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Official Quant thread for CAT 09-III (September onwards)
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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mahesh88 mahesh88 is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:50 AM

Quote:
Originally Posted by fillintheblanks View Post
the line will b parallel to 20 side

a/21=x/20 ....1 x is length of line dividing


1/2ax=1/2*20*21-1/2*ax(areas are equal)

ax=210.........2


we get ans as 10 sqroot2....

why shouldnt we take the perpendicular to the hypotenuse?? it divides exactly into two equal triangles...right??
then i get 20*sqrt2
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drkunjan drkunjan is offline
5th december 3:30 pm
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:51 AM

Quote:
Originally Posted by mahesh88 View Post
a triangular piece of land is divided b/w thow brothers equally. what is the length of the shortest wall that can be build b/w their plots if the legnths of the sides of the plot are 20,21,29 m


please solution with explanation!!!!
20^2+21^2= 29^2.
so this is a right angle triangle.
we can also imagine as a triangle drawn inside a semicircle.
now we want the shortest wall length to divide the triangle in two equal part,
so we should draw it from vertex to hypotenuse.( midpoint becomes to center of semicircle)
which is radius it self. so answer r= 29/2 14.5.

another approach:

wall is built from 90 degree vertex to midpoint of hypotenuse,
so (20^2 + 21^2 ) = 2( X^2 + 29^2/4 ) [ Apollonius theorem ]
=> 29^2/2 = 2*x^2
x = 29/2

P.S. i made one mistake here. I thought both part should be triangle also.if it was said that two part are also triangle than only my ans holds true.


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Last edited by drkunjan; 25-09-2009 at 01:51 AM.
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divishth divishth is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:53 AM

Out of 3n consecutive Integers, 3 are selected at random...Find the probability
1. Sum is divisible by 3
2. Product is divisible by 3


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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:54 AM

Mahesh.. i got 14.5 coz.. wen u want to divide a right angle triangle in to 2 parts . u hav to take perpendicular to the hypotenuse... n that distance is half of hypotenuse itself for right angled triangle.. so 29/2.. -- 14.5


correct me if m wrong..
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fillintheblanks fillintheblanks is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:56 AM

Quote:
Originally Posted by mahesh88 View Post
why shouldnt we take the perpendicular to the hypotenuse?? it divides exactly into two equal triangles...right??
then i get 20*sqrt2

for ans we will need base not hypo....
so i took perpendicular to base rather than hypo...
hope you got that
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mahesh88 mahesh88 is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:56 AM

Quote:
Originally Posted by ramakanth.b View Post
Mahesh.. i got 14.5 coz.. wen u want to divide a right angle triangle in to 2 parts . u hav to take perpendicular to the hypotenuse... n that distance is half of hypotenuse itself for right angled triangle.. so 29/2.. -- 14.5


correct me if m wrong..

yeah got it bro.. thankss..
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 12:59 AM

Quote:
Originally Posted by divishth View Post
Out of 3n consecutive Integers, 3 are selected at random...Find the probability
1. Sum is divisible by 3
2. Product is divisible by 3


1. is the answer 1/2 for first qs??
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mahesh88 mahesh88 is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 01:01 AM

in a square of 8c, side an idefinite no. of sqrs r formed sucesivley by joining the mid ppts of the sides of adj sides.wat is the ratio of numerical values of sum of perimtrs of sqrs to tat of sum of areas of these??
1.2+sqt2:2 2.2+sqt2:4 3.2sqt2:3 4 2sqt2:2sqt2+2 5.2+sqt2:3

plz sol with explanation!!!
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fillintheblanks fillintheblanks is offline
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 01:03 AM

Quote:
Originally Posted by divishth View Post
Out of 3n consecutive Integers, 3 are selected at random...Find the probability

2. Product is divisible by 3

in 3n consecutive there are n numbers having 3 as factor

so probability=nC3+nC1 2nC2 +nC2 2nC1/3nC3 (in 3n ,n will b have 3 as factor)
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Re: Official Quant thread for CAT 09-III (September onwards) - 25-09-2009, 01:06 AM

Quote:
Originally Posted by karthikm View Post
my take is 16.. what s OA?
what is the problem with all three of them taking 11 identical tests...
nobody takes 2 tests.
bobby takes his 5 remaining tests which nobody else gives.
emran " " 7 " " "
and the third guy takes the remaining tests.

ans 11
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