Hi All,
Note: I had posted a similar question earlier. Please note however that the questions in this attachment are different from the earlier ones.
Attached are some of the questions from GMATPrep that I got wrong. The options marked with the bold black dot in the attachment are mine and are the wrong answers. The options marked by a square blue frame are correct as these are the correct answers marked by the software. However the software does not explain why a particular choice is correct and others are wrong. I will be very grateful if some of you can help justify why the correct choice is actually correct!
Many thanks.
- TheToastedBread
Q1 M managers,D directors T task force m1 is average salary of managers and d1 and t1 are for dircotrs and task force.
2 equations 1.m+d=t 2.mm1+dd1=tt1
Now opttions 1 d1=t1+15000 2 m1=t1-5000
substitute in eqation 2 mt1-5000m+dt1+15000d=t t1
rewrite (m+d)*t1 -5000m+15000d= (m+d)t1 ( because m+d=t)
you get m=3d
you can answer the question so Answer is CQ2 form a series with (n,r) u get (5,0)/6,11/7,0/8,15/9,8/10,3/11,0/12,23/13,0
u can see the trend use both options u find remaineder is alwaus 0. so
Answer is CQ3. option 1 one country 41 A atleast 10 . assume other four 1,2,3,4. then A will be 24. if u change other four countries to 2,3,4,5 A will get diff answer. So using stamnet alone it cannot be answered. Stament B does not tell you anything. Using both stament as also you have choice of 9(others 4 6 7

and 10(others 457

or 11 (456

for A.
So Answer is EQ4. Using stament 1 xz is even. means atleast one of x or z is even. x is factor of z. if z is odd x ahs to be even. which is not possible becasue x is factor of z. so z must be even.
statment 2 if y is even z has to be even because y is factor of z.
Answer is DQ5 using staemnet1 x5=x4/2 and using stemnet 2 x5=x4/(x4+1).
using together x4=0 or 1 . if x4 is 0 all numbers in the sequence are 0.(is this considered as series ,all being 0's) i am not sure.
if x4=1 x1=8 .
Shoul d the anwer be E if we consider all 0's as a series. or anwers is C