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Neha's *Fundu* Section
Prep Resources Share and discuss exam related resources. GDs, PIs, GK, Study Notes, URLs etc. Use this forum to share information which is not related to any specific exam.

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  (#201)
richa bhatia richa bhatia is offline
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Re: Neha's *Fundu* Section - 09-06-2006, 08:09 PM

Quote:
Originally Posted by gaurav200x
Can u post the complete question, as to what are they doing.. running a rac or what. Please give the link to that question.. then it would be easy to find the answer.

Regards,
Gaurav
The question is same as above..
its post no 11 ,1st page of this thread only..
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Re: Neha's *Fundu* Section - 09-06-2006, 10:04 PM

Quote:
Originally Posted by richa bhatia
2. Ajay and Vijay are at a distance of 100 mts., when 3rd time they meet ,they are at a distance of 20mts from Vijay’s side and each of them have completed at least 100 mts., what are the ratio of the speed of Ajay and Vijay.

sum1 had posted dis ques as doubt in QQAD thread..
i had few doubts..

according to me vijay wud have travelled 180 m and ajay 280 m..
so den ratio of their speed wud be 280/180=14/9

here i m attaching a fig which shows d path dat wud b followed by ajay n vijay.. P, Q , R are the three meeting points black lines show the path followed by ajay n the red ones show the path folowed by Vijay..(my drawing is very bad.. )

please tell where i am making mistake...


Leave this question !!



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  (#203)
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Re: Neha's *Fundu* Section - 09-06-2006, 10:13 PM

Quote:
Originally Posted by richa bhatia
The question is same as above..
its post no 11 ,1st page of this thread only..
Well Richa, assuming that the guys are travelling with uniform speed and they're travelling back and forth, Ajay would have travelled 280 mts and vijay would be 220 (100+100+20)

and hence their speeds should be the ratio of the distance covered in that time interval... = 280/220 i.e. 14/11

wat do u say? watz the correct answer?


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Re: Neha's *Fundu* Section - 10-06-2006, 04:20 AM

Quote:
Originally Posted by gaurav200x
Well Richa, assuming that the guys are travelling with uniform speed and they're travelling back and forth, Ajay would have travelled 280 mts and vijay would be 220 (100+100+20)

and hence their speeds should be the ratio of the distance covered in that time interval... = 280/220 i.e. 14/11

wat do u say? watz the correct answer?
d answer given was same as yours..
par i had d doubt why not d dist travelled by vijay is 180m and by ajay 280m.. as dis cud also b the posibilty (dis i tried 2 show in d attachment attached in d previous post)
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Re: Neha's *Fundu* Section - 10-06-2006, 01:12 PM

Quote:
Originally Posted by richa bhatia
d answer given was same as yours..
par i had d doubt why not d dist travelled by vijay is 180m and by ajay 280m.. as dis cud also b the posibilty (dis i tried 2 show in d attachment attached in d previous post)
well richa, actually ur diagram wasnt very clear

however picturize this.. Ajay is at point A and Vijay at pt B.... They meet 1st time and interchange their positions. They again meet and ar back to their repective points (which they were initially.. though not at the same time, as they travel with different speeds).

Till this time, they have covered 200 mts each. When they finally meet, ajay covers 80 mts and it is 20 mts from vijay's starting pt... So ajay covers 280 mts and vijay covers 220 mts...

Hope it is crystal clear now!!


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Re: Neha's *Fundu* Section - 16-06-2006, 04:51 AM

just how do i use the table that fast neha?
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Re: Neha's *Fundu* Section - 20-06-2006, 10:31 AM

Hey Neha & all
I m new to CATMANIA
finding the stuff grt
but a lot of probs are widout answer
are they available el;sewhere
pl. help
thanks again

