=9, Y=3
for (1) X+4Y is not even.
(2) YX = 39, multiple of 3
I tried other combinations also , all satifying.

gmatgmat40 Says

Well now i think your previous reply was . correct. just think of any set of numbers of "say positive" ( thats needed) even integers with range 42 you should have same SD ? isnt it

C is the correct answer IMO

For caculating SD we NEED the no of elements in the set, that is why we need both statements.

For eg,
E1= {20,22,24,26} & E2={18,20,22,24,26,28}, both have median as 23.

E1= {0,2,4,.....38,40,42} & E2={2,4,6,...,38,40,42,44}, both have a range of 42.

But when we combine both, we get the Set,
E = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44} or a similar set E' = {0,2,4..........42}
With a median of 23 and Range of 42. And we can calculate the SD.

only A is sufficient

sorry .. misread the question .. as there is no number of terms in the question , we need median as well

so OA is C)

Well now i think your previous reply was . correct. just think of any set of numbers of "say positive" ( thats needed) even integers with range 42 you should have same SD ? isnt it

IS N= 1 ?

1 . N| = 4N-6
2. |N < 4N

help

gmatgmat40 Says

How to find SD with only range ?

sorry .. misread the question .. as there is no number of terms in the question , we need median as well

so OA is C)

i think its B

1) doesnt say anything
2) we can find SD by range

How to find SD with only range ?

X and Y are single digit positive interers.

IS X+Y multiple of 6 ?

1. X+4Y is even
2. YX ( y is tenth digit and x is ones digit) is divisible by 3

Help

E is a set of consecutive even integers.what is there standard deviations

1. median is 23
2. range is 42.

Help

My answer is "C" . what you guys say ?

E is a set of consecutive even integers.what is there standard deviations

1. median is 23
2. range is 42.

Help

My answer is "C" . what you guys say ?

i think its B

1) doesnt say anything
2) we can find SD by range

E is a set of consecutive even integers.what is there standard deviations

1. median is 23
2. range is 42.

Help

My answer is "C" . what you guys say ?

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.

(1) as diag's are perpendicular, as in case of an rhombus, a is sufficient
(2) as four sides are equal its an square. & every square is an rhombus. So sufficient.

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.


Here.. The differentiator between a square and rhombus would be the diagonals..
The Diagonals of a square are equal and bisect each other at right angles.
The Diagonals of a rhombus are not equal and bisect each other at right angles.

So both the statements are not sufficient..

great explanation ! thanks

DS: numbers greater than 30 : GMAT Data Sufficiency (DS)

If the average (arithmetic mean) of 4 different numbers is 30, how many of the numbers are greater than 30?

(a) None of the 4 numbers is greater than 60.
(b) 2 of the 4 numbers are 9 and 10, respectively.



now the solution of this Q is given as C (this is OA) but i was thinking that the Q says average of 4 numbers and not average of 4 POSITIVE numbers.....
i can say rest of the 2numbers be +1000 and -800 something also... just to make the average come to 30.
shouldnt the answer be E?

is OA debatable in this case or is it an unsaid rule in gmat that all the average Qs would be positive only?

Lets analyse:

Statement 1:
none of the numbers are >60
cud be 59, 59, 59 and one -ve => 3 numbers above 30
cud be 33 and 29,29,29 => 1 no. above 30

Not conclusive

Statement 2:
two numbers are 9 and 10
others cud be anything from -infinity to +infinity, just taht avg has to come down to 30

Not conclusive


Statement 1+ statement 2:
sum of remaining 2 numbers = 30X4 - (10+9) = 101
since no numebr is greater than 60.
both the number have to be greater than 30 to meet the criteria

Ans: both statemnets together are sufficient

DS: numbers greater than 30 : GMAT Data Sufficiency (DS)

If the average (arithmetic mean) of 4 different numbers is 30, how many of the numbers are greater than 30?

