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Re: official quant thread for cat08
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madadi
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Re: official quant thread for cat08 - 27-06-2008, 04:41 PM

Quote:
Originally Posted by phasmophobe007 View Post
There are 500 balls.A person can pick a minimum of 5 balls and maximum of 10 balls.A & B are playing this game.A starts the game.How many balls A should pick to win if:
i)Last picker wins the game
ii)Last picker looses the game.


I don't have the key to above question.
puys,pls post ur various approaches.
i feel the answer to both these parts is the same.... which is 5...
explanation:
1) A starts n has to be the one who picks up the ball last, to be the winner... now since, a minimum of 5 balls are to be picked essentially,
the series wud go as--->
A B A B A B A B A
hence A picks up 5 balls, n emerges as the winner...

2) A starts again... the last picker wud lose, in this case... the series, hence formed wud be--->
A B A B A B A B A B
B picks up the ball last, hence loses... wich implies A is the winner.. but the no of balls picked by A wud remain 5 itself...

correct me if i'm wrong, puys..
p.s: shudn't the question have been framed like... find the minimum no of balls A must pick up in order to win??


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Re: official quant thread for cat08
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themystique
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Re: official quant thread for cat08 - 27-06-2008, 07:39 PM

NUMBER OF CUBES IN 27000 :

cubes of 1,2,3,5,6,10,15,30 are present.

hence 8.
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Re: official quant thread for cat08
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themystique
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Re: official quant thread for cat08 - 27-06-2008, 08:07 PM

Quote:
Originally Posted by phasmophobe007 View Post
There are 37 balls in a bag.A person can pick minimum of 1 ball and maximum of 3 balls from this bag.The person who picks the last ball wins the game.A & B are playing this game,starting with A and alternatively picking the ball.If A wants to win the game ,how many balls shall A pick?do post ur approach also


Answer to aforesaid is
A shall pick 1 ball to win.
Approach-The approach given by srikar is a generalised one for sure.
But my approach-
ball no. 37 shall be picked up by A
so A should pick ball no. 33,29,25,.....,5,1
Hence A should pick 1 ball to win.

for this question points to be kept in mind-
A picks the first ball.After this picks(1 to 3) no. of balls.
How many balls A will pick now?
The total no. of balls picked by B(in 2nd turn) and by A(3rd turn) shall be equal to 4.If B pick 2 balls in his 2nd turn then A should also pick 2 and so on...

General formulae for above type of question
No. of ball A shall pick=Total no.of balls%(Minimum+maximum no. of balls picked)

@phasmo,

could you please tell me if the formula that you provided is true in all cases?
and in which cases it could be applied and in which it shouldn't be?

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Re: official quant thread for cat08
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ravijanjanam
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Re: official quant thread for cat08 - 27-06-2008, 09:53 PM

Quote:
Originally Posted by 80199 View Post
In the X-Y plane, the area of the region bounded by the graph of |x + y| + |x -y| - 4 is

Choose one answer.
a. 8 b. 12 c. 16 d. 20


sol: |x| can be expressed as +/- x

therfore |x+y|= +/-(x+y)
|x-y|= +/-(x-y)

=> case1: +(x+y)+(x-y)-4 = Z(suppose)

=> 2x-4=Z------------eq 1
=> case 2: -(x+y)-(x-y)-4 =Z1 (suppose)

=> -2x-4=Z1-----------eq 2

plotting eqns 1 and 2 on graph provieds us triangle with points (-2,0),(0,-4),(2,0)

therfore finding the area of this triangle is the solution
   
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Re: official quant thread for cat08
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Udit Mohan
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Re: official quant thread for cat08 - 27-06-2008, 09:59 PM

hi folks ,
pls solve these questions ...
*** How many terms are there in the expression : (y+y^3+y^5+y^7)^5
*** Find the no of positive integral solution of A*B*C*D*E=1050??
***50 kids are standing in a cirular arrangement and one of them is having a ball .....the ball is passed counter-clock wise skipping 0,1,2,3,4 & so on kids respectively i.e. the 1st kid gives it to 2 nd kid, then 2nd kid gives it to 4th kid, 4th to 7 th & so on .....after how many hands change will the ball back to the first kid ???
   
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Re: official quant thread for cat08
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dagaritesh
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Re: official quant thread for cat08 - 27-06-2008, 10:27 PM

***50 kids are standing in a cirular arrangement and one of them is having a ball .....the ball is passed counter-clock wise skipping 0,1,2,3,4 & so on kids respectively i.e. the 1st kid gives it to 2 nd kid, then 2nd kid gives it to 4th kid, 4th to 7 th & so on .....after how many hands change will the ball back to the first kid ???[/quote]

Is it 24.

By my understanding n*(n+1)/2 should be a multiple of 50 and n should be minimum.

Hence 24?
   
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Re: official quant thread for cat08
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ashishkrsaini
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Thumbs up Re: official quant thread for cat08 - 27-06-2008, 10:32 PM

Quote:
Originally Posted by prince_chittu View Post
@Srikar

Can u plz elaborate on the answers u hv given of the this question
There are 500 balls.A person can pick a minimum of 5 balls and maximum of 10 balls.A & B are playing this game.A starts the game.How many balls A should pick to win if:
i)Last picker wins the game
ii)Last picker looses the game.

Okay Here is my brain work ..
A & B will always make a combination of 15 score if B picks first and A follows ie BA = 15. eg B = 5 , A=10 or B=10, A=5

Now In case I, let A pick x balls. so we have x + 15N = 500
At N=33 and x = 5 we have a solution i.e if A picks 5 Balls initially, A will always pick last ball. Sequence would be A BA BA BA BA ...

Now In case II, let A pick x balls in first turn. Assuming B will have to pick last set of balls. In this case, B should be left with 5 to 9 balls in the last turn. P.S - In case 9 balls are left, B cannot pick 5 cause this will make 4 balls left, which cannot be picked by A!

The sequence would be A BA BA BA BA B
The equation would be x + 15N + (5...9) = 500
i.e x + 15N = (491...495)
Now for N = 32, x = 11...15
N = 33 x = 0....5

So that means, If A starts, A cannot Win.

Others .. please put your thoughts on this.
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 27-06-2008, 10:39 PM

[quote=Udit Mohan;1165346]hi folks ,
pls solve these questions ...
*** How many terms are there in the expression : (y+y^3+y^5+y^

Are there 24 terms?
   
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Re: official quant thread for cat08
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themystique
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Re: official quant thread for cat08 - 27-06-2008, 10:39 PM

Quote:
Originally Posted by dagaritesh View Post
***50 kids are standing in a cirular arrangement and one of them is having a ball .....the ball is passed counter-clock wise skipping 0,1,2,3,4 & so on kids respectively i.e. the 1st kid gives it to 2 nd kid, then 2nd kid gives it to 4th kid, 4th to 7 th & so on .....after how many hands change will the ball back to the first kid ???
Is it 24.

By my understanding n*(n+1)/2 should be a multiple of 50 and n should be minimum.

Hence 24?[/quote]

yes, i believe this is right.
i took the cue from you and tried it out for ten members.
it is the smallest value of n(n+1)/2 to be a multiple o the given no. of people.

hence 24 is correct

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Re: official quant thread for cat08
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themystique
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Re: official quant thread for cat08 - 27-06-2008, 10:56 PM

@ udit :
*** Find the no of positive integral solution of A*B*C*D*E=1050??

is there any condition that a,b,c,d,e are not distinct?

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