Hi,
your reported the reply

Pasting is again to save your hard work!
Good Luck
"this is a technique which has been passed to me by a senior--@naga25 french
the pattern says if nos are repititive
for ex:1212121212....300 times and divided by 99
thn from right konsider two sets
like 12 and 12 and add thm i.e.=24
so thy will get repeated 75 times (300/4 sets )
now 24 *75=1800
1800/99=18.1818
18 is the remainder
similarly
if we get the same qstn but didvided by 999
we will do 121 +212=333
333*50
thn 333*50=16650/999
remainder is 667 or 666
if the same no is divided by 9 thn take 1+2=3
3*150.....and go on the same way
basically if we konsider d sekond case
121212= 121000+212= 121(999)+121+212=121*999+333
remainder for first 6 digits is 333.