[LIFE HEDGER]

Originally Posted by chetna

hey can anyone solve this one for me:-

Q.If in a certain code COVET is written as FRYHW,which word would be written as SHDUO?

1)QUAKE
2)REPAY
3)VKGXR
4)PEARL

cheers,
chetna

friend..the answer is 4th option.....

from the two related codes given....we infer that every alphabet of rewritten code is 2 count + than the previous alphabet.......

so for SHDUO.......find S - 2 = P.............U - 2 = R.....and hence forth....


lh

[kittuj]

Chetna the answer is the 3rd option.
Each alphabet is being replaced by the alphabet coming 3rd after it lik A is replaced by D,B by E etc so
SHDUO bcomesVKGXR:satisfie:

[kittuj]

Originally Posted by kittuj

Chetna the answer is the 3rd option.
Each alphabet is being replaced by the alphabet coming 3rd after it lik A is replaced by D,B by E etc so
SHDUO bcomesVKGXR:satisfie:

Who then are the true philosophers?
Those who are the lovers of the vision of Truth. Plato

[chetna]

Originally Posted by LIFE HEDGER

friend..the answer is 4th option.....

from the two related codes given....we infer that every alphabet of rewritten code is 2 count + than the previous alphabet.......

so for SHDUO.......find S - 2 = P.............U - 2 = R.....and hence forth....


lh

absolutely right!!!

i m such a dumb person ...i didnt notice this "which word should be written as".

i simply thot i have to find the code for SHDUO...

thanks a ton.
u guys also kindly keep posting reasoning problems....

[chetna]

Originally Posted by kittuj

Chetna the answer is the 3rd option.
Each alphabet is being replaced by the alphabet coming 3rd after it lik A is replaced by D,B by E etc so
SHDUO bcomesVKGXR:satisfie:

hahaha

kittuj,u also did the same mistake...
we dont have to find the code for SHUDO...read the question again

tc
p.s-plz post some problems

[chetna]

ok friends
try this:-

Q.There is a five digit number.The fourth digit is 4 greater than second digit ,while thrid digit is 3 less than the second one.first digit is thrice the last one.There r three pairs whose sum is 11.find the number(consider the numbering from the right)

a)35291
b)65292
c)63072
d)95293

enjoy!!!

[siddhesh_j]

Originally Posted by chetna

ok friends
try this:-

Q.There is a five digit number.The fourth digit is 4 greater than second digit ,while thrid digit is 3 less than the second one.first digit is thrice the last one.There r three pairs whose sum is 11.find the number(consider the numbering from the right)

a)35291
b)65292
c)63072
d)95293

enjoy!!!

numbering shud be from left
my ans option b 6+5 , 9+2 and 9+2 again ... there are 2 twos

[chetna]

Originally Posted by siddhesh_j

numbering shud be from left
my ans option b 6+5 , 9+2 and 9+2 again ... there are 2 twos

ya it shud be left indeed but i got this question from BRM test IMS....anway forget that part...

i just wanted to know the pairs

i had taken 9+2 only once and hence i was not getting 3 pairs...now i got it ...thank u

[chetna]

here is another one:-

Q.A numerical machine accepts two values X and Y.Then it updates these values as X=XY and Y=Y+1 in every step.The machine stops at X>=N

if X=2 and Y=3,what should be the minimum value of N such that final value is Y is 7?
1)300
2)360
3)720
4)860

cheers,
chetna

[ernil]

nice method.