[bhavin422]

Originally Posted by fidelity

I purchased a lottery ticket, but since i did not have rs 100 with me, I took a loan of rs 50 from a friend. The next week when the results were out i found that the first 5 digits tallied with the first prize but since the last digit was torn, I could not find out if i was the winner. When i contacted my friend, he told me that the six-digit number was such that its first 6 multiples had the same 6 digits in different orders. But for this piece of information and the loan he demanded half the prize money from me. What was the last digit?

1) 2 3) 5
2) 4 4) 7

is d ans 7 ??

my logic...since d 6th multiple of six digit no is six digit, 1st no is 1...
i.e one of the first 6 multiples of 2/5/4/7 has to end with 1...
only no 7 satisfies this condition ...hence it should be 7...

i may be completely wrong..pls correct me ??:

[dashing]

Originally Posted by fidelity

I purchased a lottery ticket, but since i did not have rs 100 with me, I took a loan of rs 50 from a friend. The next week when the results were out i found that the first 5 digits tallied with the first prize but since the last digit was torn, I could not find out if i was the winner. When i contacted my friend, he told me that the six-digit number was such that its first 6 multiples had the same 6 digits in different orders. But for this piece of information and the loan he demanded half the prize money from me. What was the last digit?

1) 2 3) 5
2) 4 4) 7

Answer 7

Logic

for the other options the last digit got for the multiples is repeating
but for seven it comes as
7
4
1
8
5
2

where all the digits are diff

[fidelity]

Originally Posted by bhavin422

is d ans 7 ??

my logic...since d 6th multiple of six digit no is six digit, 1st no is 1...
i.e one of the first 6 multiples of 2/5/4/7 has to end with 1...
only no 7 satisfies this condition ...hence it should be 7...

i may be completely wrong..pls correct me ??:

Hi...U r completelyright .....The ans is 7 and the number is 1,42,857 which is a 6 digit number occurring in a cyclic form.

[eric.segal1]

pg 253 Qn 43 Arun Sharma
In a box there are
5 red balls
4 blue balls and
3 green balls
In how many ways can we select 4 balls out of it if all the balls in a box are identical?
Puys the answer given is 495 but i dont know how to get to it.
Plz help

[bhavin422]

Originally Posted by eric.segal1

pg 253 Qn 43 Arun Sharma
In a box there are
5 red balls
4 blue balls and
3 green balls
In how many ways can we select 4 balls out of it if all the balls in a box are identical?
Puys the answer given is 495 but i dont know how to get to it.
Plz help

is this a complete question? 4 balls can be selected from 12 balls in 12C4 ways= 495

is this so simple or am i overlooking smtng

[frndngl]

Hey avinav,................
buddy......
wats the cut off of SIIB??????????????

[avinav2712]

Originally Posted by frndngl

Hey avinav,................
buddy......
wats the cut off of SIIB??????????????

Yaar plz watch the thread where you're posting.... There's a separate thread for SIIB as well.... Anyways, just answering your query now.... SIIB didn't declare any cutoff but should be around 75 for General category

[the_hate]

Originally Posted by eric.segal1

pg 253 Qn 43 Arun Sharma
In a box there are
5 red balls
4 blue balls and
3 green balls
In how many ways can we select 4 balls out of it if all the balls in a box are identical?
Puys the answer given is 495 but i dont know how to get to it.
Plz help

i feel ans given by arun sharma is wrong...
12C4=495
the reason->

suppose we have 5 red balls as R1 R2 R3 R4 R5

in all the ways to select 4 balls-there will be also few ways where all 4 are red balls...
so, there will be R1 R2 R3 r4 and R2 R3 R4 R5 among those cases
but the problem is that all the balls are identical...that means we can not identify which 4 balls we have choosen....
or in other words, no of ways to select 4 balls where all 4 are red = 1

simply we have to distribute 4 in R B G
R B G
0 4 0
0 3 1
0 2 2
0 1 3
-------------------->0 0 4 missing as max no of G balls =3
1 0 3
1 1 2
1 2 1
1 3 0
2 0 2
2 1 1
2 2 0
3 0 1
3 1 0
4 0 0

if suppose we take 3rd case->
2B, 2 G balls-> no of ways to select 2 blue balls out of 4 identical blue balls and 2 green balls from 3 identical green balls =1 (as all balls are same)

that is total no of ways = 14

though i am not able to express myself clearly...but i am sure that this is correct(saving any calcln mistakes)

-----------------------------------------------------------------------------

if he had said all balls are different- then ans would have 12C4 as 5 diffent red balls,4 different blue balls is equvalent to 9 different balls....then the colour won't matter...

[Fuzon]

I am not sure about the concept that the_hate has applied ..... i think its plain simple combinatin prolblem with answer being 12c 4 - some enlightened soul please throw light on any misunderstadings or flawed reasoning

[manu hoysala]

Originally Posted by Fuzon

I am not sure about the concept that the_hate has applied ..... i think its plain simple combinatin prolblem with answer being 12c 4 - some enlightened soul please throw light on any misunderstadings or flawed reasoning

the_hate has explained in the best possible way and I cannot do better than that. But I will try and change the words.Lets see if you agree to this.
Assume the 5 red balls are numbered 1,2,3,4,5 and they are identical(numbers just for ur understanding).
Now the way in which you can pick 4 balls out of the 5 is not 5C4 since all the balls are identical. So it doesnt make a difference if you pick 1,2,3,4 or 2,3,4,5. Both these combinations are considered the same. so the no of ways you can pick 4 balls is 1.
Hope you are convinced by this.