(a) None of the 4 numbers is greater than 60.
(b) 2 of the 4 numbers are 9 and 10, respectively.



now the solution of this Q is given as C (this is OA) but i was thinking that the Q says average of 4 numbers and not average of 4 POSITIVE numbers.....
i can say rest of the 2numbers be +1000 and -800 something also... just to make the average come to 30.
shouldnt the answer be E?

is OA debatable in this case or is it an unsaid rule in gmat that all the average Qs would be positive only?

the 2nd statement suggest 8 are not students which mean the balance may or may not be. here u can find probability of other 2 to be student and then multiply with the probability of finding the women among the total flats as student.
this should give u def answer.
hence each statement alone will be sufficient.

Hi, need help in this Q:

A total of 10 women and 20 men reside in the 30 flats that are in a certain building, one person to each flat. if a person is to select one
of the flat at random, what is the probability that the resident of the
flat selected will be a woman who is a student?

(1) Of the women, 6 are students.
(2) Of the women, 8 are not students

i think the answer should be A or statement 1alone as i know how many are students. rest of the 4 can be cook, teacher, college kid, grandma; BUT 6are students for sure.


now the answer is given as D (each statement alone can do)

now where am i wrong ? please correct my approach

You have a point....in statement II it is given that 8 are not students...the rest 2 need not be students...
What is the source of the question?

i found it in some 1000DS pdf, the Qs quality is good

You have a point....in statement II it is given that 8 are not students...the rest 2 need not be students...
What is the source of the question?

Hi, need help in this Q:

A total of 10 women and 20 men reside in the 30 flats that are in a certain building, one person to each flat. if a person is to select one
of the flat at random, what is the probability that the resident of the
flat selected will be a woman who is a student?

(1) Of the women, 6 are students.
(2) Of the women, 8 are not students

i think the answer should be A or statement 1alone as i know how many are students. rest of the 4 can be cook, teacher, college kid, grandma; BUT 6are students for sure.


now the answer is given as D (each statement alone can do)

now where am i wrong ? please correct my approach

Question no 43 in DS in OG12. I am not getting the explanation. Can some one help?

The question is:

What is the tenths digit in the decimal representation of a certain number?
1) The number is less than 1/3
2) the number is greater than 1/4

Answer E, Both statements together are not sufficient.

Explanation:
1) Since the number is less that 1/3, the tenths digit can be 0,1,2, or 3; NOT sufficient
2)Since the number is greater than 1/4, the tenths digit can be 2,3,4,..,9; NOT sufficient.
From 1 and 2 taken together, the number, n, is greater than 1/4 but less than 1/3. The tenths digit can be 2 or 3.

Please help me understand how do I get to know what are the tenth digits for all the number less than 1/3 and greater than 1/4 .

Thanks

Tenths digit= the digit right after the decimal in a two-digit decimal number.
Eg. 7 is the tenths digit in 6.72
Here,
the no. is less than 1/3(0.33)...so, it may be anywhere between 0 and 0.32..but we cannot pinpoint which one, so we cannot say with certainty what is the tenth digit..
Similarly, it is greater than 0.25..so it can be any no. b/w 0.26 to infinity (infact, 0.2500001 to infinity)..again, we cannot say the precise value of the tenths digit, because the number has not been pinpointed-only it's range has been given.
BOTH TOGETHER: The no. is between 0.25 and 0.3333, but again, it's range has been provided, the no. hasn't been pinpointed, so we can't say its tenth digit with certainty..hence the question can't be answered

Hope this helped!

Question no 43 in DS in OG12. I am not getting the explanation. Can some one help?

The question is:

What is the tenths digit in the decimal representation of a certain number?
1) The number is less than 1/3
2) the number is greater than 1/4

Answer E, Both statements together are not sufficient.

Explanation:
1) Since the number is less that 1/3, the tenths digit can be 0,1,2, or 3; NOT sufficient
2)Since the number is greater than 1/4, the tenths digit can be 2,3,4,..,9; NOT sufficient.
From 1 and 2 taken together, the number, n, is greater than 1/4 but less than 1/3. The tenths digit can be 2 or 3.

Please help me understand how do I get to know what are the tenth digits for all the number less than 1/3 and greater than 1/4 .

