solve this problem

[cattie]

Originally Posted by GauravShah

Good Q

I think the second approach is the correct one and hence the naswer will be 13.4 %

As for the 1st option, here is y i feel there is an error

Hypothetically each 1 mm of distance on the height shud contain X no. of chords, which shud be equal throughout the height, But for every 1mm, the angles doesn't vary linearly.

Difficult to explain basically, please someone help

Gaurav.

I guess I get wht u'r trying to say, but the angles need not vary linearly. As long as all the possible chords(infinite Ofcourse) have a corresponding unique angle to themselves it serves the purpose. No matter in what way the angles differ frm chord-to-chord.

For every possible length of the chord there is an unique angle in the range of 0-180 which forms a triangle with the other two radii.

p.s: sorry for the wrong credits in my prev mail, redirected to roopesh_jindal.

[roopesh_jindal]

hi cattie
thnks for another answer
as if two were not causing enuf confusion
i m trying for this ques myself (ie to proove one of the ans
no, now any two answers wrong)
will tell if i come to a conclusion
ciao
roopesh

Originally Posted by cattie

Good ques roopesh,

been bogging myself since yes'day with it , the only thing that I've been able to come up with is yet another seemingly possible sol with yet another diff ans

ans3) The possible lengths of the chords ranges frm 0-2R and the favourable cases are frm 0-R.
probab= (R-0)/(2R-0)= 1/2.

might seem too stupid or simple but then, why not.

[ritika_j]

For any numbers a and b, a.b=a+b-ab

If a.b =0, which of the follwoing CANNOT be value of b?

a) 2
b) 1
c) 0
d) -1
e) -3/2

[roopesh_jindal]

Originally Posted by ritika_j

For any numbers a and b, a.b=a+b-ab

If a.b =0, which of the follwoing CANNOT be value of b?

a) 2
b) 1
c) 0
d) -1
e) -3/2

easy enuf ritika
just put in the values one by one
for b =2 we get a=2
for b=0 we get a =0
for b=-1 we get a =0.5
for b = -1.5 we get a = 0.6

but for b=1 we get -1=0 which is impossible
hence b can not be 1
this ques wud have been interesting if no options wud have been provided

ciao
roopesh

[cattie]

Originally Posted by ritika_j

For any numbers a and b, a.b=a+b-ab

If a.b =0, which of the follwoing CANNOT be value of b?

a) 2
b) 1
c) 0
d) -1
e) -3/2

In case the options had not been given,

if ab=0 => a+b - ab = 0 => b = a / (a-1) (OR) a = b / (b-1)

so in either case 'a' or 'b' cannot take the value of 1 as the case would become meaningless.

[ritika_j]

Please solve with explanation...

Q- In 1985, 45 percent of a document storage facility's 60 customers were banks, and in 1987. 25 percent of its 144 customers were banks. What was the percent increase from 1985 to 1987 in the number of bank customer the facilit had?

[cattie]

Originally Posted by ritika_j

Please solve with explanation...

Q- In 1985, 45 percent of a document storage facility's 60 customers were banks, and in 1987. 25 percent of its 144 customers were banks. What was the percent increase from 1985 to 1987 in the number of bank customer the facilit had?

is it not,
(25 % of 144) - (45 % of 60) = 9
% inc = 9/(45 % of 60) * 100= 9/27 * 100 = 33.33%

[ritika_j]

hey thatz the rite answer ... i didnt considered the percentages so got the wrong answer as 58.33%

[ritika_j]

For any +ve integer n, n>1, the "length" of n is the number of + primes (not necessarily distinct) whoseproduct is n. for example, the length of 50 is 3 since 50 = (2)(5)(5)

Q- what is the greatest possible length of a +ve integer less than 1000?
a)10
b)9
c)8
d)7
e)6

plz explain as to y which option u picked up.

[MavericK]

Originally Posted by ritika_j

Q- what is the greatest possible length of a +ve integer less than 1000?
a)10
b)9
c)8
d)7
e)6

plz explain as to y which option u picked up.

b) 9
2^9 = 512