official quant thread for cat08 - Page 51 - PaGaLGuY.com - The Everything of MBA in India and Abroad, CAT 2009, GMAT, XAT, MAT
PaGaLGuY.com - The Everything of MBA in India and Abroad, CAT 2009, GMAT, XAT, MAT
Forum Rules
» Sponsors
  PaGaLGuY.com - The Everything of MBA in India and Abroad, CAT 2009, GMAT, XAT, MAT > Exam Resources > Quantitative Questions and Answers
official quant thread for cat08
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

Tags: , ,

» Thread Closed
 
LinkBack Thread Tools Display Modes
  (#501)
Hi2All Hi2All is offline
Cool!!
Expert PaGaL
 
Hi2All's Avatar
 
Posts: 106
Join Date: Aug 2007
Location: Andhra
Groans: 0
Groaned at 1 Time in 1 Post
Thanks: 50
Thanked 6 Times in 6 Posts
Re: official quant thread for cat08 - 09-03-2008, 07:51 PM

Hi friends....Plzz Help me to solve this problem....

A school is going to have 1000 students in near future.
1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present.


Digg this Post!Add Post to del.icio.usStumble this Post!
Sponsored Links
  (#502)
implex implex is offline
is Bak
Certified PaGaL
 
implex's Avatar
 
Posts: 2,351
Join Date: Jan 2008
Location: Kanpur
Groans: 48
Groaned at 34 Times in 24 Posts
Thanks: 2,673
Thanked 2,631 Times in 933 Posts
Re: official quant thread for cat08 - 09-03-2008, 08:04 PM

Quote:
Originally Posted by Hi2All View Post
Hi friends....Plzz Help me to solve this problem....

A school is going to have 1000 students in near future.
1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present.
clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase

hence the no of students is 900
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#503)
convivial convivial is offline
has no status.
Trainee PaGaL
 
Posts: 49
Join Date: Dec 2007
Location: neverland
Groans: 0
Groaned at 16 Times in 4 Posts
Thanks: 30
Thanked 90 Times in 18 Posts
Re: official quant thread for cat08 - 10-03-2008, 06:25 AM

Quote:
Originally Posted by implex View Post
clealry the lcm of 4,5,9 is 180
now as teh no is close to 1000
we find the closest is 900, assuming the no of students increase

hence the no of students is 900
hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#504)
atshubha atshubha is offline
dead but kicking
Hardcore PaGaL
 
Posts: 358
Join Date: Feb 2007
Location: Bangalore
Groans: 8
Groaned at 6 Times in 4 Posts
Thanks: 432
Thanked 262 Times in 86 Posts
Re: official quant thread for cat08 - 10-03-2008, 02:30 PM

Quote:
Originally Posted by convivial View Post
hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................
Actually the question is really vague but with all the assumptions made by implex the number of students should be perfectly divisible by 4,5,9 .The LCM of 4,5,9 is 180 , The number of students can be a multiple of 180 .... ( as the number of students cannot be a fraction , 1/2 a student :black: )


There is no magic in magic ,it's all in the details.
Walt Disney

http://www.thedarknessisbutme.blogspot.com/


Digg this Post!Add Post to del.icio.usStumble this Post!
  (#505)
implex implex is offline
is Bak
Certified PaGaL
 
implex's Avatar
 
Posts: 2,351
Join Date: Jan 2008
Location: Kanpur
Groans: 48
Groaned at 34 Times in 24 Posts
Thanks: 2,673
Thanked 2,631 Times in 933 Posts
Re: official quant thread for cat08 - 10-03-2008, 03:59 PM

