pls help me with the solutions to these
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pls help me with the solutions to these
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pls help me with the solutions to these - 13-05-2006, 11:23 PM

hi...
Please look into the following...
1. If the price of sugar reduces by 10%, I can buy 17 Kg more sugar for Rs.612. What is the reduced price of Sugar/Kg?
a. Rs 4 b.3.6 c.4.4 d.17

2. if amit uses a parker pen, then his essay will look good and people will appreciate his essay. If Amit's essay does not look good,....
a. amit does not use a parker pen. b. ppl will not appreciate his essay. c. both 1 and 2 d. insufficient data

3.for a scholarship, at most n candidates out of 2n+1 can be selected. if the number of different ways of selection of at least one candidate is 63, the maximum number of candidates that can be selected for the scholarship is
ans. 3

4. whenever rajeev uses the internet, he dreams about spiders....
A. he did not dream about spiders.
B. he used the internet
C. He dreamt about spiders
D. he did not use the spiders
a. AD b.DC c.CB d.DA
ans is a
5. A hemispherical roof is on a circular room, inner diameter of the roof is equal to the height of the room. if 48510cm^3 air is inside the room, find the height of the room.
ans. 42 cm
6. the average of three prime numbers is 223/3. what is the difference between the greatest and smallest number?
a.8 b.16 c. inadequate data d. none
7. convert 1101.011 from base 2 to base 10
ans 13.357
8. if 1+2+3+4+5+6+7+8+9+10=100 then in how many places do u need to change + with x to make the equality hold good?
a.2 b.4 c.3 d. none

9. at a certain rate 15320 becomes 30640 in 6 years. what is the roi?
ans. 12%
10. the difference in CI and SI for 2 years at 10% is 450. wht is the Principal?
ans. 45000

thanks in advance to anyone who responds. u'll be a great help. Also does anyone of you have any softwares or methods to learn tables. I am mainly looking for tables in the range 15-30. Any flash card or softwares will be a definite help to me. please send me info on that too.
   
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Re: pls help me with the solutions to these
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Re: pls help me with the solutions to these - 18-05-2006, 12:32 PM

Here is the solution to the first problem:

In the question the price has gone down by 10%. This means tht the price is now 9/10 th of the original price.

Now you need to understand tht price and quantity are inversely related. More the price, lesser the quantity u can buy with the same amount of money and vice versa.

So if price becomes 9/10th, the quantity that I can buy must become 10/9 times of this original quantity.

To simplify things let x kg be the original quantity bought.
Then after reducing the price I can buy 10x/9 kg.

How much extra do I buy now? That is 10x/9 - x = x/9 kg

But according to the question the additional amount bought = 17 kg.

Therefore x/9=17 which gives x=153 kg.
That is originally I was buying 153 kg for Rs.612 which gives the original price of sugar to be 612/153= Rs 4/kg.

But now the price has reduced by 10% which means a reduction by 10% of Rs. 4 i.e. Rs. 0.4.

So the new price is 4 - 0.4 = Rs. 3.6

Hence option (b) is the correct answer.
   
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Re: pls help me with the solutions to these - 18-05-2006, 12:35 PM

we have similar thread running

seacrh them here

www.pagalguy.com/forum/search.php


Read what I went through to reach IIMC here and continues here
Know what am I going thru in IIMC here
I am off PG...please dont PM me
   
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Re: pls help me with the solutions to these - 18-05-2006, 01:17 PM

Here is the solution to the tenth problem:

What u need to understand here is that for one year the SI as well as the CI are equal. But for two or more years they are different. Let's see the reason for this.

During the second year SI gives U interest only on the principal amount.
But during the second year CI gives U interest on the principal amount as well as the interest of the first year.

To simplify:

For two years:

Total SI = (SI for year 1) + (SI for year 2)
Total CI = (SI for year 1) + (SI for year 2) + (SI on SI for year 1)

Remember it may take u a while to get hang of this, but what I've written here is correct and even if U have to memorize it, do it bcus this is a standard type of problem.
So the difference in the final interest in SI or CI is due to the above reason only.

Now in the above problem difference between SI and CI is Rs 450.
This difference must be due to the interest on the interest of the first year.

At 10% if the interest on first year's interest is rs. 450 the first year's interest must be Rs. 4500.

Now if first years interest is Rs. 4500 at 10% then the pricipal must be Rs. 45000 which is the required answer.
   
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Re: pls help me with the solutions to these
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Re: pls help me with the solutions to these - 18-05-2006, 01:20 PM

If U want solutions to any more problems first post in a comment whether U are finding my help useful or not.

I don't want to waste my time if it's not useful to anyone.

I'm asking U to do this bcus I need to be sure that U're still there on the forum and still need my help.
   
