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official quant thread for cat08
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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convivial convivial is offline
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official quant thread for cat08 - 27-12-2007, 08:10 PM

hi frnds
as cat 07 is over and there r puys who want to gear up for cat 08....i am starting this official quant thread for cat 08....i request the administrator and other puys to make it an official thread.
best of luck





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Re: official quant thread for cat08 - 27-12-2007, 08:13 PM

Quote:
Originally Posted by convivial View Post
hi frnds
as cat 07 is over and there r puys who want to gear up for cat 08....i am starting this official quant thread for cat 08....i request the administrator and other puys to make it an official thread.
best of luck





************cogito_ergo_sum*********************** ************
one more thing guys.....plz start posting questions
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Re: official quant thread for cat08 - 27-12-2007, 09:44 PM

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Originally Posted by convivial View Post
one more thing guys.....plz start posting questions

ok frnds..here's first one 4m me.....an easy one just 2 start up

1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3
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Re: official quant thread for cat08 - 06-01-2008, 12:42 AM

Quote:
Originally Posted by convivial View Post
ok frnds..here's first one 4m me.....an easy one just 2 start up

1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3

Ans is 2 values....-1 and -2.
Just plug in the values..correct me if I'm wrong


Peace..
Yudhajeet

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Re: official quant thread for cat08 - 06-01-2008, 11:24 PM

Quote:
Originally Posted by convivial View Post
ok frnds..here's first one 4m me.....an easy one just 2 start up

1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3
Is the answer 0? I could not find any negative integer till -3 to satisfy this condition and as the value of x decreases further the difference between the RHS and LHS values increases. Thus there could not be any any other value beyond -3.

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Re: official quant thread for cat08 - 07-01-2008, 12:51 AM

Quote:
Originally Posted by convivial View Post
ok frnds..here's first one 4m me.....an easy one just 2 start up

1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3

is it 0????


Cheers,

Trideep


IF IT IS TO BE, IT IS UP TO ME
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Re: official quant thread for cat08 - 07-01-2008, 01:26 AM

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Originally Posted by bubai376 View Post
is it 0????
the answer is 1 i.e option (b)

Last edited by convivial; 07-01-2008 at 01:29 AM.
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Re: official quant thread for cat08 - 07-01-2008, 01:48 AM

Guys Guys.... easy yaaro.... please follow the rules of the previous years Official Quant threads... like no posting of reply before certain fixed time daily....( you can refer to them on previous official threads...) otherwise, there is no use of having a chat like thread b/w 4-5 people solving as soon as questions are posted, as that will not help weaker students.... wanna be official, then act like one.
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Re: official quant thread for cat08 - 07-01-2008, 02:01 AM

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Originally Posted by HeadsMan View Post
Guys Guys.... easy yaaro.... please follow the rules of the previous years Official Quant threads... like no posting of reply before certain fixed time daily....( you can refer to them on previous official threads...) otherwise, there is no use of having a chat like thread b/w 4-5 people solving as soon as questions are posted, as that will not help weaker students.... wanna be official, then act like one.

ok frnd....thanx 4 ur advise...will keep this in mind...carry on
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Re: official quant thread for cat08 - 08-01-2008, 09:57 AM

Can u please explain how the answer is 1.
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