official quant thread for cat08 - Page 177
PaGaLGuY.com - The Everything of MBA, CAT 2008, GMAT, XAT, IIM
         Home          MBA Forums         PG Office Blog         Contact Us         About Us                  Jobs @ PG
Exclusive Bschool Content:      Interviews      B-School Watch     MBAs speak     Placements     GMAT & MBA Abroad      Form Notifications
» Sponsors






Go Back   PaGaLGuY.com - The Everything of MBA, CAT 2008, GMAT, XAT, IIM > Exam Resources > Quantitative Questions and Answers

Notices
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

Tags: , ,

Reply
 
Thread Tools Display Modes
Re: official quant thread for cat08
Old
  (#1761)
jha16june
to err is human.
Hardcore PaGaL
 
jha16june's Avatar
 
Status: Offline
Posts: 453
Groans: 9
Groaned at 16 Times in 6 Posts
Thanks: 32
Thanked 99 Times in 77 Posts
Join Date: Apr 2005
Location: Bangalore
Re: official quant thread for cat08 - 24-04-2008, 10:55 AM

Quote:
Originally Posted by nikunj14_83 View Post
Hi all,
One brain teaser from geometry ...I ma not able to solve the same so help me out with the sol....

1)
Hexagon ABCDEF is inscribed in a circle. The sides AB, CD, and EF are each x units in length whereas the sides BC, DE, and FA are each y units in length. Then, the radius of the circle is
a. [(x^2 + y^2 + xy)/3]^1/2
b. [(x^2 + y^2 – xy)/2]^1/2
c. [(x^2 + y^2 + xy)/2]^1/2
d. [(x^2 + y^2 – xy)/3]^1/2
Answer is option a. put x=y u must get x as the answer.
Posting other 2 soon.


Keep going ...
  Send a message via Yahoo to jha16june  
Reply With Quote
Sponsored Links
Re: official quant thread for cat08
Old
  (#1762)
man_on_mission
has no status.
Hardcore PaGaL
 
man_on_mission's Avatar
 
Status: Offline
Posts: 349
Groans: 17
Groaned at 3 Times in 3 Posts
Thanks: 364
Thanked 505 Times in 164 Posts
Join Date: May 2007
Location: City where life runs @ more dan 100mph
Re: official quant thread for cat08 - 24-04-2008, 10:55 AM

Quote:
Originally Posted by nikunj14_83 View Post
Hi all,
One brain teaser from geometry ...I ma not able to solve the same so help me out with the sol....

1)
Hexagon ABCDEF is inscribed in a circle. The sides AB, CD, and EF are each x units in length whereas the sides BC, DE, and FA are each y units in length. Then, the radius of the circle is
a. [(x^2 + y^2 + xy)/3]^1/2
b. [(x^2 + y^2 – xy)/2]^1/2
c. [(x^2 + y^2 + xy)/2]^1/2
d. [(x^2 + y^2 – xy)/3]^1/2

is it a. [(x^2 + y^2 + xy)/3]^1/2

got it by taking the limiting case...put x = y and 1st option staisfies..


All that i have said about CAT

Importance of Group studies..!!
------------------------------------------------------------------------------
Desire is like circle...it has no end!!!


Last edited by man_on_mission; 24-04-2008 at 10:59 AM..
   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1763)
shikhajejani
has no status.
Newbie PaGaL
 
Status: Offline
Posts: 13
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 2
Thanked 0 Times in 0 Posts
Join Date: Feb 2008
Location: pune
Age: 23
Wink Re: official quant thread for cat08 - 24-04-2008, 10:57 AM

Quote:
Originally Posted by naga25french View Post
can u jus explain ur approach ?
i got the answer as 2^44....

oh i corrected my ans....its 2^44...
i misinterpreted it at my first attempt...



shikha
   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1764)
implex
is Bak
Certified PaGaL
 
implex's Avatar
 
Status: Offline
Posts: 2,227
Groans: 18
Groaned at 18 Times in 12 Posts
Thanks: 2,051
Thanked 2,146 Times in 851 Posts
Join Date: Jan 2008
Location: Kanpur
Re: official quant thread for cat08 - 24-04-2008, 11:02 AM

question 2) join BC and BD
and now just use the fact that angle subtended by arcs of equal length is equal
also angle subtended at centre is twice the angle at the segment

so we get
3(40+x)+x-180=0
x=15
   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1765)
man_on_mission
has no status.
Hardcore PaGaL
 
man_on_mission's Avatar
 
Status: Offline
Posts: 349
Groans: 17
Groaned at 3 Times in 3 Posts
Thanks: 364
Thanked 505 Times in 164 Posts
Join Date: May 2007
Location: City where life runs @ more dan 100mph
Re: official quant thread for cat08 - 24-04-2008, 11:06 AM

Quote:
Originally Posted by nikunj14_83 View Post
Hi all,
One brain teaser from geometry ...I ma not able to solve the same so help me out with the sol....






3)
What is the value of PR?

Choose one answer.
a. 10(5)1/2 b. 5(13)1/2 c. 20
d. 24
i think answer is c. 20

given QT = 10 and TR = 15 so QR = 25.
Now we know 3:4:5 is a pythogoras triplet....so 15:20:25 is also a puthogoras triplet...and hypotenuse is 25...

