official quant thread for cat08

[vivs_d]

Originally Posted by amitkrsingh

is it 16!+1. It is multiple of 17 and satisfies all conditions also but I am not sure if its the least....

is there any conditions(like positive, natural) in first question or are they all real....

i guess 16!+1 is not a multiple of 17.

[implex]

Originally Posted by pallaviagrawal

u have said that A1,A2 etc are VERTICES of the polygon..then 1/A1A2 etc dsnt make any sense..do u mean the sides of the polygon wen u say
1/A1A2=1/A1A3+1/A1A4??

1/A1A2 makes no sense??
it means the reciprocal of the length of side A1A2. whats wrong there??
This is a very popular problem. Everyone here who has passed class 12 must have solved this .

let me make it more clear
if A and B are vertices of a triangle
what does AB mean?

[implex]

Originally Posted by vaibhav2cool

i think the answer will be 2^5*3^2*5^2*7*11*13 +1=7207201

here is my approach-
lcm of 2,3,4,.......16 is 2^4*3^2*5*7*11*13
so the number is (2^4*3^2*5*7*11*13)k+1=17m

2^4*3^2*5*7*11*13 wen divided by 17 gives 5 as the remainder, so k is 10
so the number is 2^5*3^2*5^2*7*11*13 +1=7207201

naah it is much smaller than that

[implex]

Originally Posted by amitkrsingh

is it 16!+1. It is multiple of 17 and satisfies all conditions also but I am not sure if its the least....

is there any conditions(like positive, natural) in first question or are they all real....

no it is not that big either!!

[implex]

Originally Posted by naga25french

is the question complete?? i guess some condition is missing..

the question is perfect and the answer is perfect as well, at least I framed it in good faith

[Hi2All]

Originally Posted by hellion

Now this leaves me confused
Can someone clear it up??

sorry to all...
It was me who misunderstood the question..

I didn't check the question properly..
as i got the answers as male=80 and female=175
and these answers satisfies the question..so i thought it would me right...

But the correct approach is given by r_abhinav..
Those answers are correct..

once again sorry for all the confusions..
Cheers,
Sidh..

[selebratinglife]

Originally Posted by implex

New Problem!!
Given that a,b and c are roots of the equation x^3-ax+bx-c=0. find the number of ordered triplets (a,b,c)

a)0 b) 1 c) 2 d) 3 e) none of these

is it ax^2 by any chance..Just a clarification..

[implex]

Originally Posted by selebratinglife

is it ax^2 by any chance..Just a clarification..

no.. it's not . why people are asking about the question there is no problem with the question

[Hi2All]

Originally Posted by hellion

Now this leaves me confused
Can someone clear it up??

sorry for all the confusions that arised because of me...
It was me who misunderstood the question..

I wrongly interpreted the question as f-15=2m..
But ur approach was correct i.e. m=2(f-15)
As i got the answers as m=80 and f=175 which satisfied the question..
I didn't recheck my work..

The approach given by r_abhinav is correct...This is the way the problem can be understood and it should be proceeded...Thanks to u all as u rightly pointed out my mistake..

sorry once agin..

[bhavin422]

Originally Posted by getintoiimb

puys pls solve these with steps !

5)a shopkeeper calculates % profit on the buying price and another on the SP.what will be their difference in profits if both claim a profit of 20% on goods sold for Rs 3000?

ans : Rs 100

Thanks!

% profit on CP :
CP = 3000*100/120=2500. Profit = 3000-2500 = 500

% profit on SP:
profit = 20/100*3000 = 600

diff in profits = 100