Neha's *Fundu* Section - Page 26
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Re: A cyclic number!!
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navigator09
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Re: A cyclic number!! - 22-06-2007, 02:45 PM

Quote:
Originally Posted by gokulrajulapati View Post
Hi All,

If you find any more no's like this please post it here.
would like to know what propertiesdoes those no's have?

thanks and regards,

Go Cool
mainFuncFN()
hey notice that the number is 1/7 =14.2857 %

So, 2/7=28.5714
3/7=42.8571
and so on..

So summerizing,
to find any multiple of 1/7 multiply 14 by that multiple, and then apply the cyclic rule..

this can be particularly help full in DI
   
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Re: Important Table
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Question Re: Important Table - 11-09-2007, 07:02 PM

Quote:
Originally Posted by pagalneha View Post
ok i don't mind that at all will keep on adding all i have regularly. u can rename it. its good for me.
Hi Neha

I am applying for pg in fashion management 2008 from NIFT.
Pls advise how to prepare for the entrance exam...
what books to refer, any other study material, past papers etc.

Hope to get some useful info from u.

Thanks in advance
   
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Re: Neha's *Fundu* Section
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Re: Neha's *Fundu* Section - 20-09-2007, 12:54 PM

he guys can any explain me

how AM is always greater than HM

I MEAN TO SAY
if the no are 0.2,0.3,0,4,0,5.....

then what is AM>HM
   
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Re: Neha's *Fundu* Section
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STALWART
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Re: Neha's *Fundu* Section - 05-12-2007, 02:21 PM

Quote:
Originally Posted by go2sumeet View Post
he guys can any explain me

how AM is always greater than HM

I MEAN TO SAY
if the no are 0.2,0.3,0,4,0,5.....

then what is AM>HM
If yah mean to say .. numbers are .... 2/10 , 3/10, 4/10, and 5/10 .. assuming "." instead of "," ..... And I think the assumption is right !!

Ok lets find AM first ....

AM = ( 2/10 + 3/10 + 4/10 + 5/10 ) / 4 = 56/10 = 5.6 ............... (1)

Now for HM lets make groups ....

1) 2/10 HM1 3/10
2) 4/10 HM2 5/10 and
3) HM1 HM HM2

here HM will be the final answer .....

1) Let 2/10 HM1 3/10 are in hormonic progression

==>> 10/2 1/HM1 10/3 are in Arithmatic progression
==>> 2/HM1 = 10/2 + 10/3
==>> HM1 = 12/50

Similarly .....
2) HM2 = 40/90

Now ...
2) 12/50 HM 40/90 are in HP

==>> 50/12 1/HM 90/40 are in AP.
==>> 2/HM = 50/12 + 90/40

==>> HM = 240/770 ~~ 0.3117 ............. (2)

On comparing (1) and (2)
(1) > (2)

==>> AM > HM

.. Sayonara
   
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Re: Neha's *Fundu* Section
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Talking Re: Neha's *Fundu* Section - 23-12-2007, 08:56 PM

hey puys..leave this posting..i just wanna subscribe this thread.

Wishing u al a


R@KsRoX


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Re: Neha's *Fundu* Section
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Re: Neha's *Fundu* Section - 10-01-2008, 12:38 PM

Hey guys,
Can anyone tell me where to find the soultions to the problems posted in this thread. Thanks in advance.

Last edited by nightwalker; 10-01-2008 at 03:24 PM.
   
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Re: Neha's *Fundu* Section
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Re: Neha's *Fundu* Section - 13-04-2008, 01:46 PM

dfdf
   
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Re: Neha's *Fundu* Section
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Re: Neha's *Fundu* Section - 16-05-2008, 09:34 AM

Good Neha...
This thread will be of a great help to me.....as well as other puys
Its been a long time since i have touched my maths books...
and i love maths...
So i would love to subscribe to this thread
and will try to solve some of the queries here ...lets c if my knowledge is of some help to ppl here...

Keep posting ....

Regards
Tanu Panwar
   
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Re: Neha's *Fundu* Section
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Smile Re: Neha's *Fundu* Section - 01-07-2008, 12:35 PM

i want to know the dates of application of the various mba exams.
can anybody help me...
is there any link which lists out all important dates regarding application and
date of examination....
   
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Re: Neha's *Fundu* Section
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Re: Neha's *Fundu* Section - 10-07-2008, 02:46 PM

i am not clear with the above table
   
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