Thanks

Yes...but a square is also a type of rhombus...
Rhombus is the superset and squares are a subset of it....because any square will always have the properties of a rhombus (viz. opposite sides equal and parallel,adjacent sides equal)...in addition, squares have few additional properties of their own (perpendicular sides)....so all squares are necessarily a rhombus, but a rhombus need not be a square...

Plz correct if wrong!

IMHO,
D....each statement alone is sufficient.

How? Statement 2 may be a square as well. right?

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.

IMHO,
D....each statement alone is sufficient.

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.

IMO E

for distance to be equal, following eq'n must be satisfied,
r^2 + s^2 = u^2 + v^2
Clearly op A alone is insufficient as no info of "u" and "V" is given
Op B again alone insufficient as the eq'n, u+v= 2-(r+s), gives no information

if u combine both the options then u get u+v =1, now one may think that
as u + v =1
and r + s =1,
so the necessary condition r^2 + s^2 = u^2 + v^2 will be fulfilled, BUT its NOT TRUE
for ex u = 1/2 and v = 1/2 and r = 2/3 and s = 1/3
so here,
u + v =1
and r + s =1,

But r^2 + s^2 NOT EQUAL TO u^2 + v^2

while if u make all the coordinates equal to 1/2 then the above condition will satisfy,

so u didn't get any definite answer, hence E

take a case of
R = 0 and S = 1
U = 1, V = 0

R= 2/3 S = 1/3
U = 1/3 V = 2/3


So it must be E

Ques : If n + 5 = 5, what is the value of n?
(1) n^2 is not equal to 0.
(2) n^2 + 10n = 0
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient

IMHO : D

But OA is A.

Please explain.

According to what u have asked, below is the solution :
n+5 = 5
=> n=0

Since the statement given itself gives u a definite value of n as 0. So no need of seeing the given statements.

I think that you forgot to put MOD sign to the LHS of given equation. it shud be n+5| = 5.

Then the solution will be as below

Given : |n+5 = 5
=> n = 0 or -10

Statement 1 : n^2 != 0
=> n!=0
=>n=-10 (only 0 and -10 are to be checked) - Sufficient

Statement 2 : n(n+10) = 0
=> n= 0 or -10
No definite value of n, hence Not Sufficient.
So from given equation and statement 1 we get n=0. So, Option A.

Here is how I worked it out:

L+M+H = 444 ==> sum of the weights of 3 persons.

Statement 1) L = 120
so,M+H = 324, M = 121 , H= 203 or M= 150 , H= 174.
So statement 1 is insuff.

Statement 2) M-L = H-M
2M = H+L

2M = 444-M

3M = 444.
So, M = 148
Statement 2 alone is suff.


I would go with option B

-Deepak.

The ans is B only, for information, there is trap that it can solved by both the option, like all three are in AP so u can simply use the AP formula : n/2((2a+(n-1)d))
nd get the value of d.

Here is how I worked it out:

L+M+H = 444 ==> sum of the weights of 3 persons.

Statement 1) L = 120
so,M+H = 324, M = 121 , H= 203 or M= 150 , H= 174.
So statement 1 is insuff.

Statement 2) M-L = H-M
2M = H+L

2M = 444-M

3M = 444.
So, M = 148
Statement 2 alone is suff.


I would go with option B

-Deepak.

As a rule, In consecutive integers or equally spaced integers, Mean = Median. Remembering this might save us few precious minutes :-P.
Thing to note here is that the reverse is not true (If mean=median, then it may or may not be a series of consecutive integers or equally spaced integers).

Cheerz,
Ravi.

absolutely right. the ans is B.
The source of this q is princeton online test
Great job Deepak

The average weight of three people is 148 pounds. If none of the three people weighs the same, what is the weight of the middle person?

(1) The lightest persons weight is 120 pounds.
(2) The difference between the weights of the lightest person and the middle person is the same as the difference between the weights of the middle and heaviest person.

Here is how I worked it out:

L+M+H = 444 ==> sum of the weights of 3 persons.

Statement 1) L = 120
so,M+H = 324, M = 121 , H= 203 or M= 150 , H= 174.
So statement 1 is insuff.

