[Hi2All]

Hi friends....Plzz Help me to solve this problem....

A school is going to have 1000 students in near future.
1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present.

[implex]

Originally Posted by Hi2All

Hi friends....Plzz Help me to solve this problem....

A school is going to have 1000 students in near future.
1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present.

clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase

hence the no of students is 900

[convivial]

Originally Posted by implex

clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase

hence the no of students is 900

hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................

[atshubha]

Originally Posted by convivial

hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................

Actually the question is really vague but with all the assumptions made by implex the number of students should be perfectly divisible by 4,5,9 .The LCM of 4,5,9 is 180 , The number of students can be a multiple of 180 .... ( as the number of students cannot be a fraction , 1/2 a student :black: )

[implex]

Originally Posted by convivial

hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................

its simple
as no of students cant be a fraction.
it should be divisble by 4,5 and 9
now lcm is 180
so we take it near to 1000 .. that is 900

[vicky113]

a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers

[SUPER XERO]

Originally Posted by vicky113

a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers

least no. of digits that k can have = 23 ....... temme if i m correct so tht i cn explain the procedure

[nbangalorekar]

Originally Posted by vicky113

a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers

answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number

2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18...

[vivs_d]

hey IOTA

PLZ POST THE SOLN FOR THAT VINAY AND MINI QUIZ MASTER QUESTION.

[SUPER XERO]

Originally Posted by nbangalorekar

answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number

2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18...

dude........ agree with ur second answer......
but in the first one it shud be a 2 digit number.........