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18-09-2007, 11:41 AM
Quote:
Originally Posted by HarshaRocks  Please help me with these.
Saw them in the thread earlier,but cannot make out the solution.
The difference between the LCM and HCF of two natural numbers a and b is 57. What is the minimum value of a+b ?
1) 22 2) 27 3) 31 4) 58
The HCF of two numbers is 6 and the product of the two numbers is 4320. How many pairs of numbers exist, which satisfy the above conditions ?
1) 2
2) 3
3) 4
4) None of these
Thanks |
Is the ans to second one 4?
At the age of 20 we always think of what others think of us; At the age of 40 we don’t care what others think of us; At the age of 60 we realize that nobody has been thinking of us Energy saved is equal to twice the energy produced. Save energy. | | |  | | | | |
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18-09-2007, 11:50 AM
Quote:
Originally Posted by HarshaRocks Please help me with these.
Saw them in the thread earlier,but cannot make out the solution.
The difference between the LCM and HCF of two natural numbers a and b is 57. What is the minimum value of a+b ?
1) 22 2) 27 3) 31 4) 58
The HCF of two numbers is 6 and the product of the two numbers is 4320. How many pairs of numbers exist, which satisfy the above conditions ?
1) 2
2) 3
3) 4
4)None of these
Thanks | answers in bold
Last edited by krsh.vik; 18-09-2007 at 12:20 PM..
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18-09-2007, 12:17 PM
Quote:
Originally Posted by HarshaRocks Please help me with these.
Saw them in the thread earlier,but cannot make out the solution.
The difference between the LCM and HCF of two natural numbers a and b is 57. What is the minimum value of a+b ?
1) 22 2) 27 3) 31 4) 58 |
(mn-1)h=57 , where a=hm and b=hn
Minimum is for m=4,n=5 and h=3 =>12+15=27 Quote: |
Originally Posted by HarshaRocks The HCF of two numbers is 6 and the product of the two numbers is 4320. How many pairs of numbers exist, which satisfy the above conditions ?
1) 2
2) 3
3) 4
4) None of these
Thanks | 36xy=4320 =>xy=120=2^3*3*5
The number of ways in which N can be resolved in two factors such that both the factors are co-prime to each other are 2^(n-1) , where n is the number of prime factors
Hence no. of pairs =2^2=4
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18-09-2007, 07:40 PM
How many paor of natural numbers are there,whose product is 2^5 x 3^7 x 5^11 ?
Ans
1.288
2.4
3.576
4.8 | | | | | | | |
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19-09-2007, 12:13 AM
Quote:
Originally Posted by sidcool007 How many paor of natural numbers are there,whose product is 2^5 x 3^7 x 5^11 ?
Ans
1.288
2.4
3.576
4.8 | ans. 1
total factors=(5+1)(7+1)(11+1)=576
in pairs=576/2=288 | | | | | | | |
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19-09-2007, 07:44 AM
What is sum of the reciprocals of divisors of the number 1800. | | | | | | | |
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19-09-2007, 10:10 AM
Quote:
Originally Posted by anil_sharma What is sum of the reciprocals of divisors of the number 1800. | Is the answer 15/4
If it is correct I shall post the approach
Prime Numbers are what is left when you have taken all the patterns away. I think prime Numbers are like life. They are very logical but you could never work out the rules, even if you spent all your time thinking about them.
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19-09-2007, 10:20 AM
la la la..... (duplicate post)
At the age of 20 we always think of what others think of us; At the age of 40 we don’t care what others think of us; At the age of 60 we realize that nobody has been thinking of us Energy saved is equal to twice the energy produced. Save energy.
Last edited by kondapalli; 19-09-2007 at 10:22 AM..
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19-09-2007, 10:21 AM
Quote:
Originally Posted by anil_sharma What is sum of the reciprocals of divisors of the number 1800. |
Is it anything like 403/120.
Good to see yu utsave here as well....
It's (Sum of the factors /the number itself)
At the age of 20 we always think of what others think of us; At the age of 40 we don’t care what others think of us; At the age of 60 we realize that nobody has been thinking of us Energy saved is equal to twice the energy produced. Save energy.
Last edited by kondapalli; 19-09-2007 at 10:26 AM..
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19-09-2007, 05:14 PM
Quote:
Originally Posted by utsavmamoria Is the answer 15/4
If it is correct I shall post the approach |
No answer is not 15/4
it is 403/120
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