Quote:
Originally Posted by shilpakokkanti
Hi everybody,
A train 360m in lengt,travelling at a uniform speed overtok a car,travelling parallel to the tracks at 72kmph and passed it in 12 sec.48 min later,the train starts overtaking a cyclist and passed him in 9 sec.How much time aftert the train overtook the cyclist would the car overtake him???
ans is 2hr 24 min,27 sec..
Plz plz help me out..

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Firstly, the train overtake the car in 12 sec.
So relative speed of train to car is 360/12 = 30m/s
And the train overtook the cyclist in 9 sec.
Se relative speed of train to cyclist is 360/9 = 40m/s
Now speed of car is 72 kmph = 72*[5/18] = 20m/s
so, trains speed is 50m/s
and cyclists speed is 10m/s
now the gap generated bet. the train and car in 48 min. is 48*30 = 1440 mtrs
and in 9 more seconds (9/60)*30 = 4.5 mtrs
now the total gap bet. train n car = gap bet. train n cyclist at the time when train overtakes cyclist
so dividing by the relative speed of car n cycle i.e. 20-10 = 10
we get the time taken is 1444.45/10 = 144.45min = 2hrs 24 min and 27 sec
hope this solves ur query...