Statement 2) M-L = H-M
2M = H+L

2M = 444-M

3M = 444.
So, M = 148
Statement 2 alone is suff.


I would go with option B

-Deepak.

anir4187 Says

avg weight is 148 (three different weights - no need of options also to answer the question , it should be 148 only)

I beg to differ with you on this.Let me quote an example:

lets take 3 diff nos :3,7,8
Avg = 6 but the avg is not present in the series itself.So,simply by stating the avg we cannot deduce the number(s).

If you have diff opinion pls let me know

-Deepak.

The average weight of three people is 148 pounds. If none of the three people weighs the same, what is the weight of the middle person?

(1) The lightest persons weight is 120 pounds.
(2) The difference between the weights of the lightest person and the middle person is the same as the difference between the weights of the middle and heaviest person.

avg weight is 148 (three different weights - no need of options also to answer the question , it should be 148 only)

The average weight of three people is 148 pounds. If none of the three people weighs the same, what is the weight of the middle person?

(1) The lightest person's weight is 120 pounds.
(2) The difference between the weights of the lightest person and the middle person is the same as the difference between the weights of the middle and heaviest person.

Ques : If n + 5 = 5, what is the value of n?
(1) n^2 is not equal to 0.
(2) n^2 + 10n = 0
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient

IMHO : D

But OA is A.

Please explain.

.........duplicate post.........

This is going to be a long one !!

1.
5x+3y<10 , is given, we need to check if 4x+4y<10 or x+y<2.5

Stmnt 1, x<1
say x=0.9
4.5+3y<10
3y<5.5, or y<1.833
Thus x+y is not necessarily <2.5, So we cannot answer the ques based on this statement alone. Insufficient.

Stmnt 2, 11x<10, x<0.91
Similar to Stmnt 1, assume x=0.9, again, this statement is also Insufficient.

Combining both the statements,
x<1 and x<0.91, we can take x<0.91, which essentially means Stmnt 2 all over again. Insufficient.

Thus, E, cannot be answered using both statements together.

2.
See the attached image. Sorry for the bad handwriting

3.
Let d= abc.xyz
question: is y>5

Stmnt 1: Tenth digit of 10d is 7
10d = abcx.yz, now for 10d, tenth digit is y, and since y=7,
this statement alone is Sufficient.

Stmnt 2: Thousand digit of d/10 is 7
d/10 = ab.cxyz, and the thousandth digit is again y, so,
this statement alone is also Sufficient.

4.

Options: Bio, Comics, Novels
To calculate the number of combinations we will need the number of books in each category.

Stmnt 1: 4 biology and 3 comic books
No. of Novels is not mentioned, Not Sufficient.

Stmnt 2: 7 novels
No. of Bio and Comic books is not available, Not Sufficient

Combine both Stmnts: 4 Bio, 3 Comic and 7 Novels,
We can easily calculate the total number of possible combinations.
Both stmnts together, Sufficient.

Just a suggestion, maybe in the future you could post just the questions and not the answers, makes it more fun !!

Hi. i need some explanations for the questions below which i could not understand.

**************************************************
Q1:
At a certain store, each notepad costs $X and each marker costs $Y. $10 is enough to buy 5 notepads and 3 markers. Is $10 enough to but 4 notepads and 4 markers?
A: Each notepad costs less than $1.
B: $10 is enough to buy 11 notepads.
Answer: Both statements together are not sufficient.
**************************************************
Q2:
Number of points a circle can intersect a triangle?
A: 2 and 6
B: 4 and 6
C: 1, 2, 3 and 6
D: 1, 2, 3, 4 and 6
E: 1, 2, 3, 4, 5 and 6
Answer: E
********************************************************************************
Q3:
Is the 100th digit of decimal d>5?
A: Tenth digit of 10d is 7.
B: Thousand digit of d/10 is 7.
Asnwer: Either statement alone is suffiecient.
*********************************************************************************
Q4:
A person is to select books for vacation. He can select books from biology, comics and novels. How many combinations of books are possible?
A: He has 4 biology and 3 comic books
B: He has 7 novels
Answer: Both statements together are sufficient.
***********************************************************************************

Hi. i need some explanations for the questions below which i could not understand.