So out of the given otpion only c matches so 20 is answer...


All that i have said about CAT

Importance of Group studies..!!
------------------------------------------------------------------------------
Desire is like circle...it has no end!!!

   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1766)
gautamgomzi
has no status.
Trainee PaGaL
 
gautamgomzi's Avatar
 
Status: Offline
Posts: 54
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 49
Thanked 1 Time in 1 Post
Join Date: Sep 2007
Location: Gaya
Age: 21
Re: official quant thread for cat08 - 24-04-2008, 11:11 AM

Q.) Find the no. pf consecutive zeroes at the ned of 72! ans- 18Q.) Find the remainder when 43^197 is divided by 7. Ans- 2Q.) Find the remainder when (2222^5555 + 5555^2222) / 7. Ans- 0Q.) Find the number of divisors of 1420. Ans- 12
   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1767)
implex
is Bak
Certified PaGaL
 
implex's Avatar
 
Status: Offline
Posts: 2,227
Groans: 18
Groaned at 18 Times in 12 Posts
Thanks: 2,051
Thanked 2,146 Times in 851 Posts
Join Date: Jan 2008
Location: Kanpur
Re: official quant thread for cat08 - 24-04-2008, 11:15 AM

Quote:
Originally Posted by man_on_mission View Post
i think answer is c. 20

given QT = 10 and TR = 15 so QR = 25.
Now we know 3:4:5 is a pythogoras triplet....so 15:20:25 is also a puthogoras triplet...and hypotenuse is 25...

So out of the given otpion only c matches so 20 is answer...
answer is 10.sqrt(5)

it uses the fact that if two secants are drawn from the same point to a circle the products are same
PA.PB=PC.PD
using this
we get
(PR-r)(PR+R)=25.15
also right trianle
PR^2+r^2=25^2=625
2PR^2=1000
PR=10.SQRT(5)

option a is right
   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1768)
man_on_mission
has no status.
Hardcore PaGaL
 
man_on_mission's Avatar
 
Status: Offline
Posts: 349
Groans: 17
Groaned at 3 Times in 3 Posts
Thanks: 364
Thanked 505 Times in 164 Posts
Join Date: May 2007
Location: City where life runs @ more dan 100mph
Re: official quant thread for cat08 - 24-04-2008, 11:20 AM

Quote:
Originally Posted by implex View Post
answer is 10.sqrt(5)

it uses the fact that if two secants are drawn from the same point to a circle the products are same
PA.PB=PC.PD
using this
we get
(PR-r)(PR+R)=25.15
also right trianle
PR^2+r^2=25^2=625
2PR^2=1000
PR=10.SQRT(5)

option a is right
i don remenber tat theorem correctly ..but tat is applicable wen from xternal point two secants are drawn tat is for this problem the theorem will only be valid wen RP is extended to meet circle on circumfernece but here P is center of circle.....

Please clarify my doubt...


All that i have said about CAT

Importance of Group studies..!!
------------------------------------------------------------------------------
Desire is like circle...it has no end!!!

   
Reply With Quote
Re: official quant thread for cat08
Old
  (#1769)
implex
is Bak
Certified PaGaL
 
implex's Avatar
 
Status: Offline
Posts: 2,227
Groans: 18
Groaned at 18 Times in 12 Posts
Thanks: 2,051
Thanked 2,146 Times in 851 Posts
Join Date: Jan 2008
Location: Kanpur
Re: official quant thread for cat08 - 24-04-2008, 11:23 AM

Quote:
Originally Posted by man_on_mission View Post
i don remenber tat theorem correctly ..but tat is applicable wen from xternal point two secants are drawn tat is for this problem the theorem will only be valid wen RP is extended to meet circle on circumfernece but here P is center of circle.....

Please clarify my doubt...
man, its the thing you need to do
just extend from centre to the end of diameter.

constructions are important for geometry problems!!
   
Reply With Quote
The Following User Says Thank You to implex For This Useful Post:
man_on_mission (24-04-2008)
Re: official quant thread for cat08
Old
  (#1770)
implex
is Bak
Certified PaGaL
 
implex's Avatar
 
Status: Offline
Posts: 2,227
Groans: 18
Groaned at 18 Times in 12 Posts
Thanks: 2,051
Thanked 2,146 Times in 851 Posts
Join Date: Jan 2008
Location: Kanpur
Re: official quant thread for cat08 - 24-04-2008, 11:25 AM

Quote:
Originally Posted by man_on_mission View Post
i think answer is c. 20

given QT = 10 and TR = 15 so QR = 25.
Now we know 3:4:5 is a pythogoras triplet....so 15:20:25 is also a puthogoras triplet...and hypotenuse is 25...

So out of the given otpion only c matches so 20 is answer...
they are not asking the radius !!
so pythagoras triplet theory is futile
   
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are Off
Forum Jump

» Sponsors










PaGaLGuY.com is not responsible for the views and opinions of the posters.
PaGaLGuY.com is an Inzane Labs Private Limited production.
Hosted on servers powered by Neutral Web