My take (A) Stmt 1 is sufficient...
STarting with the fact that mode=7,
This implies that 7 occurs max times:: surely more than once..
Now if 7 appeared 4 times, the sequence in increasing order will be:
7,7,7,7,a,b OR a,7,7,7,7,b OR a,b,7,7,7,7 In none of the cases, we can hav median=6 as mentioned
So 7 occurs twice or thrice, and since 7> median the two/three occurances must be on right hand side of mid-point
Now if 7 were the greatest number, then all numbers have to be equal to 7 ( 'coz mean=7)
which is not the case...(median=6)
So 7 occurs twice and on 4th and 5th order in increasing sequence...
The series as of now stands at: a,b,c,7,7,d
Since median=6, => c=5
So the seuence becomes: a,b,5,7,7,d
Mean=7 => sum =42
a+b+5+7+7+d=42
or a+b+d=23 (3)
Now taking condition (1) (a+b) = (7+d)/5
Putting in(3) (7+d)/5 +d =23 This gives d=18...
So statement (1) is sufficient
(2) tells us what we already know.... So not sufficient
Hence answer = (A)