Quote:
Originally Posted by convivial View Post
hi
i did not get ur logic......plz explain in detail



cogito,ergo,sum................
its simple
as no of students cant be a fraction.
it should be divisble by 4,5 and 9
now lcm is 180
so we take it near to 1000 .. that is 900
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#506)
vicky113 vicky113 is offline
atlast the long wait is over, and its the end to my slumber
Addicted PaGaL
 
vicky113's Avatar
 
Posts: 851
Join Date: Dec 2007
Location: kolkata
Groans: 49
Groaned at 43 Times in 19 Posts
Thanks: 656
Thanked 396 Times in 209 Posts
Re: official quant thread for cat08 - 12-03-2008, 08:47 PM

a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#507)
SUPER XERO SUPER XERO is offline
has left pagalguy. :w00t:
Hardcore PaGaL
 
SUPER XERO's Avatar
 
Posts: 359
Join Date: Apr 2007
Location: Land of Entrepreneurs
Age: 24
Groans: 5
Groaned at 60 Times in 20 Posts
Thanks: 3,632
Thanked 1,083 Times in 213 Posts
Re: official quant thread for cat08 - 12-03-2008, 09:15 PM

Quote:
Originally Posted by vicky113 View Post
a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers
least no. of digits that k can have = 23 ....... temme if i m correct so tht i cn explain the procedure

Last edited by SUPER XERO; 12-03-2008 at 09:22 PM.
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#508)
nbangalorekar nbangalorekar is offline
happy with no status
Hardcore PaGaL
 
Posts: 347
Join Date: Dec 2007
Location: Mumbai
Age: 23
Groans: 1
Groaned at 5 Times in 3 Posts
Thanks: 69
Thanked 156 Times in 93 Posts
Re: official quant thread for cat08 - 12-03-2008, 09:20 PM

Quote:
Originally Posted by vicky113 View Post
a function y=f(n) is defined, for all natural numbers, as the sum of the digits of n.

1. if k is a natural number such that f(f(f(f(k))))=1 and k>f(f(k)).f(f(f(k)))>1 what is the least number of digits that k can have?

2. for a natural number m, which of the following could be the value of f(f(m-f(m)))?

a.12 b.15 c.18 d.21



plz post ur solutions along with the answers
answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number

2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18...


Krishna to the greatest hero Arjuna:
tyaktvottistha parantapa
Arise O scorcher of enemies!!!

Digg this Post!Add Post to del.icio.usStumble this Post!
The Following 2 Users Say Thank You to nbangalorekar For This Useful Post:
kastor (01-04-2008), SUPER XERO (12-03-2008)
  (#509)
vivs_d vivs_d is offline
hmmm.....
Trainee PaGaL
 
vivs_d's Avatar
 
Posts: 76
Join Date: Jul 2007
Location: Bangalore
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 7
Thanked 12 Times in 10 Posts
Re: official quant thread for cat08 - 12-03-2008, 09:22 PM

hey IOTA

PLZ POST THE SOLN FOR THAT VINAY AND MINI QUIZ MASTER QUESTION.
Digg this Post!Add Post to del.icio.usStumble this Post!
  (#510)
SUPER XERO SUPER XERO is offline
has left pagalguy. :w00t:
Hardcore PaGaL
 
SUPER XERO's Avatar
 
Posts: 359
Join Date: Apr 2007
Location: Land of Entrepreneurs
Age: 24
Groans: 5
Groaned at 60 Times in 20 Posts
Thanks: 3,632
Thanked 1,083 Times in 213 Posts
Re: official quant thread for cat08 - 12-03-2008, 09:24 PM

Quote:
Originally Posted by nbangalorekar View Post
answers:
1) since f(f(k)).f(f(f(k)))>1
f(f(k)) has to be atleast > 10
so k has to be at least a 3 digit number

2) let k=1000a+100b+10c+d
so (m-f(m) = 999a+99b+9c
so f(f(m-f(m)))%9 = 0
the only option that satisfies this is 'c'
answer is 18...
dude........ agree with ur second answer......
but in the first one it shud be a 2 digit number.........
Digg this Post!Add Post to del.icio.usStumble this Post!
» Thread Closed

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are Off

Forum Jump

» Sponsors

PaGaLGuY.com is not responsible for the views and opinions of the posters.
PaGaLGuY.com is an Inzane Labs Private Limited production.