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| Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe ! | | | |
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Join Date: Aug 2007 Location: Andhra | Re: official quant thread for cat08 -
09-03-2008, 07:51 PM
Hi friends....Plzz Help me to solve this problem.... A school is going to have 1000 students in near future. 1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present. Whatever you do will be insignificant, but its very important that you do it -Gandhiji | | | | | | | |
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Join Date: Jan 2008 Location: Kanpur | Re: official quant thread for cat08 -
09-03-2008, 08:04 PM
Quote:
Originally Posted by Hi2All Hi friends....Plzz Help me to solve this problem.... A school is going to have 1000 students in near future. 1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present. | clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase
hence the no of students is 900 | | | | | | | |
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Join Date: Dec 2007 Location: neverland | Re: official quant thread for cat08 -
10-03-2008, 06:25 AM
Quote:
Originally Posted by implex clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase
hence the no of students is 900 | hi
i did not get ur logic......plz explain in detail cogito,ergo,sum................ | | | | | | | |
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Join Date: Feb 2007 Location: Bangalore | Re: official quant thread for cat08 -
10-03-2008, 02:30 PM
Quote:
Originally Posted by convivial hi
i did not get ur logic......plz explain in detail cogito,ergo,sum................ | Actually the question is really vague but with all the assumptions made by implex the number of students should be perfectly divisible by 4,5,9 .The LCM of 4,5,9 is 180 , The number of students can be a multiple of 180 .... ( as the number of students cannot be a fraction , 1/2 a student  ) | | | | | | | |
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Join Date: Jan 2008 Location: Kanpur | Re: official quant thread for cat08 -
10-03-2008, 03:59 PM
Quote:
Originally Posted by convivial hi
i did not get ur logic......plz explain in detail cogito,ergo,sum................ | its simple
as no of students cant be a fraction.
it should be divisble by 4,5 and 9
now lcm is 180
so we take it near to 1000 .. that is 900 | | | | | | | |
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Join Date: Dec 2007 Location: kolkata | Re: official quant thread for cat08 -
12-03-2008, 08:47 PM
a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.
1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?
2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?
a.12 b.15 c.18 d.21
plz post ur solutions along with the answers | | | | | | | |
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Join Date: Apr 2007 Location: timBUCKtoo | Re: official quant thread for cat08 -
12-03-2008, 09:15 PM
Quote:
Originally Posted by vicky113 a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.
1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?
2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?
a.12 b.15 c.18 d.21
plz post ur solutions along with the answers | least no. of digits that k can have = 23 ....... temme if i m correct so tht i cn explain the procedure CAT IN THE UNDERTOW!!
JUST......CAT IN THE UNDERTOW!!
Last edited by SUPER XERO; 12-03-2008 at 09:22 PM..
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Join Date: Dec 2007 Location: Mumbai Age: 22 | Re: official quant thread for cat08 -
12-03-2008, 09:20 PM
Quote:
Originally Posted by vicky113 a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.
1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?
2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?
a.12 b.15 c.18 d.21
plz post ur solutions along with the answers | answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number
2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18... Krishna to the greatest hero Arjuna: tyaktvottistha parantapa
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hmmm.....
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Join Date: Jul 2007 Location: Bangalore | Re: official quant thread for cat08 -
12-03-2008, 09:22 PM
hey IOTA
PLZ POST THE SOLN FOR THAT VINAY AND MINI QUIZ MASTER QUESTION. | | | | | | | |
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Join Date: Apr 2007 Location: timBUCKtoo | Re: official quant thread for cat08 -
12-03-2008, 09:24 PM
Quote:
Originally Posted by nbangalorekar answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number
2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18... | dude........ agree with ur second answer......
but in the first one it shud be a 2 digit number......... CAT IN THE UNDERTOW!!
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