**************************************************
Q1:

At a certain store, each notepad costs $X and each marker costs $Y. $10 is enough to buy 5 notepads and 3 markers. Is $10 enough to but 4 notepads and 4 markers?
A: Each notepad costs less than $1.
B: $10 is enough to buy 11 notepads.

Answer: Both statements together are not sufficient.
**************************************************
Q2:

Number of points a circle can intersect a triangle?

A: 2 and 6
B: 4 and 6
C: 1, 2, 3 and 6
D: 1, 2, 3, 4 and 6
E: 1, 2, 3, 4, 5 and 6

Answer: E

********************************************************************************
Q3:

Is the 100th digit of decimal d>5?

A: Tenth digit of 10d is 7.
B: Thousand digit of d/10 is 7.

Asnwer: Either statement alone is suffiecient.

*********************************************************************************
Q4:

A person is to select books for vacation. He can select books from biology, comics and novels. How many combinations of books are possible?

A: He has 4 biology and 3 comic books
B: He has 7 novels

Answer: Both statements together are sufficient.

***********************************************************************************

@above:

You are right.
I missed out on that one...Thanks!

@Crab, both of us need to start reading the posts more carefully and analyze what has been written.
I misread your post and you bought my explanation, both of us need to keep our eyes open:cheerio:

I think it should be A, can be answered using Statement 1 Alone.

Crab has given a good explanation for the first statement, so I will not reiterate that. Just reaad the previous post.

I differ with the reasoning given for the second statement.
We also need to consider the min case apart from the max case.

In the min case, the values of B=20, G=12, Y=5, Total = 37, Thus we need a discount of at least 3.7 (10%)
But 40% of 5(Y) = 2

So we can see that we get both the situations (>10% and <10% discount) when we use only this statement, we cannot say definitely that the discount is more than 10%.

Please confirm if this reasoning is correct.

Mistake in this reasoning was pointed by Ashish (Education Aisle).

Statement2: There is no situation where discount becomes >10%, it will always be less than 10%. I read Crab's post and assumed that he had covered only one case and took on the other case. Mistake.
The question can be answered with Statement2 alone, as well.
So the correct answer is indeed D.

Thanks to ashish for pointing this.

@above:

You are right.
I missed out on that one...Thanks!

Every item in an apparel shop has a tag that is either blue, green or yellow in colour. The items with a blue tag are priced between $20 and $30. The items with a green tag are priced between $12 and $18 and the items with a yellow tag $5 and $10. Mary buys three items, each with a different color tag. Is the total discount on three items greater than 10%?......

1) The discount on the items with a blue tag is 20% and that on the items with a green tag is 25%.
2)The discount on the items with a yellow tag is 40%.


Please provide the answer with your explanation....Thanks in advance.

I think it should be A, can be answered using Statement 1 Alone.

Crab has given a good explanation for the first statement, so I will not reiterate that. Just reaad the previous post.

I differ with the reasoning given for the second statement.
We also need to consider the min case apart from the max case.

In the min case, the values of B=20, G=12, Y=5, Total = 37, Thus we need a discount of at least 3.7 (10%)
But 40% of 5(Y) = 2

So we can see that we get both the situations (>10% and <10% discount) when we use only this statement, we cannot say definitely that the discount is more than 10%.

Please confirm if this reasoning is correct.

Every item in an apparel shop has a tag that is either blue, green or yellow in colour. The items with a blue tag are priced between $20 and $30. The items with a green tag are priced between $12 and $18 and the items with a yellow tag $5 and $10. Mary buys three items, each with a different color tag. Is the total discount on three items greater than 10%?......

1) The discount on the items with a blue tag is 20% and that on the items with a green tag is 25%.
2)The discount on the items with a yellow tag is 40%.


Please provide the answer with your explanation....Thanks in advance.

