[vineet.nitd]

Puys ...This thread i am opening for discussing problems of higher difficulty level .Intresting and lovely problems .

Those people who are intrested to participate on this thread can come here ..rest can seek help if they need and the other junta can stay away if they feel its irrelevant wrt there requirements .


I will post all the basics for Higher Algebra , Geometry , Numbers.. time to time ..So i feel it will benefit every one in some way or the other ..depending upon what they want to filter out from here .

We wil discuss stylish methods ....graphical ..analytical nd all..


I would sugget mba aspirants to peep in often and if intrested be active on this thread ...Should help a great deal...


For regular Maths lover..i hope it proves an excellent place to fine tune and enhance there skills to a greater level ....

I would request not to spam with irrelevant sums and posts .

Hope to cyah all active here .......All da Best .... :satisfie:

[varun nakra1]

Wats the purpose of this thread??to discuss concepts or to discuss quesns,which are relatively tuff as far as the mba xamz are concerned??

[varun nakra1]

If it is the latter(posting good quesns) then lemme start with two of mine

1)If x<1 then prove that

(1-2x)/(1-x+x^2) + (2x-4x^3)/(1-x^2+x^4) + (4x^3-8x^7)/(1-x^4+x^ + ....................infinitely = (1+2x)/(1+x+x^2)



2)Two points are taken at random on the given straight line AB of length 'a'. Prove that the probability of their distance exceeding a given length 'c' (<a) is equal to (1-c/a)^2.

[warrior]

Originally Posted by varun nakra1

Wats the purpose of this thread??to discuss concepts or to discuss quesns,which are relatively tuff as far as the mba xamz are concerned??

I believe it should be both.

Discuss topics like
1. Coordinate Geometry - Ellipse, Parabola, hyberbola
2. Trigonometry - Inverse Trigonometry
3. Calculas - Functions, Limits,Diffrentiation, Integration, Diffrential Equation, Area under the curve
4. Vectors
5. Complex numbers
6. 3-D geometry
7. Binomial theorem
8. Probability
9. Induction
10. Convergence and Number series

and all other topics which we have studied in 12 but just lost the touch.

Let the party begin

[vineet.nitd]

Originally Posted by varun nakra1

Wats the purpose of this thread??to discuss concepts or to discuss quesns,which are relatively tuff as far as the mba xamz are concerned??

Varun , this thread will not be limited by the MBA stuff ...I am planning to touch high levels of maths ..Thats y i have told ..participate only at ur own discretion .

Remember the mindblowing thread started by sumit khanna ...We can make this thread start on the same lines ....Discuss concepts ... and solve olympiad level questions at ease ...

In short we will try to do R&D and explore the beauty of the subject .

Hope the purpose of the thread is clear to you

[varun nakra1]

Originally Posted by vineet.nitd

Hope the purpose of the thread is clear to you

theek hai..main do quesns se agaaz kar chuka hoon thread ka....

Ill chip in with more after these hav been cracked..yes it will be an njoyable nd a knowledgeable thread

[Aarav]

I felt intimidated by the title of this thread. Will try to keep pace with you all. Take my contribution to this thread from this question.

Let a, b be whole numbers such that ab = 72. Let a^b denotes a raised to the power of b e.g. 4^3 = 64. For what b does b^(a^1/2) takes the max value?

(a) 6 (b) 8 (c) 9 (d) none

[warrior]

Originally Posted by Aarav

I felt intimidated by the title of this thread. Will try to keep pace with you all. Take my contribution to this thread from this question.

Let a, b be whole numbers such that ab = 72. Let a^b denotes a raised to the power of b e.g. 4^3 = 64. For what b does b^(a^1/2) takes the max value?

(a) 6 (b) 8 (c) 9 (d) none

take a= 72/b and sub in second eq y = b^(a^1/2). Take log on both sides and diff

we get b= e^2 ( b= 7.46 and a = 9.64) and b= 1

obviously we have min at b= 1 and max at b= 7.46

so any of 6 and 8 can give max

b=6 a= 12 a^1/2 = 3.46 y= 492
b=8 a=9 a^1/2 = 3 y= 512

so max at b= 8

[warrior]

Originally Posted by warrior

take a= 72/b and sub in second eq y = b^(a^1/2). Take log on both sides and diff

we get b= e^2 ( b= 7.46 and a = 9.64) and b= 1

obviously we have min at b= 1 and max at b= 7.46

so any of 6 and 8 can give max

b=6 a= 12 a^1/2 = 3.46 y= 492
b=8 a=9 a^1/2 = 3 y= 512

so max at b= 8

here's the graph for tha same

[Aarav]

Originally Posted by warrior

take a= 72/b and sub in second eq y = b^(a^1/2). Take log on both sides and diff

we get b= e^2 ( b= 7.46 and a = 9.64) and b= 1

obviously we have min at b= 1 and max at b= 7.46

so any of 6 and 8 can give max

b=6 a= 12 a^1/2 = 3.46 y= 492
b=8 a=9 a^1/2 = 3 y= 512

so max at b= 8

Kudos to you for your solution :-)

I'm happy by the initiatives taken by some of you to start this thread, but if possible please change the title of this thread. Don't scare the newbies

Continue and Enjoy :-)