CAT 2008: Quantitative Questions a Day 1 to 50 - The discussions

Udit Mohan

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Quantitative Question # 049
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srikar2097

Quote:

Originally Posted by Aarav

Hello All,

People who are also seeing last year questions in the NL will realise that we took a hint from the suggestion given by past QQAD students and made QQAD slightly easier. The polling of 200 people indicate that we are on the right track, but however if you feel we are going over the board in toughness or delivering too easy problems then please feel free to speak your mind.

Please note that I'm travelling today and hence wouldn't be able to access NL software to put the names of people who solve QQAD 049 after now. You will get the NL tomorrow on time and I will join you for the discussions tomorrow afternoon.

The 2nd practice Test will be delivered on July 1st.

Aarav, I think QQAD is fine in its current shape

. On the whole I feel there is not much to change as far as level of problems are concerned.

But you can now and then (maybe 2-3 days a week) pepper us with some shockers, toughies

slam

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Quantitative Question # 050
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Each question is followed by two statements X and Y. Answer each question using the following instructions:

Choose 1 if the question can be answered by X only
Choose 2 if the question can be answered by Y only
Choose 3 if the question can be answered by either X or Y
Choose 4 if the question can be answered by both X and Y
Choose 5 if the question can not be answered by combining X and Y also

If 1 < a < 2 and k is an integer, then what is [ak/(2 - a)], where [x] denotes the greatest integer not larger than x.

(X) [a[k/(2 - a)] + a/2] = p
(Y) [a[k/(2 - a)] + (a+1)/2] = q and k is even

sabsebadapaagal

Quote:

Originally Posted by slam

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Quantitative Question # 050
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Each question is followed by two statements X and Y. Answer each question using the following instructions:

Choose 1 if the question can be answered by X only
Choose 2 if the question can be answered by Y only
Choose 3 if the question can be answered by either X or Y
Choose 4 if the question can be answered by both X and Y
Choose 5 if the question can not be answered by combining X and Y also

If 1 < a < 2 and k is an integer, then what is [ak/(2 - a)], where [x] denotes the greatest integer not larger than x.

(X) [a[k/(2 - a)] + a/2] = p
(Y) [a[k/(2 - a)] + (a+1)/2] = q and k is even

Just substituted a=1.6 k=1-----(1) and got the answer using X....
In order to test even values for K substitued a=1.6 and K=2.. now also got the answer using X but Y didnt give the correct answer... thus the above question can be answered by using X only.....
thus option 1

...
Working on for finding exact solution ....

kk_sonam

Quote:

Originally Posted by sabsebadapaagal

Just substituted a=1.6 k=1-----(1) and got the answer using X....
In order to test even values for K substitued a=1.6 and K=2.. now also got the answer using X but Y didnt give the correct answer... thus the above question can be answered by using X only.....
thus option 1

...
Working on for finding exact solution ....

can u please explain me your solution

nbangalorekar

do we have to find out [ak/(2 - a)] as odd/even?
Aarav please be more specific in the questions.

sabsebadapaagal

Quote:

Originally Posted by kk_sonam

can u please explain me your solution

I have just plugged in different values for odd and even values of K ... and found that in all cases I am getting the answer using X but not Y...

again this is not an ideal way of doing this type of question , it is just a mean to find the answer...

This may be wrong for a few cases .. but till now I havent found any

kk_sonam

Quote:

Originally Posted by sabsebadapaagal

I have just plugged in different values for odd and even values of K ... and found that in all cases I am getting the answer using X but not Y...

again this is not an ideal way of doing this type of question , it is just a mean to find the answer...

This may be wrong for a few cases .. but till now I havent found any

i dint understand what does p and q denote
and are they even
or is k even