Quote:
Originally Posted by pagalneha
1. A product is made by mixing two kinds of metals in the ratio of 1:3 and the costs are in the ratio of 5:2. If it is sold at 50% profit to the retailer, who adds 25p and sells it at Rs. 8.50 per Kg. What is the C.P. of each per Kg.
2. Raghu wanted to sell something at a profit of 15%, then his C.P. decreased by 5.Raghu decided to earn a profit of 20%, but in totality he received Rs. 3000 less than before. What was the C.P. of the article.
3. If a shopkeeper marks his goods 50% above the C.P., but he gives 2 articles free if a person purchases 20 articles. Further the shopkeeper gives a discount of 10%. I a customer bought 230 Articles. What is the profit%.
4. I bought 40 lts. Of milk for Rs. 600, when I went to sell it, I made a loss of as much money, which I received by selling 10 lts, what is my S.P.
5. A company invested Rs. 200 crores. Manufacturing cost comes to Rs. 6000 per unit for the 1st 10000 units, after that it reduces to 5000 per unit. If it is being sold at Rs. 8000 per unit, what is the break even point in terms of unit and in terms of sale.
6. A company manufactures computer chips in lots of Rs 100, if any defective chips found, the co. has to pay Rs. 50 per chip, so it can give its chip s for checking , 1st co. charges Rs. 2000 for checking 100 chips, but it can correct only 80% of the chips, another company charges Rs3000, but it corrects all the chips.
a. upto how many wrong chips per 100 we shud not use any rectification process.
b. At what level we should prefer 2nd rectification process over the 1st.

7. A contractor hired 30 men to complete a job in 50 days with 8 hrs, of working, 30 days passed and only 25% work was complete. He called some extra worker and made them work for 12 hrs in a day and he completed the work in time, How many more men did he employ.
8. A can finish a work in 9 days , B in 15 days, after how many days B should join so that work is completed on the 6th day.
9. 5 women & 7 men can complete a work in 8 days, 3 women & 10 men complete it in 6 days, then 10 men and 10 women will complete the work in how many days.
10. In a garrison there is food for 10000 men and it lasts for 1 month if 2kg per head is given everyday. Due to a war 10000 more men join and ration was reduced to 1.5 kgs. And the food got over by 10th day. If instead of 10000 men 5000 men would have joined and the earlier supply would have continued. Than food would have lasted for how many days.
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Re: Neha's *Fundu* Section - 20-06-2006, 03:32 PM

Quote:
Originally Posted by pagalneha
SIMPLE INTEREST AND COMPOUND INTEREST.


Here’s a table for calculating SI and CI
------------------ S.I. ------------- C.I.
1--------------------S -------------Upto S
2------------------2S--------------- Upto 2S+X
3------------- -----3S--------------- Upto 3S+3X+
4--------------------4S ------------ Upto 4S=6X++
5--------------------5S ------------ Upto 5S+10X+++
6-------------------6S ------------ Upto 6S+15X+++

“++” it roughly takes a value of Rs. 2 for Rs 100 of X.

Q. the difference between CI and SI is Rs 9848 at 8% interest put out for 4 yrs. What ids the principle?

Method-
For 4 yrs. The value that corresponds is 6X++
So 6X++ = 9848
Here we divide the amt. by 100 and ignore the decimal part so we get 98 and now we subtract 2 from it and now we get 96
So 6x =96 , x =16
8% of SI= 16
So 1% of SI = Rs. 2.
100% of SI =200
200 is 8 % of principle therefore the principle is 2500.
-------------------------------------------------------------------------------------------------------
-------------"
guys this was a post by neha .. i cudnt understand this method.. how can the difference b/w the S AND C interest be 4 times the principal at 8%(i mean even if u calculate interest in a normal way i.e. by using proper formula. u dont get this answer of 984. explain it in detail if u understand it.
thnx

cheerz
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Re: A cyclic number!! - 21-06-2006, 01:21 PM

Hi all
Fundoo funda for reciprocal of 7
1/7=0.142857
2/7=0.285714
3/7=0.428571
4/7=0.571428
5/7=0.714285
6/7=0.857142


Got it
it is in cyclic order
byeeeeeeeee
142857*5=714285
142857*6=857142

Could anyone explain the reason!!Or in more general terms suggest how to find more more cyclic numbers!!!:crazyeye:
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Re: Neha's *Fundu* Section - 24-06-2006, 01:55 AM

picture this

1/11 = .0909
2/11 = .1818
3/11 = .2727
.
.
23/11 = 2.0909
.
.
N/11 = m . (rem)9 where m is whole num quotient(less decimal) obtaind by N/11
eg. 0 for 1 to 10 and rem is d remainder(in two digits) when N is divided by 11

eg. 23/11 = 2 . (01)9 = 2.09090909

although looks pretty big...but thtz just 2 explain...

ciao


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