USING STATEMENT 1 ALONE:
Let us assume that the "blue tag" item be worth $20(the least) Price after discount=$16.
"Green tag"=$12 and after discount=$9
"Yellow tag"=$10(take the maximum).
Net amount=$42
Total discount =$3+$4=$7/42 X 100 >10%
Thus using this alone we can say that the net discount will always be more than 10%.(beacause if green and blue items are more expensive, then discount will also increase, but price of yellow tag will not be more than $10, and it does not have any discount, for now.)

NOW USE STAEMENT 2 ALONE:
Let the item with yellow tag be worth $10. We take the maximum because other two items do not have discount, and based on the discount on the yellow item alone we have to determine whether total discount exceeds 10%.
Price of yellow item after discount=$6.
Let prices of green and blue items respectively be $18 and $30. We take the max because we want to know if the maximum possible discount exceeds the maximum possible total amount by 10%.
Discount = 4/58 X 100 , <10%

Now consider maximum possible discount on the minimum possible amount. It happends when price of yellow item is $10 and other two are $12 and $20.
Discount = $4/42 X 100 = , <10%.
So, in this case also the discount will always be less than 10%

So, my take is . ie. either statement alone is sufficient.

Every item in an apparel shop has a tag that is either blue, green or yellow in colour. The items with a blue tag are priced between $20 and $30. The items with a green tag are priced between $12 and $18 and the items with a yellow tag $5 and $10. Mary buys three items, each with a different color tag. Is the total discount on three items greater than 10%?......

1) The discount on the items with a blue tag is 20% and that on the items with a green tag is 25%.
2)The discount on the items with a yellow tag is 40%.


Please provide the answer with your explanation....Thanks in advance.

ANSWER-C
x- SQUARE OF AN INTEGER N CUBE OF AN INTEGER IS 64
8*8=64
4*4*4=64

The equation gives us 2 values for "x" i.e (-1,9)
now the f(x) can be broken down to x^2 - 1*|y. Coming on to the conditions -
(1) to calculate maximum we also need the value of y
so this alone is insufficient
(2) y|<=9 and x^2-1 has only two values (0,80)
so f(x) max will be 80 * 9=720
this alone is sufficient.

Hence my take will be B

whats the OA

If (X^2) - 8X - 9 = 0, What is the maximum value of f(x) = ?

(1) x| Less than or equal to 9
(2) |Y Less than or equal to 9


Please explain your answers.....

even if you combine the two statements:
"2w" :- the no of women who voted in favour of x
"w" :- women who voted against X
"m" :- men who voted against X

You'll come down to an equation which looks something like
(2w+3000) + (m+w) = 9000
i.e. (3w+m)=6000

and we can have multiple options with this eqn in hand.

so my take will be E
correct me if I am wrong

I will strengthen above logic with my take as E....though deepak sir gave the best explanation..

Of the 9,000 people who voted in a recent election, how many women voted for candidate X?

(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.

I will go with option E for the above DS. Here is how I worked it out

Statement A - Only talks abt the %.Nothing concrete. Nt suff

Statement B - Talks about the Men..Nt suff

Combining both, No of Men voted for Candidate X = 3000..Huv many Women voted in the election?How many Men voted in the Election?Ans cannot be derived from the above information.

So,I would go with option E

-Deepak.

Of the 9,000 people who voted in a recent election, how many women voted for candidate X?

(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.

my take is E...correct?

Of the 9,000 people who voted in a recent election, how many women voted for candidate X?

(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.

What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16

IMO B as well.....

1) n(n+1)=6
can be factored as (n+3)(n-2)=0, which gives us 2 values of n
Not sufficient

2) 2^2n=16
=> 2^2n=2^4
=> 2n=4, i.e n=2
Only one value of n, thus sufficient .

What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16

i think the answer should be B

reason:

1>
n = 2 : 2(2+1) = 2(3) = 6
n = -3: (-3)(-3+1) = (-3)(-2) = 6

hence two possible values of n. NOT SUFFICIENT.

2>

n=2 : 2^(2*2) = 2^4 = 16.

just one possible value for n. SUFFICIENT.

What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16