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Re: pls help me with the solutions to these - 19-05-2006, 11:09 PM

Quote:
Originally Posted by sidxxx
If U want solutions to any more problems first post in a comment whether U are finding my help useful or not.

I don't want to waste my time if it's not useful to anyone.

I'm asking U to do this bcus I need to be sure that U're still there on the forum and still need my help.

Hey sidxx, my mistake!!
I should have posted a BIG THANK YOU without u having to ask 4 it... u truly are a great help and I am closely following all the solutions u post... its truly a great way to discuss our problems here online and not having to keep searching for solutions who might not be able to solve themselves.... plz keep posting .. I am sure they are a help to others also.
amitnsitian, can u post the link to the thread u are refering to?
   
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Re: pls help me with the solutions to these
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Re: pls help me with the solutions to these - 20-05-2006, 02:35 AM

Here is the solution to the seventh problem:

Now in order to convert any number from base 2 to base 10 U need to follow the following procedure wherein first of all U need to understand the following pattern:

......digit2 digit1 digit0 . digit(-1) digit(-2) digit(-3)........


U must carefully note that I have numbered the digits to the left of the decimal point as 0,1,2 and so on while on the right hand side of the decimal as -1,-2,-3 and so on.

Actually these digits represent powers of 2 with which we we will multiply them. It will be better to understand this with the solution of the above problem.

The answer has to consist of two parts: the one before the decimal and the one one after the decimal.

Let us first calculate the part before the decimal. The given number is 1101.011. The part before the decimal is 1101.

Now starting from the rightmost digit of 1101 multiply the digits of 1101 by increasing powers of 2 as 2^0, 2^1, 2^2and so on and add. So it becomes

(1 x 2^3) + (1 x 2^2) + (0 x 2^1) + (1 x 2^0)

= 8 + 4 +0 +1
= 13 which is the required answer before the decimal.

For the the part after the decimal U need to multiply by -ve powers of 2. So the part after the decimal is 011 which gives

(0 x 2^(-1) ) + (1 x 2^(-2) ) + (1 x 2^(-3) )

which is equivalent to

(0 x 1/2) + (1 x 1/4) + (1 x 1/

=0 + .25 + .125
=.375 which is the answer to the right of the decimal.

Combining the two results the final answer is 13.375 which is the required answer (not 13.357 what U've given here).

To simplify things just take a look below:

Digits: 1 1 0 1 . 0 1 1
Multipliers: 2^3 2^2 2^1 2^0 2^(-1) 2^(-2) 2^(-3)

i.e. 8 4 2 1 1/2 1/4 1/8

Increasing Decreasing
powers of <<---- ---->> powers of
2 2
   
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Re: pls help me with the solutions to these - 20-05-2006, 11:15 PM

hey thanks Sid
U are really a great help... keep pouring the solutions.
I found it rather strange (and somewhat amusing) that people with hundreds of posts on this forum (who actively participate in most discussions) did not respond and post any solutions whereas a guy with hardly 4-5 posts has helped me wonderfully. . Guys are you all too comfortable with these problems and don't really find them worth it? Or is it just a matter of priorities?
   
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Re: pls help me with the solutions to these - 27-05-2006, 02:00 PM

Quote:
Originally Posted by anupamjain008
........................
thanks in advance to anyone who responds. u'll be a great help. Also does anyone of you have any softwares or methods to learn tables. I am mainly looking for tables in the range 15-30. Any flash card or softwares will be a definite help to me. please send me info on that too.
exactly what kind of s/ws r u looking for????
i'm attaching some files which i have...check them out n c if u find them useful.
there's a "tables"file, of which i've taken many printouts and pasted them all over the walls of my room(isin't that a good method????)

also, check out this thread-"desktop dictionary" in English prep. resources.
its an excellent s/w.

Disclaimer: these files r not my creation...its from a similar MBA prep. site...
and i just want to share them. So, no complaints.
Attached Files
File Type: zip prep.zip (122.7 KB, 57 views)


"Imagination is more important than Knowledge"
Mai website: http://ravishankar.s5.com
   
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Re: pls help me with the solutions to these
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Re: pls help me with the solutions to these - 27-05-2006, 06:12 PM

Quote:
Originally Posted by ravikalluri
exactly what kind of s/ws r u looking for????
i'm attaching some files which i have...check them out n c if u find them useful.
there's a "tables"file, of which i've taken many printouts and pasted them all over the walls of my room(isin't that a good method????)

also, check out this thread-"desktop dictionary" in English prep. resources.
its an excellent s/w.

Disclaimer: these files r not my creation...its from a similar MBA prep. site...
and i just want to share them. So, no complaints.

hey thanks
Exactly the material I was looking for, though I'd like a feature in your calculations software to restrict questions till 30x10. Thats because I (and most others) have learned tables till 30x10 and want to build on them ... so please see if someone has that kind of software.
   
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