Quote:
Originally Posted by mahesh88
a triangular piece of land is divided b/w thow brothers equally. what is the length of the shortest wall that can be build b/w their plots if the legnths of the sides of the plot are 20,21,29 m
please solution with explanation!!!!
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20^2+21^2= 29^2.
so this is a right angle triangle.
we can also imagine as a triangle drawn inside a semicircle.
now we want the shortest wall length to divide the triangle in two equal part,
so we should draw it from vertex to hypotenuse.( midpoint becomes to center of semicircle)
which is radius it self. so answer r= 29/2 14.5.
another approach:
wall is built from 90 degree vertex to midpoint of hypotenuse,
so (20^2 + 21^2 ) = 2( X^2 + 29^2/4 ) [ Apollonius theorem ]
=> 29^2/2 = 2*x^2
x = 29/2
P.S. i made one mistake here. I thought both part should be triangle also.if it was said that two part are also triangle than only my ans holds true.